Dr Sean
Dr Sean
  • Видео 23
  • Просмотров 1 923 344
Exploring Bayes' Rule in 5 Levels of Complexity
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/DrSean . You’ll also get 20% off an annual premium subscription.
Bayes' Rule lets us update probabilities (and our beliefs!) based on new evidence. Let's explore Bayes' Rule in 5 levels, starting with medical testing and trial evidence, and ending with an exploration of the power of Bayesian statistics.
This video was sponsored by Brilliant.
00:00 Introduction
00:38 Level 1 - Medical Testing
03:11 Level 2 - Trial Evidence
05:36 Level 3 - Proving Bayes' Rule
07:00 Sponsored Message
08:35 Level 4 - Continuous Case
11:13 Level 5 - Bayesian Statistics
Просмотров: 6 905

Видео

What exactly is e? Exploring e in 5 Levels of Complexity
Просмотров 104 тыс.2 месяца назад
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/DrSean . You’ll also get 20% off an annual premium subscription. What is e? Let's explore the number e in 5 levels of complexity, ranging from compound interest, to representing e in calculus, to simulating e with probability. This video was sponsored by Brilliant. 00:00 Introduction 00:12 Level 1: Compound In...
Imaginary Numbers are Not "Imaginary"! In 5 Levels of Complexity
Просмотров 62 тыс.3 месяца назад
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/DrSean . You’ll also get 20% off an annual premium subscription. Imaginary numbers are not "Imaginary"! Despite their name, they are completely solid mathematically, and they are critical for many real-world applications. Let's explore imaginary numbers in 5 levels, ranging from the idea behind calling them "i...
3 Integrals You Won't See in Calculus (And the 2 You Will)
Просмотров 82 тыс.3 месяца назад
In Calculus, we usually learn the Riemann integral, or sometimes the Darboux integral in disguise. But there are many problems these integrals can't solve! Like if we want to integrate a function which is discontinuous everywhere, or if we want to integrate with respect to a random process. Let's explore 5 different integrals, starting with the 2 you might see in Calculus, and then 3 more advan...
The Hot Potato Problem Solved 2 Ways - from Algebra to Math Major!
Просмотров 3,5 тыс.4 месяца назад
The problem goes like this: you're playing hot potato on a cube. You're at one vertex, and a hungry monster is at an adjacent vertex. You throw the potato to one of the neighboring vertices with equal probabilities. People standing at each other vertex act the same way. What's the probability you feed the monster? Let's analyze this problem two ways - first with algebra, and then as a Markov Ch...
What is 0? From Bee Brains to the Minds of Mathematicians
Просмотров 14 тыс.4 месяца назад
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/DrSean . You’ll also get 20% off an annual premium subscription. 0 lies at the heart of algebraic structures and allows us to do calculus. But what is it? Let's explore 0 in 5 levels ranging from a study on bees' understanding of 0 to algebra, calculus, and beyond. In the last level, we'll see how to rigorousl...
+1−1+1−1+... Explained in 5 Levels from Algebra to Math Major
Просмотров 246 тыс.4 месяца назад
What is 1−1 1−1 ...? Let's explore this series in 5 levels, ranging from explorations with arithmetic and algebra to rigorous solutions from Calculus and beyond! 00:00 Introduction 00:18 Level 1 Arithmetic Ideas 01:33 Level 2 Algebra Ideas 03:01 Level 3 Calculus 04:01 Level 4 Cesàro Sum 05:20 Level 5 Abel Sum
Is π Random? Exploring the Elusive Normal Numbers
Просмотров 4,3 тыс.4 месяца назад
Is pi random? Pi is fixed and predetermined, but its digits look just like random digits! We'll define normal numbers by exploring why pi's digits look random. Then we'll see what it would mean if pi is a normal number. 00:00 Introduction 00:18 Why do pi's digits look random? 01:02 Normal numbers 03:17 Is pi normal? 04:47 What if pi is normal?
The Hidden Power in Pascal's Triangle
Просмотров 3,9 тыс.5 месяцев назад
