CoA Physics
CoA Physics
  • Видео 1 658
  • Просмотров 151 255

Видео

Physics 4A - Derivation of Relative Velocity Relationship (Elastic Collision)
Просмотров 62 часа назад
Recording from Fall 2024 PHYS 4A class
Physics 4B - Problem Solving with ChatGPT 4o - Set 8
Просмотров 1316 часов назад
Recording from Fall 2024 PHYS 4B class
Physics 4B - Problem Solving with ChatGPT 4o - Set 7
Просмотров 1719 часов назад
Recording from Fall 2024 PHYS 4B class
Physics 4A - Problem Solving with ChatGPT 4o - Set 7
Просмотров 4414 дней назад
Recording from Fall 2024 PHYS 4A class
Physics 4B - Electrostatics Multiple Choice Timed Assessment Demos 3 (with ChatGPT 4o) and 4 (w/o)
Просмотров 1014 дней назад
Recording from Fall 2024 PHYS 4B class
Physics 4B - Electrostatics Freeform Timed Assessment Demo - Conducting Plates
Просмотров 2014 дней назад
Recording from Fall 2024 PHYS 4B class
Physics 4A - Problem Solving with ChatGPT 4o - Set 6
Просмотров 2621 день назад
Recording from Fall 2024 PHYS 4A class
Physics 4B - Problem Solving with ChatGPT 4o - Set 6
Просмотров 2521 день назад
Recording from Fall 2024 PHYS 4B class
Physics 4B - OpenStax University Physics Vol 2, Chapter 7, Problems 36, 40, 63, and 81
Просмотров 3121 день назад
Recording from Fall 2024 PHYS 4B class
Physics 4B - OpenStax University Physics Vol 2, Chapter 8, Problems 25, 26, and 28
Просмотров 1821 день назад
Recording from Fall 2024 PHYS 4B class
Physics 4B - OpenStax University Physics Vol 2, Chapter 8, Problems 21 and 41
Просмотров 3021 день назад
Recording from Fall 2024 PHYS 4B class
Physics 4A - Chapter 9 Overview
Просмотров 4321 день назад
Recording from Fall 2024 PHYS 4A class
Physics 4B - Problem Solving with ChatGPT 4o - Set 5
Просмотров 5228 дней назад
Recording from Fall 2024 PHYS 4B class
Physics 4A - Forces Freeform Timed Assessment - Inclined plane and two masses (Portable TA 9-5)
Просмотров 27Месяц назад
Recording from Fall 2024 PHYS 4A class
Physics 4A - Forces Multiple Choice Timed Assessment Demos 3 (with ChatGPT 4o) and 4 (without)
Просмотров 25Месяц назад
Physics 4A - Forces Multiple Choice Timed Assessment Demos 3 (with ChatGPT 4o) and 4 (without)
Physics 4A - Chapter 8 Overview
Просмотров 25Месяц назад
Physics 4A - Chapter 8 Overview
Physics 4A - Problem Solving with ChatGPT 4o - Set 5
Просмотров 18Месяц назад
Physics 4A - Problem Solving with ChatGPT 4o - Set 5
Physics 4B - Problem Solving with ChatGPT 4o - Set 4
Просмотров 20Месяц назад
Physics 4B - Problem Solving with ChatGPT 4o - Set 4
Physics 4A - Chapter 7 Overview
Просмотров 13Месяц назад
Physics 4A - Chapter 7 Overview
Physics 4B - Problem Solving with ChatGPT 4o - Set 1
Просмотров 50Месяц назад
Physics 4B - Problem Solving with ChatGPT 4o - Set 1
Physics 4A - Problem Solving with ChatGPT 4o - Set 4
Просмотров 68Месяц назад
Physics 4A - Problem Solving with ChatGPT 4o - Set 4
Physics 4B - Online Orientation Session
Просмотров 16Месяц назад
Physics 4B - Online Orientation Session
Physics 4A - Chapter 6 Overview, Part 2
Просмотров 39Месяц назад
Physics 4A - Chapter 6 Overview, Part 2
Physics 4A - Motion Multiple Choice Timed Assessment Demos 5 (with ChatGPT 4o) and 6 (without)
Просмотров 6Месяц назад
Physics 4A - Motion Multiple Choice Timed Assessment Demos 5 (with ChatGPT 4o) and 6 (without)
Physics 4A - Problem Solving with ChatGPT 4o - Set 3
Просмотров 11Месяц назад
Physics 4A - Problem Solving with ChatGPT 4o - Set 3
Physics 4A - Chapter 6 Overview, Part 1
Просмотров 29Месяц назад
Physics 4A - Chapter 6 Overview, Part 1
Physics 4A - Problem Solving with ChatGPT 4o - Set 2
Просмотров 28Месяц назад
Physics 4A - Problem Solving with ChatGPT 4o - Set 2
Physics 4A - Chapter 5 Overview
Просмотров 39Месяц назад
Physics 4A - Chapter 5 Overview
Physics 4A - Online Orientation Session (Fall 2024, reference only, extra long)
Просмотров 142 месяца назад
Physics 4A - Online Orientation Session (Fall 2024, reference only, extra long)

