MathGH
MathGH
  • Видео 161
  • Просмотров 161 130
Set Operations Practice
Please comment if you have any questions or suggestions!
Просмотров: 40

Видео

Pascals TrianglePascals Triangle
Pascals Triangle
Просмотров 2526 лет назад
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Set Builder NotationSet Builder Notation
Set Builder Notation
Просмотров 856 лет назад
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Intro to CountingIntro to Counting
Intro to Counting
Просмотров 2766 лет назад
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Practice with Truth TablesPractice with Truth Tables
Practice with Truth Tables
Просмотров 466 лет назад
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Power SetsPower Sets
Power Sets
Просмотров 306 лет назад
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Proofs with Truth TablesProofs with Truth Tables
Proofs with Truth Tables
Просмотров 816 лет назад
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Introduction to Mathematical ProofsIntroduction to Mathematical Proofs
Introduction to Mathematical Proofs
Просмотров 1876 лет назад
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Harder Practice with Permutations and CombinationsHarder Practice with Permutations and Combinations
Harder Practice with Permutations and Combinations
Просмотров 39 тыс.6 лет назад
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Combinations IntroCombinations Intro
Combinations Intro
Просмотров 5936 лет назад
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FactorialsFactorials
Factorials
Просмотров 1496 лет назад
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Proof by ContradictionProof by Contradiction
Proof by Contradiction
Просмотров 1446 лет назад
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Basic Logic LawsBasic Logic Laws
Basic Logic Laws
Просмотров 876 лет назад
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Intro to Sets RevisedIntro to Sets Revised
Intro to Sets Revised
Просмотров 1266 лет назад
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Binomial TheoremBinomial Theorem
Binomial Theorem
Просмотров 1 тыс.6 лет назад
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Комментарии

  • @wild_imaginatorII
    @wild_imaginatorII Месяц назад

    In the last question of the video, why wasn't the number of cards(shapes whatever) for each of the cards specified. Like why wasn't it written that there are 13 diamonds in the set etc.

  • @narsinghyadav1071
    @narsinghyadav1071 3 месяца назад

    I like to think of the 1st question differently. From my what I learned about circular permutation, we can think of it as linear arrangement but we've overcounted by the possible rotations. We can rotate the table in such possible arrangement, and it happens 'n times for n seats'. I'd like check my understanding here, I'll be glad if anyone could help... So what I did was (for the 1st question)-- First I considered linear arrangements, I came up with 2 possible cases - MenWomenMean...+ WomenMenWomen... And divided by 8 (8 seats) And got the same answer I just wanted to check if theres something wrong with my logic

    • @TragicGFuel
      @TragicGFuel 3 месяца назад

      How do you account for cases where the two supposed cases just happen to be the same? MWMW could be interpreted as WMWM based on the starting point

  • @d00p58
    @d00p58 3 месяца назад

    helps so much thank you

  • @alphagamer2864
    @alphagamer2864 4 месяца назад

    Well explained however it would have been to explain a more complexed function with transformations and such.

  • @venusisalwaysabove
    @venusisalwaysabove 4 месяца назад

    this was so helpful, thank you !

  • @danielfrt
    @danielfrt 4 месяца назад

    Second problem is not right, we can prove it easily by stating the problem as: A bookshelf has 5 fiction books and 6 non-fictioon books. In how many ways can we choose two books of each type? the answer is not 150. the equation for the original question is simply 6x=150

    • @ZoeZ.U.
      @ZoeZ.U. 22 дня назад

      The answer in the vedio is correct. There are 5 non fiction books. That equation you're talking about is wrong, because what is x supposed to represent

  • @soulful-intellect
    @soulful-intellect 4 месяца назад

    stupid teacher

  • @bingw4416
    @bingw4416 7 месяцев назад

    wu

  • @dianacguz
    @dianacguz 8 месяцев назад

    what a g, thanks for doing the things my math teacher can’t🙏🏼

  • @giovannipaoloboyd-trevisan752
    @giovannipaoloboyd-trevisan752 8 месяцев назад

    this is amazing Thank you very much

  • @marktan8423
    @marktan8423 9 месяцев назад

    Never thought of using song to memorize mundane information like that. So amazing, you're an amazing teacher!