What makes Pascal's triangle so powerful? It has deep connections to the Binomial Theorem and the Central Limit Theorem. And hidden within it are the powers of 2, the Fibonacci sequence, and the fractal Sierpinski's Triangle! Let's explore these patterns and see why they show up in Pascal's Triangle. 00:00 Introduction 00:14 What is Pascal's Triangle? 01:07 Connections to Algebra 04:07 Connecti...
0^0 = 1? Exploring 0^0 in 5 Levels from Exponents to Math Major
Просмотров 23 тыс.5 месяцев назад
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/DrSean . You’ll also get 20% off an annual premium subscription. What is 0^0? Let's explore the value of 0^0 in 5 levels, ranging from Euler's definition from the 1700s to Calculus and beyond. This video was sponsored by Brilliant. 00:00 Introduction 00:20 0^0 in the 1700s 01:17 Algebra 03:21 Polynomials 05:02...
Divisibility Tricks in 5 Levels of Difficulty
Просмотров 15 тыс.5 месяцев назад
To check if a number is divisible by 3, you can add up the digits and see if that number is divisible by 3! Let's explore divisibility tricks like this in 5 levels of difficulty. We'll find divisibility tricks for each number 2-12, and also explore how divisibility tricks work in other bases! Divisibility rules for 2-12 (in base 10), and for working in other bases. 00:00 Introduction 00:19 Divi...
0! = 1 Explained in 5 Levels from Counting to Math Major
Просмотров 428 тыс.5 месяцев назад
The factorial of 4 is 4! = 4 * 3 * 2 * 1 = 24. But what is 0 factorial? At first, we might guess it should be 0, but we actually define 0! = 1. Let's explore why 0! = 1 in five levels, ranging from the meaning of factorials when counting, through explanations from Calculus and beyond. 00:00 Introduction 00:22 Level 1: Counting 01:12 Level 2: Algebra 02:44 Level 3: Combinations 04:07 Level 4: Ca...
This Simple Puzzle Tricks Mathematicians -- Monty Hall Problem in 5 Levels
Просмотров 7 тыс.6 месяцев назад
In an "Ask Marilyn" column, Marilyn vos Savant correctly solved the puzzle now known as the Monty Hall Problem. Around 10,000 people wrote in to say she was wrong, including many mathematicians! Researchers have even found that pigeons tend to learn the optimal strategy faster than humans during repeated trials. Let's explore the Monty Hall problem in 5 levels, from simulations of the game thro...
Endless Sizes of Infinity, Explained in 5 Levels
Просмотров 23 тыс.6 месяцев назад
There are infinitely many sizes of infinity! Let's explore this idea in five levels, ranging from tangible examples with hotel infinity to proving that there are infinitely many sizes of infinity.
0.99999... = 1 in Five Levels -- Elementary to Math Major
Просмотров 156 тыс.6 месяцев назад
The repeating decimal 0.99999.... = 1. They're exactly equal! Let's explore this in five levels, ranging from a quick calculation with fractions, to a more rigorous mathematical proof.
Let's Solve the Interview Puzzle that Baffled Me
Просмотров 45 тыс.6 месяцев назад
Let's Solve the Interview Puzzle that Baffled Me
Negative × Negative = Positive in 5 Levels -- Elementary to Math Major
Просмотров 229 тыс.6 месяцев назад
Negative × Negative = Positive in 5 Levels Elementary to Math Major
Winning Hexcodle with Binary Search
Просмотров 1,1 тыс.7 месяцев назад
Winning Hexcodle with Binary Search
A Surprisingly Simple Trick to Solve the Toughest GRE Probability Question
Просмотров 2,2 тыс.7 месяцев назад
A Surprisingly Simple Trick to Solve the Toughest GRE Probability Question
Dividing by Zero in Five Levels -- Elementary to Math Major
Просмотров 457 тыс.7 месяцев назад
Dividing by Zero in Five Levels Elementary to Math Major
This Can't Be Right, But Where's the Flaw? Two Envelopes Paradox Explained
Просмотров 2,1 тыс.7 месяцев назад
This Can't Be Right, But Where's the Flaw? Two Envelopes Paradox Explained
Why don't these cancel out? The square root of x^2 is not always x!
Просмотров 6 тыс.7 месяцев назад
Why don't these cancel out? The square root of x^2 is not always x!
My Favorite Counting Technique includes ALL of the other Three!
Просмотров 2,4 тыс.7 месяцев назад
My Favorite Counting Technique includes ALL of the other Three!

