David Wright
David Wright
  • Видео 78
  • Просмотров 642 614
Rearrange to make x the subject
Change the subject of equations by learning how to rearrange for x and y and other variables. GCSE | IGCSE (Higher Tier).
Transcript:
Hi everyone and welcome to my channel.
In this video I’m going to give you a step-by-step guide about how to answer questions that ask you to rearrange equations in order to change the subject.
In this question we are given an equation where y is the subject (note that this means it is on its own on the left), and we are asked to make x the subject, which is currently part of a more complicated expression on the right.
So what we are going to learn how to do is to take the y variable over here on the left and move it over to the right-hand side of the equation....
Просмотров: 1 891

Видео

Circle the factor of ( GCSE algebra )Circle the factor of ( GCSE algebra )
Circle the factor of ( GCSE algebra )
Просмотров 1,5 тыс.Год назад
Learn how to find factors in algebraic expressions. Knowing how to factorise is an important skill for higher tier GCSE. Transcript: This video is going to use the following exam-style question to show you how to answer GCSE questions involving the factorisation of algebraic expressions. So, in this question, we are asked to circle the factor of the following algebraic expression, and are given...
Use approximations to estimate | GCSEUse approximations to estimate | GCSE
Use approximations to estimate | GCSE
Просмотров 563Год назад
Improve your estimating, estimation, approximation & estimate skills. GCSE Exam style question. Transcript: Hi everyone. Today’s video is going to focus on how you can use your estimating and approximation skills to answer the following exam-style question. This question’s typical of the type of question you might be asked in the GCSE higher tier exam and I’m going to show you how to answer thi...
Bounds | Upper bound | Lower bound | GCSEBounds | Upper bound | Lower bound | GCSE
Bounds | Upper bound | Lower bound | GCSE
Просмотров 207Год назад
This video is going to show you how to solve maths calculations that are based on using the upper bound and lower bound of a measurement. This is a core skills video, so I’ll be explaining the basics of bound calculations and I’ll build on this in a later video that will have harder questions needed for higher level study. But to begin with, let’s look at a standard question requiring the use o...
How to calculate VAT | GCSEHow to calculate VAT | GCSE
How to calculate VAT | GCSE
Просмотров 4,2 тыс.2 года назад
This video shows you how to work out how much VAT needs to be added to a price (excluding VAT) or how much VAT has been included in a price (including VAT). Get in touch via the comments section if you need help with this type of calculation. Transcript: This video is going to show you how to calculate VAT, which in the UK (where I live) is an acronym for Value Added Tax. The video is in two pa...
Find the value of x (in a power or exponent) | GCSEFind the value of x (in a power or exponent) | GCSE
Find the value of x (in a power or exponent) | GCSE
Просмотров 4,8 тыс.2 года назад
This videos shows how to find the value of x (or any variable such as y, p, q) when it is part of powers, indices or exponents. It uses a typical exam question to teach you how to solve this type of problem. Transcript: In this video I want to show you how to find the value of x if it is part of the power of a number, such as here where we have a base number of three and the unknown x is part o...
Midpoint of a line | GCSEMidpoint of a line | GCSE
Midpoint of a line | GCSE
Просмотров 2402 года назад
This video shows you how to calculate the midpoint of a line and its length when you are given two coordinates. It uses an exam-style question that you might be asked in UK GCSE / IGCCE exams. Transcript: Hi everyone, in this video we’re going to look at how to calculate the midpoint of a line and its corresponding length. So here, we have been given an exam-style question and we’re told that P...
Solve simultaneous equations | GCSESolve simultaneous equations | GCSE
Solve simultaneous equations | GCSE
Просмотров 4822 года назад
This video teaches you how to solve simultaneous equations in two unknowns using the elimination method. GCSE. Transcript: In this video I’m going to show you how to solve the following pair of simultaneous equations. But before we start it’s worth mentioning what it means to solve simultaneous equations such as these. Well, because they are simultaneous, it means that there is a single value o...
Inversely proportional to | GCSEInversely proportional to | GCSE
Inversely proportional to | GCSE
Просмотров 1,2 тыс.2 года назад
This video shows you how to answer questions that use the words y is inversely proportional to x. It uses an exam-style question to teach the method required. GCSE. Transcript: This video is going to show you how to answer maths questions that use the words “inversely proportional to”. And I’m going to show you how to solve this type of question using the following exam question. This states th...
Directly proportional to | GCSEDirectly proportional to | GCSE
Directly proportional to | GCSE
Просмотров 2582 года назад
This video teaches you how to answer questions about direct proportionality. It is an exam-style question at GCSE & IGCSE higher or extended level. Transcript: This video is going to show you how to answer questions about direct proportionality. My focus will be on questions that use the words “directly proportional to”. If you’re trying to find out how to answer a question that uses the words ...
The cosine rule | GCSE | IGCSE | HigherThe cosine rule | GCSE | IGCSE | Higher
The cosine rule | GCSE | IGCSE | Higher
Просмотров 3002 года назад
This video teaches you how to use the cosine rule to find the length of an unknown side in a triangle. It uses an exam-style question for GCSE / IGCSE higher or extended level. #cosinerule Transcript: In this exam-style question we are asked to use the cosine rule to find the length of side CB, which is the side of the triangle that we find here. Now this question represents one of the situatio...
Sine Rule Example ( GCSE / IGCSE )Sine Rule Example ( GCSE / IGCSE )
Sine Rule Example ( GCSE / IGCSE )
Просмотров 2092 года назад
This video shows you how to use the sine rule to find unknown angles in a triangle. This is part of the extended (or higher level) curriculum for GCSE / IGCSE. #GCSEmaths2022 #IGCSEmaths2022 Transcript: This video is going to use the following exam question to teach you about the sine rule, which is sometimes called the law of sines. So in this question we’re asked to use the sign rule to find ...
Quotient Rule | A LevelQuotient Rule | A Level
Quotient Rule | A Level
Просмотров 2732 года назад
This video demonstrates the quotient rule. Essential for calculus students. A Level. Transcript: Hi everyone. Today I’m going to demonstrate how the quotient rule can be used to differentiate the following functions. Now, a key feature of these functions is that they can be described as having a function as the numerator at the top. And a different function as the denominator at the bottom; i.e...
Stem and leaf plots ( GCSE / IGCSE )Stem and leaf plots ( GCSE / IGCSE )
Stem and leaf plots ( GCSE / IGCSE )
Просмотров 4852 года назад
Improve your understanding of stem & leaf diagrams and how they are used to represent statistical data. Transcript: In this video we’re going to look at stem and leaf plots and a typical question that you might get in an exam. So in this question we’re given the following stem-and-leaf diagram and are told that this represents the number of hours that 18 students studied last week. We’re then a...
How to calculate ratios (GCSE / IGCSE )How to calculate ratios (GCSE / IGCSE )
How to calculate ratios (GCSE / IGCSE )
Просмотров 4992 года назад
Learn how to calculate ratios in the short exam revision video. Transcript: Hi everyone. This short video is going to show you how to answer maths questions about ratios. This exam-style question tells us that three taxi drivers travel and total distance of 8232 kilometres in the ratio 5 to 2 to 7. We are asked to use this information to calculate the distance each driver travels. I’m going to ...

