maths . 666k
maths . 666k
  • Видео 207
  • Просмотров 12 246

Видео

--3/10 + 12/-10 + 14/10|-5/10 + 9/7 + 3/20 + -11/14|5/36 + -7/8 + 6/-72 + -3/-12#simplification
Просмотров 14 часа назад
Simplify - -3/10 12/-10 14/10 -5/10 6/13 8 -5/10 9/7 3/20 -11/14 5/36 -7/8 6/-72 -3/-12 #simplification
for x = 1/10 and y = -3/5 z = 7/20 Find the values of (x - y) - z and x - (y - z) are they equal ?
Просмотров 77 часов назад
Find the values of x - y and y - x for x = 2/3 and y = 5/9 are they equal ? for x = 1/10 and y = -3/5 z = 7/20 Find the values of (x - y) - z and x - (y - z) are they equal ?
The sum of two rational numbers is -5 if one of the umber is 2/3 find the other.#subtraction
Просмотров 109 часов назад
The sum of two rational numbers is -5 if one of the umber is 2/3 find the other. What number should be added to -3/7 so as to get 1. What number should be subtracted from -1 so as to get 5/3
Subtraction Of Rational Number|Find the value of -6/7 - (-5/7)5/24 - 7/369/10 - 7/ -15 #subtraction
Просмотров 712 часов назад
Subtraction Of Rational Numbers Find the value of - 6/7 - (-5/7) 5/24 - 7/36 9/10 - 7/ -15 -3/8 - (-6/20) Subtract - 5/9 from -7/9 -5/7from 0 5/11 from - 8/23 -2/9 from 7/6
Subtraction Of Rational Numbers|Commutative property|Associative property|Identity element|Inverse
Просмотров 1114 часов назад
Subtraction Of Rational Numbers Commutative property Associative property Identity element Inverse #operationonrationalnumbers #subtraction
verify x + (y + z) = (x + y) + z for following values of x and y | x = 3/4 and y = 5/6 and z = -7/8
Просмотров 1019 часов назад
verify x (y z) = (x y) z for following values of x and y x = 3/4 and y = 5/6 and z = -7/8 x = 2/3 and y = -5/6 and z = -7/9 x = 3/5 and y = -6/9 and z = 2/10 x = -3/5 and y = -7/10 and z = -8/15 #associative #associativelaw
verify x + y = y = x for values of x and y|x = 5/7 and y = -3/2|x = 5 and y = 3/2 #commutative
Просмотров 821 час назад
verify x y = y = x for following values of x and y x = 5/7 and y = -3/2 x = 5 and y = 3/2 x = -8 and y = 9/2 x = -5/14 and y = -1/21 #commutative #commutativeproperty
Add the following- 2/7 + 5/7-5/9 + 7/92 * 3/11 + 9/ -11-5/4 + 5/4-2 * 5/6 + 13/-6-21/3 + 18/3
Просмотров 14День назад
Add the following- 2/7 5/7 -5/9 7/9 2 * 3/11 9/ -11 -5/4 5/4 -2 * 5/6 13/-6 -21/3 18/3 find the values of - 4/9 7/4 -7/11 1/4 5/8 -3/5 10/63 6/7 -7/64 3/-16 5/12 -9/20 #addition #rationalnumbers
Properties of rational numbers in ADDITION |Identity element of addtion|- x is additive inverse of x
Просмотров 7День назад
Properties of rational numbers in ADDITION - Identity element of addtion - x is additive inverse of x #rationalnumbers
Properties of rational numbers ADDITION|Commutative Property|Associative Property #rationalnumbers
Просмотров 12День назад
Properties of rational numbers in ADDITION - Commutative Property Associative Property #rationalnumbers
( 7th class) Operations on rational numbers | how to add rational numbers #rationalnumbers #videos
Просмотров 14День назад
( 7th class) Operations on rational numbers | how to add rational numbers #rationalnumbers #videos
how to draw Kazutora Hanemiya | tokyo revengers #tokyorevengersviral #anime #drawing
Просмотров 13514 дней назад
how to draw Kazutora Hanemiya | tokyo revengers #tokyorevengersviral #anime #drawing
write each of the following numbers in the form k * 10^n 1384000 | 12.32005 | 2157.957 | 0.0000085
Просмотров 282 месяца назад
