Видео

How to repair OR replace the LCD of DYNA-51 KIT

Resistors✅ not registers

Mam is ur name sadia??

❤❤❤❤❤❤❤❤q❤❤q

thankuu

Super mam I clearly understand

Thank you maam 🥹🫶🏻

Tq mam

Thank you so much mam❤🎉

Thank you❤️ so much mam so much of gratitude on u

Can u plz speak little Louder

Thank you mam

thanks a lot ma'am

M =5 bits ?

keep the book aside and explain on your own what kind of teacher are you😔🥱

3:55 whatt? msb of 'A' can determine if the whole' A' is -ve??

10:15 DSSS

Nice information to share, thank you and keep it up :)

Thank you!!

why is a initialized to 0000 why is count 4 You should tell the reasoning for all of this

Thank you ma'am

Where I get it

Tasm folder link

Explaining is nice but voice is low so speek loud mam

Speak faster, okay? No need to repeat the name of the register twice.

Thank you madam 😊😊

good morning sirs

Nice

Arrived at the "Keyboard Matrix" stayed for the pasta🤘

5:03 how 1 is less than 0 mam?

Clear cut explaining mam

its reallly nice teaching

thanks alot didi

maam when you do the middle byte addition , in some cases there might be a carry for example FEFF * FF . so how to compensate for that carry bit?

Good

Thank you so much!!❤️

this is confusing..... You mix up a binary nr and a BCD nr ... BCD is defined as binary digit code which only exist out of nrs from 0 to 9 . If you e.g. would start with the hex nr A1F4, then your algorithm goes wrong, as hex A is decimal 10 or 1010 in binary. in BCD code the nr 10 decimal is formed out of 1 packed BCD wich is then: 0001000 or two BCD's 0001 and 0000. Your process goes right, but you are converting a hex nr with digits smaller /qual to 9 , if you would convert e.g. hex A1F4, this would be in your algorithm result in 1010 0001 1111 0100, here the 1010 and the 1111 are no BCD codes. the second step is right, but it converts the decimal nr from the resulting binary nr to its decimal digits

DOUBT-2: In the 3rd step A => 1100 When we right shift it is supposed to be 0110 right but why it is 1110 ?? but Q right shift was done well, but A become 1110 after right shift ??

DOUBT-1: Not sure what is Q-1 ??? why it has to be zero also not sure ??? Similarly What is A (name of that register) & why we have to initialize to Zeros not getting from the video

Very good mam

Mam entha ppt enga download panninga... Link share pannunga mam

Very low valuem Or voice so please increase your base

0:40 I question whether a vacuum is a "medium".

thankyou maam, explanation is very clear.

en que va esa programacion?

very nice explanation mam,Thanks a lot mam

tomorrow i have exam and this video is going to save me

delay why loaded with FF and 06 mam

Tqqqq very much mam

Thank you for this!