Комментарии

  • @my-iron-lung
    @my-iron-lung 4 дня назад

    thank you! appreciate the videos

  • @koketsobotlhale6353
    @koketsobotlhale6353 4 дня назад

    Thank you❤

  • @josegiovanni404
    @josegiovanni404 11 дней назад

    Thanks this was very helpful👍

  • @champabhattacharjee9866
    @champabhattacharjee9866 13 дней назад

    Draw a diagram to show the following compass bearings and journey.Use a scale of 1cm:1km.North can be taking to be a line vertically up the page. Start at point A.Travel a distance 7km on a bearing of 135° to point B.From B,travel 12 km on a bearing of 250° to point C.Measure the distance and bearing of A from C. Please give me the solution.

  • @alfredgomes3074
    @alfredgomes3074 16 дней назад

    tnx a lot, work both way.😃

  • @AnnorEmmanuel-h8g
    @AnnorEmmanuel-h8g 17 дней назад

    5 exponet3x+6=12 exponet5

  • @tylerandrew-g4g
    @tylerandrew-g4g Месяц назад

    I have my test coming up and this helps a lot thank you

  • @eimanElhag
    @eimanElhag Месяц назад

    thank you!

  • @iga279
    @iga279 Месяц назад

    finally a reasonable explanation;

  • @MaureenObiorah-pj4cj
    @MaureenObiorah-pj4cj Месяц назад

    Thank you. Looking forward to seeing the solution using logarithm

  • @innocentemeka5948
    @innocentemeka5948 2 месяца назад

    Please help me with 742.01

  • @Hi-jd7xh
    @Hi-jd7xh 2 месяца назад

    Thanks sir, It’s really helpful

    • @DavidWrightUK
      @DavidWrightUK 2 месяца назад

      I'm glad the video helped. Best of luck with your studies 👍

  • @SaqPK
    @SaqPK 2 месяца назад

    I hate how ur not giving more of the same questions u move on so fast damn

    • @DavidWrightUK
      @DavidWrightUK 2 месяца назад

      It saddens me that you are so upset about this. Try to calm down.

