Engr. Uchechukwu Onwuasoanya (Lustepford)
Engr. Uchechukwu Onwuasoanya (Lustepford)
  • Видео 363
  • Просмотров 142 624
How to calculate friction factor and downstream pressure part 2
Welcome to our channel! In today’s video, we’ll dive into the essential concepts of calculating the friction factor and downstream pressure in fluid dynamics. Whether you’re a student, engineer, or just curious about the science behind fluid flow, this tutorial is designed for you!
🔍 What You’ll Learn:
- The importance of the friction factor in fluid flow calculations.
- Step-by-step methods to calculate the friction factor using various equations, including the Darcy-Weisbach equation.
- How to determine downstream pressure and its significance in engineering applications.
- Practical examples and tips to help you apply these calculations in real-world scenarios.
📊 Who Is This For?
This video i...
Просмотров: 0

Видео

How to calculate friction factor and downstream pressure part 1
Просмотров 92 часа назад
Welcome to our channel! In today’s video, we’ll dive into the essential concepts of calculating the friction factor and downstream pressure in fluid dynamics. Whether you’re a student, engineer, or just curious about the science behind fluid flow, this tutorial is designed for you! 🔍 What You’ll Learn: - The importance of the friction factor in fluid flow calculations. - Step-by-step methods to...
How to calculate the friction factor and upstream pressure in a natural gas pipeline
Просмотров 24 часа назад
In this informative video, we dive deep into the essential calculations for natural gas pipelines. Learn how to accurately determine the friction factor and upstream pressure, two critical components for ensuring efficient gas flow. We’ll break down the formulas, provide step-by-step examples, and share practical tips to help you apply these concepts in real-world scenarios. Whether you're a st...
How to calculate the Reynolds number of natural gas flowing through a pipeline
Просмотров 117 часов назад
Welcome to Engr. Uchechukwu Onwuasoanya (Lustepford)! 🌟 In this video, we dive into the fascinating world of fluid dynamics to explore how to calculate the Reynolds number for natural gas flowing through a pipeline. Understanding the Reynolds number is crucial for engineers and scientists as it helps determine the flow regime, whether it's laminar or turbulent, which impacts the efficiency and ...
How to calculate the gas velocity, and pipeline length of a natural gas pipeline
Просмотров 109 часов назад
In this informative video, we dive into the essential calculations for natural gas pipelines. Whether you're an engineering student, a professional in the energy sector, or simply curious about how gas transportation works, this tutorial will guide you through the process of calculating gas velocity and determining pipeline length. We'll cover: - The fundamental principles of gas flow in pipeli...
How to Calculate the compressibility factor of a gas mixture Using CNGA method
Просмотров 5День назад
Welcome to our channel! In this video, we dive deep into the world of thermodynamics to explore the CNGA (Compressibility of Natural Gas Association) method for calculating the compressibility factor of gas mixtures. Whether you're a student, engineer, or enthusiast, this tutorial will guide you through the step-by-step process, ensuring you grasp the concept with ease. What You'll Learn: - An ...
How to calculate the compressibility factor, gas gravity, and apparent molecular weight
Просмотров 10День назад
Welcome to our comprehensive guide on calculating the Compressibility Factor, Gas Gravity, and Apparent Molecular Weight! In this video, we’ll explore these essential concepts that are vital for anyone working with gases in engineering, chemistry, or environmental science. What You’ll Learn: - Compressibility Factor (Z): Understand what the Compressibility Factor is and why it’s crucial for pre...
How to calculate the Compressibility factor using the Standing Katz compressibility chart
Просмотров 14День назад
In this video, we discuss the essential topic of calculating the Compressibility Factor (Z) using the Standing Katz compressibility chart. Understanding the Compressibility Factor is crucial for engineers and scientists working with gases, as it helps them accurately predict gas behaviour under various conditions. Join us as we break down the steps to effectively use the Standing Katz chart, in...
How to calculate the adjusted pseudo critical temperature and pressure
Просмотров 8День назад
Dive into the world of thermodynamics with our latest tutorial on calculating the adjusted pseudo-critical temperature and pressure. Whether you're a student, engineer, or enthusiast, this video will guide you through the essential steps and formulas to master this complex topic. With clear explanations and practical examples, you'll gain the confidence to tackle real-world engineering challeng...
Mastering Adjusted Pseudo Critical Temperature & Pressure: A Step-by-Step Guide
Просмотров 2День назад
