Shiwam's Classes
Shiwam's Classes
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  • Просмотров 44 686
Two biased dies are tossed Die 1 has 1 on two faces, 2 on two faces, 3 and 4 on other faces | JEE
Two biased dies are tossed. Die 1 has 1 on two faces, 2 on two faces, 3 and 4 on other faces, while die 2 has 2 on 2 faces, 4 on 2 faces and 1 and 3 on other faces. Then the probability that when throwing these dices we get sum of 4 or 5 is. 1) 3/7 2) 2/3 3) 4/9 4) 8/9.
🔥 JEE Main 2025 Probability Question Solved! 🔥
In this video, we tackle an exciting probability question from JEE Main 2025 involving two biased dice 🎲🎲. Given that each die has non-uniform number distributions, we calculate the probability of obtaining a sum of 4 or 5 when rolling these dice.
We break it down step-by-step with clear explanations and logical reasoning, making it easy to understand and boost your JEE probabil...
Просмотров: 2

Видео

Number of ways to form 5 digit numbers greater than 50000 with the use of digits 0, 1, 2, 3, 4, 5, 65:14Number of ways to form 5 digit numbers greater than 50000 with the use of digits 0, 1, 2, 3, 4, 5, 6
Number of ways to form 5 digit numbers greater than 50000 with the use of digits 0, 1, 2, 3, 4, 5, 6
Просмотров 262 часа назад
Number of ways to form 5 digit numbers greater than 50000 with the use of digits 0, 1, 2, 3, 4, 5, 6, 7 such that sum of first and last digit is not more than 8, is equal to? (1) 5119 (2) 5120 (3) 4607 4) 4608 In this video, we solve a fascinating combinatorics problem from JEE Main 2025. The problem requires us to count the number of 5-digit numbers greater than 50000, using the digits {0, 1, ...
JEE Main 2025 Integration Trick | Solve ∫ 1/[(x-1)^(11/13) * (x+15)^(15/13)] dx FAST!5:29JEE Main 2025 Integration Trick | Solve ∫ 1/[(x-1)^(11/13) * (x+15)^(15/13)] dx FAST!
JEE Main 2025 Integration Trick | Solve ∫ 1/[(x-1)^(11/13) * (x+15)^(15/13)] dx FAST!
Просмотров 1124 часа назад
Let I = Integration of (1/[(x-1)^11/13*(x 15)^15/13)), then I is? 🚀 The integration question that left students speechless in JEE Main 2025! ∫ (1/[(x-1)^11/13*(x 15)^15/13]) dx = ? Why This Video Will Blow Your Mind: 🎯 Unusual fractional powers 🎯 Hidden pattern that 99% students missed 🎯 Simple solution once you spot the trick 🎯 Game-changing integration technique 🔥 JEE Main 2025 Integration Qu...
If I = ∫[from -π/2 to π/2] [96x²cos²x/(1+e^x)] dx = π(απ² + β), then (α + β)² = ?13:11If I = ∫[from -π/2 to π/2] [96x²cos²x/(1+e^x)] dx = π(απ² + β), then (α + β)² = ?
If I = ∫[from -π/2 to π/2] [96x²cos²x/(1+e^x)] dx = π(απ² + β), then (α + β)² = ?
Просмотров 2657 часов назад
If I = ∫[from -π/2 to π/2] [96x²cos²x/(1 e^x)] dx = π(απ² β), then (α β)² = ? (1) 100 (2) 144 (3) 169 (4) 196 In this video, we solve a challenging integral problem that appeared in JEE MAIN 2025. The problem involves evaluating the integral: I = ∫[from -π/2 to π/2] [96x²cos²x/(1 e^x)] dx and expressing it in the form: π(απ² β) We then find the value of (α β)² Watch as we break down the solutio...
Let PQR be a triangle.The point A, B and C are on the sides QR, RP & PQ | Vector| JEE Main PYQ 20238:00Let PQR be a triangle.The point A, B and C are on the sides QR, RP & PQ | Vector| JEE Main PYQ 2023
Let PQR be a triangle.The point A, B and C are on the sides QR, RP & PQ | Vector| JEE Main PYQ 2023
Просмотров 179 часов назад
