Rulmeca Corporation
Rulmeca Corporation
  • Видео 112
  • Просмотров 343 436
MINEXPO 2024 Rulmeca Corp
Here is a glimpse of what visitors can expect to see at MINEXPO 2024 at the Rulmeca exhibit in WEST HALL Booth #12177. Join us in Las Vegas, NV September 24-26, 2024. You won't be disappointed. The full portfolio of Rulmeca conveyor components will be on display.
Просмотров: 221

Видео

CLDA Graduation Video 2023 2024 RUS
Просмотров 1155 месяцев назад
Rulmeca Corporation joined other Wilmington, North Carolina manufacturers in presenting tours for middle school students in the 2023-2024 Career and Leadership Development Academy, sponsored by Wilmington Chamber of Commerce and New Hanover County Schools. Patrick Hassett, Rulmeca's Production Engineer, gave a tour at the company's facility.
hour glass thick wall
Просмотров 2166 месяцев назад
This video shows how Rulmeca Corporation assembles and tests special Motorized Pulleys for non-belt applications with the "hour glass" shell with a "thick wall".
Rulmeca Pulleys for Poultry
Просмотров 1757 месяцев назад
Video shows features and assembly techniques for model 220H Rulmeca Motorized Pulley with thick-wall profiled stainless steel shell to drive modular belt in major US poultry processing plant.
Student Tour at Rulmeca Feb 2024
Просмотров 718 месяцев назад
Committed to the educational goals of the Cape Fear Manufacturing Partnership, Rulmeca Corporation hosted another group of middle school students in the 2/7/2024 Career and Leadership Development Academy, sponsored by the Wilmington Chamber of Commerce and New Hanover County Schools.
Rulmeca Hosts Middle School Students 2024
Просмотров 729 месяцев назад
Rulmeca Corporation cooperated with other Cape Fear Manufacturing Partnership members to help host the 2024 Career and Leadership Academy on January 3, 2024, sponsored by the Wilmington, North Carolina Chamber of Commerce and the New Hanover County Schools We introduced middle school students to careers in manufacturing and sales and explained the training necessary for these jobs.
Brickmaking 2023
Просмотров 180Год назад
This video displays several Rulmeca Motorized Pulleys and dead-shaft idler pulleys working within a brick manufacturing plant. Models include 320M and UT320.
hopper lecture excerpt
Просмотров 318Год назад
This lecture explains how to calculate hopper feeder conveyor belt drag due to hopper pressure and suggests a method to reduce pressure by installed "pressure relief bars". Rulmeca software is used to simplify and demonstrate the methodology. The software is available at no charge from Rulmeca Corporation.
How to Plot Material Trajectory
Просмотров 537Год назад
This is a short excerpt from the full lecture on bulk conveyor drive design. It shows how to use the Rulmeca software to plot material trajectories to select an optimal belt speed.
Rulmeca and UNCW Cameron School 2023
Просмотров 37Год назад
This video summarizes the Rulmeca Corporation goal and organization and highlights the relationship between the company and the University of North Carolina at Wilmington Cameron School.
PAEA Webinar September 2023
Просмотров 1,6 тыс.Год назад
Purpose of Webinar: This video was recorded during the September 2023 meeting of the Polish-American Engineers Association meeting in Chicago, IL. It presents how to design a bulk conveyor belt drive system using CEMA "Historical Methodology" and the Rulmeca Corporation Conveyor Drive Power Calculation Program, version 7.30. Additionally, it presents and explains the equations required to minim...
Rulmeca in Salt Mining
Просмотров 129Год назад
This video features various large Rulmeca Motorized Pulleys at a major underground salt mine and barge loading facility.
Mobile Crush Screen Plants with Rulmeca Motorized Pulleys
Просмотров 233Год назад
This video shows Rulmeca Motorized Pulleys working at various mobile crushing & screening plants in the US. Featured products include the modelo 400M as the screen feed drive, the model 320H at the recirculating belt drive, and the model 220M at the cross bet drive.
Smoked Fish Processing 2023
Просмотров 414Год назад
This video shows various Rulmeca Drum Motors in service at a major US fish processing plant. Models 80LS, 113LS, and 138LS are configured with profiled stainless steel shells to drive positive drive conveyor belts and white nitrile rubber with center section V-groove to help keep belts trained.
Steel Recycling with Rulmeca Motorized Pulleys
Просмотров 467Год назад
This video shows various Rulmeca Motorized Pulleys in service at a steel recycling plant in the USA. Model 320M Motorized Pulleys drive automobile shredder refuse (ASR) conveyors which carry aluminum, copper, stainless steel, and non-ferrous materials.
Apple Processing with Rulmeca Motorized Pulleys in 2023
Просмотров 274Год назад
Apple Processing with Rulmeca Motorized Pulleys in 2023
Rulmeca Gives Student Tour
Просмотров 352Год назад
Rulmeca Gives Student Tour
Horizon Floor System
Просмотров 196Год назад
Horizon Floor System
How to Assemble and Repair Bulk Motorized Pulleys
Просмотров 1,2 тыс.Год назад
How to Assemble and Repair Bulk Motorized Pulleys
Assembly and Repair of Rulmeca Motorized Pulleys
Просмотров 3,8 тыс.Год назад
Assembly and Repair of Rulmeca Motorized Pulleys
Rulmeca Corp 60th Anniversary Celebration2
Просмотров 234Год назад
Rulmeca Corp 60th Anniversary Celebration2
Rulmeca Corp 60th Anniversary Celebration1
Просмотров 3632 года назад
Rulmeca Corp 60th Anniversary Celebration1
Rulmeca Celebration in USA
Просмотров 5752 года назад
Rulmeca Celebration in USA
Rulmeca Corporation DSI Project in France
Просмотров 1632 года назад
Rulmeca Corporation DSI Project in France
60th Anniversary Employee Party Rulmeca Corp
Просмотров 3872 года назад
60th Anniversary Employee Party Rulmeca Corp
Rulmeca Corp Facility 2022
Просмотров 7362 года назад
Rulmeca Corp Facility 2022
How to Calculate Belt Pull on Roller-Supported Conveyor Belts (metric)
Просмотров 5 тыс.3 года назад
How to Calculate Belt Pull on Roller-Supported Conveyor Belts (metric)
How to Calculate Inclined Roller Conveyor Belt Pull
Просмотров 4 тыс.3 года назад
How to Calculate Inclined Roller Conveyor Belt Pull
How to Calculate Belt Pull on Horizontal Roller Conveyors
Просмотров 5 тыс.3 года назад
How to Calculate Belt Pull on Horizontal Roller Conveyors
Webinar # 107 How to Drive a Conveyor Motor with a VFD
Просмотров 1,8 тыс.3 года назад
Webinar # 107 How to Drive a Conveyor Motor with a VFD