Комментарии

  • @hunterrhodes137
    @hunterrhodes137 7 дней назад

    Thank you for breaking this question down into easy steps. Your tips for understanding how to solve the question are very helpful.

  • @terryxd-wq3kx
    @terryxd-wq3kx 22 дня назад

    Can you help me with one exercise 😢 it is about stading waves with complex numbers

  • @terryxd-wq3kx
    @terryxd-wq3kx 22 дня назад

    I need help With one exercise

  • @stressqueen1403
    @stressqueen1403 Месяц назад

    you saved me <3

  • @kathiravanpalaniswamy8062
    @kathiravanpalaniswamy8062 4 месяца назад

    wher can i get this apparatus?

    • @CoAPhysics
      @CoAPhysics 4 месяца назад

      A number of physics instructional supplies vendors carry "heat engine apparatus". It looks like what PASCO carries (www.pasco.com/products/lab-apparatus/thermodynamics/heat-engine/td-8572a) is similar to the one shown in this demo (but not the exact same model; the model I'm showing pre-dates me and I'm not sure where we purchased it from).

    • @kathiravanpalaniswamy8062
      @kathiravanpalaniswamy8062 4 месяца назад

      @@CoAPhysics oh ok thank you sir

  • @Ohhellyeahhyunjinforever
    @Ohhellyeahhyunjinforever 4 месяца назад

    Thank you for explaining this sir my highschool teacher couldn't even compare to this 😅😅

  • @zeynep9328
    @zeynep9328 4 месяца назад

    Thank youu,it is pretty helpful <3

  • @ZaraAxelrod
    @ZaraAxelrod 5 месяцев назад

    Part d, the lab frame measures an elongated time (moving clocks are slow) of 10^-6 microseconds. Gamma is 3.2. The particle is at rest with respect to itself, so proper time Tau = (10^-6 microseconds)/3.2. Am I wrong?

    • @CoAPhysics
      @CoAPhysics 5 месяцев назад

      Oops. I think in 37:25, I misread the given time as proper time instead of being lab time. Yes, with the correct reading of 1 microS as being the lab time, the proper time would be *shorter* by the Lorentz factor. I'll pin this comment.

  • @carsmiles4035
    @carsmiles4035 5 месяцев назад

    Thank you so much for posting these videos! I have been watching over 40 videos and it is helping me a lot with physics!

  • @ZaraAxelrod
    @ZaraAxelrod 5 месяцев назад

    Yikes!

  • @ZaraAxelrod
    @ZaraAxelrod 5 месяцев назад

    It's really hard to understand part c. 35:15

    • @CoAPhysics
      @CoAPhysics 5 месяцев назад

      I'm using Lorentz transformation, using the fact that energy and momentum form a 4-vector that transforms the same way time and position coordinates do. I start with the energy-momentum 4-vector in the center of momentum frame (which is pretty simple) and transform that into the reference frame that is moving at 0.95c relative to the center of momentum frame.

  • @sima1939
    @sima1939 5 месяцев назад

    thankss

  • @ldhfpqjojjvjweojj
    @ldhfpqjojjvjweojj 5 месяцев назад

    idk what is this, i came by mistake...

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    yes "de Broy" ruclips.net/video/k45IZDkg2Pg/видео.htmlsi=1_YHzAd2KQat0bCO

    • @CoAPhysics
      @CoAPhysics 6 месяцев назад

      I think it depends on the dialect: www.physicsforums.com/threads/how-does-one-pronounce-de-broglie.236070/post-1736706 I will say that "de Broy" is the most common pronunciation I heard from my teachers, and in any case, there's no pronunciation police.

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    18:31 I need help understanding Question 7

    • @CoAPhysics
      @CoAPhysics 6 месяцев назад

      The two points given---(2 muS, 100 m) and (4 muS, 280 m)---are separated "time-like". What that means is when you calculate "c*Delta t" (here, with the numbers given, about 600 meters), that value is greater than "Delta x" (180 meters). When two spacetime coordinates have a time-like separation, there can be a causal connection between them (something traveling at the speed of light or slower can go through two coordinates), and in no inertial reference frame would two coordinates be "simultaneous" (i.e. have the same value for time coordinate).