Let PQR be a triangle. The point A, B and C are on the sides QR, RP and PQ respectively such that QA/AR = RB/BP = PC/CQ = 1/2 . Then Area ( △ PQR )/Area ( △ABC) is equal to ? Solving Triangle Area Ratio Problem Using Vectors: A Comprehensive Guide In this post, we tackle a challenging geometry problem involving triangle PQR and points A, B, C on its sides such that QA/AR = RB/BP = PC/CQ = 1/2. ...
The value of ((cos A + Cos B)/ (Sin A - SinB))^n + ((SinA + Sin B)/ (Cos A - Cos B))^n is ?2:11The value of ((cos A + Cos B)/ (Sin A - SinB))^n + ((SinA + Sin B)/ (Cos A - Cos B))^n is ?
The value of ((cos A + Cos B)/ (Sin A - SinB))^n + ((SinA + Sin B)/ (Cos A - Cos B))^n is ?
Просмотров 8712 часов назад
The value of ((cos A Cos B)/ (Sin A - SinB))^n ((SinA Sin B)/ (Cos A - Cos B))^n is ? Embark on an extraordinary mathematical journey where we solve a seemingly complex trigonometric expression that reveals a stunning, unexpected constant! Problem Challenge: Evaluate: [(cos A cos B)/(sin A - sin B)]^n [(sin A sin B)/(cos A - cos B)]^n Solution Exploration Highlights: Advanced trigonometric mani...
Given vectors a = 4i+5j−k, b = i−4j+5k, and c=3i+j−k. Find a vector d which is perpendicular to both11:17Given vectors a = 4i+5j−k, b = i−4j+5k, and c=3i+j−k. Find a vector d which is perpendicular to both
Given vectors a = 4i+5j−k, b = i−4j+5k, and c=3i+j−k. Find a vector d which is perpendicular to both
Просмотров 4114 часов назад
In this video, we solve a problem involving vectors to find a vector that is perpendicular to both given vectors 𝑏 and 𝑐, and its dot product with 𝑎 equals 21. Problem statement : Given vectors a = 4i 5j−k, b = i−4j 5k, and c=3i j−k. Find a vector d which is perpendicular to both c and b and d⋅a=21 Solution : Method 1: Let d = x i y j z k d⋅a = 21 d⋅b = 0 d⋅c = 0 Substitute a, b, c, and d into ...
Solving Simple Logarithm Questions | Logarithmic Basics Explained7:09Solving Simple Logarithm Questions | Logarithmic Basics Explained
Solving Simple Logarithm Questions | Logarithmic Basics Explained
Просмотров 916 часов назад
Dive into an exciting mathematical journey where we solve two intriguing logarithmic challenges that will sharpen your problem-solving skills! Problem Challenge: Calculate log₈(128) Find log₉(√3) Solution Exploration Highlights: Power and logarithm relationships Exponential transformations Fractional logarithm techniques Strategic problem-solving approaches Key Learning Outcomes: Master logarit...
If ∫₀ˣ t·ftdt = x²·f(x) and f(2) = 3, then f(6) equals to A) 1 B) 6 C) 3 D) 2 | JEE MAIN 20254:40If ∫₀ˣ t·ftdt = x²·f(x) and f(2) = 3, then f(6) equals to A) 1 B) 6 C) 3 D) 2 | JEE MAIN 2025
If ∫₀ˣ t·ftdt = x²·f(x) and f(2) = 3, then f(6) equals to A) 1 B) 6 C) 3 D) 2 | JEE MAIN 2025
Просмотров 10321 час назад
If ∫₀ˣ t·ftdt = x²·f(x) and f(2) = 3, then f(6) equals to A) 1 B) 6 C) 3 D) 2 In this video, we tackle a fascinating calculus problem from JEE Main 2025: If ∫₀ˣ t·ftdt = x²·f(x) and f(2) = 3, then f(6) equals to Solve integral-functional equation problem using: Initial value condition Integration techniques Function evaluation methods Systematic solution approach Check out my website for free c...
Nature of Roots of Quadratic Equations | Real, Rational & Imaginary Roots as Conjugate Pairs8:20Nature of Roots of Quadratic Equations | Real, Rational & Imaginary Roots as Conjugate Pairs
Nature of Roots of Quadratic Equations | Real, Rational & Imaginary Roots as Conjugate Pairs
Просмотров 321 час назад