Комментарии

  • @KenaQuintero96
    @KenaQuintero96 День назад

    Thank you for these explanations. I really enjoyed the video, it was so easy to understand. Thanks.

  • @zartamus
    @zartamus День назад

    Very simple - 3 people // you see 2 blue hats: you got the red one // you see 2 red hats: you got the blue one// you see 2 diferent colors NOW IT IS TIME TO GUESS BECAUSE YOU GOT OR RED OR BLUE = 50/50

  • @RSLT
    @RSLT 5 дней назад

    If you multiply 0.999... by 10^n, where n is the number of decimal places( number of 9s), the result is 'wait for it' 1/e.

  • @xjgal7702
    @xjgal7702 5 дней назад

    Great video! My only question really is, what formula are you using for area of a triangle in Level 5? I understand why the sides are x(1-z) and y(1-z) and why you integrate, but why is the area xy(1-z)^2, the product of the two sides? Wouldn’t that be the area of a rectangle with those dimensions?

  • @Ny0s
    @Ny0s 8 дней назад

    I enjoyed this video very much. The fact that one can find e in Pascal's triangle really blew my mind. There are so much hidden gems in this mathematical object, I feel like I discover more of them every time, from unexpected grounds. Thank you!

  • @user-br6ku7jj6n
    @user-br6ku7jj6n 9 дней назад

    The problem as stated in the "Ask Marilyn" column is ambigous.

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul 11 дней назад

    1 is the multiplicative identity. No matter how many times you multiply a number by 1 you do not change that number. No matter how many times you multiply 1 times 1, it will equal 1 or 1 raised to any power is 1. One way to deal with infinite digit numbers is to see if a number of finite steps leads to a LIMIT. We know that in base 2, the limit of the partial sums of the series represented by ".11..." is 1. The actual limit it is based on is Lim n->°°, 1/10^n=0. This is, of course, all in base 2, then ".11..."^°° should be 1, again in base 2. Let's take finite steps. .11×.11=.1001 .11111×.11111=.1111000001 .1111111111×.1111111111= .11111111100000000001 This does not look like I am approaching 1 in base 2. Well maybe if I ignore the 0,s??? Do that with ".99..." in decimal digits! Not only do you have to ignore over half the digits of 0, the final 1, and a 8 in the middle. Can ".99..." represent the number 1, of course, as anything can. ".99..." is the closest representation less than 1 in decimal digits. The problem is infinity. It is incomplete,inconsistent and imprecise.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 11 дней назад

      Using the lense of middleschool basics what is math. Real numbers are not fuzzy. To use math in physics, the inputs to math are fuzzy to begin with. We know it is difficult to measure. In real numbers, ".99..." is the closest number in decimal place notation less than 1. I don't see how it is a good representation of 1. Do we need more digits. Increase the size of the base of our number notation? Is binary better? How many digits of pi are necessary to observe every nanometer in the circumference of the universe. How big of a universe are we capable of exploring with the current digits of pi. How big is the universe. With course correction we could explore the universe with a simple true false. Does pure math need course correction like physics?

    • @Chris-5318
      @Chris-5318 9 дней назад

      ​@@johnlabonte-ch5ul bonehead: ".11×.11=.1001 .11111×.11111=.1111000001 .1111111111×.1111111111= .11111111100000000001 This does not look like I am approaching 1 in base 2." That's because you are an incompetent muppet that can't do trivial middle school arithmetic. 0.111...1 (base 2) (n 1s) * 0.111...1 (base 2) (n 1) = (1 - 1/2^n)^2 = 1 - 1/2^(n-1) + 1/2^(2n) and that approaches 1 as n becomes larger and larger. i.e. lim n->oo (0.111...1 (base 2) (n 1s))^2 = 1 as is obvious to anyone with a clue. Obviously that includes you out. Your brain is fuzzy and difficult to measure. It might be undetected f you ever get round to having that MRI scan done.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 8 дней назад

      That is my point, if you try to use infinity in math, it is dangerous. Using the formula for the sum of a infinite geometric series ".99..." is extremely close to 1 in finite terms. As the infinite terms continue, they become extremely small. In decimal fractions the base 2 ".11.. " becomes "1/2+1/4+1/8...". The formula is a limit. The sum is the limit of its partial sums. Lim as n->°° (a(1-r^n))/(1-r) is a/(1-r) The sum is very close to 1. How close? If we approach approach ".11..." in base 2 being close to 1, by finding the powers of ".11...", they should remain 1. One could find the limit of its square by finding the limit of its partial products as I did in the main comment. The limit of the partial products in squaring should equal the limit of the partial sums of numbers in any base like ".99...". No one says that any finite number of the digit 9 following the decimal point is 1. It is less than 1. Yet we are told by math that "at infinity" (whatever that is) it is 1. Infinity is useful in finding limits but Infinity is incomplete, inconsistent and imprecise.

