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Be Maths Solution
Индия
Добавлен 15 июн 2023
🚾 𝓣𝓱𝓪𝓷𝓴 𝔂𝓸𝓾 𝓼𝓸 𝓶𝓾𝓬𝓱 𝓯𝓸𝓻 𝓢𝓾𝓹𝓹𝓸𝓻𝓽 🚾
Hello friends
Welcome to my channel : -
"Be Maths Solution"
📖🖋🧮📝
जीवन एक गणित है।...!!
सांसे घटती रहती हैं अनुभव जुड़ते रहते हैं।....!!
हम अलग अलग पद समीकरण बुनते रहते हैं।.....!!
तो कभी गुणा तो कभी भाग लगाते रहते हैं।.......!!
लेकिन अन्तिम सत्य शून्य ही है।..!!
Learning is a lifelong voyage, and every day offers a chance to acquire something new. Welcome to this channel, where we come together to explore fresh ideas, techniques, and Math Concepts spanning from the basic to the advanced. Engaging in daily Learning enhances our mental prowess, fosters logical thinking, and equips us to tackle challenges effectively. !!
Feel free to suggest any Math topics you'd like us to cover. Your support is greatly appreciated, and we thank you for being a part of our journey.!!
#BeMathsSolution
{For any business enquiry}
:- bemathsssolution@gmail.com
Thank you ❤️
Hello friends
Welcome to my channel : -
"Be Maths Solution"
📖🖋🧮📝
जीवन एक गणित है।...!!
सांसे घटती रहती हैं अनुभव जुड़ते रहते हैं।....!!
हम अलग अलग पद समीकरण बुनते रहते हैं।.....!!
तो कभी गुणा तो कभी भाग लगाते रहते हैं।.......!!
लेकिन अन्तिम सत्य शून्य ही है।..!!
Learning is a lifelong voyage, and every day offers a chance to acquire something new. Welcome to this channel, where we come together to explore fresh ideas, techniques, and Math Concepts spanning from the basic to the advanced. Engaging in daily Learning enhances our mental prowess, fosters logical thinking, and equips us to tackle challenges effectively. !!
Feel free to suggest any Math topics you'd like us to cover. Your support is greatly appreciated, and we thank you for being a part of our journey.!!
#BeMathsSolution
{For any business enquiry}
:- bemathsssolution@gmail.com
Thank you ❤️
Japan | A Nice Math Olympiad Exponential Problem | 2^a+2^-a=4 | Find a=? | How to solve?#math
Japan | A Nice Math Olympiad Exponential Problem #math #mathematics #exponents #ExponentialEquation
This is an interesting question with amazing Concepts!
-----------------------------Description 👇--------------------------
✍️ Discover 🤔 Explore a fascinating problem from a Math Olympiad in Japan! The 2^a + 2^-a =4 challenges your understanding of exponential functions and equations. In this video/article, we'll dive into a step-by-step solution and uncover the value of a Perfect for math enthusiasts, students preparing for contests, and anyone who loves a good brain-teaser. Let’s solve it together!
.........................................................................
Hello! My Dear You T...
This is an interesting question with amazing Concepts!
-----------------------------Description 👇--------------------------
✍️ Discover 🤔 Explore a fascinating problem from a Math Olympiad in Japan! The 2^a + 2^-a =4 challenges your understanding of exponential functions and equations. In this video/article, we'll dive into a step-by-step solution and uncover the value of a Perfect for math enthusiasts, students preparing for contests, and anyone who loves a good brain-teaser. Let’s solve it together!
.........................................................................
Hello! My Dear You T...
Просмотров: 282
Видео
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? = sqrt( 17 ) - 4 > 0 <= 17 > 16
log(a*b)=log(a)+log(b)≠ log(a+b) Check please!
🎉thanks
👍 t = 2^a => t^2 - 4t + 1 = 0 t^2 - 4t + 4 = 3 ( t - 2 )^2 = 3 ... t = 2 +/- sqrt( 3 ) > 0 2^a = 2 +/- sqrt( 3 ) a = [ ln( 2 +/- sqrt( 3 ) ) ]/ln( 2 ) 😊👍👋
Thanks. So simple
Thanks alot❤
√8/2=√2 √2*√2=2 Answer B
3 sqrt( a ) ÷ a = k ; a , k > 0 3 sqrt ( a ) = a k 3 sqrt( a ) - a k = 0 [ 3 - k sqrt( a ) ] sqrt( a ) = 0 1) sqrt( a ) = 0 => a = 0 n.o.k. 2) 3 - k sqrt( a ) = 0 => a = ( 3/k )^2 😊👍👋
5
We cant assuume the answer is equal to 1 though