Комментарии

  • @GlobalboundE96
    @GlobalboundE96 9 дней назад

    Very much appreciated the for the good design and the behavior of the materials that feeding the entire conveyor system. This preview helps to inter act with the maintenance that will work on that specific design. Hence what we can only predict after this kind of design is installed in many kind industrial process lies with in the person that will assign to work with the equipment. Innovation is more than a commitment when we go for a long term productivity and efficiency of the equipent. Its really a great help to recap birds eye view of the design and movement of this kind of design conveyors as you go along your way in maintaining the equipment run effecient and looking for less maintenance.

  • @ShlokMahajan-x1f
    @ShlokMahajan-x1f 9 дней назад

    sir,can you please use Kg rather than pounds

  • @abdelkadermenzou8114
    @abdelkadermenzou8114 2 месяца назад

    thanks a lot

  • @rizanmd9334
    @rizanmd9334 4 месяца назад

    How we assume Lb -15ft, is there any change in length with any factor, then how we need make sufficient change in Lb ft

  • @rizanmd9334
    @rizanmd9334 4 месяца назад

    Thanks for information ❤ but I have few doubt

    • @rulmecacorporation4596
      @rulmecacorporation4596 4 месяца назад

      How may we help you resolve your doubts?

    • @rizanmd9334
      @rizanmd9334 4 месяца назад

      I had go threw the rulmecca problem solving section but I haven't found any details about skirt board in equation, how friction act on the conveyor

    • @rulmecacorporation4596
      @rulmecacorporation4596 4 месяца назад

      @@rizanmd9334 ruclips.net/video/5QJjy67Z-NM/видео.html please watch this video

    • @rulmecacorporation4596
      @rulmecacorporation4596 4 месяца назад

      @@rizanmd9334 ruclips.net/video/T7mgqj3bXSA/видео.html please watch this video too

  • @sakkie_5497
    @sakkie_5497 4 месяца назад

    We wont be able to get a copy of this sheet?

  • @Sigma_Rules_Bros
    @Sigma_Rules_Bros 5 месяцев назад

    Thank you professor. I dont get why few peoples here.

  • @rayzjr3762
    @rayzjr3762 5 месяцев назад

    Is this applicable to inclined slat conveyors?