In this comprehensive tutorial, we dive deep into the world of thermodynamics to help you master the calculation of adjusted pseudo-critical temperature and pressure. Whether you're a student, engineer, or simply curious about the science behind these important concepts, this step-by-step guide will provide you with the necessary knowledge and tools. 🔍 What You'll Learn: - The fundamental princ...
how to Calculate gas gravity of a mixture
Просмотров 2День назад
In this video, we dive into the essential concept of gas gravity and how to calculate it for a gas mixture. Whether you're a student, engineer, or simply curious about gas properties, this tutorial will guide you through the step-by-step process of determining gas gravity using real-world examples. We’ll cover the necessary formulas, key factors to consider, and practical applications in variou...
Calculating pseudo critical temperature and pressure of a natural gas mixture
Просмотров 12День назад
Dive into the fascinating world of thermodynamics with our latest video! In this tutorial, we unravel the complexities of calculating the pseudo critical temperature and pressure of a natural gas mixture. Whether you're an engineering student, a professional, or just curious about the science behind natural gas, this video is for you! We'll guide you step-by-step through the process, ensuring y...
GAS MIXTURE PROPERTIES CALCULATION
Просмотров 5День назад
Dive into the fascinating world of gas mixtures with our latest video, "GAS MIXTURE PROPERTIES CALCULATION"! Whether you're a student, engineer, or just curious about thermodynamics, this video is perfect for you. We'll break down the complex calculations involved in determining the properties of gas mixtures, making it easy to understand and apply. From partial pressures to molar fractions, we...
Charles Law numerical pratical problem
Просмотров 4День назад
In this video, we dive into the fascinating world of gas laws with a practical problem based on Charles's Law. Join us as we explore how temperature and volume are related for a given amount of gas. We’ll walk through a numerical example step-by-step, demonstrating how to apply Charles's Law to solve real-world problems. Whether you're a student preparing for exams or just curious about the sci...
HOW TO CALCULATE THE VISCOSITY OF A GAS MIXTURE
Просмотров 1014 дней назад
If you're wondering how to calculate the viscosity of a gas mixture, this video will explain the process in simple terms. Learn how to determine the viscosity of a gas mixture with easy-to-follow steps!
Want Accurate Calculations? Learn Gas Mixture Viscosity NOW
14 дней назад
Want Accurate Calculations? Learn Gas Mixture Viscosity NOW
Why x+1, x+3, and x+5 Can Never Be Consecutive in a G.P. | Geometric progression
Просмотров 194 месяца назад
Why x 1, x 3, and x 5 Can Never Be Consecutive in a G.P. | Geometric progression
If x+1, x+3, x+7 are consecutive terms of a G P find x
Просмотров 404 месяца назад
If x 1, x 3, x 7 are consecutive terms of a G P find x
Secrets Revealed: Solving for a and r in Geometric Progression
Просмотров 74 месяца назад
Secrets Revealed: Solving for a and r in Geometric Progression
Exploring Geometric Progression Fundamentals | Mastering Geometric Progression Basics
Просмотров 54 месяца назад
Exploring Geometric Progression Fundamentals | Mastering Geometric Progression Basics
Arithmetic progression | Can you find the value of X
Просмотров 214 месяца назад
Arithmetic progression | Can you find the value of X
Arithmetic progression | Find the value of X
Просмотров 4094 месяца назад
Arithmetic progression | Find the value of X
Arithmetic progression | What is arithmetic mean
Просмотров 84 месяца назад
Arithmetic progression | What is arithmetic mean
Given that 7th term is 23, nth term is 43 and 2nth term is 91 for an A. P. , find a, d and n | maths
Просмотров 274 месяца назад
Given that 7th term is 23, nth term is 43 and 2nth term is 91 for an A. P. , find a, d and n | maths
The 2pth term of an arithmetic progression is 50 more than the pth term, and p+1th is 56, find the f
Просмотров 454 месяца назад
The 2pth term of an arithmetic progression is 50 more than the pth term, and p 1th is 56, find the f
If 10th term of an A P , is double 2nd term, find 8th term, given a=7
Просмотров 244 месяца назад
If 10th term of an A P , is double 2nd term, find 8th term, given a=7
Math Olympiad | Nice exponents | Nice Olympiad Problem
Просмотров 1324 месяца назад
Math Olympiad | Nice exponents | Nice Olympiad Problem
Math Olympiad | Nice exponents | Olympiad Math question
Просмотров 4564 месяца назад
Math Olympiad | Nice exponents | Olympiad Math question
the 9th of an A P is 3x the 5th term, a find the relation bwt a and d, and b prove that the 8th
Просмотров 254 месяца назад
the 9th of an A P is 3x the 5th term, a find the relation bwt a and d, and b prove that the 8th
The sum of 3rd & 7th terms is 38, & the 9th trem is 37 Find the A P
Просмотров 284 месяца назад
The sum of 3rd & 7th terms is 38, & the 9th trem is 37 Find the A P