write each of the following numbers in the form k * 10^n where 1 less than and = k less than 10 and n is integer 1384000 12.32005 2157.957 0.00002 0.00729 0.000000000926 520000000 0.0000085
Use of exponents in expressing large and small numbers
Просмотров 132 месяца назад
Use of exponents in expressing large and small numbers
Find the value of x so that -3^2 * (-4)^2 = (-12)^2x | (-3/2)^6 * (4/9)^3 = (1/2)^3x
Просмотров 192 месяца назад
Find the value of x so that -3^2 * (-4)^2 = (-12)^2x | (-3/2)^6 * (4/9)^3 = (1/2)^3x
Simplify4^4 * 5^-4 | 2^2 * (-1/3)^2 | (-2/3)^3 * (-3/5)^3 |(1/2) ^-2 * (2/5)^-2(-2/3)^-5 * (-3/2)^-5
Просмотров 172 месяца назад
Simplify4^4 * 5^-4 | 2^2 * (-1/3)^2 | (-2/3)^3 * (-3/5)^3 |(1/2) ^-2 * (2/5)^-2(-2/3)^-5 * (-3/2)^-5
if x and y are two rational numbers and m is integer then (x * y)^m = x^m * y^m #exponents
Просмотров 112 месяца назад
if x and y are two rational numbers and m is integer then (x * y)^m = x^m * y^m #exponents
By what number should (-12)^-1 be divided so that quotient maybe equal to (-4)^-1 #exponents
Просмотров 242 месяца назад
By what number should (-12)^-1 be divided so that quotient maybe equal to (-4)^-1 #exponents
By what number should (-3)^-2 be multiplied so that product maybe equal to 9 #exponents
Просмотров 262 месяца назад
By what number should (-3)^-2 be multiplied so that product maybe equal to 9 #exponents
if p/q = (2/3)^-3 / (3/4)^0 find (p/q)^-2 | if p/q = (2/3)^2 * (1/3)^-4 find (p/q)^-2 #exponents
Просмотров 142 месяца назад
if p/q = (2/3)^-3 / (3/4)^0 find (p/q)^-2 | if p/q = (2/3)^2 * (1/3)^-4 find (p/q)^-2 #exponents
Find the value of x so that -(3/4)^-9 * (3/4)^-7 = (3/4)^4x | (2/9)^-6 * (2/9)^3 = (2/9)^2x-1
Просмотров 232 месяца назад
Find the value of x so that -(3/4)^-9 * (3/4)^-7 = (3/4)^4x | (2/9)^-6 * (2/9)^3 = (2/9)^2x-1
check your knowledge by guessing common questions #iqtest #generalknowledge #braintest
Просмотров 392 месяца назад
check your knowledge by guessing common questions #iqtest #generalknowledge #braintest
subring|A non empty subset S of ring R is Subring iff a,b belong to S then a-b and ab belongs to S
Просмотров 792 месяца назад
subring|A non empty subset S of ring R is Subring iff a,b belong to S then a-b and ab belongs to S
Simplify | (1/12)^-2 + (1/3)^-2 + (1/4)^-2 | (2^-1 / 5^-1)^2 * (-5/8)^-1#class7maths
Просмотров 102 месяца назад
Simplify | (1/12)^-2 (1/3)^-2 (1/4)^-2 | (2^-1 / 5^-1)^2 * (-5/8)^-1#class7maths
law 3 - If x be any rational number ( x is not equal to 0 ) x^m / x^n = 1/x^n-m
Просмотров 112 месяца назад
law 3 - If x be any rational number ( x is not equal to 0 ) x^m / x^n = 1/x^n-m
Simplify (2/7)^-3 / (2/7)^-2 | (3/5)^-4 * (3/5)^4 + (1/4)^5 * (1/4)^-5
Просмотров 52 месяца назад
Simplify (2/7)^-3 / (2/7)^-2 | (3/5)^-4 * (3/5)^4 (1/4)^5 * (1/4)^-5
convert negative exponents to positive exponents (3/4)^-2 | ( (5/8)^-2)^3 | (2/5)^-3 * (2/5)^5
Просмотров 232 месяца назад
convert negative exponents to positive exponents (3/4)^-2 | ( (5/8)^-2)^3 | (2/5)^-3 * (2/5)^5
law 5 - if x be any rational number( x not equal to 0 ) and m be positive integer thenx^-m = 1/x^m
Просмотров 112 месяца назад
law 5 - if x be any rational number( x not equal to 0 ) and m be positive integer thenx^-m = 1/x^m
Find the value of x so that-(3/4)^2x + 1 = [ (3/4)^3 ]^3 | (2/5)^3 * (2/5)^6 = (2/5)^3x
Просмотров 312 месяца назад
Find the value of x so that-(3/4)^2x 1 = [ (3/4)^3 ]^3 | (2/5)^3 * (2/5)^6 = (2/5)^3x

Комментарии

  • @detsungB590
    @detsungB590 12 дней назад

    🔥🔥🔥🔥🔥

  • @thirdeyetalent5666
    @thirdeyetalent5666 17 дней назад

    Thanks mam it was very helful...!!

