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You are the one diamond which is beneath under the stones Thanks very much.... Even Google can find the answer for me

Thank u brother🎉

Solution: ∫1/tan²(x)*dx = ∫cos²(x)/sin²(x)*dx = ∫[1-sin²(x)]/sin²(x)*dx = ∫1/sin²(x)*dx-∫sin²(x)/sin²(x)*dx = ∫1/sin²(x)*dx-∫dx = -cot(x)-x+C Checking the result by deriving: [-cot(x)-x+C]’ = 1/sin²(x)-1 = [1-sin²(x)]/sin²(x) = cos²(x)/sin²(x) = 1/tan²(x) everything okay!

Finally, i found my answer 😭, respect to you man

Thanks so much, i finally understood.

Nice

Thank you. Straight to the point and easy to understand.

Good Lad !!!

Why should environment engineer study maths for the entire graduation ..... Maths is again incorporated for the first year of post graduate ......and ........studying civil engineering has become useless .....as even computer students rely on environment science ?!

It was not easier to convert 1/cos(x) to sec(x) and obtain the direct integral which is ln(sec(x) + tan(x) + c

you re wonderful bro🎉

When you integrate 1/1-u², why can't you just apply the 1/2aln(a+x/a-x) formula?

Good❤

Gracias 🎉

Ê o barulho do inferno

Fantastic🎉

Didn't get the last part. How is ln3e=1+ln3. The ans checked out and I got the number but i still don't get why it happened

9

😮😊

horrible

X/cosx

You forgot the negative sign when re-writing -du/1-u^2

Thank you so much sir

40 cm

Shikha

8......?

3?

Wish you 🎉

Scared ;(

5?

Crazy 👀

87😊

0.05$😊

150 ✌️ 👇

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Then, Look at a clear wall 👀

87

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Bro i cant know its covered..

L8

78

87

87

87 just flip your phone

170 👇

170 👇

150 cm

110?

😂🤣