SOLVING MATH PROBLEMS
SOLVING MATH PROBLEMS
  • Видео 983
  • Просмотров 307 411
Trigonometry: Prove that cot(π/4+θ)cot(π/4-θ)=1.
Trigonometry: Prove that cot(π/4+θ)cot(π/4-θ)=1.
Просмотров: 9

Видео

Trigonometry: Prove that 1+tanAtanA/2=tanAcotA/2-1=secA.4:12Trigonometry: Prove that 1+tanAtanA/2=tanAcotA/2-1=secA.
Trigonometry: Prove that 1+tanAtanA/2=tanAcotA/2-1=secA.
Просмотров 622 часа назад
Trigonometry: Prove that 1 tanAtanA/2=tanAcotA/2-1=secA.
Prove that tan(pi/4+ theta)tan(3pi/4+theta)=-1.3:46Prove that tan(pi/4+ theta)tan(3pi/4+theta)=-1.
Prove that tan(pi/4+ theta)tan(3pi/4+theta)=-1.
Просмотров 822 часа назад
Prove that tan(pi/4 theta)tan(3pi/4 theta)=-1.
Prove that cosecA-2cot2AcosA=2sinA2:05Prove that cosecA-2cot2AcosA=2sinA
Prove that cosecA-2cot2AcosA=2sinA
Просмотров 1023 часа назад
Prove that cosecA-2cot2AcosA=2sinA
Prove that corAcotB+cotBcotC+cotCcotA=1 in a triangle ABC.3:14Prove that corAcotB+cotBcotC+cotCcotA=1 in a triangle ABC.
Prove that corAcotB+cotBcotC+cotCcotA=1 in a triangle ABC.
Просмотров 102 часа назад
Prove that corAcotB cotBcotC cotCcotA=1 in a triangle ABC.
Circulating current in delta connected alternator6:15Circulating current in delta connected alternator
Circulating current in delta connected alternator
Просмотров 102 часа назад
Circulating current in delta connected alternator
Prove that tan(45+A/2)= sqrt[(1+sinA)/(1~sinA)]=secA+tanA4:42Prove that tan(45+A/2)= sqrt[(1+sinA)/(1~sinA)]=secA+tanA
Prove that tan(45+A/2)= sqrt[(1+sinA)/(1~sinA)]=secA+tanA
Просмотров 124 часа назад
Prove that tan(45 A/2)= sqrt[(1 sinA)/(1~sinA)]=secA tanA
Prove that sec(pi/4+theta)sec(pi/4-theta)=2sec(2 theta).2:48Prove that sec(pi/4+theta)sec(pi/4-theta)=2sec(2 theta).
Prove that sec(pi/4+theta)sec(pi/4-theta)=2sec(2 theta).
Просмотров 217 часов назад
Prove that sec(pi/4 theta)sec(pi/4-theta)=2sec(2 theta).
Prove that cos^2x+cos^2(x+120)+cos^2(x-120)=3/2.4:02Prove that cos^2x+cos^2(x+120)+cos^2(x-120)=3/2.
Prove that cos^2x+cos^2(x+120)+cos^2(x-120)=3/2.
Просмотров 117 часов назад
Prove that cos^2x cos^2(x 120) cos^2(x-120)=3/2.
Trigonometry: Prove that cosec^6α-cot^6α=3cosec^αcot^2α+1.3:34Trigonometry: Prove that cosec^6α-cot^6α=3cosec^αcot^2α+1.
Trigonometry: Prove that cosec^6α-cot^6α=3cosec^αcot^2α+1.
Просмотров 179 часов назад
Trigonometry: Prove that cosec^6α-cot^6α=3cosec^αcot^2α 1.
Trigonometry: If cos θ-sinθ=√2 sinθ, prove that cos θ+sinθ=√2 cosθ.3:16Trigonometry: If cos θ-sinθ=√2 sinθ, prove that cos θ+sinθ=√2 cosθ.
Trigonometry: If cos θ-sinθ=√2 sinθ, prove that cos θ+sinθ=√2 cosθ.
Просмотров 199 часов назад
Trigonometry: If cos θ-sinθ=√2 sinθ, prove that cos θ sinθ=√2 cosθ.
