Vishwanath Nagaraj
Vishwanath Nagaraj
  • Видео 1 541
  • Просмотров 48 674
Archimedes - OTSC - I - Proposition 38
The solid figure described as before in a segment of a sphere less than a hemisphere, together with the cone whose base is the base of the segment and whose apex ts the center of the sphere, ws equal to a cone whose base is equal to the surface of the inscribed solid and whose height is equal to the perpendicular from the center of the sphere on any side of the polygon.
Просмотров: 9

Видео

Archimedes - OTSC - I - Proposition 37
Просмотров 172 часа назад
The surface of the solid figure inscribed in the segment of the sphere by the revolution of LK...A...K’L’ about $AM$ is less than a circle with radius equal to AL
Euclid's Book 8 - Proposition 12
Просмотров 102 часа назад
Between two cubic numbers there are two mean proportional numbers, and the cube has to the cube the triplicate ratio of that which the side has to the side. ruclips.net/video/vDbc-abLj9w/видео.html
Archimedes - OTSC - I - Proposition 36
Просмотров 77 часов назад
The surface of the figure inscribed as before in the segment of a sphere is less than that of the segment of the sphere.
Archimedes - OTSC - I - Proposition 35
Просмотров 277 часов назад
If in a segment of a circle LAL’ (where A is the middle point of the arc) a polygon LK... A.... K'L’ be inscribed of which LL’ is one side, while the other sides are 2n in number and all equal, and if the polygon revolve with the segment about the diameter AM, generating a solid figure inscribed in a segment of a sphere, then the surface of the inscribed solid is equal to a circle the square on...
Archimedes - OTSC - I - Proposition 34
Просмотров 79 часов назад
Any sphere is equal to four times the cone which has its base equal to the greatest circle in the sphere and its height equal to the radius of the sphere. Corollary : Every cylinder whose base is the greatest circle in a sphere and whose height is equal to the diameter of the sphere is 3/2 of the sphere, and its surface together with its bases is 3/2 of the surface of the sphere.
Archimedes - OTSC - I - Proposition 33
Просмотров 1412 часов назад
The surface of any sphere is equal to four times the greatest circle in it. 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requires you to login to OneDrive please let me know in the comments.
Archimedes - OTSC - I - Proposition 32
Просмотров 3414 часов назад
If a regular polygon with 4n sides be inscribed in a great circle of a sphere, and a similar polygon be described about the great circle, and if the polygons revolve with the great circle about the diameters aa’, AA’ respectively, so that they describe the surfaces of solid figures inscribed in and circumscribed to the sphere respectively, then 1. the surfaces of the circumscribed and inscribed...
Archimedes - OTSC - I - Proposition 31
Просмотров 1819 часов назад
The Proposition says that volume of the solid of revolution of the polygon is equal to the volume of a cone (base is equal to the surface of the solid and height is equal to the radius of the sphere. Corollary : The solid circumscribed about the smaller sphere is greater than four times the cone whose base is a great circle of the sphere and whose height is equal to the radius of the sphere. 1d...
Archimedes - OTSC - I - Proposition 30
Просмотров 2421 час назад
The surface of a figure circumscribed as before about a sphere as greater than four times the great circle of the sphere. 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requires you to login to OneDrive please let me know in the comments.
