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I think the answers are 99% accurate. But am just typing the markschemes and it will come at a cost

when i get the anti log, i consider the power of 10. But if i didnt use the antilog in clculation, then its not needed

A nice website with great study materials launching soon. I am one of the contributers to the resources of Physics

cheers

Exam tomorrow and l am wondering 😂

not that i recorded before the scheme. I apologize for any errors. Thanks

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Read the question carefully it said it was initially 0 but then the 45 degree filter was added in between so now it was not 0

@@heneedsomemilk751 how can a wave be polarized if its intensity is 0

@@victor8992 Its not the intensity is 0 after the horizontal filter, remember to read the questions carefully for tommorows paper otherwise your gonna end up making mistakes all cuz you got tricked by a question

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I chose the shortcut. If you consider horizontal momentum you would get same answer. but horizantal and vertical can not be combined here

yes please. if we say x = 10, and then x increases by 5 then the new x = 15. so if the initial power is p and then it increases by 50% then the increase alone will be 0.5P so the new power is P+0.5P = 1.5P

the transmitted intensity is not the same as the amplitude. Check out the derivation of malus' law. we resolve the original amplitude to get the new amplitude

maximum means constructive interference occured. first order is the one closest to the the center

all the best

all the best

Note that E is a vector yet Vis a scalar. Potential due to positive charge is also positive so we.just add it up. Yet E due to like charges is in opposite directions for each charge so we subtract

It's better to add the part of work done

@@Px_nino_x7 I solved those papers. Check play lists

@Px_nino_x7 or u go to my channel and put in 2023 or 2024 you will see the papers

Ooooh how sweet. Thank you so much. I pray you excel

which particular one? when you open it there is an option for download

@learnPHYSICSwithIBM All of them sir

@@moussaousmane747 drive.google.com/drive/folders/1uLV6oSDHK8NjyVnQ3tkzHPxpsYYG4iWL?usp=drive_link drive.google.com/file/d/1yza9jhohSCEnhFPEvXGwItMrXolegZ8Z/view?usp=drive_link drive.google.com/file/d/1ChJ3fsVh9eifDaijQidUGbzyYUl4fQya/view?usp=drive_link

@@learnPHYSICSwithIBM thank you so much sir I have downloaded

yes

@@zzaenabz hello friend, always quote the time in your comment. I subtracted all the area above the curve because I wanted only the area below the curve. You can instead draw shapes below the curve and find the area of the shapes. Or count all the squares below the curve

@@learnPHYSICSwithIBM Alright sir, so if I for instance did not draw that horizontal line, I would count all boxes and subtract from the whole area of the grid given, I understand. Thank you so much sir.

think of the quantity you are measuring. its only time which you can consider in any direction. height is vertical, horizontal distance consider horizontal

for more explanation, check in the play lists for lessons of kinematics and go to the last 3 lessons in the play list

@annali1278 that is common but you only lose a mark for interchanging axes but along as you follow next steps there is ecf error carried forward

@@learnPHYSICSwithIBM thanks, sir, I ended up with a negative resistance because of my wrong gradient, but I believe all my methods are correct, will that be penalized,thanks

The method is what carries marks. Just be positive and focus on the remaining exams.

You can still get about 13 or 14 marks if you follow your choices carefully. At times u can even get full marks if you did correct graph, gradient which matches your choices

All the best

Its area which increases by factor of 4 so resistance decreases by same factor since they are inversely proportional

@@learnPHYSICSwithIBM yes that's absolutely right, my exam is in 10 hours I'm just getting nervous!

@@learnPHYSICSwithIBM yes that's absolutely right, my exam is in 10 hours I'm just getting nervous!

I don't think u need a clamp since u will be pulling upwards to cause a force

gd when you quote time in the comment That is not uncertainty but in finding area when the graph is not a straight line, we can not all get the same answer. So the examiner decides a range in which the answer should fall

I teach my students to write a plan, not to point out marking guide points. I encourage students to put them selves in the experiment. The experimental procedure should be workable in the lab. Nevertheless you can bullet your answer the way examiners point out marking points but I can not teach my students such. My students write alot so that the examiner picks out 15 marking points and thus score highly. Thank you.

@@learnPHYSICSwithIBM ohh ok I see🙌 but if I wrote in a bulleted way would it be equally fine though? Because I just want to stay on the safe side of things without writing too much (because I’m a slow writer)

@@connor__schmitz4619 well you are free to write in any style as long as you write alot. Because its beter to write about 20 points so you wont be able to know what the examiner will consider as major marking points. the examiner will consider 15 points though which hold more water

@@learnPHYSICSwithIBM oh ok thank you I will keep that in mind🙌😁 and for the graph in question 2, could I draw 2 different dotted triangles for each gradient of best fit and worst fit line instead of just 1? And should I state the points that I’ll take from gradient triangle right next to them or on the outside of the graph at the axes?

@@connor__schmitz4619 u can