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Nonso
Нигерия
Добавлен 5 май 2024
A resource place for senior secondary school students who use New General Mathematics as their main maths text; and for anyone else who needs a graded senior secondary school (high school) maths study guide.
Looks tricky but VERY SIMPLE | New General Maths SS3.
Test yourself with this tricky algebra question.
The problem is taken from the New General Mathematics for Senior Secondary Schools, book 3 (SS3) - Examination 1, Paper 2, Part 1, #2b (Page 249).
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It would mean a lot to me if you subscribed 😊
www.youtube.com/@NonsoMaths?sub_confirmation=1
For inquiries, please contact me through wa.me/message/OC7PRKG76VNFO1
#maths #mathematics #newgeneralmaths #science #technology #education #wassce #waec #newgeneralmathsss3 #algebra #howto #seniorsecondary
The problem is taken from the New General Mathematics for Senior Secondary Schools, book 3 (SS3) - Examination 1, Paper 2, Part 1, #2b (Page 249).
Thanks for watching.
It would mean a lot to me if you subscribed 😊
www.youtube.com/@NonsoMaths?sub_confirmation=1
For inquiries, please contact me through wa.me/message/OC7PRKG76VNFO1
#maths #mathematics #newgeneralmaths #science #technology #education #wassce #waec #newgeneralmathsss3 #algebra #howto #seniorsecondary
Просмотров: 234
Видео
Without CALCULATORS! Not an Olympiad question, but quite interesting. | New General Maths SS1
Просмотров 13414 часов назад
Learn the basic trig ratios (SOH/CAH/TOA), how to find the sine and cosine of an angle when the tangent of the angle is given (with the help of Pythagoras theorem), and how to use this knowledge to evaluate the given trigonometric expression, in this video. The problem is taken from the New General Mathematics for Senior Secondary Schools, book 1 (SS1) - revision exercise 6, #5 (Pg 171). Thanks...
Fractions in Real Life | New General Maths SS1
Просмотров 12314 дней назад
In this video, fractions are used to solve a real-life problem. The question is taken from exercise 3b (number 18) of the New General Mathematics for Senior Secondary Schools (SS1). #matheducation #mathematics #arithmetic #numericalprocesses #fractions #decimals #rates #proportions #WAEC #WASSCE #education #newgeneralmaths #newgeneralmathssolutions Thanks for watching. Please subscribe, like an...
Stop Struggling with Fractions! | Ex 3b, New General Maths SS1.
Просмотров 34128 дней назад
Stop Struggling with Fractions! | Ex 3b, New General Maths SS1.
The Simplest Geometry Theorem | Ex 2f, New General Maths SS1
Просмотров 95Месяц назад
The Simplest Geometry Theorem | Ex 2f, New General Maths SS1
SOLVED Plain Geometry Exercises | Ex 2e, New General Maths SS1
Просмотров 185Месяц назад
SOLVED Plain Geometry Exercises | Ex 2e, New General Maths SS1
Easy STEP BY STEP guide on how to write formal geometry proofs | Ex 2d, New General Maths SS1
Просмотров 2322 месяца назад
Easy STEP BY STEP guide on how to write formal geometry proofs | Ex 2d, New General Maths SS1
Mastering Isosceles Triangle Angle Calculation | Ex 2c, New General Maths SS1
Просмотров 3782 месяца назад
Mastering Isosceles Triangle Angle Calculation | Ex 2c, New General Maths SS1
Plane Geometry - Calculating angles in polygons | Ex 2a, New General Maths SS1.
Просмотров 2172 месяца назад
Plane Geometry - Calculating angles in polygons | Ex 2a, New General Maths SS1.
