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HackSussex
Великобритания
Добавлен 23 ноя 2017
Sussex University events organisation for Coding events + Hackathons 💻
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Просмотров: 276
Видео
HackSussex 2024 Hackathon Highlight Reel
Просмотров 3192 месяца назад
HackSussex's annual hackathon that took place 17th-18th February 2024 www.hacksussex.com/ HackSussex is the annual hackathon that takes place at the University of Sussex, UK. Every year students from across the country come together to work on new projects over 24 hours and compete in their choice of a range of challenges for fabulous prizes, all while enjoying games, workshops, talks, free foo...
AI Won't Replace You: Tech Insights with Dylan Beattie - HackSussex Podcast #1
Просмотров 1,2 тыс.6 месяцев назад
Join us for the debut episode of the Hack Sussex podcast as we sit down with Dylan Beattie, a renowned software engineer and development consultant. Dylan shares his journey from tinkering with 8-bit computers in his youth to becoming a leading figure in software development and architecture. He discusses his varied career, including his time as CTO of an events company and his pivot to indepen...
HackSussex 2023 Live Full Show
Просмотров 2,7 тыс.Год назад
HackSussex is the annual hackathon that takes place at the University of Sussex, UK. Every year students from across the country come together to work on new projects over 24 hours and compete in their choice of a range of challenges for fabulous prizes, all while enjoying games, workshops, talks, free food, and more. The return of HackSussex after being postponed for 3 years we bring you HackS...
HackSussex 2023
Просмотров 5 тыс.Год назад
HackSussex's annual hackathon that took place 18th-19th February 2023 www.hacksussex.com/ HackSussex is the annual hackathon that takes place at the University of Sussex, UK. Every year students from across the country come together to work on new projects over 24 hours and compete in their choice of a range of challenges for fabulous prizes, all while enjoying games, workshops, talks, free foo...
HackSussex Coders' Cup 2022
Просмотров 2,5 тыс.2 года назад
Took place June 1st 2022 in the MTL Studios, Sussex University. Director - Elias Lassalle Producer - Tom Harwood Tournament Manager - Jude Birch Presenters - Josh Kybett, Jack Speat Participants - Layton Burchell, Guy Aziz, Brandon Lodge, Antons Vasiljevs, Daniel Foulkes-Halbard, Thomas Dent, Wong Ho Lung Ryu, Kannen Joshi Vision Mixer - Coby Sharpe Graphics Operator - Tom Harwood, Louis Murphy...
this is wayyyy too underrated
sometimes I wonder do I have to morph into some creature to start being good at programming
Really thanks by watching this im getting confidence that I'm not the only one who struggles/suck at coding
R1 - G3: my solution count = 0 n = len(str1) for i in range(n): if str1[i] != str2[i]: count += 1 if count > 2: return False return count != 1
R1 - G4: my solution sq = [] for l in rectangles: sq.append(Min(l[0], l[1]) return len[x for x in sq if x == sq.max()]
R2-G1: my solution s = sorted[a,b,c] count = 0 while s[0] != 0 and s[1] != 0: if s[0] != 0: s[0] -= 1 else: s[1]-= 1 s[2] -= 1 count += 1 s = sorted[s] return count
class Solution { public: int Solve(vector<vector<int>>& rectangles,unordered_map<int,int>&my_map){ int ele = 0; int max_element = INT_MIN; for(int i = 0;i<rectangles.size();i++){ if(rectangles[i][0]>rectangles[i][1]){ ele = rectangles[i][1]; }else{ ele = rectangles[i][0]; } my_map[ele]++; if(max_element<ele)max_element = ele; } int max_freq = 0; int max_freq_key = -1; for (auto& pair : my_map) { if (pair.second > max_freq) { max_freq = pair.second; max_freq_key = pair.first; } } if(max_element==max_freq_key){ return max_freq; } return my_map[max_element]; } int countGoodRectangles(vector<vector<int>>& rectangles) { unordered_map<int,int>my_map; return Solve(rectangles,my_map); } };
its a mix of cringe, elevated IQ, suspense, bugged npcs and nerdi things all in one place
Just dump the question In chatgpt, done.
~ 31:40 Quick comment for Dylan, I'd recommend Windows IoT Enterprise LTCS if you could get your hands on it, unfortunately it's not meant for consumers, no bloat, no ads etc., and then for the issue with wanting to use Linux you can use WSL and still use Adobe Applications. Mac, well, you could technically emulate it & sign it, but too much effort in my opinion.
All the problems in this competition are easier than Div3-A on Codeforces.
