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You forgot the negative sign in your final cancellation. The answer should be -1/x^2.

Thanks!

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I'm confused on the first function of -2,1. At the end of the function, you wrote that 9/3 = 2. Should it not be three?

Hey Professor, is it possible that the s in the s(t) function stands for the position on the secant line?

Thanks for this awesome video. I think the Interval notations at the end were wrong though. They were supposed to be (-infinity , 2] Union [4 , infinity) due to the greater-than-equal-to sign. Please correct me if I am wrong. Thanks again.

I appreciate the 2nd alternative way to rewrite the formula. am definitely prone to the mistake you mentioned

For those wondering, this is the previous question which was the same except did not ask for a lead coefficient. When you see the P(x) @0:30, this is how they got that ...ruclips.net/video/ERtAmQkU-RI/видео.html

Small thing I noticed, you said sqaured for what looks like "9z^4 - 400" toward the end @2:56

hi man nice video. im from india. keep up the good work

There is an error between 5/8 x 4/7. It's supposed to be 5/8 x "3/4".

Hi

don't mind me just looking...

Is it correct?

8/4 = 2, so the interval should be [-1, 2)

9/3 = 3, correct? I'm guessing this was a typo

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great video bro

thanks, helpful

Freakin Awesome!

Awesome Math Videos! Professor Greenberg, Thank you

Math is freakin AWESOME! Thanks Professor Greenberg.

Professor Greenberg, your videos are really straightforward and fun to learn I love Math and the way you teach it makes it even more funner thank you for the videos.

You made this so easy to learn within the time of this video I got it down, I’m in college and my professor is not remotely as clear as you thanks so much lol