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    Similar demonstration I found helpful: ruclips.net/video/v-1zjdUTu0o/видео.htmlsi=nYlWP2nyxzk9bfL4

    • @ZaraAxelrod
      @ZaraAxelrod 6 месяцев назад

      Oh, I see this is the same clip you originally used.

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    I don't know how to explain this... in part (a) the calculations make enough sense to me and I see how we found beta, but the setup is meaningless to me. "In the lab reference frame not all kinetic energy can be turned into rest energy because the total momentum needs to be conserved, but in the 'center-of-momentum' reference frame (where total momentum = 0), all the kinetic energy can be turned into rest energy." That means absolutely nothing to me. Where are we getting these ideas about conservation? Why does total momentum = 0 in the center of momentum reference frame?

    • @CoAPhysics
      @CoAPhysics 6 месяцев назад

      Answering last question first: (1) total momentum = 0 in the center of momentum frame because that's how we define it---of all the different inertial reference frames where total momentum can take many different values, the "center of momentum" frame is the one inertial reference frame where the total momentum is equal to zero (by definition). (2) In the center of momentum frame, because the total momentum is equal to zero, you can have a state with all particles at rest (i.e. no kinetic energy) that is consistent with conservation of momentum (everything is at rest, no momentum, no kinetic energy). However, in other reference frames, where the total momentum is not equal to zero, you cannot have a state with all particles at rest, because having all particles at rest would mean zero total momentum (contradicted by not being in the center of momentum frame). (3) That's why it says "in the lab reference frame, not all kinetic energy can be turned into rest energy", because turning all kinetic energy into rest energy (i.e. no kinetic energy remaining in the final state) would require total momentum to be zero, and in the lab reference frame, the total momentum is not zero.

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    This makes no sense to me.

    • @CoAPhysics
      @CoAPhysics 6 месяцев назад

      One thing I'll say about derivation of relativistic momentum is, well, the result is a lot simpler than the derivation. So, if you simply remember p = gamma*m*v and use it, you'll be fine. (Also, the OpenStax textbook has its own derivation, which *I* consider to be flawed, but it may still be a good enough way to remember how to obtain the correct formula for the relativistic momentum.)

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    7:38 What is v_0?

    • @CoAPhysics
      @CoAPhysics 6 месяцев назад

      v_0 is just the initial velocity of ball B. The only necessary criterion here is that it's a non-relativistic amount of velocity, so that we can correctly approximate momentum of ball B with non-relativistic expressions.

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    d. is gamma*beta*(1 meter)/c

  • @ZaraAxelrod
    @ZaraAxelrod 6 месяцев назад

    Sage tripped out when I wrote sol = _[0]

    • @CoAPhysics
      @CoAPhysics 6 месяцев назад

      Using underscore to refer to the previous output is probably a syntax specific to the interactive environment. If you are using Sage Math Cell (which technically isn't interactive), instead you need to store outputs into variable explicitly in order to be able to refer to it later. For example, where I have just "solve(eq,v)" you need to write it as "sols=solve(eq,v)", storing the output into a "sols" variable. And in the next line, instead of "sol=_[0]", you would write it as "sol=sols[0]".

  • @ZaraAxelrod
    @ZaraAxelrod 7 месяцев назад

    37:35 m1 = -1/2 because the f1s cancel?

    • @CoAPhysics
      @CoAPhysics 7 месяцев назад

      Oh, yes, that's correct. Thank you for catching that error; with "-f1/2", the units won't make sense.

  • @joesnome
    @joesnome 8 месяцев назад

    İyi günler öğretmenim. Algoodo programında bu eğimli şekli nasıl oluşturuyoruz? Yardımcı olur musunuz?

  • @matijabreljak9947
    @matijabreljak9947 8 месяцев назад

    you can integrate it like k*σ*dS/sqrt(r^2 + l^2) while S = dθ*r^2 so dS = 2dθdr. k*σ * (Int 0 to 2π) dθ (Int 0 to +inf)dr*2r*l/(r^2+l^2)^(3/2)

  • @marcossidoruk8033
    @marcossidoruk8033 9 месяцев назад

    This has nothing to do with relativity. Classically, if the characteristic lengths and times of the rigid body are comparable to the speed of sound in the material the rigid body approximation doesn't work, and since molecular forces are EM the speed of light is the natural upper bound for the speed of sound in the material. Also the example being made here is kinda bullshit, there is nothing wrong kinematically with something moving faster than the speed of light, no contradiction is found in the spinning rod example. However, what is shown to be not possible from the equations of special relativity is to accelerate a body past the speed of light, wich has not been shown here to be impied possible by the rigid body assumption.

