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Nice one JC. Thanks.

Wow…!!! This is a wonderful puzzle and incredibly elegant. Just amazing how it unravels slowly but surely with the loop continuously being forced. Loved it! 👍🏻

The link seems to be the same link to Mod Pods JC 🙏

Very nice solve! You followed the intended solve path pretty much exactly. The key is to slowly work your way towards that "middle cell" (trying to avoid spoilers) at which point the puzzle slowly untangles.

Great puzzle!

Je ne parle pas français tres bien, mais merci pour jouer mon Sudoku!

I used the link, I think the puzzle flipped

Great to see you making videos again after a long break. My algorithm has only just let me know, so I have a few to catch up on.

Genial! T'as parle un peu a la fin de la surcontrainte. C'etait fais expres parce que je voulais un sudoku de 2/5 etoiles. Si tu veux un sudoku un peu plus complique, j'en ai un qui s'appelle "Concentric Pairs" dans la CtC sudoku testing submission chaine de Discord ~3/5 etoiles. Aussi, j'en ai un autre qui s'appelle "Sous le ciel de Paris" dans la chaine monthly puzzle prompt ~3/5 etoiles. Si tu as des sudokus, j'aimerais les essayer!

Quelle surprise...additional linked puzzles...!! 'Daytime Sleeping' was pretty tough but very satisfying to solve - an amazing construction. (I'll leave 'Three Is A Crowd' until tomorrow!!). Merci bien.

Merci JC Godart! This one was meant to be very approachable to introduced battenburg and negative constraint. Hope you enjoyed it and everyone else too!

Thank you for this great puzzle. Your solve was so impressive to me because I could only get bits and pieces of the break-in on my own. I don't understand most of the French (except the numbers), but the way you approach the puzzle makes it understandable anyway.

Thanks for solving my puzzle!

Tricky but great puzzle - worth sticking at...!!! 🙏

Nice solve!

An excellent puzzle to mark your return to posting...!!! Thank you JCG/FD&MAFC.

Oooh! What a lovely surprise! So glad to see you posting solves again; thank you for the feature :)

Welcome back! It's been so long since you posted that I thought you had given up youtube for good. So this was a very pleasant surprise. Beautiful sudoku. I do like the modular constraint. Took me well over an hour, but very enjoyable. Many thanks.

I found that shading the digits 5-9 as 'high' made the whole puzzle much more approachable (after initial struggles 😆). Great design and solve!

Love your solves! I just finished watching them all!

This can be solved more easily if you simplify your notation by using *placeholder digits,* provided you know how to use them properly. You can safely use them up to the very end of the puzzle, if you ignore the *disambiguator* (which is the weird rule about the corners of the grid). I would not be able to solve your way. You followed two "parallel" logic paths at the same time, I followed only one of them. But you are so good that you were faster than me, even though your notation was twice as complex. So, you probably don't need placeholders as much as I do, but others might. Moreover, *placeholders* are fun, elegant and powerful 💪💪💪 when you know how to properly use them, but learning requires time. This time, I learned something new: *Modular lines* are insensitive to the transformation *y = 10 - x* Any valid sequence of digits along them remains valid after being tranformed that way❗ This is also true for *German whisper* lines and *renban lines,* as I learned when I started using placeholders, a long time ago. Because of that, each placeholder digit *N* can be safely used without *loss of generality* (i.e. without "removing ambiguity") to represent either itself or *10-N.* For instance, I started by placing *7, 2, 9, 1, 8, 3* along the upper line, being aware that they represented either themselves or their complement *3, 8, 1, 9, 2, 7* Placeholders are not a *guess.* They are symbols. They remain *ambiguous* up to the end of the puzzle, in which you verify compatibility with the disambiguator. If they are not compatible, you just switch to the alternative configuration by applying the above mentioned transformation to each of them. This final transformation is fun and can be easily done in the blink of an eye (about 45 seconds) if you know how to do it properly.

Simon (Cracking the Cryptic) solved today using placeholders, but he also used colours. As I wrote above, I believe they are not needed. You want to simplify notation as much as possible if you want to minimize the risk of making mistakes.

Global entropy is a neat rule I haven't come across before. This was a really good puzzle, well constructed. I found it tricky to scan at certain points and I'm glad I had the video to consult for a couple of hints.

Very cool puzzle, and quite tricky! I found that the solution checker works if you write large digits in the sudoku grid, but only pencilmarks in the outer ring.

8 minutes in you got a 46 pair in box five. How did you eliminate the 5 from those squares. not seeing the logic to get rid of the 5 possibility at that time.

I don't quite understand why at 22:38 the loop can't turn up in R5C8 and enter box 3?

SamuPiano here - good solve! This followed my logical path the whole way, start to finish! I'm glad you enjoyed it!