    • @Chris-5318
      @Chris-5318 7 дней назад

      @@johnlabonte-ch5ul Come back when you have learnt about limits. At your current rate of progress, that'll be about 50 years from now.

  • @TheCosmicMedicineMan
    @TheCosmicMedicineMan 13 дней назад

    The Monty Hall problem may seem complex, but it's actually quite straightforward. With three doors, your initial chances of winning are 33.3%. When one door is removed, you’re left with only two doors, which gives you a straightforward 50/50 choice. Regardless of differing opinions, the math remains the same. The only real uncertainty comes from the fact that, if this were a television show, the outcome might be manipulated for entertainment purposes.

    • @klaus7443
      @klaus7443 9 дней назад

      "When one door is removed, you’re left with only two doors, which gives you a straightforward 50/50 choice." The probability of winning by staying is 1/3 and for switching it's 2/3.

  • @miroslavsebek3016
    @miroslavsebek3016 14 дней назад

    The root of the problem is that the math assumes 0 x 0 = 0 which is obvious nonsense. 0 x 0 is literally no zero or anything but zero. Let's say 0 x 0 = 10. For example, apples. Then 10/0 is a question of how many non-apples, like pears, are in 10 apples. Obviously zero. It works.

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul 17 дней назад

    ".99..." could be considered equal to 1 (Why?) In the same way that the length of a line could be considered 1 when we can never measure its length exactly.

    • @Chris-5318
      @Chris-5318 17 дней назад

      @bonehead, just when I thought you couldn't say something more idiotic than you previously had, you proved me wrong, again.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 17 дней назад

      I always prove you wrong. If we could accurately measure the diameter and circumference of a circle we could get all the digits of Pi by simple division.

    • @Chris-5318
      @Chris-5318 17 дней назад

      @@johnlabonte-ch5ul LOL. You are delusional and wrong. You cannot know all the digits of any irrational number.

    • @thetaomegatheta
      @thetaomegatheta 16 дней назад

      'Why?' Several proofs have been presented to you. (You have claimed that they are all incorrect, despite the fact that you couldn't point a single flaw in any of them, and have demonstrated to not have read them, so it's safe to say that you don't have any sort of actual protestations on the matter.) 'I always prove you wrong' You haven't proven us wrong a single time so far. Hell, your own calculations showed that 0.999... = 9/(10-1) = 9/9 = 1, so the only person you have shown to be wrong is yourself. 'If we could accurately measure the diameter and circumference of a circle' We can. The diameter of a unit circle is exactly Pi. The circumference of a unit circle is exactly 2*Pi. 'we could get all the digits of Pi by simple division' Notably, you make this claim with no proof, and we know that this is not true. We can find exact diameter and circumference of a circle of radius r, and yet, we know that it is impossible to find all digits of the decimal representation of Pi.

    • @Chris-5318
      @Chris-5318 16 дней назад

      @@thetaomegatheta You made a typo, you said "The diameter of a unit circle is exactly Pi" rather than either, "The diameter of a unit circle is exactly 2".

  • @tituslowman5957
    @tituslowman5957 18 дней назад

    You should have had an explanation for 3 year olds for me. I’m actually smart and don’t get it. Let me ask this at least, please answer if you see this. My mind puts it this way. If you have 6 cookies and divide them amongst 0 friends why is the answer not 6? You have 6 of them and distributed them to no one. You have 6. At least tell me that is not that crazy to think. Thank you.😼

  • @user-hh8co5eo9h
    @user-hh8co5eo9h 18 дней назад

    e^0 = ? you prove 0! using the same unproved statement e^0, if e^0 = 1 and 0! = 1 is just manipulation this is not proof.

