WASSCE PAST QUESTION|POLYGONS||
Interior Angles of a Regular Polygon
Formula for each interior angle:
Interior Angle=(n−2)×180∘n\text{Interior Angle} = \frac{(n - 2) \times 180^\circ}{n}Interior Angle=n(n−2)×180∘​
Where n is the number of sides of the polygon.
Example: For a regular hexagon (n=6 ):
Interior Angle=(6−2)×1806=7206=120∘\text{Interior Angle} = \frac{(6 - 2) \times 180}{6} = \frac{720}{6} = 120^\circInterior Angle=6(6−2)×180​=6720​=120∘
Exterior Angles of a Regular Polygon
Formula for each exterior angle:
Exterior Angle=360/n
The exterior angle is the supplement of the interior angle.
Example: For a regular pentagon (n=5):
Exterior Angle=360/5=72