Embark on an advanced mathematical exploration of quadratic equations ax² bx c = 0, unveiling the intricate relationships between coefficient types and root characteristics! Comprehensive Root Nature Analysis: Coefficient Type Interactions: • Real coefficients • Rational coefficients • Irrational coefficients • Conjugate pair properties Detailed Root Exploration: Real Coefficients Scenario • Co...
If α and β are real numbers such that sec^2(tan^-1α) + cosec^2(cot^-1β) = 36 and α + β = 8 |JEE MAIN4:56If α and β are real numbers such that sec^2(tan^-1α) + cosec^2(cot^-1β) = 36 and α + β = 8 |JEE MAIN
If α and β are real numbers such that sec^2(tan^-1α) + cosec^2(cot^-1β) = 36 and α + β = 8 |JEE MAIN
Просмотров 6221 час назад
If α and β are real numbers such that sec^2(tan^-1α) cosec^2(cot^-1β) = 36 and α β = 8, then (α2 β) is (α less than β). (1) 23 (3) 24 (2) 14 (4) 27 Solve complex trigonometric equation with: Inverse function properties Equation manipulation Value constraints Systematic approach Check out my website for free courses - www.shiwamsclass.com
Two persons A and B throws a pair of dice alternatively. For A to win he should throw sum of 5 | JEE6:33Two persons A and B throws a pair of dice alternatively. For A to win he should throw sum of 5 | JEE
Two persons A and B throws a pair of dice alternatively. For A to win he should throw sum of 5 | JEE
Просмотров 2121 час назад
Two persons A and B throws a pair of dice alternatively. For A to win he should throw sum of 5 before B throws sum of 8. If A throws first, then the probability that A wins, is ? (1) 8/19 (2) 8/17 (3) 9/19 (4) 9/17 Two players, A and B, throw a pair of dice alternately. A wins if he throws a sum of 5 before B throws a sum of 8. A starts the game. We calculate the probability of A's win using ke...
The area of the region bounded by S(x, y) where S = {x, y | x^2 + 4x + 2 ≤ y ≤ |x + 2|} is? | JEE6:27The area of the region bounded by S(x, y) where S = {x, y | x^2 + 4x + 2 ≤ y ≤ |x + 2|} is? | JEE
The area of the region bounded by S(x, y) where S = {x, y | x^2 + 4x + 2 ≤ y ≤ |x + 2|} is? | JEE
Просмотров 19День назад
The area of the region bounded by S(x, y) where S = {(x, y) : x^2 4x 2 ≤ y ≤ |x 2|} is ? This problem requires understanding curve intersections, absolute values, and integration to calculate the area of the enclosed region. We guide you through: Graphing the given curves: x^2 4x 2 and |x 2| Identifying the region of interest. Setting up definite integrals to compute the area step-by-step. This...
The number of 3 digit numbers which is divisible by 2 and 3 but not divisible by 4 and 9? | JEE MAIN5:36The number of 3 digit numbers which is divisible by 2 and 3 but not divisible by 4 and 9? | JEE MAIN
The number of 3 digit numbers which is divisible by 2 and 3 but not divisible by 4 and 9? | JEE MAIN
Просмотров 499День назад
The number of 3 digit numbers which is divisible by 2 and 3 but not divisible by 4 and 9? In this video, we solve a unique problem: How many 3-digit numbers are divisible by both 2 and 3 but not by 4 or 9? We break down the problem into logical steps, using concepts like divisibility rules and arithmetic progressions, to count the required numbers efficiently. This problem is perfect for studen...
If I(m,n) = ∫₀¹ x^(m-1) * (1-x)^(n-1) dx, where m, n is +ve. Then I(9,14) + I(10,13 )is ?| JEE MAIN3:55If I(m,n) = ∫₀¹ x^(m-1) * (1-x)^(n-1) dx, where m, n is +ve. Then I(9,14) + I(10,13 )is ?| JEE MAIN