Thank you for featuring Irregular Chaos! I mostly make smaller puzzles but i do occasionally make 7x7s and 9x9s. Great solve on this one!

Great puzzle!

By the way, it was fun for me, at the very beginning, figuring out that there existed only two possible configurations of the nine *4s,* which I marked with two different colours and with corner pencilmarks. In other words, I determined in each box the only two possible positions for the digit *4,* one marked in *yellow* and the other in *orange.* Then, very early in my solve, when I placed a *3* in *r1c5,* which was the yellow cell in *box 2,* I could immediately fill *4s* in all orange cells, and delete corner pencilmarks in all yellow cells.

I think this beautiful sudoku becomes simpler to notate and hence easier to solve if you use *placeholder digits,* instead of letters. That way, you don't even need colours to remember the pairings: *1-7* *2-6* *3-5* *4-4* I know you don't like placeholders, and typically you can solve much faster than me even if you don't use them, but some of your viewers might find this suggestion useful. This is not at all one of the most powerful applications of placeholders. There are several kinds of puzzles in which notation becomes much more intricate if you don't use them. However, simplifying notation, even so slightly, *significantly* reduces the risk of making mistakes during my solve and makes my scanning *significantly* more effective.

Right. There can be a difference of 0❗ I was not able to imagine that.

Fascinating line sudoku.

Hi JC Godart! Thank you very much for featuring my puzzle! This series is where I explore Numbered Rooms/Sums clue forming different type of lines constraint. I'm expanding the series to include Numbered Sums with this puzzle, and turns out it works quite well with Modular Lines! Hope everyone enjoy the puzzle!

I can see this puzzle is making the rounds! Fantastic setting, shockingly smooth solve path given all the constraints

Amaizing puzzle!! Managed to solve it myself but in 82 minutes.

Very fun logic, very nice drawings and very original ruleset 😏👍

I knew I’d seen this before. CTC have changed the line colour so it took me a while to find.

OMG! Please stop whispering into the mic! I have to turn it up so loud I hear your breathing. Move away from the mic! Speak louder! I like the puzzles but if I get stuck I have to hope I can figure out the logic on mute because it is painful to listen to you. I feel bad because you only get maybe a minute of watch time on the video if any from me. Other channels I like to watch after I solve to see if they did something very different but I just can't do that here sorry.

I really enjoy your channel. Thank you. 🥰

What an extraordinary puzzle!!! Took me close to 1h, worth every minute.

Link works for me. Solved it in 22:45. Lovely puzzle.

Really cool combination of constraints

I always find entropy to be a tricky thing to work with. Excellent solve!

36 for me. Waited to long to color the 8/9 cells.

I wish you would change your microphone placement. At the moment every tap on the keyboard is a loud thump and your voice is very boomy. You don't need an expensive mic but you do need a kind of mic stand that is a shock absorber.

I like new puzzles to view and solve but you have to get a better mic, it is literally painful to hear you talk. Until then maybe talk louder from farther away. It sounds like you are whispering into it from very close.

Your puzzles have been very difficult lately. Keep it up!

Thanks so much for featuring my puzzle, I'm glad you enjoyed it enough to turn it in to a video 😊

That is a beautiful drawing, and a perfect example to showcase the most powerful 💪 way to use *placeholder digits.* There is only one cell in the grid containing a *disambiguator* (the given 4). Every other clue is literally ambiguous❗ Both *German whispers* and *renbans* are insensitive to the difference between high and low *polarity...* So, if you are not as good as *JC Godart,* you can use *placeholders* to make your solve *hugely* easier. You are guaranteed to be able to fill in the whole grid with *placeholders* if you assume you have an ambiguous *4-6* pair in *r7c4,* rather than a *4.* This way the puzzle cannot be disambiguated. It has two alternative solutions. Both of them are valid, and you can quickly ⚡ (~45 seconds) switch from one to the other by applying the known transformation: _y_ = 10 - _x._ (that's fun, by the way) Filling the whole grid before disambiguating is useful, because disambiguating at the very end is much easier than in the middle of your solve. If you need to switch to the alternative configuration, you can do it quickly ⚡, by using double click to select all cells containing the same digit *N...* (see below for details). Just start by colouring *r7c4* in black, to remind you it must be replaced (in your mind) by a *4-6.* After corner-pencilmarking *4-5-6* in the *U-shaped renbans* and colouring the *7-cell renban,* just place *high placeholders* in green, and *low placeholders* in red (or viceversa), starting from: *6* (or 4) representing green 4-6 in *r5c9* *4* (or 6) representing purple 4-6 in *r9c5* ... This will *hugely* simplify your notation. You will have to use exactly the same logic used by *JC Godart,* but scanning placeholder digits will be *hugely* easier than scanning coloured pairs. It would be easier even for *JC Godart,* of course, but he is not significantly slowed down by advanced scanning... (I wonder how quick he would be if he used placeholders).