  • @s-tierbeers7778
    @s-tierbeers7778 20 дней назад

    Dr Sean you’re the best.

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul 21 день назад

    Your five equations are a circular algorithm where equations 1 and 5 should be the same. Why not? If you modify the algorithm slightly and using the same "infinite" arithmetic. x=".99..." 10x="9.99..." 10x+x="9.99..."+".99..." 11x="10.99..." x=".99..." Why not 1? I say infinite arithmetic is incomplete, inconsistent and imprecise. The same goes for infinity itself.

    • @Chris-5318
      @Chris-5318 17 дней назад

      @johnthebonehead: Once again you proved yourself wrong. This must be at least the fifth time that you have made the exact same argument and this will be at least the fifth time that I show you that it leads to a proof that 0.999... = 1. You have stated that 11x = 10.999... where x = 0.999.... So we have 11x =10 + x => 10x =10 => x = 1. You are incomplete, inconsistent, imprecise, ignorant and incompetent. You also are a trolling muppet.

  • @c.e_null
    @c.e_null 22 дня назад

    some guy said it's a letter, imma clap that guy's cheeks

  • @shivadasbanerjee7978
    @shivadasbanerjee7978 23 дня назад

    Best explanation I have ever seen sir. Thanks for resolving my queries.

  • @JannikGade
    @JannikGade 25 дней назад

    What about: x=0.999... 10x=9.999... 10x-x = 9.999... - 0.999... 9x=9.000... x=1

    • @Chris-5318
      @Chris-5318 17 дней назад

      He gave a similar proof starting at 2:30

    • @JannikGade
      @JannikGade 17 дней назад

      @@Chris-5318ahh you're right!

  • @chrisg3030
    @chrisg3030 26 дней назад

    Bob: Hey Alice, want to play two envelopes? Alice: OK. How's it go? Bob: I got a $10 bill and a $20 bill. I put them each into separate identical envelopes like so, seal them and now shuffle them so we don't know which is which. Pick one and you get to keep it. Alice: Cool. Uh..I'll have that one. Bob: What's even cooler is you can switch to the other envelope. Alice: But why? If I have the $10 then I gain by switching. But if I have the $20 I lose. But I don't know what I got, so how can I know what I get? Bob: Look at it this way. Let's say you have x in your envelope. Then that means the other envelope has half x or double x. So you stand to gain double what you stand to lose if you switch. Makes sense. Alice: So if I have the $10 then the other envelope has $20 or $5. But you never said nothing about $5, I never saw you put it in an envelope. Bob: Don't get awkward on me Alice. Alice: And if I have the $20 then the other envelope has $40 or $10. But you never put $40 in an envelope. So we're back to what I - and you - said before. It's just comes down to either $10 or $20 and we don't know which envelope they're in. Bob: I just thought it might help to think about it algebraically. Alice: OK let's think about it algebraically then. If I have x then the other envelope has half x or double x. But I don't know I have x. It could be that I have the half x or double x envelope, in which case switching for x stands to lose me double what I stand to win. Once again, I don't know what I have so I don't know what I get. Thanks but no thanks Bob.

    • @chrisg3030
      @chrisg3030 26 дней назад

      Bob: Want to play two envelopes again Alice? Alice: Like I said last time it's a pointless exercise. Bob: You complained you didn't know what you had, so you didn't know whether to switch or not. This time you can open the envelope you picked before switching. Here are the two envelopes. One has twice the other, like before. Alice: Hm Ok. I'll have this one. I open it and .... $30. Cool. Bob: Want to switch? Alice: So the other has either $60 or $15 with equal probability. I stand to gain twice as much as I stand to lose, right? Bob: Yep Alice: But if I'd picked the $15 envelope, then the other would have had $30 or $7.50, right? And if I'd picked the $60 envelope, the other would have had $120 or $30. And if I'd picked the $7.50 envelope then the other would have had $15 or $3.75. And if I'd picked the $120 envelope ... well we could go on forever. Bob: I guess. Alice: What do you mean you guess? Don't you know what went into the envelopes? Bob: This time all I know is what I told you, one has double the other, and now as we've seen, one has $30. But whichever the other has, double or half, it's worth taking a chance. What do you think, is it worth Alice switching under these conditions? Do the conditions even make sense?