If I(m,n) = ∫₀¹ x^(m-1) * (1-x)^(n-1) dx, where m, n is +ve. Then I(9,14) + I(10,13 )is ?| JEE MAIN
Просмотров 70День назад
If I(m,n) = integration of x^(m-1) * (1-x)^(n-1) from 0 to 1 where m,n is .ve Then I(9,14) I(10,13) is equal to ? (1) I(1, 13) (2) I(9, 1) (3) I(9, 13) (4) I(19, 29). Solve complex integration problem involving: Beta function properties Integral manipulation Systematic calculation techniques Strategic problem-solving approach Key Learning Points: Integration techniques Beta function relationshi...
If Sn = 1/2 + 1/6 + 1/12 up to n terms.The sum of first six terms in A.P. with first | JEE MAIN 20256:13If Sn = 1/2 + 1/6 + 1/12 up to n terms.The sum of first six terms in A.P. with first | JEE MAIN 2025
If Sn = 1/2 + 1/6 + 1/12 up to n terms.The sum of first six terms in A.P. with first | JEE MAIN 2025
Просмотров 96День назад
If Sn = 1/2 1/6 1/12 up to n terms.The sum of first six terms in A.P. with first | JEE MAIN 2025
If f(x) satisfies the functional equation f(x) + 6 f(1/x) = 35/3x - 7/2 , x ∈ R −{0} | JEE MAIN 20256:26If f(x) satisfies the functional equation f(x) + 6 f(1/x) = 35/3x - 7/2 , x ∈ R −{0} | JEE MAIN 2025
If f(x) satisfies the functional equation f(x) + 6 f(1/x) = 35/3x - 7/2 , x ∈ R −{0} | JEE MAIN 2025
Просмотров 44День назад
If f(x) satisfies the functional equation f(x) 6 f(1/x) = 35/3x - 7/2 , x ∈ R −{0} | JEE MAIN 2025
If for an arithmetic progression first term is 3 and sum of first four terms equal to |JEE MAIN 20254:08If for an arithmetic progression first term is 3 and sum of first four terms equal to |JEE MAIN 2025
If for an arithmetic progression first term is 3 and sum of first four terms equal to |JEE MAIN 2025
Просмотров 69День назад
If for an arithmetic progression first term is 3 and sum of first four terms equal to |JEE MAIN 2025
How many words can be formed from the letters of the words DAUGHTER such that all | JEE MAINS 20252:49How many words can be formed from the letters of the words DAUGHTER such that all | JEE MAINS 2025
How many words can be formed from the letters of the words DAUGHTER such that all | JEE MAINS 2025
Просмотров 51День назад
How many words can be formed from the letters of the words DAUGHTER such that all | JEE MAINS 2025
If S be the set of 10 distinct primes and let A be the set of products of two or more |JEE MAIN 20254:48If S be the set of 10 distinct primes and let A be the set of products of two or more |JEE MAIN 2025
If S be the set of 10 distinct primes and let A be the set of products of two or more |JEE MAIN 2025
Просмотров 141День назад
If S be the set of 10 distinct primes and let A be the set of products of two or more |JEE MAIN 2025
The greatest positive integer k, for which 49^k +1 is a factor of the sum 49^125+49^124+⋯+49^2+49+13:51The greatest positive integer k, for which 49^k +1 is a factor of the sum 49^125+49^124+⋯+49^2+49+1
The greatest positive integer k, for which 49^k +1 is a factor of the sum 49^125+49^124+⋯+49^2+49+1
Просмотров 23День назад
The greatest positive integer k, for which 49^k 1 is a factor of the sum 49^125 49^124 ⋯ 49^2 49 1
If |z/(z+i)| = 2 represents a circle with centre P then distance of P from point D(1,5) is |JEE MAIN5:12If |z/(z+i)| = 2 represents a circle with centre P then distance of P from point D(1,5) is |JEE MAIN
If |z/(z+i)| = 2 represents a circle with centre P then distance of P from point D(1,5) is |JEE MAIN
