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Amazing

More options for conveyor belt replacement lowered overall cost when considering a major wear component very nice

Very much appreciated the for the good design and the behavior of the materials that feeding the entire conveyor system. This preview helps to inter act with the maintenance that will work on that specific design. Hence what we can only predict after this kind of design is installed in many kind industrial process lies with in the person that will assign to work with the equipment. Innovation is more than a commitment when we go for a long term productivity and efficiency of the equipent. Its really a great help to recap birds eye view of the design and movement of this kind of design conveyors as you go along your way in maintaining the equipment run effecient and looking for less maintenance.

sir,can you please use Kg rather than pounds

thanks a lot

How we assume Lb -15ft, is there any change in length with any factor, then how we need make sufficient change in Lb ft

Thanks for information ❤ but I have few doubt

We wont be able to get a copy of this sheet?

Thank you professor. I dont get why few peoples here.

Is this applicable to inclined slat conveyors?

Sir is this calculation will be same for drag chain conveyor

Love this tutorial video so much!!!! Thank you sir.

I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)

I am a huge fan of rumelca material. Thank you guys.

I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km length = 5 Km , Flow = 2500 to 3000 Mt/Hr , Route inclination= zero inclination, Width = 1200 mm , trough angle=30 how much electricity will be consumed in electrical motor

hellow sir i want to calculate torque of dc geared motor which is used in side gripe conveyor which is inclined at 30 degree to pick a pvc pipe of 0.335 kg in total there are 6 pvc pipe to gripe by conveyor can u tell me how to do and also can u make a video on side grip conveyor belt which is inclided and can u give any id so i can reach u as i have some other problem related to side grip conveyor as i am making an project so

Sir what about gear box,how to select gear box on the basis of torque for similar application pls reply

Thanks. How/why do you have gravity pull as (load/ft) * h? Hmmm... I'm calculating.... I would use (sin 17.46) (250) = 75#. Same as you. But why is it also (load/ft) * h? Appreciate your help. EDIT: And if you don't mind, another question. Let's say the conveyor stops fully loaded. What is power required to get it going again? I'm assuming there must be a ramp-up time to go from 0 to 50 ft/min. So this would be the power to accelerate the total mass? I'm writing a continuing education engineering course. I studied this subject 60 years ago! Bill

Hi there. What's the average cost of a 50-60ft mobile belt conveyor for hauling dirt away?

use SI units like civilized humans! Americans are so backward

how to get the weight of the belt per ft, for 450 mm belt width. thanks

what handbook or textbook where you got this equation sir? is it possible to have this info coz I am doing my design term paper and I need to show the source of the book where the formulas you are using. thanks

Thank you very much for this video.

😎 P R O M O S M

3 lbs/feet. what parameters is that?

How do we calculate the friction coefficient, do we refer to any table?

Excellent video, Sir!

Excellent video. Well explained. Thanks a lot !

what should be the skirt design criteria if there are two chutes on a conveyor belt. The material passing out of one chute may hit the skirt of ahead chute.

Hello. How can i get this motor?

The conveyor is centre drive with rubberized drive pulley and tensioning pulley. Also head and tail pulleys are crowned pulleys. Still the tracking in one direction is difficult. Can you please guide?

Hello. I have a bidirectional incline/decline conveyor. I can't track the belt in one direction.

what is the meter of rotating parts?

How can I reduce the speed of a conveyor belt without installing a VSD? I was thinking of installing a small drive pulley but am not sure if it will work Please assist

I really enjoyed working for Rulmeca in Canada when they first opened in Wallaceburg Ontario. Over 5 years with the company taught alot...and helped me identify what I needed to do to grow in the industry. Though I have moved on I will never forget the products that I had a hand in creating when Joe Hartney was CEO and Lucas Morse was the engineer I worked for there. Congratulations to Rulmeca...When I had my picture in their book for one of the years I was there - I really felt appreciated.

✋ p̶r̶o̶m̶o̶s̶m̶

I want to buy it but the agent in Indonesia doesn't respond to my calls

Great concept and execution of a conveyor system. Such innovative solutions are instrumental in ensuring that the material handling industry makes an important contribution to the economic well-being of every country in the world. Well done Dos Santos Internatiuonal's, well done Rulmeca!

Hi Sir, Why you have neglected the gravity in the weight calculations?

Hi, Belt pull required to accelerate = mg x coeff.of friction+ma.But you have not considered ma?Is it wrong?

So professional. Thanks Master.

This is absolutely great shares!

Very nicely explained

Thank you so much Sir These are amazing. Can you please do the same for roller chain conveyors or chain conveyors

in which part exactly this oil is being used for lubrication? In its gear or where? I want to know the chemistry of oil if you can help me

Thank you for the calculation, Sir.

Hello if you dont mind me asking where did 33,000 lbs/min came from? For calculating the horsepower

Thanks for sharing this information. Excellent

You calculated the mechanical power is required, but does that mechanical power equal to the electrical power of the motor which will drive the belt ? in the case of calculation P=0.15KW , so in this case i will use an AC motor with a power at least of 0.15 KW to move all those weights ?