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Brian Bernard
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Добавлен 18 сен 2013
Brian Bernard is an Associate Professor of Engineering at Schreiner University in Kerrville, TX. This channel is meant to help engineering students pass their classes and graduate on time. I know you are busy so I hope you will find my videos to contain as much good information as I can cram into the shortest runtime possible. I try to be funny, but don't always succeed - luckily my cats make occasional appearances to save the day.
Velocity Polygon Example Problem - Graphical Velocity Analysis
Draw the Velocity Image to find the velocity of the four bar linkage coupler. Velocity polygon is a type of graphical velocity analysis, that instead of drawing perfectly scaled lengths and angles, you can solve exactly using law of sines and law of cosines.
Bookmark my Machinery and Mechanisms Playlist
ruclips.net/p/PLZEGV3UcXTiPDCygrf0v7i8PH4t2hiRm3
This problem fits into your textbook in sections called Velocity Polygon for 4 bar mechanism, Velocity Image, Velocity Diagram, or Graphical Velocity Analysis of a four bar linkage.
CHAPTERS
0:00 How to draw velocity image?
4:07 What is velocity polygon?
6:55 Posture Analysis 4 Bar Linkage
9:48 Graphical Velocity Analysis
Bookmark my Machinery and Mechanisms Playlist
ruclips.net/p/PLZEGV3UcXTiPDCygrf0v7i8PH4t2hiRm3
This problem fits into your textbook in sections called Velocity Polygon for 4 bar mechanism, Velocity Image, Velocity Diagram, or Graphical Velocity Analysis of a four bar linkage.
CHAPTERS
0:00 How to draw velocity image?
4:07 What is velocity polygon?
6:55 Posture Analysis 4 Bar Linkage
9:48 Graphical Velocity Analysis
Просмотров: 41
Видео
Instant Center of Velocity Example Problem (Hard)
Просмотров 28День назад
Instantaneous Center of Zero Velocity is a graphical method to find the velocity of sliders and angular velocity of rotating links. It involves a lot of triangle math, law of sines and law of cosines. Bookmark my Machinery and Mechanisms Playlist ruclips.net/p/PLZEGV3UcXTiPDCygrf0v7i8PH4t2hiRm3 This problem fits into your textbook in sections called Instant Centers of Velocity or Instantaneous ...
Find Velocity using Complex Algebra Method - Loop Closure
Просмотров 9914 дней назад
Complex algebra example problem using loop closure equations. Find velocity of sliders and angular velocity of links using the Loop Closure Method, also called Complex Algebra Method. Bookmark my Machinery and Mechanisms Playlist: ruclips.net/p/PLZEGV3UcXTiPDCygrf0v7i8PH4t2hiRm3 This problem fits into your textbook in sections called Complex Algebraic Velocity Analysis or Analytical Solutions f...
Minor Losses Example Problems - with Major Losses and Moody Diagram
Просмотров 1121 день назад
Minor Losses due to pipe entrance, pipe exit, sudden expansion, 90 degree bends, and valves, in 2 Fluid Mechanics Example Problems also involving the Energy Equation and Major Losses due to Friction. Master Fluid Mechanics with my full course playlist: ruclips.net/p/PLZEGV3UcXTiOWMsc47Ln012jRLrze9Y8X You will usually need to use the Darcy Weisbach Equation along with the Moody Diagram, and also...
Series vs Parallel Pumps - Draw Pump Curve and System Curve
Просмотров 251Месяц назад
Fluid Mechanics Example Problem to combine pumps in series and parallel. Draw the Pump Curve for 1 pump, 2 pumps in series, and 2 pumps in parallel. Draw the system curve. Where the curves overlap is the system operating point. Master Fluid Mechanics with my full course playlist: ruclips.net/p/PLZEGV3UcXTiOWMsc47Ln012jRLrze9Y8X Step by step walkthrough of How to Find the System Curve for Pump H...
Heat Transfer Boiling Example Problem
Просмотров 4286 месяцев назад
Nucleate Boiling example problem includes how to find critical heat flux, rate of evaporation, and surface temperature at the critical heat flux. You will also learn about the boiling curve, or boiling regimes curve. Once past the critical heat flux temperature, very different results are obtained if the system temperature increases (transition to film boiling) vs if the system heat flux increa...
