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sirby_lectures
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Добавлен 22 мар 2020
Sample Problem - Vapor Compression Cycle (ENSC111 14.02)
Sample Problem - Vapor Compression Cycle (ENSC111 14.02)
Просмотров: 195
Видео
Refrigeration System (ENSC111 - 14.01)
Просмотров 17011 месяцев назад
Refrigeration System (ENSC111 - 14.01)
Concept of Reversibility (ENSC111 - 09.05)
Просмотров 78Год назад
Concept of Reversibility (ENSC111 - 09.05)
Coefficient of Performance (ENSC111 - 09.04)
Просмотров 83Год назад
Coefficient of Performance (ENSC111 - 09.04)
Calculating System Efficiencies (ENSC111 - 09.03)
Просмотров 140Год назад
Calculating System Efficiencies (ENSC111 - 09.03)
History of 2nd Law of Thermodynamics Part 2 (ENSC111 - 09.02)
Просмотров 102Год назад
History of 2nd Law of Thermodynamics Part 2 (ENSC111 - 09.02)
History of 2nd Law of Thermodynamics Part 1 (ENSC111 - 09.01)
Просмотров 126Год назад
History of 2nd Law of Thermodynamics Part 1 (ENSC111 - 09.01)
Sample Problems Energy Balance (ENSC111 - 07.03)
Просмотров 47Год назад
Sample Problems Energy Balance (ENSC111 - 07.03)
Sample Problems Energy Balance - (ENSC111 - 07.02)
Просмотров 67Год назад
Sample Problems Energy Balance - (ENSC111 - 07.02)
The General Energy Equation - (ENSC111 - 07.01)
Просмотров 78Год назад
The General Energy Equation - (ENSC111 - 07.01)
Determining percent error (ENSC111 - 04.03)
Просмотров 100Год назад
Determining percent error (ENSC111 - 04.03)
Properties of Ideal Gas (ENSC111 - 04.01)
Просмотров 141Год назад
Properties of Ideal Gas (ENSC111 - 04.01)
Using Property Tables (ENSC111 - 03.04)
Просмотров 153Год назад
Using Property Tables (ENSC111 - 03.04)
Using Property Tables (ENSC111 - 03.03)
Просмотров 195Год назад
Using Property Tables (ENSC111 - 03.03)
States, Regions, and Property Tables (ENSC111 - 03.02)
Просмотров 127Год назад
States, Regions, and Property Tables (ENSC111 - 03.02)
Pure Substance, & Phase Change (ENSC111 - 03.01)
Просмотров 119Год назад
Pure Substance, & Phase Change (ENSC111 - 03.01)
Thermodynamic Properties Part 2 (ENSC111 - 02.02)
Просмотров 84Год назад
Thermodynamic Properties Part 2 (ENSC111 - 02.02)
Thermodynamic Properties Part 1 (ENSC111 - 02.01)
Просмотров 158Год назад
Thermodynamic Properties Part 1 (ENSC111 - 02.01)
Introduction to Thermodynamics Part 2 (ENSC111 - 01.02)
Просмотров 92Год назад
Introduction to Thermodynamics Part 2 (ENSC111 - 01.02)
Introduction to Thermodynamics Part 1 (ENSC111 - 01.01)
Просмотров 213Год назад
Introduction to Thermodynamics Part 1 (ENSC111 - 01.01)
24 - Drawing Exercise 07B & 07C (ENSC102)
Просмотров 217Год назад
24 - Drawing Exercise 07B & 07C (ENSC102)
Impedance Sample Problems (ABE164 - 05.03)
Просмотров 179Год назад
Impedance Sample Problems (ABE164 - 05.03)
Single Phase AC Supply (ABE164 - 05.01)
Просмотров 130Год назад
Single Phase AC Supply (ABE164 - 05.01)
Hi, please share the PDF of the Fan performance curve
Have you got any reference books for explained concept? Thanks
the load side and capacity side is a concept that I used based from my civil engineering background... LRFD stuffs. Other than that, manufacturer's handbook or references are always practically helpful.
Thankyou sir
you're welcome Sir
Can you please share the name of the book that you use in this video?
Hello Sir/Ma'am, I prepared my own lecture materials for this. But usually, for material handling equipment, you can check the manufacturer's catalogs, or you may look for CEMA publications. I hope that helps!
Wow I am so glad I came across your video, I'm about to design a pneumatic conveyor for my organization, this helps a lot.
I am happy that you find the videos helpful. May God grant you success in your design endeavor. =)
Do you have a clear illustration?
What units do I use for the Marhur and Klinzing Equation for solid friction factor?