The *string match* instructions @ around 40:00 or so- is is written kinda weird for me- I wonder if that threw them off a bit. There is some weird choice words used there, the main things that sticks out is the "(not necessarily different)"; what does that refer to? It can't be the indices because the indices most certainly have to be different because it's referring to one string; and if its to the strings themselves, then that was oddly placed and seems like it's giving away too much info. If someone can see what I am missing there, please point it out for me. I have been trying to figure out what they mean there for the longest- however I do get the point of the challenge, just not why its written that way-
The real question is where did they fine Coder Commentators 😂
all the problems are very easy
36:53 function swap(a,b){ array1=a.split(''); array2=b.split(''); return array1.join('')===array2.reverse().join(''); }
I like how Bramble's reaction in 32:59 is just the same as me when wondering why my code wont work _🤣🤣🤣_
2:29:09 hahahaha. It's a basic arithmetic
The thrilllllllls of the second game was crazy !!! lol
In morning i had solved the same first two questions lol and then i saw this
my eyes just burned seeing these guys struggle at baby problems.
Where i can get the text of the test, i want to test with my solutions
one of the anchors look like an Indian.
That’s because he is 😂😂😂😂😂
coolest commentators ❤
The coolest commentators ❤
these are leetcode easy wtf
Hmm, is this serious or meant to be a comedy thing? Cause I skipped to 41:30 ish and there's no way these guys are stuck like that... Especially the guy on the right flipping return false and true. Or am I missing something?
1:20:24 wtf is that "daddy chill" meme
Mei looks like 2007 Messi 😭😭
thats a dude fr
Awesome thing!! How do I participate in this?
Mei gg.... try to keep it simple :P
На первой задаче выключил. Пять методов перепробовали, хотя решение на поверхности. Выключил на моменте set.insert(). Они даже базу языка не знают. Ни алгоритмов. О чем говорить?
UPD: посмотрел задачи и решения. Единственное решение (,которое в любом случае ОЧЕНЬ долго не было написано) это Final Q1 2:00:55. Все остальное даже не близко решения задач. Олимпиадное программирование курит в сторонке. Уровень 800-1000 на codeforces. Плюс-минус тоже самое на литкоде в самых простых задачках. И даже не близко к всяким "Башни" с acmp, где ты можешь и решишь на питоне, но по времени не влезешь, а где-то и память нужно менеджить.
This is first one from you guys...😅 Veryy good.
In the second problem, can't we just use Sn = (n*(n+1))/2 formula? (Sn = sum of first n integers starting from 1) Basically, what I thought is, just calculate the running sum of each row, then compare it with the Sn, if answer is not equal to Sn then simply return false. Else go forward. This solution might look good but there might be some bug in this, like what if the row is [6, -6, 6], the row sum is valid, but it does not have all the integers.
i can't coding, but i love to watch this
Love competitions like this, after discovering my passion for programming but still lack at some skills I'd love to get challenged with stuffs like this. Bet somebody here can defeat Gennady Korotkevich
for third question, just having same characters in both the strings is enough as when we have same characters, no matter in what way they are ordered, we can always arrange them correctly by successively swapping unordered characters
For the second problem what is taking them so long, in python there is a method called isDigit() which can be called from a string object. Make a local list, iterate that nxn matrix, cast everything into a string and check whether it is a digit and not zero, if yes append in that list (use copy.deepcopy() to avoid any errors). Whilst in the for loop check the boolean list, do *= (1*1=1, 1*0=0, 0*0=0). If all is true then return that boolean else return false.
For the third problem, the commentator had already pointing out the solution. You sort both input string into a sorted array of characters, then check for every index is the character the same.
Is this like some sort of amateur competition? Because all of these are leetcode easy. This pales magnitudes in comparison to easiest problem from actual coding contests like ICPC or from platforms like Codeforces lmao
Food! :)
57:47 step 1 : function GetSquares from rectangles => step 2: function from list output for step 1 => select distric value => find maxvalue=> count value => step 3: combine all step in code. Right or not?
43:53 => for(int i = 0;i<= string1.lengt;i++){ if(string1.Substring(i,1)!=string2.Substring(string2.lenght-i,1)){return false} } return true;
So many awkward moments on this video from everyone in a funny way.
Hahaha the commentators are funny, their vocal inflections are random and out of sync with relevance emphasis, then I saw what they looked like 😂😂
Hahaha the commentators are funny, they’re vocal inflections are random and out of sync with tone, then I saw what they looked like 😂😂
I'm scared whenever I start solving problem, so I just. I need to stop doing that.
I would quit after reading second sentence of the question
Do you know if it's possible to find the test files with the instructions? so that you can do the same exercises at home x)?
Why the host's are not seeing each other
in the Bramble vs Jo match,why did they waste so much time.How i observed the only thing you need is to pass all of the test,so they just need to write a simple code does not matter if it is too long,right.I have 1 experience in python and i wrote a 19 line code in like 2 minutes.You do not need to complicate it and make as short as possible.And we really need more competitions like this!
see the issue with python language here is the programmer is not thought on how computers and compilers think, their code has barely any structure giving a false logic in coding. However it remains as a pretty popular language because of how simple it is to learn and quite alot of things you caan create with it kind if like a lego.
This is so nerdy , where do i apply ?
i tried first issue but i don't have test case def solution(inputs): start_path = inputs[0][0] current_path = start_path while True: next_path = [p for p in inputs if p[0] == current_path] if not next_path: break next_path = next_path[0] or None current_path = next_path[1] return current_path