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DSATelugu
Добавлен 30 янв 2024
Recursion in java in telugu | Full explanation Introduction to Recursion Data structures and algo
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explain...
t.me/+oRkO0JQeX_w1OWJl
recursion,
recursion playlist c++,
recursion in java for beginners,
recursion aditya verma,
recursion relation,
recursion playlist java,
recursion and backtracking playlist java,
recursion gaan,
recursion and recurrence relations playlist,
recursion in c,
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recursion animated video,
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recursion ending explained,
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recursion in dsa python,
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explain...
Просмотров: 142
Видео
Linear Search and binary search algorithms with Time complexity analysis for O(log n) derivation#dsa
Просмотров 1217 часов назад
Join our telegram group for daily assignments : t.me/ oRkO0JQeX_w1OWJl Practice Link : leetcode.com/problems/binary-search/ binary search time complexity analysis, time and space complexity analysis of binary search algorithm, binary search algorithm time complexity analysis, binary search time complexity, binary search algorithm and time complexity, binary search time complexity calculation, b...
What will be asked in the interviews? Interview Tips and tricks Interview Guidance for Freshers 2024
Просмотров 1549 часов назад
What will be asked in the interviews? Interview Tips and tricks Interview Guidance for Freshers 2024
Merge Two Sorted Arrays Leetcode GeeksforGeeks in java in telugu | DSA interview question #dsa #java
Просмотров 16114 часов назад
Merge Two Sorted Arrays Leetcode GeeksforGeeks in java in telugu | DSA interview question #dsa #java
Find the Element that appears Once | Single Element in a sorted Array in java in telugu Leetcode
Просмотров 25119 часов назад
Find the Element that appears Once | Single Element in a sorted Array in java in telugu Leetcode
Sort an array of 0s 1s and 2s | Dutch National flag Algorithm | GeekForGeeks interview #dsa #java
Просмотров 17714 дней назад
Sort an array of 0s 1s and 2s | Dutch National flag Algorithm | GeekForGeeks interview #dsa #java
Maximum Subarray sum | Kadane's Algorithm Leetcode in java in telugu Dsa in telugu Amazon interview
Просмотров 17914 дней назад
Maximum Subarray sum | Kadane's Algorithm Leetcode in java in telugu Dsa in telugu Amazon interview
2 Sum Problem | two sum Leetcode #1 Amazon interview question Dsa course in java in telugu #dsa
Просмотров 26914 дней назад
2 Sum Problem | two sum Leetcode #1 Amazon interview question Dsa course in java in telugu #dsa
Check if array is sorted or not in java in telugu leetcode | tcs interview question Dsa #dsa #shorts
Просмотров 18114 дней назад
Check if array is sorted or not in java in telugu leetcode | tcs interview question Dsa #dsa #shorts
max consecutive ones Leetcode in java in telugu | Amazon interview question DSA tcs #dsa #amazon
Просмотров 26914 дней назад
max consecutive ones Leetcode in java in telugu | Amazon interview question DSA tcs #dsa #amazon
Find missing number in an array in java in telugu Amazon interview question dsa in telugu #dsa #tcs
Просмотров 37414 дней назад
Find missing number in an array in java in telugu Amazon interview question dsa in telugu #dsa #tcs
Move zeroes to end of an array in java in telugu Leetcode | Amazon adobe interview question#dsa #tcs
Просмотров 56621 день назад
Move zeroes to end of an array in java in telugu Leetcode | Amazon adobe interview question#dsa #tcs
TCS Interview question | difference between pre increment and post increment i++ ++i in telugu #dsa
Просмотров 41621 день назад
TCS Interview question | difference between pre increment and post increment i i in telugu #dsa
Palindrome number program in java in telugu | interview question | Optimized code | #dsa #coding
Просмотров 14221 день назад
Palindrome number program in java in telugu | interview question | Optimized code | #dsa #coding
Time complexity and space complexity of an algorithm in java in telugu | Detailed Explanation #dsa
Просмотров 47321 день назад
Time complexity and space complexity of an algorithm in java in telugu | Detailed Explanation #dsa
TCS interview question | multiply and divide a number by 2 without arithmetic operators #dsa #java
Просмотров 58621 день назад
TCS interview question | multiply and divide a number by 2 without arithmetic operators #dsa #java
Find all duplicates in an array Leetcode in java in telugu optimized | interview preparation #dsa