    • @maths.666k
      @maths.666k 16 дней назад

      Glad it helped ☺️☺️

  • @HuzaifaHuzaif
    @HuzaifaHuzaif 22 дня назад

    Bahut mast explain kiya apne❤❤

    • @maths.666k
      @maths.666k 22 дня назад

      Glad it helped ☺️☺️

  • @gargiparmar969
    @gargiparmar969 Месяц назад

    ❤😊

  • @akshatmehta3872
    @akshatmehta3872 Месяц назад

    Thank you mam, it really helped 👍

    • @maths.666k
      @maths.666k Месяц назад

      Glad it helped ☺️☺️

  • @cryptoexperts5659
    @cryptoexperts5659 Месяц назад

    👍👍

  • @KumkumJaiswal8400
    @KumkumJaiswal8400 2 месяца назад

    Thanks for providing this lecture and Mathematical modeling ke bhi lectures provide Kara digiye 😊😊

    • @maths.666k
      @maths.666k 2 месяца назад

      Glad it helped ☺️☺️ and for mathematical modelling...will try to post the video's 😄

    • @KumkumJaiswal8400
      @KumkumJaiswal8400 2 месяца назад

      Thanks

  • @dakshitakumari5413
    @dakshitakumari5413 2 месяца назад

    So useful for me thank you❤❤

    • @maths.666k
      @maths.666k 2 месяца назад

      Glad it helped ☺️☺️

  • @KeyserTheRedBeard
    @KeyserTheRedBeard 2 месяца назад

    Incredible content, maths . 924k. Looking forward to seeing your next upload from you. I hit the thumbs up button on your video. Keep up the amazing work! The insights shared about the impact of recent trends on market dynamics were fascinating. How do you think these changes will shape industry standards in the coming years?

  • @AmanpreetKaur-f2b
    @AmanpreetKaur-f2b 2 месяца назад

    Mam you are supper 👌👌👌

    • @maths.666k
      @maths.666k 2 месяца назад

      Glad it helped 😄😄

  • @VIRENRAINA-w2d
    @VIRENRAINA-w2d 2 месяца назад

    Thanks❤

    • @maths.666k
      @maths.666k 2 месяца назад

      Glad it helped 😄

  • @rajni3559
    @rajni3559 3 месяца назад

    Mam plz real analysis ki 2nd chapter ki bhi videos download ker do 🙏🙏🙏🙏

    • @maths.666k
      @maths.666k 3 месяца назад

      Chapter ka name mention kardo..

    • @rajni3559
      @rajni3559 3 месяца назад

      @@maths.666k metrics , open and closed sets

    • @maths.666k
      @maths.666k 3 месяца назад

      next week upload karugi videos...

  • @rajni3559
    @rajni3559 3 месяца назад

    Very nice class mam

    • @maths.666k
      @maths.666k 3 месяца назад

      Glad it helped ☺️

  • @Sahu_da
    @Sahu_da 3 месяца назад

    सारे जहां से अच्छा हिंदुस्तान हमारा

  • @Sahu_da
    @Sahu_da 3 месяца назад

    मेरा आजाद भारत हकीकत

  • @bullyt77
    @bullyt77 3 месяца назад

    Thank you

  • @fiftyshadesofuths7820
    @fiftyshadesofuths7820 3 месяца назад

    I am sad u arenot getting views

  • @nehasingla18
    @nehasingla18 3 месяца назад

    17 theorem upload krdo

    • @maths.666k
      @maths.666k 3 месяца назад

      Tomorrow at 4:00 p.m upload kar dungi..😀

  • @Alisse-hx1xu
    @Alisse-hx1xu 7 месяцев назад

    Excelent, thank you very much!!!

    • @maths.666k
      @maths.666k 7 месяцев назад

      Glad it helped!

  • @rpsingh_18
    @rpsingh_18 10 месяцев назад

    Thank you mam

    • @maths.666k
      @maths.666k 10 месяцев назад

      Most welcome 😊

  • @rpsingh_18
    @rpsingh_18 10 месяцев назад

    Thank you mam .. these are helpful for me 🎉

    • @maths.666k
      @maths.666k 10 месяцев назад

      Glad to hear that