    • @SaqPK
      @SaqPK 2 месяца назад

      @@DavidWrightUKim good bro, it’s just some criticism learn how to take it😂

    • @DavidWrightUK
      @DavidWrightUK 2 месяца назад

      @@SaqPK I've taken note. Thank you.

    • @SaqPK
      @SaqPK 2 месяца назад

      @@DavidWrightUK 👍

  • @rakhiskitchen3328
    @rakhiskitchen3328 2 месяца назад

    Can u pls tell what if the equal to value also has a negative base? Kindly tell

  • @elizabethconcepcion2151
    @elizabethconcepcion2151 2 месяца назад

    Thank you ever knew

  • @MUZANGALUMUNZENZI
    @MUZANGALUMUNZENZI 3 месяца назад

    Y can't you reduce the words on the screen ,we easily get obstructed.

  • @ShoaibKhan-wx8sn
    @ShoaibKhan-wx8sn 3 месяца назад

    I have this same calculator but the problem is I dont know how use its functions like those on the mode menu. Can you guide me? And also where is the matrix option in this couldn't find it

  • @SamiuelaMakaafi
    @SamiuelaMakaafi 4 месяца назад

    Not me watching this 2 hours before my math exam

  • @11KNOCKOUT
    @11KNOCKOUT 4 месяца назад

    👏👏👏👏👏👏👏👏🌹

  • @jameeltarekTarek
    @jameeltarekTarek 4 месяца назад

    Thank u w❤❤❤❤❤❤❤

  • @bobbu95
    @bobbu95 4 месяца назад

    Thank you very much. Clear and concise explaination. Cheers!

    • @DavidWrightUK
      @DavidWrightUK 4 месяца назад

      No problem. Glad the video helped👍

  • @somecommentarydude
    @somecommentarydude 4 месяца назад

    Using this in my college exams

    • @DavidWrightUK
      @DavidWrightUK 4 месяца назад

      Best of luck. Hope the video helps 👍

  • @dathrangkiopakyntein5000
    @dathrangkiopakyntein5000 5 месяцев назад

    Thanks🙏

  • @hamsterelephant2055
    @hamsterelephant2055 5 месяцев назад

    Thank you!!! As an IG student i found your videos very very helpful! Pleases keep going with this channel❤❤

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      Thank you for leaving such a nice comment. I appreciate it and plan to start making videos again in the autumn. I hope your studies go well and wish you all the best.

  • @benjaminmaurice9740
    @benjaminmaurice9740 5 месяцев назад

    The Cos -π/4 didn't give me 2 so how'd you get yours??

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      You have to make sure your calculator is set in radians. You also might be getting an answer that is equivalent. For example 1/sqrt(2) is the same as sqrt(2)/2.

  • @crystalcoleman7343
    @crystalcoleman7343 5 месяцев назад

    What do you do if they don’t give you all the values

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      The question should give a clue about what the total should be.

  • @yogendramishra1125
    @yogendramishra1125 5 месяцев назад

    thank u very much Guruji for the video ❤

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      No problem. Glad I could help 😃

  • @CocoCutiePie
    @CocoCutiePie 5 месяцев назад

    watching this while omw to exam hall

  • @chibangatryson6379
    @chibangatryson6379 5 месяцев назад

    Thanks 👍👍🙏🙏

  • @shariqkhan8181
    @shariqkhan8181 5 месяцев назад

    Thank you

  • @travler2899
    @travler2899 6 месяцев назад

    Fx991es?

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      Unfortunately there isn't a factorial button on this model.

  • @travler2899
    @travler2899 6 месяцев назад

    I have fx991es plus 😢

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      A few people have mentioned this before because the FX991ES doesn't seem to have the factorial function.

  • @mwanikaalex4931
    @mwanikaalex4931 6 месяцев назад

    Voice is blurred

  • @Black.Switch
    @Black.Switch 6 месяцев назад

    Thank's Davied I appreciate it so much

    • @DavidWrightUK
      @DavidWrightUK 6 месяцев назад

      No problem. Best of luck with your studies.

  • @NathanVillanuevaBC
    @NathanVillanuevaBC 6 месяцев назад

    Aren't you to add 2π to -π/4? I've solved it differently and this is my result: Z = 2sqrt(2) (cos(7π/4) + isin(7π/4))

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      The two answers are equivalent because the difference is 2*pi as you've mentioned. Some university courses want an answer between 0 and 2 pi, whilst others want answers from 0 to pi / 0 to minus pi. There isn't a standard convention for this which is why sometimes you will get different (but equivalent) answers in this type of problem.