Archimedes - OTSC - I - Proposition 29
Просмотров 30День назад
In a figure circumscribed to a sphere in the manner shown in the previous proposition the surface 1s equal to a circle the square on whose radius is equal to AB x (BB’ CC’ ...). 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requires you to login to OneDrive please let me know in the comments.
Archimedes - OTSC - I - Proposition 28
Просмотров 42День назад
The surface of the figure circumscribed to the given sphere is greater than that of the sphere itself. 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requires you to login to OneDrive please let me know in the comments.
Archimedes - OTSC - I - Proposition 27
Просмотров 2314 дней назад
The figure inscribed in the sphere as before is less than four times the cone whose base is equal to a great circle of the sphere and whose height is equal to the radius of the sphere. 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requires you to login to OneDrive please let me know in the comments.
Archimedes - OTSC - I - Proposition 26
Просмотров 1714 дней назад
The figure inscribed as above in a sphere ts equal [in volume] to a cone whose base is a circle equal to the surface of the figure inscribed in the sphere and whose height is equal to the perpendicular drawn from the center of the sphere to one side of the polygon. 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requir...
Archimedes - OTSC - I - Proposition 25
Просмотров 2014 дней назад
The surface of the figure inscribed in a sphere as in the last propositions, consisting of portions of conical surfaces, is less than four times the greatest circle in the sphere. 1drv.ms/b/c/ecdf6ebf9ed7cd9b/EQLv-S9sTrdKphQxtdtpxbcBwxBqe_dpDEfGGxxQlvO4uQ?e=HwaeuL In case the above link does not work or requires you to login to OneDrive please let me know in the comments.
Archimedes - OTSC - I - Proposition 24
Просмотров 3914 дней назад
Archimedes - OTSC - I - Proposition 24
Archimedes - OTSC - I - Proposition 23
Просмотров 1714 дней назад
Archimedes - OTSC - I - Proposition 23
Archimedes - OTSC - I - Proposition 22
Просмотров 6214 дней назад
Archimedes - OTSC - I - Proposition 22
Archimedes - OTSC - I - Proposition 21
Просмотров 1221 день назад
Archimedes - OTSC - I - Proposition 21
Archimedes - OTSC - I - Proposition 20
Просмотров 2321 день назад
Archimedes - OTSC - I - Proposition 20
Archimedes - OTSC - I - Proposition 19
Просмотров 1521 день назад
Archimedes - OTSC - I - Proposition 19
Archimedes - OTSC - I - Proposition 18
Просмотров 1921 день назад
Archimedes - OTSC - I - Proposition 18
Archimedes - OTSC - I - Proposition 17
Просмотров 2621 день назад
Archimedes - OTSC - I - Proposition 17
Archimedes - OTSC - I - Proposition 16
Просмотров 3528 дней назад
Archimedes - OTSC - I - Proposition 16
Archimedes - OTSC - I - Proposition 15
Просмотров 3228 дней назад
Archimedes - OTSC - I - Proposition 15
Archimedes - OTSC - I - Proposition 14
Просмотров 4428 дней назад
Archimedes - OTSC - I - Proposition 14
Archimedes - OTSC - I - Proposition 13
Просмотров 24Месяц назад
Archimedes - OTSC - I - Proposition 13
Archimedes - OTSC - I - Proposition 12
Просмотров 21Месяц назад
Archimedes - OTSC - I - Proposition 12
Archimedes - OTSC - I - Proposition 11
Просмотров 16Месяц назад
Archimedes - OTSC - I - Proposition 11
Archimedes - OTSC - I - Proposition 10
Просмотров 22Месяц назад
Archimedes - OTSC - I - Proposition 10

