Adam Bergeron
Adam Bergeron
  • Видео 28
  • Просмотров 340 237
Introduction to Cell Division & DNA Structure
Introduction to Cell Division & DNA Structure
Просмотров: 680

Видео

Structure and Function of the Mitochondrion
Просмотров 1,8 тыс.7 лет назад
Structure and Function of the Mitochondrion
Introduction to Cell Biology: Prokaryotes vs Eukaryotes
Просмотров 2447 лет назад
Introduction to Cell Biology: Prokaryotes vs Eukaryotes
Three point testcross
Просмотров 17 тыс.8 лет назад
Three point testcross
How to Use the Dilution Equation
Просмотров 157 тыс.9 лет назад
How to Use the Dilution Equation
Explain Everything
Просмотров 2299 лет назад
Made with Explain Everything
Prof. Development - Flipped Classroom
Просмотров 949 лет назад
Prof. Development - Flipped Classroom
Abnormal Chromosome Numbers
Просмотров 5 тыс.9 лет назад
Abnormal Chromosome Numbers
Calvin Cycle and Photorespiration
Просмотров 5159 лет назад
Calvin Cycle and Photorespiration
Photosynthesis - Light Reactions
Просмотров 4039 лет назад
Photosynthesis - Light Reactions
Facilitated Diffusion and Active Transport
Просмотров 6859 лет назад
Facilitated Diffusion and Active Transport
Osmosis
Просмотров 3199 лет назад
Osmosis
Membrane Transport - Diffusion
Просмотров 3319 лет назад
Membrane Transport - Diffusion
Membrane Structure and Function
Просмотров 6399 лет назад
Membrane Structure and Function
Energy and Enzymes
Просмотров 63210 лет назад
Energy and Enzymes
Structure and Function of Carbohydrates
Просмотров 32 тыс.10 лет назад
Structure and Function of Carbohydrates
Structure and Function of Lipids
Просмотров 30 тыс.10 лет назад
Structure and Function of Lipids
Evidence for DNA as the Genetic Material
Просмотров 2,5 тыс.10 лет назад
Evidence for DNA as the Genetic Material
Origin and Propagation of the Action Potential - Part 2
Просмотров 60810 лет назад
Origin and Propagation of the Action Potential - Part 2
Origin and Propagation of the Action Potential - Part 1
Просмотров 1,4 тыс.10 лет назад
Origin and Propagation of the Action Potential - Part 1
Origin of the Resting Membrane Potential
Просмотров 5 тыс.10 лет назад
Origin of the Resting Membrane Potential
Neurons and Neuroglia
Просмотров 21 тыс.10 лет назад
Neurons and Neuroglia
Biological Functional Groups
Просмотров 42 тыс.11 лет назад
Biological Functional Groups
Acid, Base, and Buffer Chemistry
Просмотров 3,4 тыс.11 лет назад
Acid, Base, and Buffer Chemistry
Drawing Lewis Structures for Biol. Mol.
Просмотров 32111 лет назад
Drawing Lewis Structures for Biol. Mol.
Hypotheses, Variables, and Controls
Просмотров 15 тыс.11 лет назад
Hypotheses, Variables, and Controls
How to Create a Shared Folder using Google Drive
Просмотров 32711 лет назад
How to Create a Shared Folder using Google Drive
How to Make Accurate Scientific Measurements
Просмотров 1,5 тыс.11 лет назад
How to Make Accurate Scientific Measurements

Комментарии

  • @Eiser_grayon
    @Eiser_grayon 8 дней назад

    thanks for the explanation

  • @NyamaiLiah
    @NyamaiLiah 3 месяца назад

    Thanks

  • @Paula-lt3ev
    @Paula-lt3ev 3 месяца назад

    Dietetics student here 😊 . Your videos are excellent. Very helpful.

  • @mamtalall6750
    @mamtalall6750 10 месяцев назад

    Thank you so much. Excellent simplified explanation.

  • @rahafrahaf73886
    @rahafrahaf73886 Год назад

    Thank you

  • @osmirod1
    @osmirod1 Год назад

    IMPORTANT QUESTION: in what situation if ever are you able to solve for one of the two variables on the right side of the equation, that is, either c2 or v2?

  • @IWusHErE303
    @IWusHErE303 Год назад

    Bro thank you I had to make a dilution lab and I forgot how this works you saved my butt thank you!

  • @uniteamerica9446
    @uniteamerica9446 Год назад

    Thank you. I'm diluting rooting hormone to soak green giant arborvitae tree cuttings overnight. Now I know how to dilute my stock solution. I will successfully root my tree cuttings and sell them next year. You helped me make money grow on trees. Money really does grow on trees if you propagate and sell the right ones. Propagate and sell screening plants, hedge plants and ground covers. People usually by a lot more than 1 of these type of plants,

  • @rottenapple2276
    @rottenapple2276 2 года назад

    The mitochondria is the powerhouse of the cell

  • @kamlablake6753
    @kamlablake6753 2 года назад

    are the parents male or female i am confused as hell

  • @Alice444V
    @Alice444V 2 года назад

    very helfpul and clear thanks!

