JaberTime
JaberTime
  • Видео 272
  • Просмотров 211 889
Inverse Relations and functions
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JaberTime
Просмотров: 203

Видео

Continuity Part IV
Просмотров 7612 часов назад
Find the x-value at which f is discontinuous and determine whether f is continuous from the right, or from the left, or neither. Thanks for watching! JaberTime
Continuity Part III_ Intermediate Value Theorem.
Просмотров 10812 часов назад
Use the Intermediate Value Theorem to show that there is a root of the given equation x^2 x-9=0 in the interval (1,2). Thanks for watching! JaberTime
Continuity Part I
Просмотров 4812 часов назад
Sketch the graph of a function that is continuous except for the stated discontinuity. Discontinuous, but continuous from the right at 2. Thanks for watching! JaberTime
Continuity Part II
Просмотров 5112 часов назад
How can you eliminate the discontinuity of f? In other words, how would you set f(5) to ensure f is continuous at 5? Thanks for watching! JaberTime
Math 3 Final Review 1st Sem.
Просмотров 282Месяц назад
Graphing Quadratic Functions. Imaginary Numbers. Complex Numbers. The Conjugate. Square Root Property. Completing the Square. The Vertex Form. The Quadratic Formula. The Discriminant. Thanks for watching! JaberTime
The Quadratic Formula and the Discriminant.
Просмотров 3032 месяца назад
Solving Quadratic Equations using the Quadratic Formula. Four Examples. Thanks for watching! JaberTime
Solve Quadratic Functions by factoring.
Просмотров 2073 месяца назад
Thanks for watching! JaberTime
Total and Annual Return.
Просмотров 563 месяца назад
Thanks for watching! JaberTime
Evaluate the following Integrals.
Просмотров 1509 месяцев назад
Thanks for watching! JaberTime
Riemann Sum. Right Hand, Left Hand and Midpoint Rule.
Просмотров 519 месяцев назад
Thanks for watching! JaberTime
Optimization. What is the Maximum Vertical Distance between y=x+2 and y=x^2 for x in [-1, 2].
Просмотров 1079 месяцев назад
Thanks for watching! JaberTime
Curve Sketching. Inc. & Dec. Concave Up. Concave Down, Abs Max, and Abs Min. The Extreme Value Th.
Просмотров 619 месяцев назад
Thanks for watching! JaberTime
Optimization. Find two positive numbers whose Product is 100 and whose Sum is a Minimum.
Просмотров 5799 месяцев назад
Thanks for watching! JaberTime
The Mean Value Theorem.
Просмотров 829 месяцев назад
Let f(x) = -3x^2 2x 4. Find the value(s) of x that satisfy the Mean Value Theorem on the interval [ -1, 1]. Graph the Secant Line, the Tangent Line, and f(x). Thanks for watching! JaberTime
A man 6-ft tall walks away from a streetlight mounted on a 15-ft tall pole at a rate of 5-ft/s.
Просмотров 70410 месяцев назад
A man 6-ft tall walks away from a streetlight mounted on a 15-ft tall pole at a rate of 5-ft/s.
Find the linearization of the function f(x) = SQR(x+5) at a = 4 and use it to approximate SQR (3.8).
Просмотров 8410 месяцев назад
Find the linearization of the function f(x) = SQR(x 5) at a = 4 and use it to approximate SQR (3.8).
Find the limit as x approaches " - infinity". L'Hospital's Rule " infinity * zero".
Просмотров 9210 месяцев назад
Find the limit as x approaches " - infinity". L'Hospital's Rule " infinity * zero".
Find the limit as x Approaches 0 of (e^4x -1-4x)/x^2. L'Hospital's Rule_ Intermediate form (0/0).
Просмотров 13910 месяцев назад
Find the limit as x Approaches 0 of (e^4x -1-4x)/x^2. L'Hospital's Rule_ Intermediate form (0/0).
Differentiate y=SQR (1+4 sin(x)). And find equations of the tangent line and the normal at (0, 1).
Просмотров 7810 месяцев назад
Differentiate y=SQR (1 4 sin(x)). And find equations of the tangent line and the normal at (0, 1).
Implicit Differentiation. Find dy/ dx for 2x^3+x^2y-xy^3=2.
Просмотров 40610 месяцев назад
Implicit Differentiation. Find dy/ dx for 2x^3 x^2y-xy^3=2.
Differentiate y = x ^(SQR x).
Просмотров 17210 месяцев назад
Differentiate y = x ^(SQR x).
Differentiate f(x) = x^2 ln(2x+1).
Просмотров 24610 месяцев назад
Differentiate f(x) = x^2 ln(2x 1).
Differentiate y = ln ( cosh (3x)).
Просмотров 50710 месяцев назад
Differentiate y = ln ( cosh (3x)).
Differentiate y = 3^ (x ln x)
Просмотров 1,1 тыс.10 месяцев назад
Differentiate y = 3^ (x ln x)
Differentiate the following y = e^(cosx) + cos(e^x)
Просмотров 2,4 тыс.10 месяцев назад
Differentiate the following y = e^(cosx) cos(e^x)
Epsilon and delta Explained with an Example in Calculus.
Просмотров 11511 месяцев назад
Epsilon and delta Explained with an Example in Calculus.
The Quotient Rule Proof in Calculus.
Просмотров 11311 месяцев назад
The Quotient Rule Proof in Calculus.
Limit involving infinity
Просмотров 6411 месяцев назад
Limit involving infinity
Limit sin 3x over x
Просмотров 26611 месяцев назад
Limit sin 3x over x