Synchronous Generator: Find the terminal voltage at leading pf.10:05Synchronous Generator: Find the terminal voltage at leading pf.
Synchronous Generator: Find the terminal voltage at leading pf.
Просмотров 1216 часов назад
Synchronous Generator: Find the terminal voltage at leading pf.
Algebra: Solve equation: (2x+1)^2/5-(4x-1)^2/20=(15/8)+3(4x+1)/40.4:18Algebra: Solve equation: (2x+1)^2/5-(4x-1)^2/20=(15/8)+3(4x+1)/40.
Algebra: Solve equation: (2x+1)^2/5-(4x-1)^2/20=(15/8)+3(4x+1)/40.
Просмотров 1216 часов назад
Algebra: Solve equation: (2x 1)^2/5-(4x-1)^2/20=(15/8) 3(4x 1)/40.
Trigonometry: Find sinθ if tanθ+cotθ=2.1:57Trigonometry: Find sinθ if tanθ+cotθ=2.
Trigonometry: Find sinθ if tanθ+cotθ=2.
Просмотров 1121 час назад
Trigonometry: Find sinθ if tanθ cotθ=2.
Trigonometry: Find tanθ if 3sec^4θ+8 =10 sec^2θ.3:38Trigonometry: Find tanθ if 3sec^4θ+8 =10 sec^2θ.
Trigonometry: Find tanθ if 3sec^4θ+8 =10 sec^2θ.
Просмотров 1221 час назад
Trigonometry: Find tanθ if 3sec^4θ 8 =10 sec^2θ.
Algebra: Solve equations: xy+(x/y)=10, xy+(y/x)=17/2.5:35Algebra: Solve equations: xy+(x/y)=10, xy+(y/x)=17/2.
Algebra: Solve equations: xy+(x/y)=10, xy+(y/x)=17/2.
Просмотров 5День назад
Algebra: Solve equations: xy (x/y)=10, xy (y/x)=17/2.
Trigonometry: If cotθ+cosecθ = 5, find cosθ.4:02Trigonometry: If cotθ+cosecθ = 5, find cosθ.
Trigonometry: If cotθ+cosecθ = 5, find cosθ.
Просмотров 10День назад
Trigonometry: If cotθ cosecθ = 5, find cosθ.
Single phase circuits: Find power, current, impedance and power factor.6:45Single phase circuits: Find power, current, impedance and power factor.
Single phase circuits: Find power, current, impedance and power factor.
Просмотров 3День назад
Single phase circuits: Find power, current, impedance and power factor.
Synchronous generator: Determine the emf generated by an alternator.6:09Synchronous generator: Determine the emf generated by an alternator.
Synchronous generator: Determine the emf generated by an alternator.
Просмотров 10День назад
Synchronous generator: Determine the emf generated by an alternator.
Prove that (secAtanA+sec^2A)/[1+(secA+tanA)^2]=1/2.3:19Prove that (secAtanA+sec^2A)/[1+(secA+tanA)^2]=1/2.
Prove that (secAtanA+sec^2A)/[1+(secA+tanA)^2]=1/2.
Просмотров 414 дней назад
Prove that (secAtanA sec^2A)/[1 (secA tanA)^2]=1/2.
Prove that C0/1.2+C1/2.3+C2/3.4+………+Cn/(n+1)(n+2)=[2^(n+2)-n-3]/(n+1)(n+2).8:30Prove that C0/1.2+C1/2.3+C2/3.4+………+Cn/(n+1)(n+2)=[2^(n+2)-n-3]/(n+1)(n+2).
Prove that C0/1.2+C1/2.3+C2/3.4+………+Cn/(n+1)(n+2)=[2^(n+2)-n-3]/(n+1)(n+2).
Просмотров 1714 дней назад
Prove that C0/1.2 C1/2.3 C2/3.4 ……… Cn/(n 1)(n 2)=[2^(n 2)-n-3]/(n 1)(n 2).