  • @TheDavidlloydjones
    @TheDavidlloydjones 9 месяцев назад

    I'm not going to watch this. But if there were no air resistance you've gotta wonder how that balloon is 100 metres "in the air."

    • @CoAPhysics
      @CoAPhysics 9 месяцев назад

      Hot air balloon works by buoyancy force; air resistance is given by the drag force. Given the different physical origin, there can be a set of parameters where air resistance is negligible (i.e. low speeds) while buoyancy force is not (also, buoyancy force on the *ball* would still be negligible; it's buoyancy force on the hot air balloon that is not negligible). And, this is lower-division physics; the point is to handle simple systems (sometimes using approximations that are not entirely realistic) that beginning students can learn to handle.

  • @cozumel5608
    @cozumel5608 10 месяцев назад

    thanks king

  • @umangsaini8559
    @umangsaini8559 11 месяцев назад

    Very under rated video. I was brain storming the 2 concepts, had an intuition that they might be related. And search it on youtube. The only video I found related to it is provided by you only. Thanks a lot🙂

  • @TheLoudButton
    @TheLoudButton 11 месяцев назад

    Thank you, sir. You saved me :)

  • @LanPham-l1j
    @LanPham-l1j 11 месяцев назад

    thank for your lesson that help a lot

  • @leonardolimadesouzalopes2007

    Thank you for this video

  • @goated9415
    @goated9415 Год назад

    what do you do if there is an I5 but no R5?

    • @CoAPhysics
      @CoAPhysics Год назад

      If by "no R5" you meant R5 is zero, then the exact same approach and equations can be used (just set R5=0; the circuit can actually be simplified further, but that isn't necessary for solution). If by "no R5" you mean R5 has an unknown value, this setup is underspecified, because all the loop-rule equations we can get are necessary to solve for V1, V2, and R4 (and none of the junction rule equations we could write down actually help with solving for R5; they just tell us the values of currents that we already know anyway).

    • @goated9415
      @goated9415 Год назад

      @@CoAPhysics the R5 just is not there. There is an I5 going in the direction of the battery but no R5. I am referring to OpenStax University Physics Vol 2, Chapter 10, Problem 41. When in a situation like this, do I just assume R5=0?

    • @CoAPhysics
      @CoAPhysics Год назад

      @@goated9415 That's an entirely different problem; you have to do the analysis again from scratch, using Kirchhoff's rules (both the junction rule and loop rule; you should have 5 equations to solve for 5 unknown currents). There are lectures on application of Kirchhoff's rules that might help you.

    • @goated9415
      @goated9415 Год назад

      @@CoAPhysics doesnt the amount of equations depend on how many loops there are? I used the laws and put together only 3 equations (since there are three loops in this question much like problem you did in the video) , so im not sure how I can get 5.

    • @CoAPhysics
      @CoAPhysics Год назад

      @@goated9415 ​ You have 3 loop rule equations and 2 junction rule equations. In the situation in the video, the two junction rule equations were unnecessary because the system was overspecified (the currents that don't need to be given were given by the problem). A system that is exactly specified (e.g. Problem 41) will need the junction rule equations written down as well.

  • @lucasaugusto5735
    @lucasaugusto5735 Год назад

    thanks for the explanation!