    • @mikegawinski3450
      @mikegawinski3450 5 месяцев назад

      unfortunately, it only applies to flat rubber belt conveyors.

  • @nishantdhengre8569
    @nishantdhengre8569 6 месяцев назад

    Sir is this calculation will be same for drag chain conveyor

    • @mikegawinski3450
      @mikegawinski3450 6 месяцев назад

      The calculation is not valid for drag chain conveyors. You should contact a drag chain conveyor manufacturer for assistance

  • @eric-fm3bb
    @eric-fm3bb 8 месяцев назад

    Love this tutorial video so much!!!! Thank you sir.

  • @tzb05
    @tzb05 9 месяцев назад

    I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

    • @rulmecacorporation4596
      @rulmecacorporation4596 9 месяцев назад

      Dear sir, We will be happy to help you. Please provide your name and email address. Thanks, Mike

  • @tzb05
    @tzb05 10 месяцев назад

    I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

  • @bvrunowerneck1234
    @bvrunowerneck1234 10 месяцев назад

    I am a huge fan of rumelca material. Thank you guys.

  • @tzb05
    @tzb05 10 месяцев назад

    I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor

    • @rulmecacorporation4596
      @rulmecacorporation4596 10 месяцев назад

      Your question cannot be answered until you specify a belt speed at which the material will be carried. 1 watt = 1 newton-meter per second. Once you calculate the required tension (newtons) to pull the belt you must multiply that force by the desired belt speed (m/s). For example, a 5 km long horizontal conveyor carrying 3000mt/hr might have a belt speed of 5 m/s. If belt pull = 222 kilo newtons, then required electric power will be approximately 222 kN x 5 m/s = 1,110 kW.

    • @tzb05
      @tzb05 10 месяцев назад

      belt speed = 2.5m/s and material is dsand with density 1.55 Mt/M3 @@rulmecacorporation4596

    • @tzb05
      @tzb05 10 месяцев назад

      @@rulmecacorporation4596 here we are with full data I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

  • @neelchauhan9326
    @neelchauhan9326 10 месяцев назад

    hellow sir i want to calculate torque of dc geared motor which is used in side gripe conveyor which is inclined at 30 degree to pick a pvc pipe of 0.335 kg in total there are 6 pvc pipe to gripe by conveyor can u tell me how to do and also can u make a video on side grip conveyor belt which is inclided and can u give any id so i can reach u as i have some other problem related to side grip conveyor as i am making an project so

  • @kiranmathure880
    @kiranmathure880 Год назад

    Sir what about gear box,how to select gear box on the basis of torque for similar application pls reply

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      We have a video which addresses gear box torque, etc. would you like the link to the video?

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      ruclips.net/video/4dTvSlyYQp4/видео.htmlsi=dHYj7olGX81jB-SG

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      ruclips.net/video/KLg5uWEuqgs/видео.htmlsi=MsiWN0Y_rHFkVile

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      ruclips.net/video/PbSYe44UKnM/видео.htmlsi=ISUwxTH7IiO-x1nV

  • @billwells8054
    @billwells8054 Год назад

    Thanks. How/why do you have gravity pull as (load/ft) * h? Hmmm... I'm calculating.... I would use (sin 17.46) (250) = 75#. Same as you. But why is it also (load/ft) * h? Appreciate your help. EDIT: And if you don't mind, another question. Let's say the conveyor stops fully loaded. What is power required to get it going again? I'm assuming there must be a ramp-up time to go from 0 to 50 ft/min. So this would be the power to accelerate the total mass? I'm writing a continuing education engineering course. I studied this subject 60 years ago! Bill

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      Hi Bill. You could use trigonometry, but the result will be exactly the same since the belt pull required to overcome gravity is linearly proportional to the change in elevation. Rather than provide a complete "derivation" I simply showed the accurate short cut method we use to calculate the force.

  • @jamig.7254
    @jamig.7254 Год назад

    Hi there. What's the average cost of a 50-60ft mobile belt conveyor for hauling dirt away?