Комментарии

  • @AASQ
    @AASQ 8 дней назад

    change dim uche to (2,0)

  • @Thxiuy
    @Thxiuy 25 дней назад

    why did you do it so hardly , you can simply use the formula AP=a+b/2

  • @NearEmotion
    @NearEmotion Месяц назад

    The mean difference is deducted from the value obtained in case of cosine while calculating the value using the log table

  • @farhansadikvubon6639
    @farhansadikvubon6639 4 месяца назад

    thank you very much for shearing your knowledge I have been benefited from this video and I thank you for your efforts. have a nice one :)

  • @MalcolmX-qv7po
    @MalcolmX-qv7po 4 месяца назад

    Reference books pls?

  • @alejandroperalta2748
    @alejandroperalta2748 6 месяцев назад

    How do I make backspace?

  • @winnieelward992
    @winnieelward992 8 месяцев назад

    Promo_SM 😋

  • @KipIngram
    @KipIngram 8 месяцев назад

    2, by five seconds of inspection. Another couple seconds show that 3 also works.

  • @ContactCall
    @ContactCall 8 месяцев назад

    Uncle you are doing it more complex. Let, perpendicular of the triangle be "a" Base of triangle be "b" Given, Perimeter=120 and Hypotenuse=51 ATQ a+b+51=120 Or, a+b=120-51 Or, a+b=69 According to Pythagoras Theorem, a²+b²=51² Or, (a+b)²-2ab=51² Or, 69²-2ab=51² Or,69²-51²=2ab Or,(4761-2601)÷2= ab Or,ab= 1080 We know that area of triangle 1/2 × perpendicular × Base Or 1/2ab Or 1080/2 Or 540 So area =540

  • @magatouve
    @magatouve 8 месяцев назад

    How come you assumed that 2a+1 and 2b+1 are integers (as factors of 13)? Was that given? For example, a=5/3, b=1 is a solution for a+2ab+b=6, yet 2a+1 = 13/3. It's not necessarily 13, 1, -13, -1 as you concluded in your solution.

  • @eltayebeltayeb1568
    @eltayebeltayeb1568 8 месяцев назад

    We can follow and read the solution

  • @PranavGarg_
    @PranavGarg_ 8 месяцев назад

    dude... at 1:16, you were done if you really understood what logarithms mean. you had 3^x = 6. By definition of logarithm, x = log_3(6). you waste like 4 minutes using log base 10 unnecessarily.

  • @John17.24
    @John17.24 8 месяцев назад

    I got there in the end with minimal help from you but it took me a long time. I don't think I would have thought to make triangle ABE on my own. I enjoyed the challenge. Thanks.

  • @DanDart
    @DanDart 8 месяцев назад

    I'm sure it would be much more clear if you upgraded your microphone and tried to avoid background noise. Still, following along with the notation doesn't seem too difficult.

  • @edsznyter1437
    @edsznyter1437 8 месяцев назад

    More than a minute in before you bother to mention that it's a right triangle.

  • @Llanchlo
    @Llanchlo 8 месяцев назад

    Given that an integer solution is stipulated, it takes five seconds to work this out mentally. Applying pythagoras you need two squares whose difference is 25, and a quick estimate shows 12 and 13 are the values - even if you don't remember the first few standard integer pythag triangles in the first place.

  • @inthefogs
    @inthefogs 8 месяцев назад

    damn bro

  • @williammarshal4043
    @williammarshal4043 8 месяцев назад

    If ab =y , if ac = 5 then area = 5y/2 finding bc would bebirrelevant

    • @williammarshal4043
      @williammarshal4043 8 месяцев назад

      I think you guys should know this, 5, 12, 13 is a triangle but if one side only known like 5, to make a right triangle the value of y is up to you, as long as its angle 90° the hypotenuse will expand as the increment of y, so does the area of the triangle.