Просмотров 78День назад
If |z/(z i)| = 2 represents a circle with centre P then distance of P from point D(1,5) is |JEE MAIN
If the equation a(b-c)x^2 +b(c-a)x+c(a-b)=0 has equal roots and if a+c= 5 and b= 16/5 |JEE MAIN 20254:40If the equation a(b-c)x^2 +b(c-a)x+c(a-b)=0 has equal roots and if a+c= 5 and b= 16/5 |JEE MAIN 2025
If the equation a(b-c)x^2 +b(c-a)x+c(a-b)=0 has equal roots and if a+c= 5 and b= 16/5 |JEE MAIN 2025
Просмотров 4114 дней назад
If the equation a(b-c)x^2 b(c-a)x c(a-b)=0 has equal roots and if a c= 5 and b= 16/5 |JEE MAIN 2025
How many different words can be formed by jumbling the letters in the word MISSISSIPPI | JEE 20083:53How many different words can be formed by jumbling the letters in the word MISSISSIPPI | JEE 2008
How many different words can be formed by jumbling the letters in the word MISSISSIPPI | JEE 2008
Просмотров 2214 дней назад
How many different words can be formed by jumbling the letters in the word MISSISSIPPI | JEE 2008
4 boys and 3 girls are to be seated in a row such that all girls sit together and two |JEE MAIN 20252:574 boys and 3 girls are to be seated in a row such that all girls sit together and two |JEE MAIN 2025
4 boys and 3 girls are to be seated in a row such that all girls sit together and two |JEE MAIN 2025
Просмотров 33614 дней назад
4 boys and 3 girls are to be seated in a row such that all girls sit together and two |JEE MAIN 2025
If ∑[r=1 to 30] r² * (³⁰Cᵣ)² / (³⁰Cᵣ₋₁) = α * 2²⁹, then find the value of α | JEE MAIN 2025 Binomial9:40If ∑[r=1 to 30] r² * (³⁰Cᵣ)² / (³⁰Cᵣ₋₁) = α * 2²⁹, then find the value of α | JEE MAIN 2025 Binomial
If ∑[r=1 to 30] r² * (³⁰Cᵣ)² / (³⁰Cᵣ₋₁) = α * 2²⁹, then find the value of α | JEE MAIN 2025 Binomial
Просмотров 14714 дней назад
If ∑[r=1 to 30] r² * (³⁰Cᵣ)² / (³⁰Cᵣ₋₁) = α * 2²⁹, then find the value of α | JEE MAIN 2025 Binomial
The sum of the following series 1 + 6 + 9(1^2 + 2^2 + 3^2)/7 + 12(1^2 + 2^2 + 3^2 + 4^2)/9 | JEE6:54The sum of the following series 1 + 6 + 9(1^2 + 2^2 + 3^2)/7 + 12(1^2 + 2^2 + 3^2 + 4^2)/9 | JEE
The sum of the following series 1 + 6 + 9(1^2 + 2^2 + 3^2)/7 + 12(1^2 + 2^2 + 3^2 + 4^2)/9 | JEE
Просмотров 2614 дней назад
The sum of the following series 1 6 9(1^2 2^2 3^2)/7 12(1^2 2^2 3^2 4^2)/9 | JEE
The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is | JEE Mains 20164:37The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is | JEE Mains 2016
The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is | JEE Mains 2016
Просмотров 2014 дней назад
The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is | JEE Mains 2016
Let ω be a complex number such that 2ω+1 = z, where z = √-3 if |1 1 1, 1 -ω^2-1 ω^2, 1 ω^2 ω^7|5:02Let ω be a complex number such that 2ω+1 = z, where z = √-3 if |1 1 1, 1 -ω^2-1 ω^2, 1 ω^2 ω^7|
Let ω be a complex number such that 2ω+1 = z, where z = √-3 if |1 1 1, 1 -ω^2-1 ω^2, 1 ω^2 ω^7|
Просмотров 1414 дней назад
Let ω be a complex number such that 2ω 1 = z, where z = √-3 if |1 1 1, 1 -ω^2-1 ω^2, 1 ω^2 ω^7|
The six digit numbers that can be formed using digits 1, 3, 5, 7, 9 such that each | JEE Main 20203:40The six digit numbers that can be formed using digits 1, 3, 5, 7, 9 such that each | JEE Main 2020
The six digit numbers that can be formed using digits 1, 3, 5, 7, 9 such that each | JEE Main 2020
Просмотров 1314 дней назад
The six digit numbers that can be formed using digits 1, 3, 5, 7, 9 such that each | JEE Main 2020

