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This is nice... 💯

Love eet

Interesting 🎉

First, find the total number of chicken days, which is 80 chickens × 18 days = 1,440 chicken days, then divide by the number of chickens to be fed. Thus; 1,440 chicken days -------------------------------- = 12 days 120 chickens 120 chickens can be fed with one sack of grain in 12 days.

Ratio, rate and proportion topic in maths...

I love this

Nonny is making math learnable!!!!

Omo I need to go back to sec school oh

If only maths was this easy when I was a kid 😊😊😊 On the lighter side, in a real elections, these numbers never add up😂

Add digits Divide sum by the given base Carry the quotient Write down the remainder - Repeat till the end.

Nice one bruh

w

ty u make it ez

ty

I like 💯

I spent all of JSS and SSS without knowing this second method of simplification. I need to start lesson classes Atanonny. How much are you charging please?

00:00 - Question 1 - Addition, subtraction, multiplication and division of fractions. 08:09 - Question 3 - Determine which is the greatest of 7/9, 3/4, and 10/13. [WAEC] 10:51 - Question 5 - Express 0.575 as a fraction in its lowest terms. 11:52 - Question 7 - A flagpole 6.3 m long is driven 1.4 m into the ground. What fraction of the pole is above the ground? [WAEC] 13:11 - Question 9 - How much less than 6 is the sum of 2+(3/4) and 2+(4/5)? 14:46 - Question 11 - After spending 2/5 of her money on food and 1/6 on cosmetics, a woman was left with =N=1300. How much money did she have originally? 17:48 - Question 13 - Ayuba can hoe a yam plot in 5 hours and Salihu can hoe it in 4 hours. What fraction of the plot can each of them hoe in 1 hour? If they work together, what fraction of the plot will they hoe in 1 hour? How long will it take them to hoe the whole yam plot working together? 20:43 - Question 17 - 3/4 of the girls in SSS1 play basketball and 4/7 play volleyball. Every girl plays at least one of these games. If 27 girls play both games, how many girls are there in the class? 26:19 - Question 19 - A man made a will in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child. The rest was to be shared equally among his four younger children. If each of the younger children received =N=108,000, what was his wife's share? *'Parts', 'places' and 'portions' are used interchangeably in this video.* Thanks for watching.

I really pray that you land a gig with a big school that won't stress your kidneys... This step by step teaching is just gold. We didn't have this luxury in our time... Good work, Nonso...

Your teaching style is incredibly soothing and engaging. It really makes it easy to stay focused and absorb the material. Keep going!

안 영하새요

🎉🎉

Thanks for watching. Please Subscribe, Like and Share to support the channel. www.youtube.com/@NonsoMaths?sub_confirmation=1

0:00 - Introduction of concepts 01:14 - Question 1 03:26 - Question 3 07:14 - SUBSCRIBE and turn on notifications www.youtube.com/@NonsoMaths?sub_confirmation=1 07:22 - Extras Thanks for watching, and see you in the next one.

Nice one

Nice one 💯

Very educative! Thanks

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Since you have already solved it, here is another method. Simplify the exponents on the right side, then take the Logarithm of both sides. (4x - 1)Log2 = Log 1 (4x - 1)Log2 = 0 (Log 1 = 0 by definition) Divide both sides by Log2. 4x - 1 = 0 4x = 1 (Transpose 1 to the right side) x = 1/4 (Divide both sides by 4).

Nice one uncle

I counted and you are very right ✅️.

The correct answer is 6+1/4 (Choice C). Reasoning/Method. A quadratic function in the form of a (perfect square) trinomial has the discriminant b^2 - 4ac = 0. Therefore; b^2 = 4ac (Transpose 4ac to right side) Given; a = 1, b = 5, and c = k b^2 = 4ac 5^2 = (4)(1)(k) 25 = 4k 4k = 25 k = 25/4 k = 6 + 1/4 The correct answer is Choice C.

We should always remember that 6Log2 = 3Log4, since 2^6 = 64, and 4^3 = 64.

I love this Keep up the good work boss😊

Wish I had someone that taught me this way. Jisike nwannem.

I counted and you are right 👍

0:00 - Question 1: Counting parallelograms/rectangles 02:16 - Question 3: In the figure, ABCD and CDEF are parallelograms and ABEF is a straight line. If |BE| = 2 cm and |DC| = 3 cm, find |AF|. 03:43 - Question 5: In the figure, ABCD is a rhombus and APCQ is a square. If angle PAB = 21 degrees, calculate the four angles of ABCD. 08:25 - Question 7: ABCDEF is a regular hexagon with O at its centre. What kind of quadrilaterals are ABCO and ACDF? 13:26 - Question 9: ABC is a triangle and M is the mid-point of line BC. A line through C parallel to line AB cuts line AM produced at X. Prove |MX| = |MA|. Please subscribe, like and Share to support the channel. www.youtube.com/@NonsoMaths?sub_confirmation=1 Thanks for watching.

Nice

Mathematics made easy😊❤

Wow. So simplified.

My best part of maths.

Algebra is sweet shaaa... 💯

💯

Thank you.

You're doing an absolutely amazing job 💪

👍👍👍👍👍👍👍👍👍 👍👍👍👍

👍👍👍👍👍👍👍👍👍 👍👍👍👍

0:00 - Question 1: Give a formal proof that a quadrilateral with one pair of opposite sides equal and parallel is a parallelogram. 03:02 - A brief discussion on transversals, corresponding angles, vertically opposite angles and alternate angles. 07:46 - **The condition for congruence is SAS (Side - Angle - Side)** 11:15 - Question 2: Give a formal proof that the diagonals of a rhombus, i) bisect each other at right angles, ii) bisect the angles of the rhombus. 33:17 - Congruent Triangles.

sir please reason for congruency 18:56

This is educative. I learnt something new today