  • @SpotterVideo
    @SpotterVideo Год назад

    Conservation of Spatial Curvature (both Matter and Energy described as "Quanta" of Spatial Curvature) Is there an alternative interpretation of "Asymptotic Freedom"? What if Quarks are actually made up of twisted tubes which become physically entangled with two other twisted tubes to produce a proton? Instead of the Strong Force being mediated by the exchange of gluons, it would be mediated by the physical entanglement of these twisted tubes. When only two twisted tubules are entangled, a meson is produced which is unstable and rapidly unwinds (decays) into something else. A proton would be analogous to three twisted rubber bands becoming entangled and the "Quarks" would be the places where the tubes are tangled together. The behavior would be the same as rubber balls (representing the Quarks) connected with twisted rubber bands being separated from each other or placed closer together producing the exact same phenomenon as "Asymptotic Freedom" in protons and neutrons. The force would become greater as the balls are separated, but the force would become less if the balls were placed closer together. ------------------------ String Theory was not a waste of time, because Geometry is the key to Math and Physics. However, can we describe Standard Model interactions using only one extra spatial dimension? What if we describe subatomic particles as spatial curvature, instead of trying to describe General Relativity as being mediated by particles? Quantum Entangled Twisted Tubules: “We are all agreed that your theory is crazy. The question which divides us is whether it is crazy enough to have a chance of being correct.” Neils Bohr (lecture on a theory of elementary particles given by Wolfgang Pauli in New York, c. 1957-8, in Scientific American vol. 199, no. 3, 1958) The following is meant to be a generalized framework for an extension of Kaluza-Klein Theory. Does it agree with the “Twistor Theory” of Roger Penrose? During the early history of mankind, the twisting of fibers was used to produce thread, and this thread was used to produce fabrics. The twist of the thread is locked up within these fabrics. Is matter made up of twisted 3D-4D structures which store spatial curvature that we describe as “particles"? Are the twist cycles the "quanta" of Quantum Mechanics? When we draw a sine wave on a blackboard, we are representing spatial curvature. Does a photon transfer spatial curvature from one location to another? Wrap a piece of wire around a pencil and it can produce a 3D coil of wire, much like a spring. When viewed from the side it can look like a two-dimensional sine wave. You could coil the wire with either a right-hand twist, or with a left-hand twist. Could Planck's Constant be proportional to the twist cycles. A photon with a higher frequency has more energy. ( E=hf, More spatial curvature as the frequency increases = more Energy ). What if gluons are actually made up of these twisted tubes which become entangled with other tubes to produce quarks. (In the same way twisted electrical extension cords can become entangled.) Therefore, the gluons are a part of the quarks. Quarks cannot exist without gluons, and vice-versa. Mesons are made up of two entangled tubes (Quarks/Gluons), while protons and neutrons would be made up of three entangled tubes. (Quarks/Gluons) The "Color Force" would be related to the XYZ coordinates (orientation) of entanglement. "Asymptotic Freedom", and "flux tubes" are logically based on this concept. The Dirac “belt trick” also reveals the concept of twist in the ½ spin of subatomic particles. If each twist cycle is proportional to h, we have identified the source of Quantum Mechanics as a consequence twist cycle geometry. Modern physicists say the Strong Force is mediated by a constant exchange of Mesons. The diagrams produced by some modern physicists actually represent the Strong Force like a spring connecting the two quarks. Asymptotic Freedom acts like real springs. Their drawing is actually more correct than their theory and matches perfectly to what I am saying in this model. You cannot separate the Gluons from the Quarks because they are a part of the same thing. The Quarks are the places where the Gluons are entangled with each other. Neutrinos would be made up of a twisted torus (like a twisted donut) within this model. The twist in the torus can either be Right-Hand or Left-Hand. Some twisted donuts can be larger than others, which can produce three different types of neutrinos. If a twisted tube winds up on one end and unwinds on the other end as it moves through space, this would help explain the “spin” of normal particles, and perhaps also the “Higgs Field”. However, if the end of the twisted tube joins to the other end of the twisted tube forming a twisted torus (neutrino), would this help explain “Parity Symmetry” violation in Beta Decay? Could the conversion of twist cycles to writhe cycles through the process of supercoiling help explain “neutrino oscillations”? Spatial curvature (mass) would be conserved, but the structure could change. Gravity is a result of a very small curvature imbalance within atoms. (This is why the force of gravity is so small.) Instead of attempting to explain matter as "particles", this concept attempts to explain matter more in the manner of our current understanding of the space-time curvature of gravity. If an electron has qualities of both a particle and a wave, it cannot be either one. It must be something else. Therefore, a "particle" is actually a structure which stores spatial curvature. Can an electron-positron pair (which are made up of opposite directions of twist) annihilate each other by unwinding into each other producing Gamma Ray photons? Does an electron travel through space like a threaded nut traveling down a threaded rod, with each twist cycle proportional to Planck’s Constant? Does it wind up on one end, while unwinding on the other end? Is this related to the Higgs field? Does this help explain the strange ½ spin of many subatomic particles? Does the 720 degree rotation of a 1/2 spin particle require at least one extra dimension? Alpha decay occurs when the two protons and two neutrons (which are bound together by entangled tubes), become un-entangled from the rest of the nucleons . Beta decay occurs when the tube of a down quark/gluon in a neutron becomes overtwisted and breaks producing a twisted torus (neutrino) and an up quark, and the ejected electron. The phenomenon of Supercoiling involving twist and writhe cycles may reveal how overtwisted quarks can produce these new particles. The conversion of twists into writhes, and vice-versa, is an interesting process. Gamma photons are produced when a tube unwinds producing electromagnetic waves. >>>>>>>>>>>>>>>>>>>>>> Within this model a black hole could represent a quantum of gravity, because it is one cycle of spatial gravitational curvature. Therefore, instead of a graviton being a subatomic particle it could be considered to be a black hole. The overall gravitational attraction would be caused by a very tiny curvature imbalance within atoms. We know there is an unequal distribution of electrical charge within each atom because the positive charge is concentrated within the nucleus, even though the overall electrical charge of the atom is balanced by equal positive and negative charge. >>>>>>>>>>>>>>>>>>>>>> In this model Alpha equals the compactification ratio within the twistor cone, which is approximately 1/137. 1= Hypertubule diameter at 4D interface 137= Cone’s larger end diameter at 3D interface where the photons are absorbed or emitted. The 4D twisted Hypertubule gets longer or shorter as twisting or untwisting occurs. (720 degrees per twist cycle.) >>>>>>>>>>>>>>>>>>>>>>> How many neutrinos are left over from the Big Bang? They have a small mass, but they could be very large in number. Could this help explain Dark Matter? >>>>>>>>>>>>>>>>>>>>>>>> Why did Paul Dirac use the twist in a belt to help explain particle spin? Is Dirac’s belt trick related to this model? Is the “Quantum” unit based on twist cycles? ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ I started out imagining a subatomic Einstein-Rosen Bridge whose internal surface is twisted with either a Right-Hand twist, or a Left-Hand twist. The model grew out of that simple idea. I was also trying to imagine a way to stuff the curvature of a 3 D sine wave into subatomic particles. .