Просмотров 28121 день назад
Find all duplicates in an array Leetcode in java in telugu optimized | interview preparation #dsa
Remove duplicates from sorted Array Leetcode in java in telugu optimized interview preparation #dsa
Просмотров 24921 день назад
Remove duplicates from sorted Array Leetcode in java in telugu optimized interview preparation #dsa
Rotate array by K places in java in telugu | optimal approach | interview question | #dsa course
Просмотров 17021 день назад
Rotate array by K places in java in telugu | optimal approach | interview question | #dsa course
Count frequency of each element in an array java in telugu | DSA interview questions #dsa #interview
Просмотров 22221 день назад
Count frequency of each element in an array java in telugu | DSA interview questions #dsa #interview
Reverse an array in java in telugu optimized | Interview preparation | DSA couse #dsa #interview
Просмотров 24128 дней назад
Reverse an array in java in telugu optimized | Interview preparation | DSA couse #dsa #interview
Palindrome program in java in Telugu Optimized | interview preparation | DSA course #dsa #interview
Просмотров 50628 дней назад
Palindrome program in java in Telugu Optimized | interview preparation | DSA course #dsa #interview
Hlo bro
Hi bro
@@DSATelugu0321 bro I want to talk to you
@@DSATelugu0321 how I can contact to you
You can DM me in telegram
Excellent brother! Late ga vachindi Feeds lo ki! Mi efforts Mi Hardwork 👌💯. keep Going Champ!
Thank you 😊
hi Should not i use str[left] Instead of str.chartAt(left) ?
If you are doing in java You have to use str.charAt(left) str[left] - this is used for array But here in our problem we are dealing with strings so to retreive each character in a string we use charAt( ) function in java Hope this is helpful 😊
@@DSATelugu0321 String also supports index based access right? Correct me if I am wrong.
@@avdsuresh No, in java it is not possible! But in python it is possible .
Amazing :-) please keep going
Thank you! 😊
which clg bro?
Clg kadhu bro Job chesthunna working as SDE
@@DSATelugu0321 which company bro?
Linear search returns the value or index
Index
You have to print print (i) index value In the video while I am explaining It will be as Print(arr[i] +"is found at "+ i); Here i is the index. In leetcode you have to return the index so that's why I kept that code returning the index. Hope this is helpful 😊
@@DSATelugu0321ok bro
Miru coding.... Very easy gaa chestunnaru bro..... Java.. tutorial chestam maalanti variki use avuthundhi bro...
We r interested bro...on opps
Ok 👍
Anna maximum interview ki kavalisina important topics anni cheppu anna
If I miss anything, I will add in part 2 Don't worry😊 Please like share Subscribe 😊
#2nd approach code in python arr1 = [1, 2, 4, 5] arr2 = [0, 3, 7, 8, 9] # Swap elements to balance the two arrays i = len(arr1) - 1 j = 0 while i >= 0 and j < len(arr2): if arr1[i] > arr2[j]: arr1[i], arr2[j] = arr2[j], arr1[i] i -= 1 j += 1 else: break # Sort both arrays arr1.sort() arr2.sort() # Concatenate the sorted arrays result = arr1 + arr2 print(result) # Output: [0, 1, 2, 3, 4, 5, 7, 8, 9]
#1st approach code in python: arr1 = [1, 2, 4, 5] arr2 = [0, 3, 7, 8, 9] ans = [] # Initialize an empty list to store the result i, j = 0, 0 # Merge the two arrays while i < len(arr1) and j < len(arr2): if arr1[i] < arr2[j]: ans.append(arr1[i]) i += 1 else: ans.append(arr2[j]) j += 1 # Append remaining elements of arr1, if any while i < len(arr1): ans.append(arr1[i]) i += 1 # Append remaining elements of arr2, if any while j < len(arr2): ans.append(arr2[j]) j += 1 print(ans)
playlist create cheyu bro classes ani
Ok 👍
DSA with python beginners to pro level course chy broo
Super
Thanks😊
Bro dp topic nkaa problems chepandi
Nee videos super bro but maku basics kavala kadha
Basics nunchii
Striver take u forward suggested
Bro nuvvu dsa nerchukivadaniki aa channel prefer chasavu
After 2 we get 2^3 vastundhi kadha bro
Internal ga process nenu explain chesinattu jaruguthundi Like 2^3^2 undi anukondi Position ekkadunna twice unnai ante avi 0 avthundi Answer 3 vasthundi Example : 2^3^2^2^3 Then answer 22 33 - 0 ayyi Answer 2 vasthundi Hope you understand Artham ayyindi anukuntanu
@@DSATelugu0321 ok bro thanks for fast reply
You are welcome 😊
Please tell data structure from basics
Bro please continue this video's
👍
❤
Congratulations bro.....🎉🎉🎉🎉🎉🎉 thank you so much for teaching... other I know bro but ur videos are more helpful to me..... Like this u go a head u will definitely achieve ur goal.. thank you bro...