Комментарии

  • @Ebby9936
    @Ebby9936 5 дней назад

    Loved it❤, Thank you so much

    • @19917119
      @19917119 6 часов назад

      You're welcome 😊 I just started my own website: Www.JaberTime.Com Organizing my videos by subject.

    • @Ebby9936
      @Ebby9936 5 часов назад

      @19917119 ty

  • @thapelosz
    @thapelosz 29 дней назад

    Thank you, where can we download the notes

    • @thapimash5124
      @thapimash5124 29 дней назад

      Yea good question

    • @19917119
      @19917119 21 день назад

      I am building a website under my name. I will publish it soon. It will be under www.JaberTime.com I will have links to my videos by subject and I will be adding links to worksheets and more. JaberTime!

  • @Mathematics-z6k
    @Mathematics-z6k Месяц назад

    Sir explain in hindi plz😢

    • @19917119
      @19917119 21 день назад

      Hi, I wish I can speak Hindi. I have a lot that are watching my channel from India. JaberTime!

  • @ghassanabu2012
    @ghassanabu2012 Месяц назад

    Thanks 1 million

    • @19917119
      @19917119 Месяц назад

      You are welcome!

  • @dumindukarunarathne7438
    @dumindukarunarathne7438 Месяц назад

    Thanks a lot !

    • @19917119
      @19917119 Месяц назад

      You are welcome!

  • @dumindukarunarathne7438
    @dumindukarunarathne7438 Месяц назад

    Thankyou Sir !!

  • @ghassanabu2012
    @ghassanabu2012 2 месяца назад

    I really appreciate your RUclips videos thank you very much

  • @HucksterYT
    @HucksterYT 2 месяца назад

    Granted just took the exam a few hours ago, so I havent gotten the results back yet, but I feel really confident I did well on your exam because of this video. Thank you very much Prof Jaber.

    • @19917119
      @19917119 2 месяца назад

      @@HucksterYT glad that it was helpful!

  • @bouhmana7828
    @bouhmana7828 2 месяца назад

    Thank you so much you were a big help ❤

  • @chinenyeogueke1928
    @chinenyeogueke1928 3 месяца назад

    I need AI

  • @boye4812
    @boye4812 3 месяца назад

    the speed with which I hit that subscribe button...wow!

  • @kashirnaidoo3909
    @kashirnaidoo3909 3 месяца назад

    Yensen from iron man is out here helping us

  • @potatoesalad5103
    @potatoesalad5103 3 месяца назад

    great video professor, I'm glad you showed what your sketch looks like, as it's what I mostly struggle with in this section.

    • @19917119
      @19917119 3 месяца назад

      Visualizing is key!