  • @SpotterVideo
    @SpotterVideo Год назад

    Is there an alternative interpretation of "Asymptotic Freedom"? What if Quarks are actually made up of twisted tubes which become physically entangled with two other twisted tubes to produce a proton? Instead of the Strong Force being mediated by the exchange of gluons, it would be mediated by the physical entanglement of these twisted tubes. When only two twisted tubules are entangled, a meson is produced which is unstable and rapidly unwinds (decays) into something else. A proton would be analogous to three twisted rubber bands becoming entangled and the "Quarks" would be the places where the tubes are tangled together. The behavior would be the same as rubber balls (representing the Quarks) connected with twisted rubber bands being separated from each other or placed closer together producing the exact same phenomenon as "Asymptotic Freedom" in protons and neutrons. The force would become greater as the balls are separated, but the force would become less if the balls were placed closer together. ------------------------ String Theory was not a waste of time. Geometry is the key to Math and Physics. What if we describe subatomic particles as spatial curvature, instead of trying to describe General Relativity as being mediated by particles? Quantum Entangled Twisted Tubules: “We are all agreed that your theory is crazy. The question which divides us is whether it is crazy enough to have a chance of being correct.” Neils Bohr (lecture on a theory of elementary particles given by Wolfgang Pauli in New York, c. 1957-8, in Scientific American vol. 199, no. 3, 1958) The following is meant to be a generalized framework for an extension of Kaluza-Klein Theory. Does it agree with the “Twistor Theory” of Roger Penrose? During the early history of mankind, the twisting of fibers was used to produce thread, and this thread was used to produce fabrics. The twist of the thread is locked up within these fabrics. Is matter made up of twisted 3D-4D structures which store spatial curvature that we describe as “particles"? Are the twist cycles the "quanta" of Quantum Mechanics? When we draw a sine wave on a blackboard, we are representing spatial curvature. Does a photon transfer spatial curvature from one location to another? Wrap a piece of wire around a pencil and it can produce a 3D coil of wire, much like a spring. When viewed from the side it can look like a two-dimensional sine wave. You could coil the wire with either a right-hand twist, or with a left-hand twist. Could Planck's Constant be proportional to the twist cycles. A photon with a higher frequency has more energy. ( E=hf, More spatial curvature as the frequency increases = more Energy ). What if gluons are actually made up of these twisted tubes which become entangled with other tubes to produce quarks. (In the same way twisted electrical extension cords can become entangled.) Therefore, the gluons are a part of the quarks. Quarks cannot exist without gluons, and vice-versa. Mesons are made up of two entangled tubes (Quarks/Gluons), while protons and neutrons would be made up of three entangled tubes. (Quarks/Gluons) The "Color Force" would be related to the XYZ coordinates (orientation) of entanglement. "Asymptotic Freedom", and "flux tubes" are logically based on this concept. The Dirac “belt trick” also reveals the concept of twist in the ½ spin of subatomic particles. If each twist cycle is proportional to h, we have identified the source of Quantum Mechanics as a consequence twist cycle geometry. Modern physicists say the Strong Force is mediated by a constant exchange of Mesons. The diagrams produced by some modern physicists actually represent the Strong Force like a spring connecting the two quarks. Asymptotic Freedom acts like real springs. Their drawing is actually more correct than their theory and matches perfectly to what I am saying in this model. You cannot separate the Gluons from the Quarks because they are a part of the same thing. The Quarks are the places where the Gluons are entangled with each other. Neutrinos would be made up of a twisted torus (like a twisted donut) within this model. The twist in the torus can either be Right-Hand or