Binomial Theorem: Prove that 1C1+3C3+5C5+…….=n.2^(n-2).3:38Binomial Theorem: Prove that 1C1+3C3+5C5+…….=n.2^(n-2).
Binomial Theorem: Prove that 1C1+3C3+5C5+…….=n.2^(n-2).
Просмотров 1614 дней назад
Binomial Theorem: Prove that 1C1 3C3 5C5 …….=n.2^(n-2).
Binomial Theorem: Prove that 1.2C2+2.3C3+3.4C3+……….+(n-1)nCn = (n-1)n.2^(n-2).4:01Binomial Theorem: Prove that 1.2C2+2.3C3+3.4C3+……….+(n-1)nCn = (n-1)n.2^(n-2).
Binomial Theorem: Prove that 1.2C2+2.3C3+3.4C3+……….+(n-1)nCn = (n-1)n.2^(n-2).
Просмотров 1714 дней назад
Binomial Theorem: Prove that 1.2C2 2.3C3 3.4C3 ………. (n-1)nCn = (n-1)n.2^(n-2).
Binomial Theorem: Prove that C0/1+C1/2+C2/3+.........+Cn/(n+1)=[2^(n+1)-1]/(n+1).4:17Binomial Theorem: Prove that C0/1+C1/2+C2/3+.........+Cn/(n+1)=[2^(n+1)-1]/(n+1).
Binomial Theorem: Prove that C0/1+C1/2+C2/3+.........+Cn/(n+1)=[2^(n+1)-1]/(n+1).
Просмотров 2614 дней назад
Binomial Theorem: Prove that C0/1 C1/2 C2/3 ......... Cn/(n 1)=[2^(n 1)-1]/(n 1).
Binomial Theorem: Prove that C1+2C2+3C3+,,,,,,,,,,,+nCn=n.2^(n-1).3:09Binomial Theorem: Prove that C1+2C2+3C3+,,,,,,,,,,,+nCn=n.2^(n-1).
Binomial Theorem: Prove that C1+2C2+3C3+,,,,,,,,,,,+nCn=n.2^(n-1).
Просмотров 1114 дней назад
Binomial Theorem: Prove that C1 2C2 3C3 ,,,,,,,,,,, nCn=n.2^(n-1).
Evaluate: Integral (cos2x-cos2α) dx/(cosx-cosα).3:40Evaluate: Integral (cos2x-cos2α) dx/(cosx-cosα).
Evaluate: Integral (cos2x-cos2α) dx/(cosx-cosα).
Просмотров 3321 день назад
Evaluate: Integral (cos2x-cos2α) dx/(cosx-cosα).
Evaluate: integral (cosx-sinx)dx /(1+sin2x).3:04Evaluate: integral (cosx-sinx)dx /(1+sin2x).
Evaluate: integral (cosx-sinx)dx /(1+sin2x).
Просмотров 221 день назад
Evaluate: integral (cosx-sinx)dx /(1 sin2x).
Physics: Magnetic circuit: Determining magnetic flux density in an iron ring having air gap.5:17Physics: Magnetic circuit: Determining magnetic flux density in an iron ring having air gap.
Physics: Magnetic circuit: Determining magnetic flux density in an iron ring having air gap.
Просмотров 2321 день назад
Physics: Magnetic circuit: Determining magnetic flux density in an iron ring having air gap.
Trigonometry: Find sum of the series: sinθ+sin2θ+sin3θ+…………+sin nθ.6:10Trigonometry: Find sum of the series: sinθ+sin2θ+sin3θ+…………+sin nθ.
Trigonometry: Find sum of the series: sinθ+sin2θ+sin3θ+…………+sin nθ.
Просмотров 1221 день назад
Trigonometry: Find sum of the series: sinθ sin2θ sin3θ ………… sin nθ.
Trigonometry: Find sum of the series: cosθ+cos3θ+cos5θ+……..+cos(2n-1)θ.5:09Trigonometry: Find sum of the series: cosθ+cos3θ+cos5θ+……..+cos(2n-1)θ.
Trigonometry: Find sum of the series: cosθ+cos3θ+cos5θ+……..+cos(2n-1)θ.
Просмотров 1628 дней назад
Trigonometry: Find sum of the series: cosθ cos3θ cos5θ …….. cos(2n-1)θ.