How can calculate the presion of the secrew
Which reference book used for this
Hello! I wrote to you a couple years back and here I am again! @29:00 you mention vacuum system needs higher velocities than pressure system, but the way you wrote the equation it should be the opposite? In my experience you are write that negative systems require higher velocities so the equation should be Ve(-) = 1.8*Ve(+)
hi, it's good to hear again from you. yes it's the opposite; what you have written is correct Ve(-)=1.8*Ve(+). should you need my lecture handout on that topic, just let me know your email.
You and your videos are underrated. I need some refresher and you saved my day.
i am happy to know that it helped you. =)
I work on conveyors in the mining sector. I appreciate your illustrations and technical know how.
thank you. thanks for appreciating.
Awesome video. What if we try to transport solids from outside where the pressure is atmospheric, inside a vessel with negative pressure, let's say ... -0.5 bar ?
What shall 2:55 be 2:55 of impeller if pipe inlet dia is 3 inch and motor rpm is 1,800rpm and what be the pressure,static pressure of the system,considering installation is 1m above sea level?
Do you have a formula or manual calculation formula?
yes, there is in succeeding parts. just checkout the playlist.
I appreciate your help in providing me a brief equation or rule of thumb to calculate the specific energy consumption as Kwh/Mt/Km , belt speed = 2.5 meter per second, trough angle = 30 , surcharge = 25, material = excavated soil (sand) , lump size less than 150 mm , density =1,550 kg/M3 , belt length = 5 Km (multiple flights ) , Flow = 3500 to 4,000 Mt/Hr , Route inclination= zero inclination, Width = 1,200 mm , considering these inputs , how much electricity will be consumed in electrical motor as Kwh per metric ton (Weight) per Km (distance)
Good explanation 😊
thank you sir. i appreciate it. =)
Horse power trick is interesting. For a vertical screw the cos(90)=0 then the HP is become infinite!! Anyway thank you for your time.
you're welcome. that's fascinating about mathematics. there's actually another one.. in electrical equations... P=V^2/R... a zero resistance will produce infinite power.
You can multiply the "Incline Factor" with the Capacity For example, in the GOST standard: 0 degree - c = 1 (Horizon) 5 degree - c = 0.9 10 degree - c = 0.8 15 degree - c = 0.7 20 degree - c = 0.65 So, with the incline the actual capacity of screw conveyor is lower than horizontal screw. This mean you re-choose lager Dia or speed to make sense (actual Cap = req Cap). Then you can calculate the HP
thank you sir, but for the references that you used like where those formulas come from? is it from a journal or from a book?
Hello. I dont remember exactly now. It's been years already since I taught that subject. Mostly I think comes from reports and/or journals available.
for computing water power why did you directly put the kW without canceling the length unit of meter?
the water hp is already a unit of power hence you just need the conversion of 746W/hp
Thank you very much for sharing your knowledge and experience.
you're welcome. =) Thanks for appreciating!
Thank you for your lectures. Just want to let you know, that your help is appreciated From Zambia, Africa.
you're welcome. i am glad that you appreciated it. =)
Thank you sir
you're welcome ma'am. =)
Thanks youtube for this gem
you're welcome =). thanks for appreciating.
What about the Elevation If screw conveyor Angle 45° The same formula Apply ??
Reviewing to figure out my HW! Thank you!!! TOTALLY cleared up my confusion around the hydrosstic equation(s)
You're welcome. I'm glad it helped you. =). Thank you also.
great lecture... Can I get the manuscript
Thank you. May I know where you will use the manuscript/lecture materials?
Sir, shouldn't we use 1.48/n for the constant since it's in english unit or is 1/ n still applicable?
Yes you're right. For english units that should be 1.48/n. Thank you!
What is the reference you used for the design calculation?
I think it's been more than a year already since the last time I taught this subject. If I remember correctly, you can refer to CEMA publications
such a horrible video!!!!!! the sound is horrible, delete this please, such a waste of time
Sir any further explaination in getting the value of t.....
i mistook it as the slope, but it should be the horizontal distance. since the side that we want is the diagonal distance (or hypotenuse). sorry about that. thanks for pointing out.
how about the materials to be conveyed like pellets is bagged. what is the computation of the conveyor capacity?
hello sir, i havent experienced yet designing conveying in bags. but i think the principle in capacity is the same... how many bags (or its kg equivalent) per hour do we want or can the machine do. then what comes into play is the physical properties (friction, width, etc.) of the bags rather than the bulk materials. another option we can always do is to consult/look at the manufacturer's catalogs. i hope that answers your question.