  • @user-hk4dk5xs6d
    @user-hk4dk5xs6d 11 месяцев назад

    In the first example where did you get 10 from

    • @BiBiartist0
      @BiBiartist0 8 месяцев назад

      10 is the number of digits in your passcode

  • @cmimic7479
    @cmimic7479 Год назад

    Ah, thank you sooo much!! 💜💜💜

  • @i-uniquecodm_1652
    @i-uniquecodm_1652 Год назад

    thanks

  • @simon-pierredandrea2928
    @simon-pierredandrea2928 Год назад

    Thanks

  • @siyavuyanyilika3340
    @siyavuyanyilika3340 Год назад

    Can direction be a negative

  • @meghan1843
    @meghan1843 Год назад

    THANKS!! This help so much. I was so confused when I should add 180

  • @abdulqayyum455
    @abdulqayyum455 Год назад

  • @Brayden_Hoffart
    @Brayden_Hoffart Год назад

    Thanks! Helped a lot

  • @sk99gaming99
    @sk99gaming99 Год назад

    I solved the 2 question using quadraticn formula I got 1+-root 79/2

  • @abrilthom895
    @abrilthom895 Год назад

    Hello, why if it is not divisible by 3, we got the cases of 3m+1 & 3m+2

    • @stacksepc
      @stacksepc Год назад

      First. Every multiple of 3 can be represented by 3m (3 times any number) . Therefore any number that is not a multiple of 3 can be represented by THAT number (3m) plus 1 or 2….. ie 3m +1, or 3m +2. This is b\c every number that is divisible by 3 is 3 digits away from every number divisible by 3. (3,6,9,12…. Etc). You have to represent the numbers in between numbers that are divisible by 3 which can only be 1 or 2 away.

    • @abrilthom895
      @abrilthom895 Год назад

      @@stacksepc What about 3m-1, is that a non multiple

    • @tanayshrivastava8915
      @tanayshrivastava8915 9 месяцев назад

      ya it is but that would already be accounted from the previous 3k with a plus 2@@abrilthom895

    • @FelaKayi
      @FelaKayi 18 дней назад

      @@stacksepc you saved a life,thank you

    • @stacksepc
      @stacksepc 15 дней назад

      @@FelaKayi good luck kid

  • @justingamer6695
    @justingamer6695 Год назад

    How 9+4=5?

  • @justingamer6695
    @justingamer6695 Год назад

    Thank you 🇵🇭

  • @franekorlowski5410
    @franekorlowski5410 Год назад

    So underrated! Thank you‼️

  • @rahelbakr3532
    @rahelbakr3532 Год назад

    7/-5 sir

  • @themctom11
    @themctom11 Год назад

    had to see this video and reach this point of my life to know that I don't have to remember by heart how to simplify a squared binomial, but just distribute. 6:30 Thanks

  • @marleniom3210
    @marleniom3210 2 года назад

    Thank you! You saved me hours!

  • @MuccisJag
    @MuccisJag 2 года назад

    Buddy. This helped SO much. My flippin textbook has NO mention on how to solve for direction angle. I've been at a single problem for 4 hours, evidently because I wasn't clever enough to notice/remember that I could find the angle I need using basic Trig functions. Thanks for this!

  • @mariuszpopieluch7373
    @mariuszpopieluch7373 2 года назад

    Interesting problems but poor formulations and explanations.

  • @lover_rosie
    @lover_rosie 2 года назад

    thank u for helping me!

  • @michaelpalma902
    @michaelpalma902 2 года назад

    is it 7/5 or 7/-5?

    • @rahelbakr3532
      @rahelbakr3532 Год назад

      He literally confused me lol

    • @thhndy
      @thhndy Год назад

      7/-5 bc it's in the 2nd quadrant

  • @darkast2679
    @darkast2679 2 года назад

    this explanation is better then other ones, really good helped me out, just maybe a third example on quadrant 3

  • @mohammadhasan5255
    @mohammadhasan5255 2 года назад

    Thank you!