Комментарии

  • @AmarjeetSelwal
    @AmarjeetSelwal 4 часа назад

    Realy brilliant brother

  • @AshokKumaryadav-ed9qy
    @AshokKumaryadav-ed9qy 7 дней назад

    Please explain zero kaise kar diya

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 6 дней назад

      @@AshokKumaryadav-ed9qy Applying integral theorem given in video, we get numerator as zero as explained in video. Hence, integral will be zero.

  • @Winkkin
    @Winkkin 11 дней назад

    I appreciate the effort but reading your script is being a pharmacist.

  • @anuragtomar125
    @anuragtomar125 13 дней назад

    Sir this question is from which book Please tell me sir 😢😢😢

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 13 дней назад

      @anuragtomar125 This problem has been taken from the famous book, "Problems in Electrical Engineering ' by S Parker Smith.

  • @Sincie_megisa
    @Sincie_megisa 14 дней назад

    Explain properly

  • @Sincie_megisa
    @Sincie_megisa 14 дней назад

    Disgusting

  • @Masab-y6s
    @Masab-y6s 16 дней назад

    Very bad writing ✍️ Improved your writing plzzz

  • @vimathsansilu
    @vimathsansilu 21 день назад

    thank you

  • @nikethan8541
    @nikethan8541 24 дня назад

    U made a huge mistake. You cannot use that formula which u used to find the roots at the beginning since b^2-4ac<0. If b&2-4ac is less than zero then we get negative number . Root of negative number is undefined.

  • @AbhishekDey91
    @AbhishekDey91 26 дней назад

    Just apply sin²A-sin²B = sin(A+B)sin(A-B). This will solve the problem in 2 lines

  • @prasantagogoi3361
    @prasantagogoi3361 26 дней назад

    L.H.S = W.K.T sec^2A - tan^2A = 1 . Than put in place of 1 sec^2A - tan^2A / Sec A - TanA than use the formula for sec^2 A - Tan^2A = (SecA+ tanA )( SecA - tan A ) / secA - tan A than cut nemerator and denominator secA - tan A than we left with secA + tanA = R.H.S 😂 soo easy

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 26 дней назад

    I like this answer.

  • @GrandProtectorDark
    @GrandProtectorDark Месяц назад

    Dude, I really don't understand why it seems to be so annoyingly difficult to find speficic examples of this exact Integral notation that isn't a closed path. This Video helped a lot.

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 25 дней назад

      Thanks for viewing the video.. I will upload some more videos on line integrals, double integral and triple integrals.

  • @jimmydejulian7033
    @jimmydejulian7033 Месяц назад

    ⁉⁉⁉

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS Месяц назад

      @jimmydejulian7033 The nonlinear equation can not be so easily solved by using algebraic techniques.

    • @jimmydejulian7033
      @jimmydejulian7033 Месяц назад

      @@SOLVINGMATHPROBLEMS Oh, i'm sorry but it's not about how it was solved or being solved, but rather it's the texts that were too small to read and understand. I stopped reading after 3 lines.

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS Месяц назад

      @jimmydejulian7033 I will try to make larger in future videos. Sorry for inconvenience. Try to enlarge and listen .

  • @YouTakeNotes
    @YouTakeNotes Месяц назад

    you have the worst hand writing i have ever seen wtf are you writing after "-20" @1:50

  • @Pw.Motivational38
    @Pw.Motivational38 Месяц назад

    Thanks sir nice explanation ❤❤

  • @VaibhavSingh-eq8kv
    @VaibhavSingh-eq8kv Месяц назад

    Wrong h

  • @Sigma.Infinity
    @Sigma.Infinity Месяц назад

    I didn't understand the cross multiplication until I discovered that it is identical to conversion of equations into symmetric form (in 3D geometry). Then I had something I could look up to learn the method. Thanks for the video, it was very helpful.

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS Месяц назад

      It gives me a pleasure to note that you could understand. Please let me know if you have any other questions.

  • @m8_k10_v7
    @m8_k10_v7 Месяц назад

    Nice class❤

  • @umangraj5038
    @umangraj5038 2 месяца назад

    Ans nhi match kr raha hai

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 2 месяца назад

      @@umangraj5038 please forward answer. I will look into it and see why answer is not matching.