Комментарии

  • @ksatyaprakashreddy5717
    @ksatyaprakashreddy5717 5 дней назад

    Good effort viswanadh Sir Hats off to you Sir

  • @Chillagma_Work-ok9kz
    @Chillagma_Work-ok9kz Месяц назад

    This is a milestone. You are the only channel i know that finished all 13 books on euclid! with 450+ propositions that is a monumnetal effort. If you had a place to donate i would do it. Thanks. I would love to know how you understand the logic of these with such clarity. That is an amazing gift!

    • @VishyKN
      @VishyKN Месяц назад

      @@Chillagma_Work-ok9kz Thank you sir for the compliment. Much much appreciated.

    • @askliro1
      @askliro1 18 дней назад

      You are amazing!!!

  • @TheBeast-gx1kw
    @TheBeast-gx1kw Месяц назад

    Thank you sir ❤

  • @ArchieUplifts
    @ArchieUplifts 2 месяца назад

    wonderful

  • @ArchieUplifts
    @ArchieUplifts 2 месяца назад

    Which tool do you use for geometric modelling??

    • @VishyKN
      @VishyKN 2 месяца назад

      @@ArchieUplifts GeoGebra.org

    • @VishyKN
      @VishyKN 2 месяца назад

      @@ArchieUplifts you can do it all on the website itself.

  • @ArchieUplifts
    @ArchieUplifts 2 месяца назад

    THANK YOU SOOOO MUCHHH

  • @Jotheswar.i
    @Jotheswar.i 2 месяца назад

    Tq sir use full vedios thanks 🎉❤

  • @rameshks8449
    @rameshks8449 2 месяца назад

    Well explained

    • @VishyKN
      @VishyKN 2 месяца назад

      Have you had a look at the pdf book. Any feedback would be appreciated.

    • @rameshks8449
      @rameshks8449 2 месяца назад

      @@VishyKN I will

  • @rameshks8449
    @rameshks8449 2 месяца назад

    Does it mean that the similar polygons areas are also in proportion.

    • @VishyKN
      @VishyKN 2 месяца назад

      @@rameshks8449 Thank you sir. Actually in 2D when we say a figure is to a figure as something is to something we are talking of their area. In case of solids it is volume.

    • @rameshks8449
      @rameshks8449 2 месяца назад

      @@VishyKN yes sir

  • @rameshks8449
    @rameshks8449 3 месяца назад

    Pls mark all points in Black Bold font easy to recognize

    • @VishyKN
      @VishyKN 3 месяца назад

      Can't change the caption font and color. Geogebra default settings get applied. Sorry about that.

    • @rameshks8449
      @rameshks8449 3 месяца назад

      @@VishyKN OK sir

    • @VishyKN
      @VishyKN 3 месяца назад

      Sir, took care of it. Have a look in this video ruclips.net/video/QNnF8nnbEWg/видео.html Proposition 11.22. Thanks for the feedback.

  • @rameshks8449
    @rameshks8449 3 месяца назад

    ಯೂಕ್ಲಿಡೀಯ ಚಿಂತನೆ ಎಷ್ಟು ಅದ್ಭುತ!

    • @VishyKN
      @VishyKN 3 месяца назад

      @@rameshks8449 so true

  • @rameshks8449
    @rameshks8449 3 месяца назад

    Greetings, are using one note to all these?

    • @VishyKN
      @VishyKN 3 месяца назад

      @@rameshks8449 Yes sir.

  • @rameshks8449
    @rameshks8449 3 месяца назад

    Very useful, sir. Must for all highschool students

    • @VishyKN
      @VishyKN 3 месяца назад

      @@rameshks8449 Thank you sir.

  • @askliro1
    @askliro1 5 месяцев назад

    Amazing!!!

  • @MartandPuri
    @MartandPuri 6 месяцев назад

    Sir I first time viewer I confused with terms 'medial '

    • @VishyKN
      @VishyKN 6 месяцев назад

      It would be better if you start from the 1st proposition of book 10. Most of these terms have been covered in previous propositions.

    • @VishyKN
      @VishyKN 3 месяца назад

      Dear Martand Puri, Have a look at ruclips.net/video/bYdctpLuoWY/видео.html. Formulas for the various terms used is given.

  • @punditgi
    @punditgi 8 месяцев назад

    Vishwanath Nagaraj, can you add the link to the download site for your notes in the Description of this video? I am not able to see the link in the video. Thank you! 😃

    • @VishyKN
      @VishyKN 8 месяцев назад

      Done Sir. Sorry about that.