Комментарии

  • @Prashanth-x4c
    @Prashanth-x4c День назад

    Thank you sir

  • @ShivaDagar-fe3bu
    @ShivaDagar-fe3bu 3 дня назад

    ❤❤❤❤

  • @shiwamsclasses
    @shiwamsclasses 4 дня назад

    You can check two other ways to do the same questions here . 1) ruclips.net/video/eCVAkksH13A/видео.htmlsi=bD9nLFfW5syvkJ5n 2) ruclips.net/video/C95WiaMmpNM/видео.htmlsi=lPIHD0HxMSN9vyDF

  • @cutetofulabrador3928
    @cutetofulabrador3928 4 дня назад

    Thanks

  • @otgarpit
    @otgarpit 7 дней назад

    ❤😂

  • @Divyansh-Dubey99
    @Divyansh-Dubey99 7 дней назад

    Where is your offline coaching in Arrah sir ?

  • @AdityaKumarSingh-j1g
    @AdityaKumarSingh-j1g 10 дней назад

    Nice explanation sir

  • @mayajoshi501
    @mayajoshi501 13 дней назад

    Sir please tell how do you guess denominotor in 8:21

    • @shiwamsclasses
      @shiwamsclasses 13 дней назад

      Great question. Focus on the first element of the denominator, it will be of the form n*(n-1) + 1 i.e. (1*0 + 1) , (2*1+1), (3*2 +1)...so last one will be (10*9+1) and then for second term we need to add 2n to the first term.

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 14 дней назад

    Excellent.💯

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 14 дней назад

    Excellent Sir 💯

  • @raghvendrasingh1289
    @raghvendrasingh1289 17 дней назад

    👍 or 2(1/3 - 1/4 +1/5 -.....) = 2 ( ln 2 - 1/2) = ln (4/e)

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 20 дней назад

    Excellent💯

  • @raghvendrasingh1289
    @raghvendrasingh1289 24 дня назад

    👍 a^3+b^3+c^3+d^3 = (a+b+c+d)^3 - 3(a+b+c+d)(ab+ac+ad+bc+bd+cd) + 3(abc+bcd+cda+dab) = 3^3 - 3(3)( - 2)+3( - 3) = 27+18 - 9 = 36

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 25 дней назад

    Excellent Sir. 💯 Thank you so much. 😊

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 26 дней назад

    Excellent Sir 💯. Thank you so much😊

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 26 дней назад

    Nice explanation Sir. 😊

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 26 дней назад

    Excellent Sir 💯. Thank you very much. 😊

    • @shiwamsclasses
      @shiwamsclasses 26 дней назад

      I'm glad you found the explanation helpful!

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 27 дней назад

    Nice explanation Sir 😊

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 27 дней назад

    Excellent, Sir 💯. Thank you very much😊.

  • @SubhamGhosh-s5v
    @SubhamGhosh-s5v 27 дней назад

    Wow ❤ Excellent calculation. 💯💯

    • @shiwamsclasses
      @shiwamsclasses 27 дней назад

      I'm glad you found the calculation clear!

    • @SubhamGhosh-s5v
      @SubhamGhosh-s5v 27 дней назад

      @shiwamsclasses Thank you Sir. 😊

  • @raghvendrasingh1289
    @raghvendrasingh1289 Месяц назад

    👍 consider diagram at 4:00 hypotenuse of right angled isosceles triangle with vertices (0,0) , (3,0) & (0,3) is 3√2 hence r = 3√2/2 finally R+r = 9√2/2 because in an equilateral triangle R = 2r

  • @raghvendrasingh1289
    @raghvendrasingh1289 Месяц назад

    or eliminating y (1+m^2)x^2- 4 x+1/m^2 = 0 for equal roots b^2 = 4 ac 4 = 1+1/m^2 m = 1/√3 , - 1/√3

  • @raghvendrasingh1289
    @raghvendrasingh1289 Месяц назад

    👍 slope of normal at P(x,y) = - y/3 hence (y+8)/(x-5) = - y/3 3 y+24 = 5 y - y^3/6 y^3 - 12 y+144 = 0 y = - 6 x = 6 slope of tangent = 3/y = -1/2 let Q is (-3/2 , k) (k+6)/(-3/2 - 6) = -1/2 k+6 = 15/4 k = -9/4

    • @shiwamsclasses
      @shiwamsclasses Месяц назад

      Nice approach to the problem. Well done.

  • @sanjuktaseth2421
    @sanjuktaseth2421 Месяц назад

    5:21 well i just solved seeing only a thumbnail 😂

  • @chakravarthiponmudi1418
    @chakravarthiponmudi1418 Месяц назад

    please explain step by step here all not a genius

    • @shiwamsclasses
      @shiwamsclasses 6 дней назад

      Thanks for your comment. Here is another video explaining in detail : ruclips.net/video/mS4w1gNF2EU/видео.html. Please let me know if you have any questions

  • @Deepak-j3h
    @Deepak-j3h Месяц назад

    Sir aap online padhate ho mujhe bhi batch lena hai online wala

    • @shiwamsclasses
      @shiwamsclasses Месяц назад

      Main iss website pe online classes leta hoon -> www.urbanpro.com/bangalore/shiwam-iit-graduate-mathematics-expert-for-iit-jee-main-advance-10th-11th-12th . Reach out to me here and we can discuss.