  • @qozia1370
    @qozia1370 Год назад

    use SI units like civilized humans! Americans are so backward

  • @f3nunez
    @f3nunez Год назад

    how to get the weight of the belt per ft, for 450 mm belt width. thanks

    • @Sigma_Rules_Bros
      @Sigma_Rules_Bros 5 месяцев назад

      divide your belt total weight(1kg =9.81N)by the active length you will get the weight load distribution. make sure to convert your unit to Meters

  • @f3nunez
    @f3nunez Год назад

    what handbook or textbook where you got this equation sir? is it possible to have this info coz I am doing my design term paper and I need to show the source of the book where the formulas you are using. thanks

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      Dear Fidel, I took the equations from the Rulmeca Group Main Catalog, which was originally published by our company more than 50 years ago. If you will send me your email address I will send you specific info about the book. Best regards, Mike Gawinski

    • @f3nunez
      @f3nunez Год назад

      @@rulmecacorporation4596 I want also want regarding the roller conveyor design

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      @@f3nunez ok. For the bulk roller conveyor equations we used the Conveyor Equipment Manufacturers Association guide book, fourth edition. For the unit roller conveyor equations we used the Rulmeca Group catalog

    • @f3nunez
      @f3nunez Год назад

      Is it possible to have soft copy of the said catalog? Thanks

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      @@f3nunez do you want digital copies?

  • @f3nunez
    @f3nunez Год назад

    Thank you very much for this video.

  • @marshalldaniels9836
    @marshalldaniels9836 Год назад

    😎 P R O M O S M

  • @intanpratiwi4499
    @intanpratiwi4499 Год назад

    3 lbs/feet. what parameters is that?

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      3 lbs/ft = the weight per foot of the belt.

    • @intanpratiwi4499
      @intanpratiwi4499 Год назад

      @@mikegawinski3450 how to calculate belt weight per foot ?

  • @onearyf1641
    @onearyf1641 Год назад

    How do we calculate the friction coefficient, do we refer to any table?

  • @nasreenmunshi9268
    @nasreenmunshi9268 Год назад

    Excellent video, Sir!

  • @PingXie-ur7pk
    @PingXie-ur7pk Год назад

    Excellent video. Well explained. Thanks a lot !

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      You are very welcome. If you have any questions, feel free to ask them.

  • @rishabhsharma6061
    @rishabhsharma6061 Год назад

    what should be the skirt design criteria if there are two chutes on a conveyor belt. The material passing out of one chute may hit the skirt of ahead chute.

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      The calculation is straightforward. You simply make the calculation as is the chute were continuous. In other words, if the first skirt is 3 meters long and the second skirt is 3 meters long, you simply use 6 meters as the skirtboard length. This will yield the appropriate estimate of total skirtboard drag.

  • @ibadovsadiq5491
    @ibadovsadiq5491 Год назад

    Hello. How can i get this motor?

    • @mikegawinski3450
      @mikegawinski3450 Год назад

      Good morning Mr Sadie. We will simply need your location and contact information. Thanks

  • @jacobthomas785
    @jacobthomas785 Год назад

    The conveyor is centre drive with rubberized drive pulley and tensioning pulley. Also head and tail pulleys are crowned pulleys. Still the tracking in one direction is difficult. Can you please guide?

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      Dear Jacob, We will be happy to give you some suggestions. You can obtain our contact info from our website rulmecacorp.com/contact-us/

  • @jacobthomas785
    @jacobthomas785 Год назад

    Hello. I have a bidirectional incline/decline conveyor. I can't track the belt in one direction.

  • @cemdaloglu417
    @cemdaloglu417 Год назад

    what is the meter of rotating parts?

  • @tebohomasiea2879
    @tebohomasiea2879 Год назад

    How can I reduce the speed of a conveyor belt without installing a VSD? I was thinking of installing a small drive pulley but am not sure if it will work Please assist

    • @rulmecacorporation4596
      @rulmecacorporation4596 Год назад

      If you change the diameter of your pulley you will need someone to verify you have enough power available in your electric motor.

  • @williamb1817
    @williamb1817 2 года назад

    I really enjoyed working for Rulmeca in Canada when they first opened in Wallaceburg Ontario. Over 5 years with the company taught alot...and helped me identify what I needed to do to grow in the industry. Though I have moved on I will never forget the products that I had a hand in creating when Joe Hartney was CEO and Lucas Morse was the engineer I worked for there. Congratulations to Rulmeca...When I had my picture in their book for one of the years I was there - I really felt appreciated.

  • @eddiediaz1165
    @eddiediaz1165 2 года назад

    ✋ p̶r̶o̶m̶o̶s̶m̶

  • @apankdefaa2835
    @apankdefaa2835 2 года назад

    I want to buy it but the agent in Indonesia doesn't respond to my calls

  • @JensHagenau
    @JensHagenau 2 года назад

    Great concept and execution of a conveyor system. Such innovative solutions are instrumental in ensuring that the material handling industry makes an important contribution to the economic well-being of every country in the world. Well done Dos Santos Internatiuonal's, well done Rulmeca!