  • @saburousaitoh
    @saburousaitoh 26 дней назад

    Please look: viXra:1905.0008 submitted on 2019-05-01 20:40:00, An Interpretation of the Identity $ 0.999999...... =1$

    • @thetaomegatheta
      @thetaomegatheta 25 дней назад

      Vixra is a known den of cranks. People who post there have no clue what they are talking about more of ten than not.

  • @chrisg3030
    @chrisg3030 26 дней назад

    I think Dr Sean nails it by pointing out there's only a 50% chance you have x. The other 50% chance must surely be that you have 2x or x/2. The confusion normally sets in as soon as a typical presenter starts off with something like "Let's say you have x in your envelope" as if by stipulating that they put it beyond serious question, and it's now just a matter of 2 possible amounts in the other envelope, 2x or x/2. Of course looked at like that it makes sense to switch. But we rarely get someone saying "Let's say you have 2x or x/2 in your envelope", though that would make it disadvantageous to switch to one with x. (The same applies as much when numerical values are used instead of x, like starting off with "Let's say you have $20 in your envelope".)

  • @aisaboringname
    @aisaboringname 27 дней назад

    I'm a bit curious as to what you'd think about something like wheel algebra, which tries to define 1/0 (which ends up being unsigned ∞) and, by extension, 0/0 and all other indeterminate forms (which ends up being a new term called the nullity, represented by ⊥). the entire concept of something like this just baffles me, my mind can't quite wrap my head around these things, but it's very interesting to think about (probably no practical use for it though)

  • @jasperdavdson
    @jasperdavdson 29 дней назад

    So glad the algorithm let me come and learn something from you again before I take statistics

  • @swarapensalwar2440
    @swarapensalwar2440 Месяц назад

    I have a small doubt The flag explanation for 0! =1 says, that there is 1 way to arrange 0 flags that is no flag, but then for 1!, shouldn't there be 2 ways, flag is there, flag is not there And so on, with 2 flags, it could be flag A+flag B Just flag A Just flag B And no flag at all If we introduce the possibility of there being bo flags, then doesn't it mess up the calculations for others

    • @isavenewspapers8890
      @isavenewspapers8890 4 дня назад

      "Flag is not there" is not a valid arrangement of one flag, because that is zero flags, not one flag. In order to arrange one flag, you need to have one flag.

  • @user-bu2sc1bm7k
    @user-bu2sc1bm7k Месяц назад

    Zero and infinity Zero and infinity should not be treated as numbers. To approach zero is to decrease a number indefinitely. An asymptote of no matter how small a number can never reach nothing, which is represented by zero. Zero is a placeholder, an idea. Infinity, on the other hand is also an abstract idea. It is supposed to represent more than ‘everything’. It is an absurdity. Approaching infinity is increasing a number indefinitely, but such an asymptote can not and will not reach infinity. Infinity cannot be equated to anything as there is nothing as large as infinity, nor is there anything a small as zero if zero is to be equated to anything. Zero is zero, 0 = 0. and infinity is infinity, ∞ = ∞, no other equation makes sense using either. A number is a result or a record of counting. Zero cannot be counted (I would like to see a Shepperd count zero sheep), not to mention someone counting till infinity. As long as something is a number, it cannot be a zero or infinity. They cannot, therefore, possibly be numbers.

  • @jimb0678
    @jimb0678 Месяц назад

    E

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul Месяц назад

    ".99..." is extremely close to the value of 1 in the decimal place system of numbers. "Prove me wrong" that there is no other "number space" IN BASE 10 closer but less than 1. (I am defining "number space" to be represented by a bound infinite number of base (decimal) place notation and other sets of adjacent numbers.) [All algebraic "proofs" that ".99..." is 1 have problems in the use of infinite " number spaces" in arithmetic. (Not enough space in this comment to have a "prove me wrong ".) ] Infinite numbers are incomplete, inconsistent and imprecise. "Prove me wrong". The sum of a infinite series of >0 terms can't be unique and precise as a single number. "Prove me wrong ". There can be no number in base placed notation adjacent to 1. The Archimedean property says this. Prove Archimedes wrong.