  • @musamohammedmaud2497
    @musamohammedmaud2497 2 года назад

    you’re indeed a man of your words #Dr.Ani John on RUclips, after purchasing and using his herbal product for HSV2 I was totally cured permanently within few days. Thanks to #Dr.Ani John for the fast recovery

  • @annusharma4016
    @annusharma4016 2 года назад

    Thank you 🙏🙏🙏

    • @musamohammedmaud2497
      @musamohammedmaud2497 2 года назад

      you’re indeed a man of your words #Dr.Ani John on RUclips, after purchasing and using his herbal product for HSV2 I was totally cured permanently within few days. Thanks to #Dr.Ani John for the fast recovery

  • @mohfa1806
    @mohfa1806 2 года назад

    Hello and thank you for your great videos , i have a question please : when diluting a weak acid i noticed in the book that they use the dilution formula :C1V1=C2V2 based on the fact that the number of moles will stay constant , however for weak acid we know that upon adding water the dissociation of the weak acid increases to maintain balance and hence the number of moles of the weak acid decreases , so based on that how the dilution formula still applied?...thank you in advance.

    • @beautyqueen5002
      @beautyqueen5002 Год назад

      The number of moles of weak acid does not change upon dilution because the dissociation of the weak acid in water is a reversible process. As the weak acid dissociates in water, it produces hydronium ions and the conjugate base of the acid. The concentration of hydronium ions increases, which increases the acidity of the solution and causes the weak acid to dissociate less. This is known as the common ion effect. When the weak acid is diluted with water, the total number of moles of the acid remains constant, but the volume of the solution increases. This results in a decrease in the concentration of the weak acid, which in turn decreases the concentration of hydronium ions in the solution. As a result, the dissociation of the weak acid increases to maintain the equilibrium concentration of hydronium ions. However, the increase in dissociation upon dilution is small compared to the total amount of weak acid present, and the total number of moles of the weak acid remains essentially constant. The dilution equation, C1V1=C2V2, assumes that the number of moles of solute remains constant upon dilution, which is generally true for weak acids and bases.

  • @douglasheinl250
    @douglasheinl250 2 года назад

    Great video, thank you.

  • @wilmerpadron3622
    @wilmerpadron3622 3 года назад

    You said early that you can't cancel unit's but later you do

  • @anamshehzadi5695
    @anamshehzadi5695 3 года назад

    clearly explained

  • @devikanair44
    @devikanair44 3 года назад

    I don’t imagine you’ll see this comment but I am a bit confused with negative control. You said if you remove the IV then you don’t get the DV. but in the situation with the bugs and meat the cover was the IV so if you removed it you’d get an effect no?

  • @ashrafshahrour6698
    @ashrafshahrour6698 3 года назад

    ❤️❤️

  • @SachinSingh-xg8gg
    @SachinSingh-xg8gg 3 года назад

    Thanks

  • @anitatiwari8688
    @anitatiwari8688 4 года назад

    Ty so much ....it helped me allot sir....keep it up ...make more helpful videos for us ...❤❤☺

  • @Cosmuex
    @Cosmuex 4 года назад

    "Scientist who guess are unemployed" lmaoo

  • @Dr-Garry
    @Dr-Garry 4 года назад

    In our institute we take AP chemistry and I am just in grade 9-ASP( Advanced Science program)

  • @leslieenriquez4085
    @leslieenriquez4085 4 года назад

    I just have trouble knowing what’s the c1 v1 and c2 v2 word problems confuse me 😥

  • @axtonjay3162
    @axtonjay3162 4 года назад

    why is this so confusing????

    • @dejaharris735
      @dejaharris735 Год назад

      literally didnt even write out the problem worked. Wish these tutors would go more in depth! Lazy

  • @mangsialthang585
    @mangsialthang585 5 лет назад

    So useful 🙂

  • @toneshav340
    @toneshav340 5 лет назад

    I thought Ketone has an attached Hydrogen not carbon ...

  • @tinnesarmin3258
    @tinnesarmin3258 5 лет назад

    U r superb

  • @arpanalimbu9145
    @arpanalimbu9145 5 лет назад

    Thanksss

  • @tezadoctorat7357
    @tezadoctorat7357 5 лет назад

    Hey. Unfortunately the dilution equation can be applied only on molar concentrations. See Skoog : Fundamentals of analytical chemistry, 9th edition. page 75. " This equation is based on the fact that the number of moles of solute in the diluted solution must be equal the number of moles in the concentrated reagent.' For example: Let's say that you want to prepare 1 L of 15% H2SO4 solution (density: 1.095 g/mL) from 60 % H2SO4 (density 1.498 g/mL). We have to find out the volume needed. If we use the dilution equation we get that we need 250 mL of 60% H2SO4, but if we calculate correctly we obtain that we actually need only 182.7 mL. Here is the correct calculation: 15% means that 15 g H2SO4 is in 100 g solution. Using its density we calculate the solution's volume, that is V=m/d=100/1.095=91.32 mL. Next we calculate the amount of pure H2SO4 that is in 1L=1000 mL solution, which is going to equal 164.25 g pure H2SO4. Than we say that 60 g H2SO4 is in .......100 g solution 164.25 g H2SO4.........x = 273.76 g solution. And finally we transform the obtained mass into volume using it's density and the formula given earlier, so we get 182.7 mL, instead of 250 mL that we would get using the dilution equation.