Forced Convection over Cylinder in Cross Flow - Example Problem
Просмотров 2576 месяцев назад
External forced convection example problem with convective heat transfer due to external flow over a cylinder in cross flow. Full step by step explanation and solution. This heat transfer problem has 4 modes of heat transfer, regular m dot cp delta T heat loss from a fluid, solar radiation, thermal radiation, and external forced convection. The main part of the problem involves finding the heat...
Power Loss in Hydraulic Jump - Step by Step Solution
Просмотров 3846 месяцев назад
Hydraulic Jump example problem solved using Froude Number to find Height after Hydraulic Jump. Then the Energy Equation is used to find Head Loss, and finally the Pump Power Equation is used to convert head loss to power. Master Fluid Mechanics with my full course playlist: ruclips.net/p/PLZEGV3UcXTiOWMsc47Ln012jRLrze9Y8X Hydraulic Jump problems will be found in the Open Channel Flow chapter of...
Accelerating Control Volume - Fluid Momentum Example Problem
Просмотров 2937 месяцев назад
Don't use the Tsiolkovsky Rocket Equation! It doesn't account for external forces like gravity or drag. You must use Fluid Momentum to solve accelerating control volume problems. Master Fluid Mechanics with my full course playlist: ruclips.net/p/PLZEGV3UcXTiOWMsc47Ln012jRLrze9Y8X Draw your Free Body Diagram, set it equal to your Kinetic Diagram, write your equilibrium equation, and solve. That'...
How to Find Surface Temperature during Transient Conduction due to Sudden Convection
Просмотров 1717 месяцев назад
The transient conduction one-term approximation method is used to first find the centerline temperature during one dimensional transient conduction. Then plots or equations can be used to find the surface temperature for these sudden convection problems. Surface Temperature for a Plane Wall, Infinite Cylinder, and a Sphere are all found in this unsteady state conduction example problem. Along t...
One Term Approximation vs Lumped Heat Capacity
Просмотров 2177 месяцев назад
Transient Conduction problem solved using both Lumped Heat Capacity method and also the One Term Approximation Method for Sudden Convection, solving for both the surface temperature and the centerline temperature of a plane wall. For Unsteady Conduction, you will learn how to calculate the Biot Number, how to calculate the Fourier number, how to determine whether the Lumped Capacitance model is...
How to Solve Fin Efficiency Problems (and Fin Effectiveness)
Просмотров 5207 месяцев назад
Rectangular Fin example problem solving for fin efficiency, fin effectiveness, and heat transfer through the fin. Along the way, we'll find the Fin Perimeter, 2 different Fin Areas, the Fin Cross Sectional Area, and the overall Fin Area (ie Fin Surface Area), Fin Corrected Length, and the Fin Parameter m - which doesn't really have a name. Sad. We could name it "TA Serenity's Number"? Extended ...
Heat Transfer through Extended Surfaces Fins - Infinite vs Insulated Tip
Просмотров 3907 месяцев назад
Cylindrical Pin Fin example problem solved using 3 different boundary conditions: infinite length assumption, insulated tip assumption (also called adiabatic tip assumption), and a convection tip using the corrected length. Extended Surfaces Heat Transfer problems can sometimes be easy plug n chug, as long as you make the right fin design assumptions, to choose the right version of the fin equa...
How to Draw a Thermal Circuit Diagram for a Composite Wall
Просмотров 2037 месяцев назад
One-Dimensional Conduction in Series and Parallel example problem to demonstrate how to draw a thermal circuit diagram. 2D wall is modeled as one dimensional conduction and using the conduction thermal resistance of each section of the composite wall arranged as a thermal circuit network model, we can solve for overall rate of heat transfer through a composite wall. This thermal resistance exam...
Thermal Circuit Diagram with Conduction, Convection, and Radiation Thermal Resistance in Series
Просмотров 6777 месяцев назад
Thermal resistance example problem shows how to draw a thermal circuit in series and how to find the thermal resistance equations for conduction thermal resistance, convection thermal resistance, and radiation thermal resistance. Overall thermal resistance of a double pane window is modeled as primarily a one dimensional conduction problem, in two different ways, once with stagnant air in the c...
