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Easy Numericals
Добавлен 24 апр 2012
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- Numerical methods
- Civil engineering applications
- Math fundamentals
- Practice problems and solutions
Ideal for students, professionals, and educators seeking clarity and precision. Subscribe now and enhance your skills!"
Lecture 12 - Design of Strap Footing (Part IV)
BTCE-601 (Design of concrete structures-II) For PDF Notes:
drive.google.com/file/d/1fB_z42O6DtNLTuYsmeKszB0GgoJD5yeY/view?usp=drivesdk
drive.google.com/file/d/1fB_z42O6DtNLTuYsmeKszB0GgoJD5yeY/view?usp=drivesdk
Просмотров: 4 235
Видео
Lecture 11 - Design of Strap Footing (Part-III)
Просмотров 5 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 10 - Design of Strap Footing (Part-II)
Просмотров 6 тыс.4 года назад
BTCE-601 (Design of concrete structures-II)
Lecture 9 - Design of Strap Footing (Part-1)
Просмотров 16 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 7 - Design of Trapezoidal Footing - Part III
Просмотров 2,2 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 6 - Design of Trapezoidal Footing - Part II
Просмотров 3,5 тыс.4 года назад
BTCE-601 Design of Concrete Structures-II
How to make Tiny URL | Hindi | Shorten lengthy URLs or Google Drive Links
Просмотров 2,4 тыс.4 года назад
This video explains how to make short URL for lengthy URLs of Google drive links using TinyURL.com
Lecture 5 - Design of Trapezoidal Footing (Part-I)
Просмотров 17 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 4 - Design of Combined Footing (Part-II)
Просмотров 6 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 3 - Design of Combined Footing (Part-I)
Просмотров 25 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 2 - Design of Unsymmetrical Footing (Part-2)
Просмотров 4984 года назад
BTCE-601 (Design of Concrete Structures-II)
Lecture 1 - Design of Unsymmetrical Footing (Part 1)
Просмотров 1,5 тыс.4 года назад
BTCE-601 (Design of Concrete Structures-II)
How you have taken the b value sir
sir the column size of column B is 0.5 x 0.5, while calculating bo you have taken 0.4 instead of 0.5 (while checking for effective depth for punching shear)
Repeated notation makes confusion
Sir ye side distance 0.35 or 0.9 kaise liye
Hello sir, you haven’t upload lecture 8. Could you please upload to complete solution.
ruclips.net/video/3S_Ed4Wdza4/видео.htmlsi=Grxr4HHMRyTxjGxG
Good information
Where is part 2 of this video..
X bar value will be 3.67 m from A If not then Sigma M about a or b won't equalise
very useful video 👌 it solved all my queries with ease
Thanks sameen
Nyc explanation sir ❤❤❤❤
Sir net upward pressure mein load ko factor krte hai 1.5 se vo kyu nahi kra isme?
This is upto you k jbb load calculations kr rahe ho ussi time multiply krdo 1.5 se ya jbb moment analysis krna hai tbb krdo. In this video 1.5 se multiply moment analysis k time Kiya Hua hai
Punching shear calculation is wrong
While calculating...Nominal shear stress....the denominator is wrong...it must be 4( 0.4 +d)*d
Solution dekh ke me bhi reading kar sakta hu
Nice
Sir d is coming 814 mm from punching shear check
From which book you took these questions sir, plz tell 🙏
Nice
step by step neatly and clearly explain karna,explanation is gd but taking values should be clearly explain karro
Thank u sir
Nice thank you...
How shear reinforcement is provided in Foundation. Please do explain
Sir I have query about this question can you mail me at rankawat.bhr@gmail.com So that I can clear it
Sir from do you pick up this question
@@bhaveshrankawat9184 RPSC AE Civil Mains Paper 2
what if the 2nd point of contra flexure exceeds the length of footing we provided? Can it happen? shoul we reconsider the length?
Dear, Point of contra flexure is calculated with respect length of footing and loads (upward soil pressure and loads on columns) I.e. moment. Parameters has pre defined w r t IS 456 hence no chance what u said.
@@EasyNumericals oh okay, must have made an error somewhere in the process. Anyways thank you for the swift reply and your lectures, it has helped alot.
@@ujjwalbajracharya4360 thanks you for appreciation... I will count. with you tube now.
Sir how to design if there is a rectangular columns and they are not oriented in one direction (one col is horizontal and another is vertical) ...plz tell how to design such type.
Osm sir
Sir please upload the reinforcement detailing diagram
How to provide steel in footing practically ? Please draw a plan and cross section of the footing!
Will share it soon
Sir please one calculation find out.ms ingots ka question hai.find out wight
500+700=1200
Self weight of footing should be added which may vary 10% to 20% of axial or service load....thanks
Sir send notes of degin of combinde rectangular footing plz send sir
Hello sir , your explanation is very good. Pls also explains design combined footing with strap beam with numrical example.
Already uploaded
Sir ji,your explanations just *Kamaal kar ditta* awesome sir
Thanks and welcome
10.54 sf at outer face x=a=.85 how it comes ?
Yes ???
@@nidhimandavi9120 value of *a=1* (in starting we saw),and the distance from inner face to edge *B1* is (1-0.15=0.85),where 0.15 is the half of the width of the column (0.3/2=0.15)
RCC design by Limit State Methods....B.C Punmia
drive.google.com/file/d/1fB_z42O6DtNLTuYsmeKszB0GgoJD5yeY/view?usp=drivesdk
TRANSVERSE REINFORCEMENT DESIGN
Sir, Practical not possible to provided shear reinforcement in foundation , we must check the Depth of foundation or to increase depth as per codes to varify shear check , presentation is good , require more about shear check , bending moment is ok Thank you need detailing of steel.
Sir, For Finding point of Contra flexure where bending moment changes its sign , after solving quadratic equation , Getting two values 1) x1 =0.081m and x2 = 3.085 m, then Moment calculated values is right =-360.56(KNM) When x1=0.081 m
Writing Mistake... Considered
Great presentation. Well delivered. Thank you very much Sir. We need more of your tutorials.
Thanks, will do!
SHEAR FORCE AT INNER EDGE OF COLUMN B ,F3=-219-(273X1/2(2.5-0.4)=-506 KN, UPWARD PRESSURE FOR SHEAR FORCE SIGN WILL BE NEGATIVE
Writting error... Thanks for noticing
Sir, got lot of knowledge on your explanation, please complete all design part
sir require next part for design and detailing
drive.google.com/file/d/1fB_z42O6DtNLTuYsmeKszB0GgoJD5yeY/view?usp=drivesdk
Upload 5th video
drive.google.com/file/d/1fB_z42O6DtNLTuYsmeKszB0GgoJD5yeY/view?usp=drivesdk
ruclips.net/video/3S_Ed4Wdza4/видео.html
Sir , Moment calculation width considered 2.4 m , it should be 1 m ?
Whatever the value of BM across the footing, shall we always take the depth of strap beam on the basis of the Moment on the Edge of Eccentric Footing?
calculation is in 3 part element as sir explanation, 1) eccentric footing , 2)isolated footing and 3)strap beam (inverted T beams) and maximum moment hogging moment 721.5 km
sir, For finding cg of foundation , easier method of find reference axis from y to find cg x, BEST EXPLANATION
Thanks
i got clear idea for T beam as per explanation .
Pls check my link for complete numerical notes
sir shear check d parameter also to be check BS code
however moment calculated 721.5kn-m hogging moment at edge D , Reinforcement to provided on top in section. sir.
sir require next part part 5 , not available