Hi, Thanks for the video. May I know how to compute for the stresses in a screw conveyor? Thank you so much
you're welcome. if you are interested in stresses, the simplest way is to assume a statically determinate situation but in 3D so that you can take into account the effect of combined loadings and get into the stress elements. if you anticipate some dynamic loadings in the system, then you have to take that into account by applying appropriate factors. you may want to visit my playlist on machine design if you like... ruclips.net/p/PLIwmhEE4g3TQAtoYjsqc3UHPzs1ftOEif.
hi po sir bayaw? pwdi po mahinge ung link , copy sa paes 303 2000 tnk u in advance
Hello Ma'am, here's the link... amtec.ceat.uplb.edu.ph/engineering-materials/
hi , do you the software for calculated the screw conveyor or simulation
Hello Sir, I did not use any software or simulation for this course.
why was this recommended to me
13:49 I think there is a mistake. You have used Vs = 10.34 m/s for positive pressure conveyance when calculating the K factor. Should be used 20.68 m/s instead, for negative pressure conveyance?
THANK YOU SIR!
You're welcome. =)
Is there software to calculate and design it?
I believe there are softwares available for pneumatic calculations. But the method may not be exactly the same.
PneuCalc
Good evening My name is Maicon Jefferson, I from Brazil your material is very good, I'd like to make download this book, is it possible? Thanks.....
Hello sir! I appreciate that you like it. It's not actually a book yet. It's just my lecture handouts I used for my class. What do you like about it specifically?
I have an inclined pipe pneumatic conveyer. I'm wondering how can I calculate L. Should I consider it as a horizontal and a vertical pipe? Or I should just add the length of the inclined pipe + k for 45 degree elbow? Thanks,
you should take the inclined distance. the k value will depend upon your type of fitting if it's 45 or 60 or whatever.
It was very useful...easy to understand Thanks for sharing such a good video.
you're welcome =). i'm glad you liked it.
thankyou
you're welcome =).
Can you do step by step solving for the 316.2m?
hello sir, here it is... x=sqrt(100/0.001)=316.2. i hope that helps
Can you share the book resources?!
hello sir/ma'am. the main reference that i used for this is the ASABE Standards.
@@sirby_lectures That's great!! Thank you (y)
I am still going through this and making an Excel file out of it if you are interested. As someone else pointed out in the comments for the Saltation velocity I get 23.8m/s compared to your 10.34m/s. I get the same values for gamma and beta though. Here is my calculation below maybe I am mixing values or maybe you made a mistake ;) Usalt = ((4*(1000/3600)*10^2.176*9.81^2.665*0.075^(2.665/2-2))/(pi*1.18))^(1/3.665) (you can copy paste into WolframAlpha) Cheers!
As I was reviewing my lecture handouts, I've found that I forgot to write that the exponent of 9.81 should be 2.665/2. ((4*(1000/3600)*10^2.176*9.81^2.665/2*0.075^(2.665/2-2))/(pi*1.18))^(1/3.665) Sorry about that mistake. The exponent has to be divided by 2. With regard to your excel file, sure, I'm interested! I'm actually amazed that you and many others have find this helpful/interesting. Especially you, that you want to make a program out of it. It's been more than a year already since I teach this course. Originally the course wasn't about design, but I just oriented it toward design applications.
@@sirby_lectures Thanks for clarifying this :) It works now!
I see that you are not using the iterative approach as suggested in A.T. Agarwal, 2005. Aren’t you concerned that as gas expands along the pipeline, velocity increases? Therefore by using Usalt as your average velocity, your total pressure drop is actually lower than it should be. Usalt should only be used as Vinitial from what I understand. I guess your method still gives a good approximation though. Thanks for the videos, super helpful!
Thanks for bringing that up. I haven't thought of the relationship of the gas expansion and the pressure drop. I do believe that would really matter if we go into the details. However, in the context of engineering design and having a lot of constraints to fully understand everything in a given time, I always think of the computed value as a range especially for such system as this without codes/standards like that of structural design, or design of pressure vessels, or none that I know of so far. So I always expect for some deviations. Of course the lesser the deviation, the better. But I'll look into that gas expansion when I encounter this course/project once again. You're welcome, and thank you too. =)
great video
thanks! =)
Thank you for sharing sir. May I know where did you get your formulas? Or standards? Or any books to recommend for designing?
you're welcome. with regard to standards, i suggest the CEMA publications for material handling equipment. but you can also find a wealth of information in manufacturer's catalog. Another one is, since bucket elevators are common equipment in postharvest processing technology, then you can check postharvest technology handbooks/textbooks as well. Lastly, books in unit operations in chemical engineering also includes that topic.
Thank you so much sir...
Hi sir, I think W2 should be 0.0104 not 0.014 that is why it does not fit. Therefore, W3 = [(0.6) (0.0084) + (0.23) (0.0104)] / 0.83 = 0.0089542168674 = 0.009 0.009 will fit
good point. you're right. thanks!