  • @Undiscoverd-e5h
    @Undiscoverd-e5h 6 месяцев назад

    this advice is abselutley garbage its shit

  • @ClaudiaJanuary-mu7ii
    @ClaudiaJanuary-mu7ii 6 месяцев назад

    What if the equation is like X plus A equal X plus B divided by C change the subject to X

    • @DavidWrightUK
      @DavidWrightUK 5 месяцев назад

      Try splitting the right-hand side into two fractions. Then apply the ideas shown in the video.

  • @vandanathomas658
    @vandanathomas658 6 месяцев назад

    U explained it very nicely .Thank u very much .

    • @DavidWrightUK
      @DavidWrightUK 6 месяцев назад

      No problem. I'm glad the video helped 😃

  • @charlesokuom8747
    @charlesokuom8747 6 месяцев назад

    Well explained

  • @AayushPoddar-st3zn
    @AayushPoddar-st3zn 6 месяцев назад

    why did '3y/2' changed to '3/2*y'?

    • @DavidWrightUK
      @DavidWrightUK 6 месяцев назад

      3y means 3*y. Therefore 3y/2 is the same as 3/2*y. You can test this on your calculator. For example, if y=4 then (3*4)/2=6 and (3/2)*4=6. Hope this helps.

  • @arinzeanthony7447
    @arinzeanthony7447 6 месяцев назад

    Do we use general argument when finding polar equivalent or is it a must or a standard to use principal arguments?

    • @DavidWrightUK
      @DavidWrightUK 6 месяцев назад

      It is standard to use the principle argument which is the fraction in it's lowest form. For example, cos(pi/4) is the same as cos(9pi/4) and cos( 17pi/4) etc, the only difference is that 2*pi has been added to take account of one revolution around the unit circle. However your teacher might be asking you to consider the odd and even nature of sine and cosine functions. For example cos(pi/4) is the same as cos(minus pi/4), which is also the same as cos (7pi/4). I would need to make a separate video to cover this but you can find out more information if you research the properties of the unit circle.

    • @arinzeanthony7447
      @arinzeanthony7447 6 месяцев назад

      @@DavidWrightUK ohh. I now understand. Thanks a lot.

  • @goatlps
    @goatlps 6 месяцев назад

    0:28 It's quicker to just put in .2 x 115. Is there a way to calculate "50% more" without doing (.5 x 115) + 115 = 172.5? Apart from 1.5 x 115, obviously.

    • @DavidWrightUK
      @DavidWrightUK 6 месяцев назад

      1.5 x 115 is pretty quick on a calculator. If you are doing the calculation in your head then you could add on 50% of 100 first, giving 150. Then add on 50% of 15, giving 22.5. The total is therefore 172.5.

  • @danielkelsosmith
    @danielkelsosmith 7 месяцев назад

    Why have we gone in a negative direction? That’s what I’m failing to understand. If we are working in the 3rd and 4th quadrant are we going in a negative direction?

    • @danielkelsosmith
      @danielkelsosmith 7 месяцев назад

      And how would you do one in the third quadrant?

    • @DavidWrightUK
      @DavidWrightUK 7 месяцев назад

      It is convention to regard the third and fourth quadrant as the negative direction so that none of the angles are more than plus or minus pi.

    • @danielkelsosmith
      @danielkelsosmith 7 месяцев назад

      @@DavidWrightUK thank you. Lost sleep over this question haha

  • @SundaeOfDoom
    @SundaeOfDoom 7 месяцев назад

    Thank you for explaining it so clearly!

    • @DavidWrightUK
      @DavidWrightUK 7 месяцев назад

      You're welcome. I'm glad the video was helpful 😃

  • @phill12345
    @phill12345 7 месяцев назад

    Thanks ❤❤❤ On point 📌

    • @DavidWrightUK
      @DavidWrightUK 7 месяцев назад

      Appreciated, thank you 👍

  • @kaymo7498
    @kaymo7498 7 месяцев назад

    Wow i was in so much stress because i could not understand this polar form thing but you just made it so simple and easy to understand,thank for the work that your doing,God bless your brother.

    • @DavidWrightUK
      @DavidWrightUK 7 месяцев назад

      I'm glad the video helped and wish you all the best with your studies 👍

  • @AkhoPama
    @AkhoPama 7 месяцев назад

    We're nothing without you

  • @dgossymax
    @dgossymax 7 месяцев назад

    Thanks mate you're a good lad

    • @DavidWrightUK
      @DavidWrightUK 7 месяцев назад

      No problem. Glad I could help 👍

  • @mujiman182
    @mujiman182 7 месяцев назад

    Who let him cook

  • @Blair-y3d
    @Blair-y3d 8 месяцев назад

    Thank you morning before big test 3.51 am thank you 👌

    • @DavidWrightUK
      @DavidWrightUK 8 месяцев назад

      That's a long night. Hope the test goes well 😀