Thank you so much 😀 bro
Thank you Anna
You're welcome 🙂
Tq Anna
You're welcome ☺
ilanti DSA based topics ni telugu lo explain chesevaaru chala takkuva bro. Don't worry ,Future lo ni channel growth ekkadiko velthundi. Just upload your content consistently. kuncham last lo code raasi kuda pai-paina explain chey bro
Ok bro Thank you for your support ☺👍
@@DSATelugu0321good explanation keep it up
###APPROACH 2: DUTCH NATIONAL FLAG ALGORITHM def sort_012(arr): low = 0 mid = 0 high = len(arr) - 1 while mid <= high: if arr[mid] == 0: arr[low], arr[mid] = arr[mid], arr[low] low += 1 mid += 1 elif arr[mid] == 1: mid += 1 else: # arr[mid] == 2 arr[high], arr[mid] = arr[mid], arr[high] high -= 1 return arr
Thank you for sharing the python code 👏👏 . This will be helpful for our subscribers 👍
###APPROACH 1: def sort_012(arr): count_0 = 0 count_1 = 0 count_2 = 0 # Count occurrences of 0s, 1s, and 2s for num in arr: if num == 0: count_0 += 1 elif num == 1: count_1 += 1 elif num == 2: count_2 += 1 # Reconstruct the array index = 0 # Place all 0s in the array for _ in range(count_0): arr[index] = 0 index += 1 # Place all 1s in the array for _ in range(count_1): arr[index] = 1 index += 1 # Place all 2s in the array for _ in range(count_2): arr[index] = 2 index += 1 return arr
Time and space complexity ki best resource recommend chey bro
❤
Better solve company asked questions in interview then leetcode
Super Brother. Meeru videos Post chestune Undandi.
ni linked in pettu anna
🔥
Bro sort chasi negative index vadi chayachu ga
Sort chesthe O(nlogn) complexity terskuntundi so interviewer accept cheyyadu Optimize cheyyamantadu Hope your doubt is clarified ☺
Miru cheppetappudo.... Little bit confusing avuthundhi bro... Voice back ravatam valla...adhokkati correct cheyyandi bro Thank for teaching ❤bro...
You're welcome. Yeah bro adi channel starting appudu na daggara mic ledhu bro anduke nenu voice over ichanu so adi sync avvaledhu. But ippudu vache prathi video bane untundi. Adi na patha video so ala undi dont worry ippudu elanti quality problem undadhu. And long videos follow avvandi main ga chala detailed ga explain chesthunna prathi concept. Thank you for your support 🙂
Bro....miii explanation is too good bro but.... Voice back vastundhi
Bro you have amazing talent , thank you so much bro, meeru recent ga cheppina tcs interview question vinna next day naku tcs interview lo adhe question adigaru meeru cheppina logic cheppa,today offer letter vachindhi bro ,naku digital role vachindi bro i hope got placed because of you bro tq again,keep doing more interview questions and help us
Congratulations bro🎉🥳 All the best and keep it up. Keep supporting our channel and share to your friends as well. Thank you❤
Bro eppudu interview ayyindi broo entha time pattindhi offer letter kii inka document verification mail ki
Good work🎉
Thank you ☺
Super bro
Thank you 🙂
Great work,nice explanation bro.keep doing bro.
Thank you 🙂
Bro keep it up bro By the way ur working bro already
¯\_(ツ)_/¯
Your Explanation skills are superb brother 👍👍
Explain whole java with DSA ..if possible in future..it might helpful for so many people 🤝🤝💥
Will try 👍
Great explanation brother 🤝❤...ni videos mundey enduku kanapadaledu bro .
Do more shorts don't give up ALL the. Best bro
Thank you bro 😊 You can also watch the long videos of these shorts in our channel with clear explanation.
anna nee explanation chaala bagundi nuvvu views raavatledu ani em baadapadaku trust the process but ur explanation is very excellent please continue this dsa series i am in 3rd year
Thank you for your support 🙂