Lumped Capacitance Method Example Problem - Unsteady State Conduction
Просмотров 1417 месяцев назад
Lumped Capacitance Method Example Problem - Unsteady State Conduction
Calculate Pipe Insulation Thickness - Thermal Resistance Example Problem
Просмотров 1,3 тыс.7 месяцев назад
Calculate Pipe Insulation Thickness - Thermal Resistance Example Problem
Internal Heat Generation in Cylinder - Example Problem
Просмотров 3788 месяцев назад
Internal Heat Generation in Cylinder - Example Problem
Pump Curve vs System Curve - Example Problem
Просмотров 3,4 тыс.8 месяцев назад
Pump Curve vs System Curve - Example Problem
Fluid Momentum - Moving Control Volume Problem with Constant Velocity
Просмотров 6899 месяцев назад
Fluid Momentum - Moving Control Volume Problem with Constant Velocity
How to solve Parallel Pipe Systems with Head Loss
Просмотров 6129 месяцев назад
How to solve Parallel Pipe Systems with Head Loss
Find Height of Hydraulic Jump - Example Problem and Explanation
Просмотров 75810 месяцев назад
Find Height of Hydraulic Jump - Example Problem and Explanation
Mastering Orthographic Projection: Drawing Complex Cylinders in Multi-View Engineering Graphics
Просмотров 55510 месяцев назад
Mastering Orthographic Projection: Drawing Complex Cylinders in Multi-View Engineering Graphics
How to Draw Orthographic Views of Cylinders with an Angled Surface
Просмотров 63910 месяцев назад
How to Draw Orthographic Views of Cylinders with an Angled Surface
How to Draw FRONT, TOP, and RIGHT side views with OBLIQUE Faces in Orthographic Projection
Просмотров 1,9 тыс.11 месяцев назад
How to Draw FRONT, TOP, and RIGHT side views with OBLIQUE Faces in Orthographic Projection
How to Draw Orthographic Views of OBLIQUE Surfaces using XYZ Coordinate System
Просмотров 70611 месяцев назад
How to Draw Orthographic Views of OBLIQUE Surfaces using XYZ Coordinate System
Force on a Pipe Bend - Fluid Momentum Example Problem
Просмотров 3,2 тыс.11 месяцев назад
Force on a Pipe Bend - Fluid Momentum Example Problem
Mastering MISSING LINES - Surprisingly Tricky Examples
Просмотров 1,5 тыс.11 месяцев назад
Mastering MISSING LINES - Surprisingly Tricky Examples
Non-Circular Pipe Flow - Hydraulic Diameter Example Problems
Просмотров 395Год назад
Non-Circular Pipe Flow - Hydraulic Diameter Example Problems
This channel deserves more views and subscribers wtf?
If you have a classmate that you think these videos would help Please send them a link. Getting discovered is hard. I appreciate personal recommendations so much.
Nice and logical explanation. 1:15 In some schools the operation of the siphon is still explained as the result of atmospheric pressure.
It's probably not harmful to think of it that way, even if technically not fully correct. Similar to in electrical circuits, we think of current flowing from positive to negative, even though we now know its electrons that are moving, and they move the other way. There's a bunch of these sorts of things throughout engineering curriculums, that while not entirely correct, it's still kind of ok to think that way, because it may still be useful in understanding a bigger picture, even if the details are a bit off.
@@BrianBernardEngineering Thanks for the reply. I agree. We should keep in mind as many possibilities as possible for some conclusion in order to be able to see what works to what extent. It should not be exclusive. Doubt about correctness leads to the right answer. I don't speak English very well, sorry if there are mistakes.
3 minutes in and it's already better than the lecture, thank you!
You're welcome. Good luck this semester!
This video did a great job at explaining how to use the formula corresctly. Thank you!
You're very welcome. This is maybe the best example in any engineering class to demonstrate that if you understand the formula, you don't actually need to know the formula at all. You can just do it on your own.
Your channel truly is a hidden gem. Keep it up!
Thanks so much. I'll try. You might also be interested - I just launched an additional channel, "Explained By Cats" that is still educational, but a lot more entertaining, not just solving homework problems.
Thanks a lot. I didn't have time to write explanations to the calculations in my lecture notes so they have no context. Massive help.
Happy to help. Most of the course will be 2D problems. But there will be a little 3d sprinkled in here and there.
Thnq sir for this video its very usefull to my studies 🙏🇱🇰
You're very welcome. I hope you do great!