Logarithms | Ex 1l, New General Maths SS1
Просмотров 1614 месяца назад
Logarithms | Ex 1l, New General Maths SS1
Standard Form | Ex 1g, New General Maths SS1
Просмотров 1224 месяца назад
Standard Form | Ex 1g, New General Maths SS1
Indices Equations | Ex 1f, New General Maths SS1
Просмотров 655 месяцев назад
Indices Equations | Ex 1f, New General Maths SS1
Negative indices | Ex 1e, New General Maths SS1
Просмотров 855 месяцев назад
Negative indices | Ex 1e, New General Maths SS1
Product of indices | Ex 1c, New General Maths SS1
Просмотров 875 месяцев назад
Product of indices | Ex 1c, New General Maths SS1
Mastering The LAWS OF INDICES (Exponents) | Ex 1d, New General Maths SS1
Просмотров 2345 месяцев назад
Mastering The LAWS OF INDICES (Exponents) | Ex 1d, New General Maths SS1
Laws of indices | Ex 1a, New General Maths SS1
Просмотров 1305 месяцев назад
Laws of indices | Ex 1a, New General Maths SS1
This is nice... 💯
Thanks for watching! Please remember to share.
Love eet
Interesting 🎉
First, find the total number of chicken days, which is 80 chickens × 18 days = 1,440 chicken days, then divide by the number of chickens to be fed. Thus; 1,440 chicken days -------------------------------- = 12 days 120 chickens 120 chickens can be fed with one sack of grain in 12 days.
Great!
Ratio, rate and proportion topic in maths...
I love this
Thanks for watching. Remember to share 😁
Nonny is making math learnable!!!!
Thanks, Nnam.
Omo I need to go back to sec school oh
If only maths was this easy when I was a kid 😊😊😊 On the lighter side, in a real elections, these numbers never add up😂
Most especially in Nigeria. It never adds up.
I am here to make it easy for your children!!!
Hahahaha Hopefully, one day it will begin to add up. No condition is permanent.
Add digits Divide sum by the given base Carry the quotient Write down the remainder - Repeat till the end.
Nice one bruh
Daalu, Nna.
w
ty u make it ez
ty
Thank you
I like 💯
I spent all of JSS and SSS without knowing this second method of simplification. I need to start lesson classes Atanonny. How much are you charging please?
00:00 - Question 1 - Addition, subtraction, multiplication and division of fractions. 08:09 - Question 3 - Determine which is the greatest of 7/9, 3/4, and 10/13. [WAEC] 10:51 - Question 5 - Express 0.575 as a fraction in its lowest terms. 11:52 - Question 7 - A flagpole 6.3 m long is driven 1.4 m into the ground. What fraction of the pole is above the ground? [WAEC] 13:11 - Question 9 - How much less than 6 is the sum of 2+(3/4) and 2+(4/5)? 14:46 - Question 11 - After spending 2/5 of her money on food and 1/6 on cosmetics, a woman was left with =N=1300. How much money did she have originally? 17:48 - Question 13 - Ayuba can hoe a yam plot in 5 hours and Salihu can hoe it in 4 hours. What fraction of the plot can each of them hoe in 1 hour? If they work together, what fraction of the plot will they hoe in 1 hour? How long will it take them to hoe the whole yam plot working together? 20:43 - Question 17 - 3/4 of the girls in SSS1 play basketball and 4/7 play volleyball. Every girl plays at least one of these games. If 27 girls play both games, how many girls are there in the class? 26:19 - Question 19 - A man made a will in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child. The rest was to be shared equally among his four younger children. If each of the younger children received =N=108,000, what was his wife's share? *'Parts', 'places' and 'portions' are used interchangeably in this video.* Thanks for watching.
I really pray that you land a gig with a big school that won't stress your kidneys... This step by step teaching is just gold. We didn't have this luxury in our time... Good work, Nonso...
Thanks a lot.
Your teaching style is incredibly soothing and engaging. It really makes it easy to stay focused and absorb the material. Keep going!
Thanks a lot!
안 영하새요
🎉🎉
Thanks for watching. Please Subscribe, Like and Share to support the channel. www.youtube.com/@NonsoMaths?sub_confirmation=1
0:00 - Introduction of concepts 01:14 - Question 1 03:26 - Question 3 07:14 - SUBSCRIBE and turn on notifications www.youtube.com/@NonsoMaths?sub_confirmation=1 07:22 - Extras Thanks for watching, and see you in the next one.