  • @gracehu3031
    @gracehu3031 2 года назад

    Thank you! :)

  • @victorialeguizamon5699
    @victorialeguizamon5699 2 года назад

    Great video. Thanks so much.

  • @ay9085
    @ay9085 2 года назад

    thanks

  • @thanatosiax
    @thanatosiax 2 года назад

    lifesaver

  • @Dhruvbala
    @Dhruvbala 2 года назад

    I'm still a little confused as to why you don't divide by 8 on the first one. Wouldn't it be a different arrangement if each individual shifted over by one?

    • @doublematter6132
      @doublematter6132 2 года назад

      Yeah that's what I wanted to ask

    • @sudiptabhaskor6060
      @sudiptabhaskor6060 2 года назад

      Think it this way. What if the table wasn't a circular one but a straight one? In that case, the number of possible arrangement would be 2*4!*4!*. The 2 accounts for the fact that you could start the arrangement either with a man or a woman. So 2 ways. Now when you think of a circular table, you have to consider Rotational Symmetry( That's the key term). For 8 people we have 8 rotational symmetry,right? So you actually divide up everything by 8. You have 144.

  • @grape2713
    @grape2713 2 года назад

    i had no idea what the transverse axis was, tysm

  • @kaby3440
    @kaby3440 2 года назад

    Thx man buyed me a short time

  • @emmanuelokpeh3259
    @emmanuelokpeh3259 2 года назад

    Great piece!!!. It would had been better if your questions are made legible by increasing the size of your character.

  • @aspektstv3149
    @aspektstv3149 2 года назад

    You call this hard practice??? What's easy then??

    • @ZoeZ.U.
      @ZoeZ.U. 22 дня назад

      I didnt understand the first one

    • @ZoeZ.U.
      @ZoeZ.U. 22 дня назад

      Or third

  • @sanjoemathew5583
    @sanjoemathew5583 3 года назад

    Yo u the g

  • @SoFia-fd6qj
    @SoFia-fd6qj 3 года назад

    May i ask what category does number 1 belongs to?? Is it a permutation or a combination?

    • @ogkakulalo3872
      @ogkakulalo3872 3 года назад

      permutation

    • @Iseeyou0165
      @Iseeyou0165 3 года назад

      permutation as the order matters (men and female needs to be alternate to each other)!

  • @ibahmed6645
    @ibahmed6645 3 года назад

    Wow thank you very much

  • @kathleenolivier1588
    @kathleenolivier1588 3 года назад

    Hi sir or anyone can you tell me the answer for this question. A coach has 16 players and can pick from 11 players for a match. it consist of 7 specialist batsmen, 4 fast bowlers, 3 spinner and 2 wicketkeeper. how many different teams can be formed if it must comprised of 6 specialist batsmen, 3 fast bowlers , 1 spinner and a wicketkeeper.

    • @oliwood1592
      @oliwood1592 3 года назад

      7C6 (batsmen) x 4C3 (bowlers) x 3C1 (spinners) x 2C1 (wicketkeepers) = 168

    • @HHH21
      @HHH21 2 года назад

      More accurate question: A coach need 11 players and can pick from 16 players for a match.

    • @billlu1076
      @billlu1076 2 года назад

      @@HHH21 16C11

    • @mynameisjeff9124
      @mynameisjeff9124 2 года назад

      @@HHH21 No, that's wrong. The correct one is the answer by @Oli Wood, because if you choose 11 players from 16, then this also has the possibility to pick all 7 specialist batsmen and all 4 fast bowlers and one of the others.

    • @HHH21
      @HHH21 2 года назад

      @@mynameisjeff9124 How can you pick from only 11 players if total are 16? And there isn't any possibility to pick all 7 batsman and more because restrictions are already given

  • @Markjohn26
    @Markjohn26 3 года назад

    It help me thanks

  • @daniellejones1616
    @daniellejones1616 3 года назад

    thank you this helped alot

  • @noeltuplano6085
    @noeltuplano6085 3 года назад

    Great one!

  • @RG-tl5jl
    @RG-tl5jl 3 года назад

    We divided 4 for men because thats the society wants . Femenism Bruhhhh