  • @KimberlyBernardo-h2b
    @KimberlyBernardo-h2b 3 месяца назад

    Great video, thank you!!

    • @19917119
      @19917119 3 месяца назад

      Glad you liked it!

  • @ghassanabu2012
    @ghassanabu2012 3 месяца назад

    Thank you very much. I appreciate your help.

    • @19917119
      @19917119 3 месяца назад

      You're welcome!

  • @JahnaeJames
    @JahnaeJames 3 месяца назад

    Thanks

    • @19917119
      @19917119 3 месяца назад

      You are welcome!

  • @RaiShockz
    @RaiShockz 3 месяца назад

    you are so helpful thank you

    • @19917119
      @19917119 3 месяца назад

      Happy to help!

  • @lordshadowz58
    @lordshadowz58 4 месяца назад

    Bless you sir

    • @19917119
      @19917119 4 месяца назад

      Thank you sir.

  • @fgpontanal
    @fgpontanal 4 месяца назад

    wow! superb!

  • @adelalmahdi4567
    @adelalmahdi4567 4 месяца назад

    why did u choose r positive?

    • @19917119
      @19917119 4 месяца назад

      R is always positive unless it is stated differently. Here is another video about Polar Coordinates: Double Integrals in Polar Coordinates. ruclips.net/video/5y0b2Ng7Qfk/видео.html

  • @ari-vn5so
    @ari-vn5so 4 месяца назад

    Thank you sir

    • @19917119
      @19917119 4 месяца назад

      All the best.

  • @kemisolaakinbobola9894
    @kemisolaakinbobola9894 4 месяца назад

    Nice buh I don’t understand well

    • @19917119
      @19917119 4 месяца назад

      Try my other video: Adding in base 5. ruclips.net/video/5rYAyo4LqB0/видео.htmlsi=3dRL_ane4vIB2m8h

  • @vvvawdad1767
    @vvvawdad1767 4 месяца назад

    your voice is very soothing bro very nice

  • @Abinash_Pantha
    @Abinash_Pantha 4 месяца назад

    Thank you genius sir just subbed

    • @19917119
      @19917119 4 месяца назад

      Thanks for the sub!

  • @bhanupenukonda9282
    @bhanupenukonda9282 4 месяца назад

    Thanks a lot sir for all ur videos....in very clear way...logic explained

    • @19917119
      @19917119 4 месяца назад

      You're most welcome

  • @heronkulukul4156
    @heronkulukul4156 5 месяцев назад

    Thank you very much. This is very helpful!!

    • @19917119
      @19917119 5 месяцев назад

      Glad it was helpful!

  • @senvers3459
    @senvers3459 5 месяцев назад

    Thank you sir 🐬✨

    • @19917119
      @19917119 5 месяцев назад

      You are very welcome.

  • @aland.6695
    @aland.6695 5 месяцев назад

    Wonderful job!

    • @19917119
      @19917119 5 месяцев назад

      Glad you like it!

  • @FrancoGeovany
    @FrancoGeovany 5 месяцев назад

    Here all people on digital design evil class. 😂 bruh, well explained.

  • @JaidenCrumley
    @JaidenCrumley 5 месяцев назад

    he is the best in the world!

    • @19917119
      @19917119 5 месяцев назад

      Thank you for the comment! It is JaberTime 24/7.

  • @sumerasyed700
    @sumerasyed700 5 месяцев назад

    Well Explained

    • @19917119
      @19917119 5 месяцев назад

      Thank you!

  • @Claudia21677
    @Claudia21677 5 месяцев назад

    Thank you !! 🎉😊

    • @19917119
      @19917119 5 месяцев назад

      You're welcome 😊

  • @melbahndhlovu1723
    @melbahndhlovu1723 6 месяцев назад

    Thanks, am good to go

    • @19917119
      @19917119 6 месяцев назад

      You are welcome!

  • @GiovanniCathi
    @GiovanniCathi 6 месяцев назад

    Hello, good afternoon. Excuse me, from what book did you get this problem?

    • @19917119
      @19917119 6 месяцев назад

      That was a while ago, I don’t remember.