Nice one
Nice one 💯
Very educative! Thanks
💯
Since you have already solved it, here is another method. Simplify the exponents on the right side, then take the Logarithm of both sides. (4x - 1)Log2 = Log 1 (4x - 1)Log2 = 0 (Log 1 = 0 by definition) Divide both sides by Log2. 4x - 1 = 0 4x = 1 (Transpose 1 to the right side) x = 1/4 (Divide both sides by 4).
I greatly appreciate your input. Thanks a lot!!! But i have a problem with dividing zero by anything (or worse still, dividing anything by zero 😣) From the point where: (4x - 1)Log2 = 0 My argument will be: "Since given the above product and knowing that Log2 is not 0, then" 4x - 1 must be equal to 0 from where x = 1/4 😁
@NonsoMaths Dividing 0 by Log2 is not the same as dividing by 0. Dividing 0 gives zero, but division by zero is undefined. The only reason for dividing by Log2 is to remove Log2 from both sides and leave 4x - 1 = 0, which can be solved as a linear function.
He never said they were the same. He said that instead of saying that you divided zero by a number, realize the fact that if the product of two items is zero, then they are either both zero, or one of them is zero. And since log 2 very clearly can NOT be zero, then (4x - 1) = 0.
@NkechiR I do not see a problem or the need for an argument over this. You can divide both sides by Log2 to get rid of it or use a Zero Product Property to reason it.
Nice one uncle
Thanks
I counted and you are very right ✅️.
😊
The correct answer is 6+1/4 (Choice C). Reasoning/Method. A quadratic function in the form of a (perfect square) trinomial has the discriminant b^2 - 4ac = 0. Therefore; b^2 = 4ac (Transpose 4ac to right side) Given; a = 1, b = 5, and c = k b^2 = 4ac 5^2 = (4)(1)(k) 25 = 4k 4k = 25 k = 25/4 k = 6 + 1/4 The correct answer is Choice C.
Correct!
We should always remember that 6Log2 = 3Log4, since 2^6 = 64, and 4^3 = 64.
6log2 = 3log4 6log2 = 3log(2^2) 6log2 = 2*3log2 6log2 = 6log2 😁
I love this Keep up the good work boss😊
Thanks! 😄
Wish I had someone that taught me this way. Jisike nwannem.
I counted and you are right 👍
0:00 - Question 1: Counting parallelograms/rectangles 02:16 - Question 3: In the figure, ABCD and CDEF are parallelograms and ABEF is a straight line. If |BE| = 2 cm and |DC| = 3 cm, find |AF|. 03:43 - Question 5: In the figure, ABCD is a rhombus and APCQ is a square. If angle PAB = 21 degrees, calculate the four angles of ABCD. 08:25 - Question 7: ABCDEF is a regular hexagon with O at its centre. What kind of quadrilaterals are ABCO and ACDF? 13:26 - Question 9: ABC is a triangle and M is the mid-point of line BC. A line through C parallel to line AB cuts line AM produced at X. Prove |MX| = |MA|. Please subscribe, like and Share to support the channel. www.youtube.com/@NonsoMaths?sub_confirmation=1 Thanks for watching.
Nice
Mathematics made easy😊❤
Wow. So simplified.
My best part of maths.
Algebra is sweet shaaa... 💯
Aswear
💯
Thank you.
You're doing an absolutely amazing job 💪
Thank you so much!!
👍👍👍👍👍👍👍👍👍 👍👍👍👍
👍👍👍👍👍👍👍👍👍 👍👍👍👍
0:00 - Question 1: Give a formal proof that a quadrilateral with one pair of opposite sides equal and parallel is a parallelogram. 03:02 - A brief discussion on transversals, corresponding angles, vertically opposite angles and alternate angles. 07:46 - **The condition for congruence is SAS (Side - Angle - Side)** 11:15 - Question 2: Give a formal proof that the diagonals of a rhombus, i) bisect each other at right angles, ii) bisect the angles of the rhombus. 33:17 - Congruent Triangles.
sir please reason for congruency 18:56
The reason for congruency is SAS (Side - Angle - Side). Thanks for watching. Please share.
This is educative. I learnt something new today