  • @aseemop6667
    @aseemop6667 2 месяца назад

    Sir I want vinay kumar from where can I get it😊

  • @sushmitakarmakar1642
    @sushmitakarmakar1642 2 месяца назад

    Very helpful

  • @HarshitaNITSXR23
    @HarshitaNITSXR23 2 месяца назад

    how you found assumed the synchronous speed

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 2 месяца назад

      Here supply frequency is 5Hz. Number of poles can be 2,4,6,......Hence, synchronous speed will be 120f/p= 120*50/2 = 3000 rpm if p =2, synchronous speed = 120*50/4 = 1500 rpm if p =4, synchronous speed = 120*50/6 =1000 rpm if p =6 and so on Here full load sped =1440 rpm and nearest synchronous speed is 1500 rpm and we will have to consider this synchronous speed.

  • @krish45678
    @krish45678 2 месяца назад

    thank you sir

  • @aseemop6667
    @aseemop6667 2 месяца назад

    Sir clear nhi hau

  • @academic8093
    @academic8093 2 месяца назад

    sir at second last step you accidently written +root 3 twice in addition of denominator ..............answer change nhi hoga kya ...........please confirm and reply sir ji

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 2 месяца назад

      Thanks for viewing and commenting. Residue z =-2+sqrt(3) as it is inside unit circle.. So we have to put this value of z. This is what is done here. I hope you are aware about complex integral.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    Triangle area calculation is quite good and new approach. No need to remember any formula.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    I like 2nd method.

  • @yogasehihoga295
    @yogasehihoga295 3 месяца назад

    Thankyou sir I scrolled all the long videos and shorts but I can't find solution but here you explained it properly

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 3 месяца назад

      You are most welcome. What I have presented here is the simplest and shortest method.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    2nd method not given in books.

  • @motivation_for_billionaires
    @motivation_for_billionaires 3 месяца назад

    Thanks a lot 🙏🏻🙏🏻

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    Quite good answer.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    What you have given here is totally new approach. Never seen before anywhere else either in books or videos. Keep it up.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    Never seen such approach.

  • @Thegoat-c2g
    @Thegoat-c2g 3 месяца назад

    Solve it by elemination or substitution method

  • @kanwaljitsingh3248
    @kanwaljitsingh3248 3 месяца назад

    Kuch nahin dikhai de raha😢

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    As always, yr answers are short and simple.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 3 месяца назад

    Nice answer. Keep it up.

  • @KamleshYadav-nm1ev
    @KamleshYadav-nm1ev 4 месяца назад

    Lage rahiye

  • @KamleshYadav-nm1ev
    @KamleshYadav-nm1ev 4 месяца назад

    Nice sir ji

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 4 месяца назад

    Quite short and simple answer.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 4 месяца назад

    Short and efficient method

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 4 месяца назад

    2nd method is generally not given in books.

  • @Manojj.k
    @Manojj.k 4 месяца назад

    Thanks a lot 🎉

  • @Archimedes_Notes
    @Archimedes_Notes 4 месяца назад

    Again this is the wrong solution

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 4 месяца назад

    Is there any other method to solve this problem?

  • @aseemop6667
    @aseemop6667 5 месяцев назад

    Nice problem

  • @aseemop6667
    @aseemop6667 5 месяцев назад

    Nice problem sir

  • @aseemop6667
    @aseemop6667 5 месяцев назад

    Sir aap mere questions kab banaye gai

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 5 месяцев назад

      If there was only one or two questions, I could have tried to reply early but here you have asked 20-25 questions. It will take time. I can not commit any particular time but I will try.

    • @aseemop6667
      @aseemop6667 5 месяцев назад

      @@SOLVINGMATHPROBLEMS sir if not every question pls solve q 15

    • @SOLVINGMATHPROBLEMS
      @SOLVINGMATHPROBLEMS 5 месяцев назад

      I will reply it today.

  • @user-xf6kx7qn1f
    @user-xf6kx7qn1f 5 месяцев назад

    Very simple method.