  • @sonikakumari6106
    @sonikakumari6106 Месяц назад

    Thank u so much Sir.. But ek doubt hai -8 kyu nhi lenge answer mein?

    • @shiwamsclasses
      @shiwamsclasses Месяц назад

      Aap agar summation ∑ D k wala dekhoge to samajh mein aayega ki n ek positive integer hai. Summation wale part mein k,1 to n vary kar raha hai so humko usse positive integer treat karna padega.

    • @sonikakumari6106
      @sonikakumari6106 Месяц назад

      @@shiwamsclasses ok thank-you sir

  • @Mriitian-i7p
    @Mriitian-i7p Месяц назад

    ❤❤❤❤

  • @ynes9238
    @ynes9238 Месяц назад

    💀💀

  • @KartikChandRamola
    @KartikChandRamola 2 месяца назад

    Sir explain b karna hota hai

    • @shiwamsclasses
      @shiwamsclasses Месяц назад

      You are right. I should make a longer detailed video on this explaining all the steps.

  • @AdityaKankate-o1f
    @AdityaKankate-o1f 2 месяца назад

    a aur d mae confusion hota hai

  • @AdityaKankate-o1f
    @AdityaKankate-o1f 2 месяца назад

    Sir d thike likho

    • @shiwamsclasses
      @shiwamsclasses 2 месяца назад

      OK, ye Pehle ka video hai. Aage ke videos Mein dhyan rakhoonga.

  • @moti6288
    @moti6288 2 месяца назад

    Great efforts

  • @kaunshivansh
    @kaunshivansh 3 месяца назад

    Great Explaination!

    • @shiwamsclasses
      @shiwamsclasses 28 дней назад

      Thank you! I'm glad you found the explanation helpful.

  • @rajyvardhansinghjadon5331
    @rajyvardhansinghjadon5331 3 месяца назад

    This video is reason why everyone should not take maths

  • @SojibDesigner-q2j
    @SojibDesigner-q2j 3 месяца назад

    Hello Boss, U need a professional RUclips thumbnail Desigher? Thanks.

  • @SojibDesigner-q2j
    @SojibDesigner-q2j 3 месяца назад

    Hello Boss, Are you looking for a professional RUclips thumbuil desigher.

  • @Omniman-tp7tw
    @Omniman-tp7tw 5 месяцев назад

    That is a great way to explain to kids why triangles add up 180 degrees considering that I’m Primary 6.

    • @shiwamsclasses
      @shiwamsclasses 5 месяцев назад

      Thank you for the kind words! It’s always rewarding to hear that my explanations resonate with learners like you.

  • @sanatan-k5s
    @sanatan-k5s 5 месяцев назад

    Amazing 🥸

  • @annthomas4411
    @annthomas4411 5 месяцев назад

    Finally.Someone who likes maths.

  • @Sweet__boy_12_12--insta
    @Sweet__boy_12_12--insta 5 месяцев назад

    90

    • @shiwamsclasses
      @shiwamsclasses 5 месяцев назад

      That's correct! You can also watch the solution video here : ruclips.net/user/shortsyEt2E-MvRRM

  • @ManitaRani-j2l
    @ManitaRani-j2l 5 месяцев назад

    ❤❤

  • @sarthakrathor-109
    @sarthakrathor-109 5 месяцев назад

    90

    • @shiwamsclasses
      @shiwamsclasses 5 месяцев назад

      That's correct! You can also watch the solution video here : ruclips.net/user/shortsyEt2E-MvRRM

  • @Aswin2009.4
    @Aswin2009.4 6 месяцев назад

    that is a truth in my life

  • @sanatan-k5s
    @sanatan-k5s 6 месяцев назад

    😮

  • @coolxify
    @coolxify 6 месяцев назад

    ❤ fax

  • @Eyeswideopennow70
    @Eyeswideopennow70 6 месяцев назад

    Be a Monster and Learn to be Humble, mistake kindness for weakness and the Monster come for you

  • @Eyeswideopennow70
    @Eyeswideopennow70 6 месяцев назад

    Truth Be Told

  • @Buy_YT_Views_21122
    @Buy_YT_Views_21122 7 месяцев назад

    The use of natural lighting in certain scenes adds an organic feel to the visuals. It's a subtle touch that contributes to the authenticity of the video.

  • @jeffreyking5278
    @jeffreyking5278 Год назад

    *Promo SM* ⭐