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120+√x^2+16x+88=5^3=125 則：√x^2+16x+88=5 x^2+16x+88-25=0 x^2+16x+63=0 (x+7)(x+9)=0 x=-7 or -9

log400/log2√5 =2log20/(1/2)(log20) =2/(1/2)=4

令2^y=a 則原式：2^3a+2a=320 10a=320 a=32=2^5 2^y=2^5 則y=5

X=0 is another solution

60%=0.6

Wrong😂

Big shoutout to this channel helps me a lot with maths thanks dude

*-√2* is also an answer (not only √2)

a² + b² = 6ab find (a + b)/(a - b) (a + b)² = a² + b² + 2ab = 8ab (a - b)² = a² + b² - 2ab = 4ab [(a + b)/(a - b)]² = 2 *(a + b)/(a - b) = ± √2*

Hi dude do u have a playlist for algebra from beginners to getting higher? Cuz im going into 3rd secondary school i need to understand algebra really good to have a foot before the othwrs appreciate and thanks for reading

Answer 1

just log both sides and put it in your calculator: xlog(9) = log(27*root3) x = log(27*root3)/log(9)

You could also do it this way: cbrt(7^2)*cbrt(7) = cbrt(7^3) = 7 7/sqrt(7) = sqrt(7)

If you can't do that in your head, you shouldn't be allowed within 10 miles of a math olympiad

Very nice job explaining 🙏

973 A^2+b^2+2ab

Keep going 🎉I am so interested to solve these..

X=2✓

36.5

32

Wtf is "nice" about this It's pathetically easy

2.

you don't want to be in Turkey's high schools...

I did it this way: ✓(50²-1/51)² Reduction of square root, 2499/51=49 Square root of 49 is 7. After contemplation i think its kinda complicated but that was my first method.

Whenever you see a X² - 1 i think it will Usually be a trick that requires that student to use the x2-y2 =( x-y) (x+y)

Very great and awsome communication, really helped me 😄

Very poor communication

cool

Where you get 11 from?

❤

1/9

2

Divide both sides by 5, then find the cube-root of 320.

4

What if its -1/9

very good 👍

Whe you take out 2^x why is it (3^x-1) and not (3-1)

6x-2x --------- = 8 2x 4x -----=8 2x 2x=8 8 x=---- 2 x=4

5