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Amazing explanation Sir 😊

Good

Time shud be 20 secnd mentalky to solve tbis q

Nice explanation. 🎉

^=read as to the power3 *=read as square root As per question *{1+*(1+t)}=t^(1/3) Takeing the square of the given equation I got the following 1+*(1+t)=t^(2/3) *(1+t)=t^(2/3) -1........eqn1 Take the square of eqn1 1+t=t^(4/3)+1- {(2×t^(2/3)} So, t=t^(4/3) -{2×t^(2/3)} t=t[t^(1/3) - {2×t^(-1/3)} t/t =t^(1/3) -{2/t^(1/3)} Let t^(1/3)=R, So t/t=R -(2/R) 1=(R^2- 2)/R R=R^2 - 2 R^2 - R - 2 =0 Here a=1, b=-1, c=-2 D = b^2 - 4a c =(-1)^2 - (4×1× -2) =1+8=9 *D=*9=3 a= (-b±*D)/2a ={-(-1)±3}/2 = (1±3)/2 So, a=(1+3)/2 or2 (1-3)/2 a=4/2 or a = -2/2 a=2 or a= -1 If a=2, then t^(1/3)=2 {t^(1/3)}^3=2^3 t=8 If a= -1 t^(1/3)=(-1) {t^(1/3)}^3=(-1)^3 t= -1 Hence t=8 or (-1) 1

Did in my mind with ease

I found it from google❤

Thank you

I found another way. x^x=x->x*In|x|=In|x|->x*In|x|-In|x|=0->In|x|(x-1)=0->In|x|=0 v x-1=0->|x|=e⁰ v x=1-> |x|=1 v x=1->x=-1 v x=1(X2)

Thank you very much sir

Nice vid

The problem is strange, because the possibilities of X are open, we just need to adjust the value of Y if X = 2 9 + 16 = 5^2*1 25 = 25 If X = 3 27 + 64 = 5^3*2*1,3964 And so one Bingo from Brasil!

If n is non positive integer we consider - 1 and 0 am i right?

Why did I get 243256.35 😢

Nice 👍

Very easy trick sir

❤❤❤

Solved in seconds

P=18 q = 0. P+q = 18

Very nice question sir

Best teacher

Good explanation sir

Wow

Aou Sir limit derivative kichi bujha paduni😢

Excellent 😂

Masta Question with nice solution

Clearly understand Sir

Thanks sir

Nice solution

Sir try to upload more videos

Thanks sir. Masta explanation

Thanks sir for solving this type of problems

Really Tricky and Important question sir

Thanks sir

Very nice solution

Sir if this video IIT then you have to use L-Hopital rule

Sir I am always waiting for your video

Simply assume the function 3x²😊

Thanks sir

Very nice solution

Thanks sir for such type solutions

awesome

Good explanation sir

Very good solution sir .

Excellent video

Thanks sir

Very nice

Thanks sir

Good Explanation

we can also directly write it as log45 to base 3 and the split it into log5 and log9 which becomes 2+log5 to base 3