Left-Hand. Some twisted donuts can be larger than others, which can produce three different types of neutrinos. Gravity is a result of a very small curvature imbalance within atoms. (This is why the force of gravity is so small.) Instead of attempting to explain matter as "particles", this concept attempts to explain matter more in the manner of our current understanding of the space-time curvature of gravity. If an electron has qualities of both a particle and a wave, it cannot be either one. It must be something else. Therefore, a "particle" is actually a structure which stores spatial curvature. Can an electron-positron pair (which are made up of opposite directions of twist) annihilate each other by unwinding into each other producing Gamma Ray photons? Does an electron travel through space like a threaded nut traveling down a threaded rod, with each twist cycle proportional to Planck’s Constant? Does it wind up on one end, while unwinding on the other end? Is this related to the Higgs field? Does this help explain the strange ½ spin of many subatomic particles? Does the 720 degree rotation of a 1/2 spin particle require at least one extra dimension? Alpha decay occurs when the two protons and two neutrons (which are bound together by entangled tubes), become un-entangled from the rest of the nucleons . Beta decay occurs when the tube of a down quark/gluon in a neutron becomes overtwisted and breaks producing a twisted torus (neutrino) and an up quark, and the ejected electron. The phenomenon of Supercoiling involving twist and writhe cycles may reveal how overtwisted quarks can produce these new particles. The conversion of twists into writhes, and vice-versa, is an interesting process. Gamma photons are produced when a tube unwinds producing electromagnetic waves. >>>>>>>>>>>>>>>>>>>>>> Within this model a black hole could represent a quantum of gravity, because it is one cycle of spatial gravitational curvature. Therefore, instead of a graviton being a subatomic particle it could be considered to be a black hole. The overall gravitational attraction would be caused by a very tiny curvature imbalance within atoms. We know there is an unequal distribution of electrical charge within each atom because the positive charge is concentrated within the nucleus, even though the overall electrical charge of the atom is balanced by equal positive and negative charge. >>>>>>>>>>>>>>>>>>>>>> In this model Alpha equals the compactification ratio within the twistor cone, which is approximately 1/137. 1= Hypertubule diameter at 4D interface 137= Cone’s larger end diameter at 3D interface where the photons are absorbed or emitted. The 4D twisted Hypertubule gets longer or shorter as twisting or untwisting occurs. (720 degrees per twist cycle.) >>>>>>>>>>>>>>>>>>>>>>> How many neutrinos are left over from the Big Bang? They have a small mass, but they could be very large in number. Could this help explain Dark Matter? >>>>>>>>>>>>>>>>>>>>>>>> Why did Paul Dirac use the twist in a belt to help explain particle spin? Is Dirac’s belt trick related to this model? Is the “Quantum” unit based on twist cycles? ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ I started out imagining a subatomic Einstein-Rosen Bridge whose internal surface is twisted with either a Right-Hand twist, or a Left-Hand twist. The model grew out of that simple idea. I was also trying to imagine a way to stuff the curvature of a 3 D sine wave into subatomic particles. .

  • @tabhashim3887
    @tabhashim3887 Год назад

    You are an excellent professor!

  • @quantum_psi
    @quantum_psi Год назад

    You're awesome, thank you very much!

  • @joachimwalewski2472
    @joachimwalewski2472 Год назад

    Very helpful, thanks!

  • @jayt675
    @jayt675 Год назад

    Could you solve this problem? Thank you very much. " A bug flying horizontally at 0.65 m/s collides and sticks to the end of a uniform stick hanging vertically. After the impact, the stick swings out to a maximum angle of 8° from the vertical before rotating back. If the mass of the stick is 10 times that of the bug, calculate the length of the stick in centimeters."

  • @eunkyungkim948
    @eunkyungkim948 Год назад

    강사님 한국분이시죠? Korean?