  • @sehrishqamar6707
    @sehrishqamar6707 7 месяцев назад

    🎉

  • @yamkelamampoza7510
    @yamkelamampoza7510 7 месяцев назад

    Thank you sir

    • @19917119
      @19917119 7 месяцев назад

      You are welcome.

  • @miku9277
    @miku9277 8 месяцев назад

    Thank you sir for teaching!

    • @19917119
      @19917119 8 месяцев назад

      You are very welcome

  • @MS-vr5vc
    @MS-vr5vc 8 месяцев назад

    Excellent way of explaining. Made it so easy to understand. Thank you doctor. I am already in love with "Who am I" problems.

    • @19917119
      @19917119 8 месяцев назад

      Glad it was helpful!

    • @MS-vr5vc
      @MS-vr5vc 8 месяцев назад

      @@19917119 Thank doctor. I appreciate your help. Magdy

  • @nikolavidrich7117
    @nikolavidrich7117 8 месяцев назад

    Shouldn't you have integrated from 0 to 5 instead since you have to bring the water over the edge of the pool?

    • @19917119
      @19917119 8 месяцев назад

      If the slice lies x sub i "*" ft below the edge of the pool ( where x sub i "*" is greater than or equal to 1 and less than or equal to 5), then the work needed to pump it out is 9000 pi x sub i "*" delta x. Thus W = integration of 9000 pi x dx from 1 to 5. Think about if the depth of the water only 2 ft, are we going to integrate from 0 to 5 still or from 3 to 5? If we integrate in both cases ( with water of depth 4 ft or 2 ft) and in both cases we integrate from 0 to 5, then the depth of water will not affect the answer which is not true. Just think about the SLICE with x varies from 1 to 5.

  • @williamwang1123
    @williamwang1123 8 месяцев назад

    Thank you!

    • @19917119
      @19917119 8 месяцев назад

      You're welcome!

  • @ghassanabu2012
    @ghassanabu2012 9 месяцев назад

    Excellent job thank you

    • @19917119
      @19917119 9 месяцев назад

      Our pleasure!

  • @ItsNaberius
    @ItsNaberius 9 месяцев назад

    omg thank you so much

    • @19917119
      @19917119 9 месяцев назад

      Happy to help

  • @jaredcoronado3058
    @jaredcoronado3058 9 месяцев назад

    Thank you for your videos!

    • @19917119
      @19917119 9 месяцев назад

      Glad you like them!

  • @ptarcher86
    @ptarcher86 9 месяцев назад

    Alternatively, you can just do the sqrt(100), as by definition, the sum is minimized by the smallest two factors (which is the sqrt).

    • @19917119
      @19917119 9 месяцев назад

      👍👍👍

    • @19917119
      @19917119 9 месяцев назад

      How about this: The product is 147 and the sum of the first number plus three times the second number is a minimum.

  • @Steven-v6l
    @Steven-v6l 9 месяцев назад

    f(x) = x +100/x; f'(x) = 1 -100/x^2 ... which is zero when x=10 ; f"(x) = 200/x^3 ; which >0 for x>0 ... so f() has a minimum at x=10. No "sampling" of f() or f'() near 10 is necessary (or even *fun*). So unless producing a graph was part of the problem ... why bother?

    • @19917119
      @19917119 9 месяцев назад

      You are 100% right. JaberTime

  • @jaredcoronado3058
    @jaredcoronado3058 9 месяцев назад

    this video is very helpful for understanding this section. Thank you!

    • @19917119
      @19917119 9 месяцев назад

      Glad to hear that!

  • @Eknoma
    @Eknoma 9 месяцев назад

    10 and 10

  • @ghassanabu2012
    @ghassanabu2012 9 месяцев назад

    Amazing explanation thank you got to the point

    • @19917119
      @19917119 9 месяцев назад

      You're welcome!

  • @Bobelprofesor
    @Bobelprofesor 9 месяцев назад

    What an amazing video.

    • @19917119
      @19917119 9 месяцев назад

      Glad you think so!

  • @leabarada2139
    @leabarada2139 9 месяцев назад

    amazing thank you

    • @19917119
      @19917119 9 месяцев назад

      Thank you too!