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X³+x²-2=0=׳=6-ײ-4-2=6-ײ-2=0

Couldn’t you also just use the laws of exponents, meaning that because 4! = 24 and root(4!) = root(24), you could rewrite this as 24^1 / 24^0.5 then use the laws of exponents the say that the answer would just be 24^0.5 or 2* root(6)?

Cool

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painful

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Very nice ,excelent teacher

5^4AB/AB 3^4AB/AB 5^12^2AB/AB 3^2^2AB/AB 1^1^1AB/AB 3^2^1^2AB/AB 3^1^1^2AB/AB 3^2/AB(B ➖ 3A+2)

3^1/2

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I did not understand why the teacher multiplied 2/5. 😢😢😢

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Genial question

Math is very nice.excelent teacher

easy

-1.5

8?...Lol...(0.5)^{-3}=[1/0.5]^3=2^3=8, if I didn't mess that up, lol...

Another approach: (√8^√2) / (√2^√8) = -------------------> √8 = 2√2 --------> √8 2^(3/2) 2^(3/2)√2 / 2^(1/2)^2√2) = 2^ [3/2 * √2 - 1/2 *2√2] = 2^ [3/2(√2) - √2] = 2^ [(1/2) (√2)] = 2^(√2/2) = 2^(2/2√2) = 2^(1/√2) Answer: D

The quadratic Formula is usually the best way to solve quadratic Equations. However, in this case with quick observation it is easy to see that the factoring method would work. X^2 -6X +8 = (X-4)(X-2) = X = 4, 2

3^3=27 3×3×3=27

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√9!/√(5!) = 3!/√120 = 6/√2³*3*5 = 6/2√30 = 3/√30 = 3√30/30 = √30/10

Menurut perhitunganku juga, x= -1½. Salam dari indonesia

Can you put -5 back into the original problem to check the answer? I tried and it didn’t work. If you graph each side they do not intersect.

Very nice,good explanation

Ha, ha, ha...

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1/8 - 1/9 =(9-8)/72 = 1/72

That was difficult...

x² -2x = 3 x² - 2x -3 x² - 3x +x -3 x(x-3) + 1 (x -3) =0 (x+1) (x-3)= 0 x = neg 1 or 3

Bem explicado

Nggak ada musiknya?

Didn't have to go all Sridhar Acharya on the final quadratic equation. It would be much easier to just split the polynomial into factors as it factors quite easily into (x-3)(X+1) = 0

amateur

A more rigorous way is to simply take logarithms base 3 on both sides. log3(27) = 3, log3(9) = 2, log3(3) = 1. Which immediately yields the quadratic equation x^2 - 2x - 3 = 0. This can be factorised as (x-3)(x+1) = 0. Therefore x = (3, -1).

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3^x²/9^x=27 3^x²/(3²)^x=27 3^x²/3^2x=3^3 3^x²-2x=3^3 x²-2x=3 x²-2x-3=0 x²-3x+x-3=0 x(x-3)+1(x-3)=0 (x-3)(x+1)=0 x=3 x=-1

An extra step at the result: (2*sqrt3 + 3*sqrt2 - sqrt3)/12 = (3*sqrt2 + (2*sqrt3 - 1*sqrt3))/12 = (3*sqrt2 + (2 - 1)sqrt3)/12 = (3*sqrt2 + sqrt3)/12 Done! x + 1/2 is not the same as (x + 1)/2 y*sqrtx: y times square root of x

|(625 + 1 - 50) - 625| - |625 - (625 + 1 + 50 49 - 51 = -2 (625 + 1 + 50) - (625 + 4 + 100) 51 - 104 = -53 -2 / -53 = 2/53

i did it in less then 10 sec lol

What about that denominator 3, it desappeared ?

Very good

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Creo que la raíz de 9 debería estar entre paréntesis para distinguir factorial de 3 de factorial de 9. En el primer caso resultará = 6. y en segundo caso = 12 por. raíz de 21.

Got the sign wrong. (-49)-(-51) equals -49+51 = 2 (not -2). So the answer is -2/53…

Sorry thumbs down due to poor layout of problem.

50^100 in my mind. Thanks 👍