  • @Scott-i9v2s
    @Scott-i9v2s 8 месяцев назад

    @lustepfordresourcecenter6176 Actually, "0" is a *VALID* answer. Simply because the DEFINITION of a triangle does NOT exclude sides of length 0. It ONLY excludes NEGATIVE line-lengths. *AND* using the formula of Pythagoras, "0^2 + 0^4 = 0^6" is a True statement. Way too many people think that ALL sides of a shape MUST be >0.🤔 Granted that in the PRACTICAL world of engineering, a value of "0" is more-often-than-not a useless answer.

  • @manuelisidroabreu4752
    @manuelisidroabreu4752 8 месяцев назад

    Vc enrolado demais.......complica as coisas fáceis....ok

  • @bruv4266
    @bruv4266 8 месяцев назад

    Thank you man for the help, Im in 7th grade, and we have this problems in my mathbook and i didn't know how to do it. Thank you so much, because of you I legit got so much better.

  • @Bertin-q3y
    @Bertin-q3y 8 месяцев назад

    (2;1), (1;2).

  • @moonwatcher2001
    @moonwatcher2001 8 месяцев назад

    Awesome, thank you

  • @magatouve
    @magatouve 8 месяцев назад

    6^m + 6^n = 42 6^n [6^(m-n) + 1 ] = 6.7 6^(n-1) . [6^(m-n) + 1] = 7. The left side of the last equation must be factors of 7, which is a prime, so they must be 1 & 7, i.e. 6^(n-1) = 6^0 and 6^(m-n) +1 = 7 n-1 = 0 and m - n = 1 n = 1 and m = 2. HOWEVER, this solution only works if we knew in advance that m and n are integers OR if there were some theorem that tells us that the left side of 6^x . (6^y + 1) = 7 must be factors of 7. It feels instinctive, but I couldn't think of a theorem to justify it.

  • @magatouve
    @magatouve 8 месяцев назад

    Nice problem and a nice solution. Thank you! My only comment is that you didn't need to prove that x > y because the hypotenuse of a right angle triangle is always greater than any of its two sides.

    • @pk2712
      @pk2712 8 месяцев назад

      The fact that the hypotenuse is always longer than the legs makes the proof both shorter and simpler . I know the Pythagorean triple 5,12,13 . Not sure ; but , I think this solution proves its the only Pythagorean triple with one of the legs equal to 5 . Most everyone knows the more famous Pythagorean triple where the hypotenuse is 5 ---> 3,4,5 .

  • @Bertin-q3y
    @Bertin-q3y 8 месяцев назад

    sin2a= 7/16

  • @lilianaprina5991
    @lilianaprina5991 8 месяцев назад

    Thank you...

  • @fisicamatematicasprofewilliam
    @fisicamatematicasprofewilliam 8 месяцев назад

    like 49 super ayudemonos a crecer en youtube

  • @lrdisco2005
    @lrdisco2005 8 месяцев назад

    That took me back 40 years.

  • @samarth2729
    @samarth2729 8 месяцев назад

    very nice

  • @danobro
    @danobro 8 месяцев назад

    fist

  • @ManirUddinBarbhuiya-ei1uc
    @ManirUddinBarbhuiya-ei1uc 8 месяцев назад

    Direct apply a+b whole square.

  • @jaggisaram4914
    @jaggisaram4914 8 месяцев назад

    (1,2) & (2,1)

  • @richardcross7070
    @richardcross7070 8 месяцев назад

    16 and 9 by inspection. Not really an Olympiad question.

  • @yk_mislyn
    @yk_mislyn 8 месяцев назад

    Simply splendid

  • @magatouve
    @magatouve 8 месяцев назад

    I'm sorry, but I might be missing something. 5 x (5/24) = (5x5)/24 = 25/24 , not 125/24. If it were 5 + 5/24, then it would be 120/24 + 5/24 = 125/24. I don't think that the two sides in each of these two equations are equal. There must be something wrong.

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      the question is the square root of a mixed fraction equal to five times the square root of a proper fraction.

    • @magatouve
      @magatouve 8 месяцев назад

      Sorry, I wrote my comment before watching the rest of your video. You do explain it later, and I get it now. I think I just didn't understand what you meant by "mixed fractions". I think it has to do with differences in notation and language between different countries. Where I come from, we say "fractional numbers" instead of "mixed fractions".

  • @welllll...ok...
    @welllll...ok... 8 месяцев назад

    Thank you!

  • @akhileshiyer296
    @akhileshiyer296 8 месяцев назад

    There is a condition here, though. Because a and b have to be whole numbers, a has be to greater than 0.

  • @jaggisaram4914
    @jaggisaram4914 8 месяцев назад

    81 - 16 = 3^4 - 2^4 . m = 4

  • @onradioactivewaves
    @onradioactivewaves 8 месяцев назад

    I take it you are not reading your comments you respond. Everyone is pointing out your mistake.