This is such a well produced video, really should have more views!
That's very kind to say, thank you so much for watching.
When you are looking at which ways the joints can move, do you look at the joints or the two links themselves? Like will both links connected to the joint have the same amount of restricted movement?
I prefer to not really think of the joints as 'things that move', and only consider the links as moving objects. I usually view a joint only restricting the motion of 1 of the attached links, not 2. Consider a 4 bar linkage. The crank has its motion restricted in 2 directions by the joint connecting crank to ground. Then the coupler is restricted in 2 directions by the joint connecting coupler to the crank. So that joint, connecting coupler to crank, I don't think of it as restricting the cranks movement, because the crank is already restricted from its other end. This isn't the only way to think about these problems, but it's my way.
Imagine we have two tank, one with the hole on the bottom, one has the pipe throughth down to hole with same area and the tank is on the same height but pipe exit below morenthan the hole. Does the tank drain faster if we add the pipe throughth down? It is sound wrong but equations seems that way.
A little counterintuitive, but yes, it would drain faster with a pipe extension to make the exit lower. Same premise works for siphoning as well. If you want to empty out something like a fish tank using a siphon, don't have the exit of the siphon right below the tank, get a longer pipe so the exit can be all the way down on the ground, lower exit is faster exit velocity since you convert more potential energy to kinetic with greater change in height.
Why do we use gauge pressure? And not the abs
It's usually the difference in pressure that actually matters. Pressure inside something pushes outward, atmospheric pressure pushes inward. The difference is important since you are summing forces in the two different directions to get a net force due to gauge pressure. This is why you don't actually measure atmospheric pressure usually. Atmospheric pressures changes a bit everyday due to weather. Since we only care about the gauge pressure, it doesn't matter exactly what the reference points absolute pressure is.
Watching this video, I actually had fun learning, two things that hardly go together. This is a masterpiece, A+!
Awesome. Unfortunate that it's rare, but glad I can be the exception. Have a great semester!
I have been working for 6 years as Rotating Engineer in oil & gas downstream and upstream and this man has refreshed my knowledge so much, easy to understand before we plan to procure the centrifugal pump.
Thanks so much for the kind words. Also especially good for students to hear that this stuff can actually have a real world application, not just homework!
But I think the calculation conversion you made from ft3/s to gal/min is wrong.😂 Correct me I been mistaken. But anyway, you did great explanation and easy to understand. Tq😂@@BrianBernardEngineering
Please add units, when you plug in numbers!
You're right - that is definitely the right way to do it. In practice I usually try to ensure all my units are consistent at the start so that I know the answer will work out to be the correct units, which allows me to get away with being lazy - but I fully concede that it is risky and lazy. I'm making a note to do better next time. Good luck this semester.
@@BrianBernardEngineering thanks! My semesters are long gone though! I am here for the joys of fluid dynamics!
This is an amazing explanation Dr. Brian. I have been scratching my head for a while now when it comes to siphons but your explanation was very clear! I have a burning question: does the siphon work better if the outlet end is submerged? Or does it not matter? (My thinking is- if it’s not submerged, air can get in more easily and break the siphon especially at low rates… but then again, if it’s not submerged, the pressure difference remains the same as time progresses. For example, if you let the outlet end of the siphon spill onto the floor, it will spill out until it’s empty, right? If submerged, the pressure difference decreases and the velocity decreases as time progresses, and a state of equilibrium is reached as you explained.)
Main difference with submerged exit is increased pressure. However far under the surface, that's extra pressure. Bernoulli Eqn from inlet to outlet, you would then have a lower change in pressure between inlet and outlet, same change in height between inlet and outlet, therefore velocity difference would have to be smaller. Flow rate would be slower.
best explanation i have ever watched in RUclips
thanks so much. that really means a lot!
This helped me stacks with my first Thermal Fluids practical, thank you!
youre welcome, that's awesome. Keep up the good work!
A good explanation for a topic that tends to be more complex than people think
Yea, this is definitely one of those things that seems like a two sentence topic ... until you try it yourself and realize there just keeps being one more step, then just one more, then ... and it keeps going lol.
@@BrianBernardEngineering yes! Then add multiple pumps in parallel, but different sized pumps. Then it becomes fun 😆 add then controls to it!