  • @wat8437
    @wat8437 5 лет назад

    Is this principle used in the manufacture of IV pharmaceutical solutions? They probably are since there's not much room for error

  • @penderchovwe351
    @penderchovwe351 6 лет назад

    Thanks a lot

  • @nadifomuse512
    @nadifomuse512 6 лет назад

    Thanks a lot

  • @mestudy6049
    @mestudy6049 6 лет назад

    amazing! cleared out my doubt! thank u!

  • @sydneea9771
    @sydneea9771 6 лет назад

    Why didn't you finish the serious of 4 😞 your videos really helped me! I need one on proteins at this moment in time.

  • @makuchii1
    @makuchii1 6 лет назад

    thank you this video helped me a a lot !

  • @vandam7656
    @vandam7656 6 лет назад

    very good explanation

  • @whelanylime
    @whelanylime 6 лет назад

    I HAVE BEEN TRYING TO FIGURE OUT MY THREE POINT TEST CROSS PROBLEM FOR 3 HOURS AND YOU HAVE SAVED ME

  • @tanisha2659
    @tanisha2659 6 лет назад

    how to find c2/vs

  • @yonasiloma2771
    @yonasiloma2771 7 лет назад

    Language use English

  • @mailewilkey9491
    @mailewilkey9491 7 лет назад

    In my school we take biology freshman year and chemistry sophomore lol

  • @sierraslyh6743
    @sierraslyh6743 7 лет назад

    Actually I dont think the mistake at 12:56 was that you forgot to cross v and v+. I think you had them switched before they crossed because the results, CV-CT-V and +-+-+ matches the result from the table of values for 89 and 94. Great video, though! Thsnks!

  • @lynnecota9103
    @lynnecota9103 7 лет назад

    So helpful!

  • @GameCritics7
    @GameCritics7 8 лет назад

    you need better audio, just a recommendation

  • @salmael_badry2926
    @salmael_badry2926 8 лет назад

    but ,sodium and potassium are positive charged ions How can the equilibrium potential of sodium positive charged and that of potassium is negative? explain ,please.

  • @InstaUEC1
    @InstaUEC1 8 лет назад

    what about ethanol?

  • @kevinpham7380
    @kevinpham7380 8 лет назад

    Thanks!

  • @TrueGoan1325
    @TrueGoan1325 8 лет назад

    Hello Adam, Greeting to you from the UK, Great video I tried to copy the formula but I'm still too slow to grab your simplified teaching may be for various reasons. I wish you can help me here. Ok here is confusion, I'm trying to make a fertilizer stock solution of Mn in ppm I need Mn 0.8 ppm, in my final solution I do have a conversion factor i.e 4.061. so 0.8 times 4.061 = 3.2488, I take out the element purity of 90% which will be 3.2 *100/90 = 3.6. So this means I must have 3.6mg/l if I'm not mistaken. Now I want to make a stock solution 600x concentrate in a 50 liter tank, so 3.6*600 =2160 to convert into grams I /(divide) by 1000, so 3.6*600/1000 = 2.16gram . Am I right until now ? If I'm right I go a little further where the confusion begins and I need your precious help So my final solution tank is 3785liter and my stock solution of 600x concentration is 37.85 liter so do I need to take the 2.16grams *(times) 37.85 liter stock tank volume to get the total salt dissolved to make a 600x concentration which is 2.16*37.85 =81.756 or 81.8grams of salt for a 600x concentrate if this is correct please guide me further on how much of stock solution to add to make a final solution for a 3785liter tank of 0.8ppm? Adam I highly appreciate your time and your efforts in getting this solved for me as if I understand this I can work on a few more salts, I'm feeling very embarrassed with my breakdown but I rather put it simple for your understanding and more over for my understanding. Alternatively you can send me a reply on sidneyspleno13@gmail.com I thank you very much for your time and do look forward of your e-teaching. Sidney Rodrigues.

    • @blxckyin8633
      @blxckyin8633 4 года назад

      Sidney Rodrigues ik you tight because they didn’t respond

  • @soulTC
    @soulTC 8 лет назад

    In the <F1 Cross> slide (3:35), why is there no recombination? The gametes produced just replicate exactly the parental chromosomes. Why, for example, is there no v+.cv+.ct+ or v.cv.ct+ gamete?

  • @arohe4705
    @arohe4705 8 лет назад

    thank u😄😌😍