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      The question is the square root of a mixed fraction is equal to three times the square root of a proper fraction. Also, read what johnmorriss5508 wrote, he or she did to say there is a mistake. He got the same as me.

  • @yakupbuyankara5903
    @yakupbuyankara5903 8 месяцев назад

    (X,Y):(6,9),(-10,-7)

  • @williamrockwell9001
    @williamrockwell9001 8 месяцев назад

    You picked about the longest hardest way to do this. Solve the second equation for a or b and substitute into first and solve. Then solve for other variable. Then take the time you spent to take nap.

  • @derwolf7810
    @derwolf7810 8 месяцев назад

    It's mindblowing to see so many people not having heard of mixed fractions. I would guess the USA started that, since they created another worldwide issue with juxtaposition ('1÷2(1+1)=1'). Just of curiosity have you heard of mixed fracture in school and where and when have you finsihed school? I finished school in 1996 in Germany (NRW) and we were taught mixed fractures (and that '1÷2(1+1)=0.25').

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      Yes, I know about mixed fraction. the expression inside the square root on the LHS is a mixed fraction and can be expressed the same as 3+3/a. e.g. 1.5 = 1 + 0.5 = 1 + 1/2 = 1 whole number 1/2

    • @derwolf7810
      @derwolf7810 8 месяцев назад

      @@lustepfordresourcecenter6176 I just realized that what i wrote was ambiguous; my apologies for that. I didn't meant to ask you about that, since you used it in the video. Instead i intended to ask everyone passing by - a little survey to everyone.

  • @DamWnoZ
    @DamWnoZ 8 месяцев назад

    3*3/а, or 3+3/а?and 3rootor cubic rooy

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      The term on the LHS is square root of (3 whole number 3 / a) which is a mixed fraction that is inside the square root. Which is the same as 3+3/a. e.g. 1.5 = 1 + 0.5 = 1 + 1/2 = 1 whole number 1/2

  • @ojasjamdar1667
    @ojasjamdar1667 8 месяцев назад

    Indian students who know this by heart seeing the video like

  • @onradioactivewaves
    @onradioactivewaves 8 месяцев назад

    This is confusing because you left out the + for sqrt ( 3 + 3/a) in the thumbnail

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      Please check this video that explain it better: ruclips.net/video/3_T-HCzRfbE/видео.htmlconfirmation=1

    • @onradioactivewaves
      @onradioactivewaves 8 месяцев назад

      @@lustepfordresourcecenter6176 check your thumbnail for the video.. I understood just fine, you have an error on the thumbnail, you left out the + inside of the radical sign, showing an equation which is either false, or can be rewritten in a form where a=0.

  • @wes9627
    @wes9627 8 месяцев назад

    3*(3/a)=9/a, not 3+3/a Squaring both sides yields 9/a=27/a, which has no solutions.

    • @onradioactivewaves
      @onradioactivewaves 8 месяцев назад

      My first thought as well was theres no solution. I think he messed up the thumbnail, the math checks out if it was sqrt (3+3/a) on the left side. My first guess was the right side was cube root when I got the wrong answer, I had to watch the video to figure out what was going on.

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      The term on the LHS is square root of (3 whole number 3 / a) which is a mixed fraction that is inside the square root. Which is the same as 3+3/a. e.g. 1.5 = 1 + 0.5 = 1 + 1/2 = 1 whole number 1/2

  • @nozack5612
    @nozack5612 9 месяцев назад

    So plug your solution a = 8 into the original equation. Hint: it isn't a solution.

    • @lustepfordresourcecenter6176
      @lustepfordresourcecenter6176 8 месяцев назад

      Please check this video to understanding problem: ruclips.net/video/3_T-HCzRfbE/видео.htmlconfirmation=1

    • @nozack5612
      @nozack5612 8 месяцев назад

      @@lustepfordresourcecenter6176 Thanks for the link; I was interpreting the first mixed fraction as a product.

  • @nasrullahhusnan2289
    @nasrullahhusnan2289 9 месяцев назад

    There must be 12 pairs solutions of (x,y), not just 3 as in the video, i.e. 99=1×99, 3×33, 9×11, giving 3 solutions only. But 99=-1×(-99), -3×(-33), -9×(-11), another 6 solutions, and their inversion as the question is cyclical.

  • @jean-paul4337
    @jean-paul4337 9 месяцев назад

    Excellent!