@11:19. The yellow link oscilates and passes through the same state ( angle) on its way there and back ( clockwise and then counterclockwise). Both blue and yellow links will be in different positiins for the same state of the yellow link...so how can i state that if i know just one angle of any element of the entire system, i can describe the rest of the system? Those are two completely different states for the same state of the yellow component? Please advise
Yes, there is a hidden assumption I made here - that this 4 bar linkage is in the "open" configuration. There is a 2nd possible set of angles that would also work, sometimes called the "crossed" configuration, where the rocker points downward instead of upwards. So, though there are technically 2 possible solutions, if you choose which one you want, then there's only one! I predict that the vast majority of your homework and test problems, you will use the open configuration, so it should be your default choice. If for no other reason, it's often easier to draw.
Wonderful explanation sir
Thanks so much. Have a good semester.
Bloody good channel and vids! Just found you.
Thanks so much. I'm happy to help.
Efficiency goes to 1 when length is 0 and goes to zero when length is infinite. So when there is no fin, the efficiency is max, which I don’t understand at all
Think of it as "diminishing returns". The first tiny bit of fin added is hugely beneficial. Then the next bit a little less, and next bit even less. a longer fin is always better (more heat transfer) than a shorter fin, but each bit of extra length you add does a little bit less than the piece before it. Eventually you've essentially maxed out, so extra length added does practically nothing extra for heat transfer, so that lowers the efficiency. A long fin, that gets longer, you add very little heat transfer, but a lot of extra length, so this is inefficient.
@@BrianBernardEngineering thanks!! That's a great way to put it!!
If we're given the top/bottom and side view and are asked to draw the front view, do we need the mitre line? Had this on my exam and kinda messed it up
Nope. Only need miter line to connect top/side views. From top to front is just straight down. Right to front just straight horizontal. I just double checked ... I have 3 different videos on missing views (easy to find in my 19 video engineering graphics playlist if you haven't seen it yet), and not one of them has an example with a missing front view. Always missing top or missing side view. Seems like an oversight I might want to create a new video for. Thank you for the idea.
@@BrianBernardEngineering Yeah, thanks for the explanation. What's funny is that the question on the exam said to draw a mitre line (in bold). My exercise bundle for the course only had missing top/side views only as well.
This was so informative, thank you for the great vid, I don't think there is another vid that explains this concept better.
This really is one of those "easy ... once you know how" topics that looks really complex at first.
Great video! But a question for you, on 8:32, shouldn't the Reynolds be in 10^5?
oh no, I think you're right. When looking up numbers on the Moody Diagram, it should be shifted left, one section, which changes the f values from about .015 to about .017. Final plot for the system curve would then be above the orange line, but below the blue line. I didn't catch any mistakes with the process. If you follow this process, but don't make division mistakes like I did, you should still be golden.
Hello again... How many types of animation in Inventor are there? So far, I've done one type: animated constraints. Is there not one called dynamic simulation? Does this not involve calculating real-world forces? Can animation types be combined into one animated scene? Hard to find tutorials on this. (I'm trying to create a rotational animation for the base of a robotic arm, and am having a crazy time doing it. Wondering what my options are.) Thank you!
Sorry, it's been awhile since I worked on more than basic animations, so don't think I can help. Good luck though!
@@BrianBernardEngineering Not a big deal :D
I was watching this in plane and after the plan landed on I thoght I saw you in the airport probably I was dreaming 😂.
I wasn't at any airports today, sorry, wasn't me. Woulda been an amazing coincidence.
Mashallah is this what it feels like to have your third eye opened
Glad I could help. Keep up the good work!
This is fantastic. I've been using Autodesk inventor, but today I've learnt a lot from on how to use joint mates..🎉
Awesome! Glad I could help.
one of the best explanation i have ever heard,thank you very much am humble 🙏
You are very welcome
I'm from Istanbul Turkey i will be in US soon if I pass my drawing exams tomorrow I'll bring you Turkish delight if I pass
good luck on your exams!
Very nice video, that problem wasn't easy ngl. But great job because I did understand everything. I wish you had WAYY more subscribers
Good news, is that this is one of the harder momentum problems you are likely to see, so if you can follow this, good chance your homework and tests might be similar or even a step down in difficulty.