    • @mikegawinski3450
      @mikegawinski3450 2 года назад

      Hi Jens! Thanks for your comment! And thanks for traveling from Germany to France to help with commissioning the equipment!

    • @JensHagenau
      @JensHagenau 2 года назад

      @@mikegawinski3450 👍

  • @youssefhassan1073
    @youssefhassan1073 2 года назад

    Hi Sir, Why you have neglected the gravity in the weight calculations?

  • @jacobthomas785
    @jacobthomas785 2 года назад

    Hi, Belt pull required to accelerate = mg x coeff.of friction+ma.But you have not considered ma?Is it wrong?

    • @mikegawinski3450
      @mikegawinski3450 2 года назад

      Please define your terms. Thanks

    • @jacobthomas785
      @jacobthomas785 2 года назад

      m=mass of the load(kg/m) +belt weight g=9.8 m/s2 a=acceleration

    • @mikegawinski3450
      @mikegawinski3450 2 года назад

      ma will always be negligible on short package conveyors which travel at 50 fpm +/-. However, if you need to accelerate very quickly to a high speed with a large load mass, then you should check it.

  • @enriquegonzalez2802
    @enriquegonzalez2802 2 года назад

    So professional. Thanks Master.

  • @kaiyang8669
    @kaiyang8669 2 года назад

    This is absolutely great shares!

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      You are very welcome. If you have any specific questions, please ask us.

  • @debasissahu3840
    @debasissahu3840 2 года назад

    Very nicely explained

  • @faizahmedbudihal6285
    @faizahmedbudihal6285 2 года назад

    Thank you so much Sir These are amazing. Can you please do the same for roller chain conveyors or chain conveyors

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      Our specialized expertise is with driving belt conveyors because we manufacture Motorized Pulleys to drive conveyor belts. You would be best served soliciting help from manufacturers of chain conveyor drives.

    • @faizahmedbudihal6285
      @faizahmedbudihal6285 2 года назад

      @@rulmecacorporation4596 Thank you for the reply, Can we suggest any book for chain drive systems

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      @@faizahmedbudihal6285 Here is something I found on the internet. It may help you. www.renold.com/upload/renoldswitzerland/conveyor_chain_-_designer_guide.pdf

  • @mfarooqiqbal
    @mfarooqiqbal 2 года назад

    in which part exactly this oil is being used for lubrication? In its gear or where? I want to know the chemistry of oil if you can help me

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      The oil circulates throughout the interior of the Motorized Pulley, lubricating all mechanical parts while also cooling the electric motor. We use Mobilgear SHC 630 synthetic oil and other brands.

  • @Ryohgantz
    @Ryohgantz 2 года назад

    Thank you for the calculation, Sir.

  • @mharith4177
    @mharith4177 2 года назад

    Hello if you dont mind me asking where did 33,000 lbs/min came from? For calculating the horsepower

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      The units used are defined by physics. In imperial units, 1 HP is defined as equal to 33,000 ft-lbs/minute (foot-pounds per minute). In metric units 1 KW = 1,000 N-m/s (newton-meters per second).

  • @jhonnyrestrepo6780
    @jhonnyrestrepo6780 2 года назад

    Thanks for sharing this information. Excellent

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      You are very welcome. If there is any way our company can help you, please let me know. My email address is mgawinski@rulmeca.com

  • @wadib3eed7
    @wadib3eed7 2 года назад

    You calculated the mechanical power is required, but does that mechanical power equal to the electrical power of the motor which will drive the belt ? in the case of calculation P=0.15KW , so in this case i will use an AC motor with a power at least of 0.15 KW to move all those weights ?

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      We have some videos explaining the relationship between calculated required mechanical power and suggested electrical power. Did you watch them yet?

    • @wadib3eed7
      @wadib3eed7 2 года назад

      @@rulmecacorporation4596 No, i did not , i will search it .

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      @@wadib3eed7 watch this webinar please m.ruclips.net/video/q5v3M6ZsrrY/видео.html

    • @wadib3eed7
      @wadib3eed7 2 года назад

      @@rulmecacorporation4596 Thank you so much for helping me.

  • @travellervkvlog552
    @travellervkvlog552 2 года назад

    I think belt weight should be equal 2 times

  • @hansikabagga
    @hansikabagga 2 года назад

    how does one know the friction coefficient?

    • @rulmecacorporation4596
      @rulmecacorporation4596 2 года назад

      precise estimates of frictional coefficients may be obtained from belt suppliers and slider bed manufacturers