  • @jethroaugustus4794
    @jethroaugustus4794 Год назад

    I'm researching Yukawa's principle for a particle accelerator research project, and this is really helping to explain everything. Thank you.

  • @giampietromartini9106
    @giampietromartini9106 Год назад

    Hi good explanation! Is it possible to access to the web resource you used?

    • @CoAPhysics
      @CoAPhysics Год назад

      The Algodoo simulation software is available here: www.algodoo.com/. It's available on Windows and Mac OS, but not on any mobile platform (except for the version for iPad that you have to pay for) or Linux/Chromebook.

    • @giampietromartini9106
      @giampietromartini9106 Год назад

      @@CoAPhysics Thank you for the quick reply. I meant the teaching resource on the website you used to implement the algodoo model. Many thank you again!

    • @CoAPhysics
      @CoAPhysics Год назад

      @@giampietromartini9106 Do you mean the lab manual? That is on the course Canvas LMS and can't be shared publicly (not without making the entire course publicly accessible). I did make sure to show on screenshare any part of the lab manual that is necessary to follow along the Algodoo simulation demo. If you still need a copy of the lab manual, the only publicly accessible version is on this PDF (coaphys.xyz/wordpress/wp-content/uploads/2022/04/PHYS-3A-Lab-Manual-1st-Ed-2022.pdf), pg. 61 (but this PDF was created for a different purpose and there may be differences between the PDF and what is on the video).

    • @giampietromartini9106
      @giampietromartini9106 Год назад

      @@CoAPhysics Thank you again for your reply and time!

  • @thomasolson7447
    @thomasolson7447 Год назад

    Is there any reason to add or subtract relativistic quantities? (m*c)/sqrt((c+v)/(c-v)) adds (m*c)*sqrt((c+v)/(c-v)) subtracts This is for momentum. γ*(m*c)*sqrt((c+v)/(c-v)) (m*c)/(γ*sqrt((c+v)/(c-v)))=m*(c-v) p=m*c*sin(arctan(i*v/c)) (m*c)*(cos(arctan(i*v/c))+i*sin(arctan(i*v/c)))=m*c/sqrt((c+v)/(c-v))=mcγ(1-(v/c)) (m*c)*(cos(arctan(i*v/c))-i*sin(arctan(i*v/c)))=m*c*sqrt((c+v)/(c-v))=mcγ(1+(v/c)) E^2=p^2*c^2+m^2*c^2=(m*c*i*sin(θ))^2*c^2+m^2*c^4 E^2=m^2*c^4*((i*sinh(arctan(v/c)))^2+1)=m^2*c^4*((1-sinh(arctan(v/c)))^2) E=m*(c^2)*cosh(arctan(v/c)) E=m*(c^2)*γ if v>c then E=m*(c^2)*i*sinh(arctanh(v/c)) E=m*c*i*γ*v

  • @jayt675
    @jayt675 Год назад

    thank you, you are very helpful

  • @xand2870
    @xand2870 Год назад

    It wasn't because the helio was more 'elegant'. It was a philosophical reason that the geo is a case for God, they prefer a non Godley world. Both geo and hello are still theories because they can't say the geo is wrong. Because there is a God who made the earth and human therein in a special place in the middle. Wake up

  • @ngawangr5324
    @ngawangr5324 Год назад

    this question was on my fucking exam and was only worth 3 points. What the hell??? You need a very deep understanding of the previous chapters regarding forces and motion, and my test isnt even supposed to have this old chapter! i was literally stuck because i thought this was a simple work problem, but no, its a long problem that requires a mastery in a previous chapter knowledge, and on top of that you need to have knowledge in the work chapter too. How is this even fair?

  • @dlrldnjs04
    @dlrldnjs04 Год назад

    For the R4 I get 6 but the answer on index in text book shows the answer is 18. And I look over your equation it gives 6 too. I think the index answer is wrong lol

    • @CoAPhysics
      @CoAPhysics Год назад

      Hm. Are you looking at a physical copy of the textbook (or maybe PDF)? The most up-to-date online version shows R4=6 Ohm (openstax.org/books/university-physics-volume-2/pages/chapter-10#fs-id1172100529328-solution). Maybe it got reported as errata earlier and got fixed.

    • @dlrldnjs04
      @dlrldnjs04 Год назад

      @@CoAPhysics yeah I think the one I downloaded from online was out dated. Thank you

  • @mario-vy6iw
    @mario-vy6iw Год назад

    Do you let to download your .pdf from somewhere? That could be nice. Thanks

  • @bey7431
    @bey7431 Год назад

    Thank you this helped a lot