Does the pressure of the water depth have any effect on siphon height? For instance say the siphon was located deep in the ocean. And assume the other end was still below relative. Somehow it’s magically emptying into the abyss or something. Could you increase the maximum height of the siphon then, beyond 10 meters? Not that there would be any particular use for this. I’m just wondering about the mechanics of the maximum height.
Yes, Pressure at the exit DOES make a difference. This video focused on examples where both ends are at atmospheric pressure, since that's the normal scenario we see most often, like when draining water out of a large aquarium. But if the exit is above atmospheric pressure, then the siphon height CAN be higher than the max I stated in this video. This is a really good sign, when you are able to learn something, and you then can find edge cases like this where it's a little bit different - shows you are understanding the bigger picture and not just memorizing details. Good work!
@@BrianBernardEngineering Great thanks a lot for the reply and the educational content :) Does the water pressure at the entrance make any difference? Or in other words, the water depth of the end of the siphon (the higher end, the one where water will enter from).
@@solank7620 Yes, you're right, both inlet and exit pressures matter, it's really the difference in pressure between inlet and outlet that is important. Regular siphon, same atm pressure both ends, the difference in height inlet to outlet is what determines the velocity in the siphon. When inlet and exit pressures are different, that difference also contributes to velocity in the siphon, just like difference in height. If inlet lower pressure than outlet, velocity will be lower than it would be based on height alone. Once you know velocity, then you can get max height. And you should get same height whether you measure above inlet or above outlet.
@@BrianBernardEngineeringthat is so interesting because it is a bit counterintuitive - that the siphon height increases with higher pressure at the outlet of the siphon. But looking at the equation, that is true. But still I can’t get my head around it!
Thanks i got an gr8 exam for Dt tommorow
Good luck!
4:08. Since the value of g does not depends upon the change in velocity and change in time, then why are we considering it as rate of change of velocity (or simply time derivative of velocity) ? The value of g varies as we move away from earth, or we can say it varies inversely by square of distance b/w object and radius of earth (i.e g=[G.M]/[r^{2}] or g=[G.M]/[(r+h)^{2}].? Any help whould be greatly appreciated..
g is not being considered as rate of change of velocity. If you let the video play a few seconds more, you'll see that the right hand side of the equation has another term in nit. And think of the overall problem, if g = acceleration, then the rocket would be in free fall. Since the rocket is accelerating upwards, not freely downwards, dv/dt will definitely not equal g. However, you are correct that technically g is not constant. This is why I needed to specifically state in my assumptions at the top that g = constant. To realistically model the rocket's motion all the way up to a zero g environment, you would definitely need to have g rewritten as a function of height.
Much appreciated. I have a question, i am given an assignment in which i am required to find miminimum fuel rate and no time interval is given. What should i do ? I think that i have to derivate the equation and derivative the minima, is it correct ?
It may be easier than that. Consider the implications of minimum fuel rate. I can think of 2. First, your fuel tanks would be empty and you only account for the weight of the rocket itself. If you have extra fuel, that requires a higher fuel rate just to lift the fuel itself. Second, your acceleration would be 0, or something incredibly small like .00001, like the rocket is just barely able to overcome gravity. Any faster fuel burn rate than this would cause a faster acceleration. I think you may be able to just do the same FBD = kinetic diagram type analysis, where the force due to burning fuel only has to exactly counter the force of weight of the rocket, and all the other terms are assumed to be zero, in this minimum fuel rate scenario.
Water distribution is carried out with the following requirements: 25 % of the time flow rate is 75 l/s and head in variable-speed operation is 20 m 50 % of the time flow rate is 90 l/s and head in variable-speed operation is 25 m 25 % of the time flow rate is 105 l/s and head in variable-speed operation is 30 m To simplify the calculation, the motor and variable-speed drive efficiencies are assumed to be 100 % The price of electricity is 0.12 €/kWh A Sulzer APP42-150 pump with closed 340 mm impeller whose characteristic curves is used to carry out the pumping task. What are the annual energy consumption and costs of this pump with variable-speed operation? Annual energy consumption: ?? MWh Annual energy costs: Euro ?? How much energy and euros are saved with variable-speed operation compared with the use of throttling valves and fixed-speed operation at 1400 rpm? Saved energy: ?? MWh Cost savings:Euro??
Sorry, but I think the method in this video won't help you with that problem. In your givens, you are already provided with both flowrate and head. This video is used when you only know one of those, in order to find the other. You'll need to find a different video with more information about pump power - and I don't have one of those sorry. Good luck to you.