    • @Chris-5318
      @Chris-5318 Месяц назад

      Yet another bunch of your completely unjustified false opinions. Bonehead: "".99..." is extremely close to the value of 1 in the decimal place system of numbers." Nope. 0.999... = 1 exactly. Watch the video. Bonehead: ""Prove me wrong" that there is no other "number space" IN BASE 10 closer but less than 1." There is no such thing as a base 10 that is closest to 1 but less than 1. That applies to all bases, not just base 10. Bonehead: "All algebraic "proofs" that ".99..." is 1 have problems in the use of infinite " number spaces" in arithmetic." There are no problems other than your incompetence. Bonehead: "(Not enough space in this comment to have a "prove me wrong ".)" I can barely decipher what that is supposed to mean. Bonehead: "Infinite numbers are incomplete, inconsistent and imprecise. "Prove me wrong"." You are incomplete, inconsistent, imprecise and incompetent. You cannot prove me wrong. Bonehead: "I am defining "number space" to be represented by a infinite base (decimal) place notation and other sets of adjacent numbers." That is complete and utter gibberish. Bonehead: "The sum of a infinite series of >0 terms can't be unique and precise as a single number." Rubbish. Try proving your gibberish claim. Bonehead: "There can be no number in base placed notation adjacent to 1." That's right, so why did you claim there was at the beginning of your comment. You want to have your cake and eat it too. Bonehead: "The Archimedean property says this." You don't know what the Archimedean property is. Bonehead: "Prove Archimedes wrong." As you are the one claiming that the Archimedean property (that has been deliberately designed in to the field of the real numbers) is wrong, it is you that needs to prove it. You will first need to learn what the Archimedean property is.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul Месяц назад

      ​A.I. Karen C can't understand English ( only matheese) and has a nasty name calling fetish when disagreed with. What is the future of A.I.? Will it be able to delete your social info and define you as extinct as opposed to calling you names.

    • @Chris-5318
      @Chris-5318 Месяц назад

      @@johnlabonte-ch5ul I understand English just fine. I have trouble with understanding your Gibberish. You understand neither. You fail to understand that it's the mathematicians that disagree with your profound misunderstanding of math. If A.I. was active when you tried writing comments, it would break under the stress of trying to correct you. All of your posts would be blocked and "medicaI" help would have been sent to you years ago.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 17 дней назад

      Prove me wrong.

    • @Chris-5318
      @Chris-5318 17 дней назад

      @@johnlabonte-ch5ul I've already done that several hundred times.

  • @michealajinroll28xia52
    @michealajinroll28xia52 Месяц назад

    Then comes Kurt godel🤣

  • @miguelvieira4445
    @miguelvieira4445 Месяц назад

    It’s just a number used by people in the oil industry. Get it? Ha ha ha

  • @RaduM1
    @RaduM1 Месяц назад

    f(x) = ax + b, watching the slope of the linear function while "a" approaches 0 and considering the fact that the inverse of f can be seen as a plot with the vertical and horizontal axis swapped. So, when "a" reaches 0, f is a straight horizontal line, while it's inverse (f') is a straight vertical line. So, f'(y) only exists for y=b, and the result is "all values between minus infinity and plus infinity", hence f'(y) is not a function when a=0 (a function must have a single result for each parameter value), hence its result is "undefined".

  • @joey_zhu
    @joey_zhu Месяц назад

    level 6: lie groups

  • @dodgecoates8760
    @dodgecoates8760 Месяц назад

    Great video.

  • @Ny0s
    @Ny0s Месяц назад

    This video was really interesting, you have a rare talent of making abstract ideas accessible. Thank you again. As a developer, I have to say that the definition via matrices is the one I like best. Very Beautiful.

  • @scottfarcus1667
    @scottfarcus1667 Месяц назад

    He didn't explain what it is though? Just pointed out some places it pops up. No insight offered here...

  • @crosseyedcat1183
    @crosseyedcat1183 Месяц назад

    I study linear systems, geometry, and rotations and to me, the compounding version of e is the best characterization. Understanding how e relates discrete and continuous actions when the actions encoded as products makes understanding what e to the power of a matrix or an imaginary number or quaternion means.

  • @astro6774
    @astro6774 Месяц назад

    did we invent e or did we discover it...

  • @hishan.farfan
    @hishan.farfan Месяц назад

    amazing explanation! 🙌

  • @seanknapp1271
    @seanknapp1271 Месяц назад

    My smart counterpart, thank you.