Insightful. The upper/lower boundary method can be very powerful. Thanks Brian!
heat transfer is a very inexact subject with lots of assumptions and estimates, so you may see this sort of approach in other parts of the course too.
This is all explained extremely clearly. Thanks Brian!
Glad it was helpful!
Thanks Brian, very helpful
You're welcome!
So "One" could say a well designed vessel is like a well balanced meal..? LoL... Your explanation for 80% of mass near the lower 20% of the bottom of vessel would create unfavorable conditions? Small Ocean going/ full displacement/ live aboard...trawler? Norhavn/ Katie krogen style ... Thank you You realize why some boats have a perfect design, when you would otherwise think ill change it... LoL And some GOOD boat designs are best left alone (for the most part) Smart ppl designing smart things (like yourself) Thank you
The most AMAZING! Explanation Ive ever seen of DOF
Thanks so much. Textbooks make this seem really convoluted. Break it down and it's not scary at all. Just gotta stay organized. Have a good summer!
Amazing! So surprised to see that only 5 like of this video😅
we're up to 6 now, Let's goooooooooo
Hey, your chart is easier to read than mine. I have one that is black color, and yours it is blue, Also more resolution. Very good explanation, I am understanding this thanks to you.
This chart came from the textbook authored by "Moran". It's definitely the paid textbook I recommend most for Thermodynamics (though I actually use free textbooks for my classes this year). You should be able to buy a used version for WAY cheaper than a new one. I see used copies for previous editions on Amazon for around $10 including shipping. Way better than buying new, if you don't need the homework problems from the new book. Very good colorful tables, even if you go back a few editions.
This video needs more exposure. You are an excellent professor and I wish I found this sooner!!
Thanks so much and I'm really glad I could help. About exposure, my channel is growing slowly, but it is growing. Every new viewer that sends a link of one of my videos to one of their classmates to help their friends out, all those links help recruit even more new students to watch and that adds up over time. Thanks again!
we meet again!
welcome back :)
You have a really good page it is odd that you don’t get the viewership you deserve… has anyone ever looked into your analytics? You are hitting all of the check marks, good thumbnail that’s simple explains the point, good content, visual backgrounds are good. I can’t put my finger on why you are not getting more views. One element is engagement, but that’s really it. There should be more people commenting on these. FYI I found you bc I’m studying for my FE. Maybe if you include FE in your caption you’d get more engagement? cheers
That comment was me I was on my personal page
@@eded4889 this is me lol
There's a lot of competition, and since I'm at a small school, I face a big disadvantage. At another school, a professor may teach 3 sections of the same class that each have 200 students in them. That's 600 students watching his videos, so that gives youtube a lot of information that this is good (even if its not). But for me, I only teach 1 section of Statics, with just 15 students. So, there's not as much up front indication to RUclips of how good it is, so it takes a lot longer before my videos start to rank higher in search and get suggested. Even though 50% of my channel's videos have been released in the last year, 9 of my top 10 videos this month are more than 2 years old. They are all hockey stick graphs, slow slow slow, until a critical audience is finally reached, then they sharply increase. Usually happens 2-3 years after a video is released before it starts getting traction.
can you give an example of interpolation I always struggle with it and finals are coming up.
Absolutely - do a youtube search for "How to Read Steam Tables - 5 Interpolation Example Problems" and you will probably find it. Or you can go to my channel page, it's one of my oldest videos so the production quality isn't as good as my newer videos, but I think it will still be useful for you. Good luck on finals!
Awesome video, thank you very much!! Love the enthusiasm, editing, and the way you go about solving problems :D
we're happy to help!
I had no idea TA Indiana liked popsicles :0
Yes, LOVES them. They are definitely his favorite treat. Not really cat food though so just on special occasions.
oh wow, I just found this channel and have binged so many of your videos for some last minute studying for a fluids final tomorrow. I absolutely love the way you explain things. I really hope you keep making videos. Definitely going to comeback and watch your other subjects just for fun. Have you considered making an civil FE prep series?
Thanks so much for watching, but sorry to say that civil FE is not coming up soon. I'm working on Heat Transfer videos now, and next on my plan is a series of Mechanical videos for Design of Machinery. Good luck on your final!