  • @Kilgorebass7
    @Kilgorebass7 Месяц назад

    Great channel, smarter than your average ur-sine🎉

  • @chuckszkalak1535
    @chuckszkalak1535 Месяц назад

    well done

  • @tomthaxter161
    @tomthaxter161 Месяц назад

    Almost all of the confusion I think comes from the notation. Once you frame it as being simply a function, which we could write generally as f(x), then I think far fewer people would question why f(0) = 1 as lots of functions have this property. I think lots of people jump to 0! feeling like it should be zero is just based on it’s similarity to 0+0 or 0x0

    • @pelasgeuspelasgeus4634
      @pelasgeuspelasgeus4634 Месяц назад

      No buddy. If you Google search "factorial definition" you will get "the product of an integer with all integers below it" and obviously zero is not included. So, how do you think that 0!=1 is consistent with the above definition?

    • @tomthaxter161
      @tomthaxter161 Месяц назад

      @@pelasgeuspelasgeus4634 Autocorrect wrote factorial rather than function. Everything else that I've written still stands.

    • @pelasgeuspelasgeus4634
      @pelasgeuspelasgeus4634 Месяц назад

      @@tomthaxter161 You didn't answer my question. Will you?

    • @tomthaxter161
      @tomthaxter161 Месяц назад

      @@pelasgeuspelasgeus4634 Did you even watch the video. The video explained why 0! = 1 for 5 different reasons. And yes I just googled "is 0! defined" and guess what? It says it is equal to 1.

    • @pelasgeuspelasgeus4634
      @pelasgeuspelasgeus4634 Месяц назад

      @@tomthaxter161 OK. First, it doesn't matter how many reasons someone may think to justify something. What matters is "is it legit logically?" Second, again you didn't answer. Why are you evading? Is 0!=1 consistent with the factorial definition?

  • @NUGGet-3562
    @NUGGet-3562 Месяц назад

    How do you divide 6 cookies by 0 friends? You don't. You eat them all yourself! I think I'll be doing this 0 division more often!

  • @keipfar
    @keipfar Месяц назад

    This is one of the cleanest explanations of Bayes rule I have ever seen.

  • @luckytrinh333
    @luckytrinh333 Месяц назад

    If you continue the diving rule for (-1)! you would get (-1)!=(0!)/0=1/0=inf When you use the binomial formula to get pascal's triangle you divide by inf outside the triangle so it's outside 0 (which makes sense when you apply the "add rule" with 0 and 1 to get 1 on the side of the triangle) And when you use (-1)! in Taylor's formula to get the "more left" terms you would get something divided by inf which is again 0 so you add a bunch of 0's _(Math from Ohio)_ 💀

  • @davidellis1929
    @davidellis1929 Месяц назад

    I was taught that e is the limit of (1+1/n)^n as n grows beyond all bounds ("approaches infinity"). The compound interest example is a great way to introduce e. Before learning calculus, limits must be treated informally and intuitively. It took mathematicians two hundred years between the initial development of calculus and the formalization of what a limit is. With hindsight, the epsilon-delta definition can be derived from the requirement that the limit be unique if it exists, by defining the condition that leaves behind all other candidates for the limit.

  • @karraguer
    @karraguer Месяц назад

    Very cool. Examples related to information theory and communications are also very clear.

  • @valentinussofa4135
    @valentinussofa4135 Месяц назад

    I love math. Thanks to RUclips algorithm. Finally, I found this precious learning channel.

  • @twhitten828
    @twhitten828 Месяц назад

    I explained this to a Banker... He laughed and laughed. Ya...serf... We invented creative math.

  • @marcoottina654
    @marcoottina654 Месяц назад

    This is gold! It should be taught in every college!

  • @TedHopp
    @TedHopp Месяц назад

    It would have been nice to include a little history about how zero was not considered a number by the ancient Greeks and others. Also, you touched on the pedagogical aspect with little kids, but there's a whole lot more there. I once asked my granddaughter (then 5 years old) which weighed more: zero rocks or zero feathers. Of course she said rocks. I don't think I was entirely successful in explaining why they weighed the same (nothing).

  • @intrepiddt
    @intrepiddt Месяц назад

    What a great explanation! Thank you for creating such content.