    • @punditgi
      @punditgi 8 месяцев назад

      @@VishyKN Perfect! Thanks again. 😇

  • @punditgi
    @punditgi 8 месяцев назад

    Many thanks for your notes! 🎉😊

  • @JamesRoolvink
    @JamesRoolvink 8 месяцев назад

    Why not draw a line between B and D? Is that production of a proof less efficient? How to define less efficiency? Using less steps and/or less propositions? P.S. Where is the proof of prop. 42? P.P.S. Great video's!!!

    • @VishyKN
      @VishyKN 8 месяцев назад

      Hi James, We could have joined B and D rather than A and C. The steps in the proof would have been the same. In that case, the triangle BDC would have been equal to the triangle BEC since these triangles are also on the same base and between same parallel lines. The proof would not have been any more or less efficient. I believe that it not the number of propositions or steps that define efficiency but the ease of understanding. In any case, since we are looking at Euclid's Elements, I am being as faithful to his choices in developing the proof. Thank you for pointing out the missing Proposition 42. Can't figure out how I missed it. By the way, have you had a look at the Book. Any comments on that would be much appreciated. Thanks for the appreciation and feedback.

    • @VishyKN
      @VishyKN 8 месяцев назад

      Hi again, Just browsed through the playlist of Book 1. Euclid's Book 1 - Proposition 42 is there.

  • @fernandodaneri2611
    @fernandodaneri2611 11 месяцев назад

    Thanks!

  • @timhochstetler
    @timhochstetler Год назад

    if fb and fc are on the same point where b=c then fb=fc

    • @VishyKN
      @VishyKN Год назад

      True, but the definition of a circle says that on a circle all the points are equidistant from the center. So we are choosing two points - point of contact and an arbitrary point somewhere else for comparison. In any case, remember the center is the assumed center. If we take the actual center, FE and FB will not be equal at any point since the centers of the two circles are not the same.

  • @aa-gc3fg
    @aa-gc3fg Год назад

    Sir how it becomes (1+y)^n= n instead of (1+y)^n =x

    • @VishyKN
      @VishyKN Год назад

      Yes Sir, you are absolutely right. Follow the steps by incorporating the change and you should be able to arrive at the limit as n goes to infinity. Thank you for identifying the error. You should end up with p < sqrt(2x / (n(n-1)) which will tend to 0 as n goes to infinity.

  • @punditgi
    @punditgi Год назад

    Many thanks for your book! 😊

  • @punditgi
    @punditgi Год назад

    Excellent videos! 😊

  • @jyothis8630
    @jyothis8630 Год назад

    Interesting

  • @jyothis8630
    @jyothis8630 Год назад

    Good

  • @jyothis8630
    @jyothis8630 Год назад

    Good

  • @jyothis8630
    @jyothis8630 Год назад

    Super

  • @bushrathabassumshaik0616
    @bushrathabassumshaik0616 Год назад

    thanks alot sir understood it better now

  • @echooscar5241
    @echooscar5241 Год назад

    Very nice video! Which program did you use to make the diagrams?

  • @TheThinkingMathematician
    @TheThinkingMathematician Год назад

    great video

  • @singingkakida4945
    @singingkakida4945 Год назад

    Sir I have searched many video but after scrolling many video I got yours ..no one explain so clearly like you..thnku sir .I will play this vdo to my class room

    • @VishyKN
      @VishyKN Год назад

      You are most Welcome. 🙏

  • @sharmaproductions9459
    @sharmaproductions9459 Год назад

    Namaste sir! Could you please update the link of the excel sheet. Currently there is an error when i try to download the excel sheet.

    • @VishyKN
      @VishyKN Год назад

      Kindly goto About page in which the working link is there.

  • @detectiveandspynovels7140
    @detectiveandspynovels7140 Год назад

    One of the best video.♥️♥️♥️♥️♥️♥️♥️

  • @avarts4432
    @avarts4432 Год назад

    Well explained:),thanks

  • @maleksalih5237
    @maleksalih5237 Год назад

    Wonderful

  • @punditgi
    @punditgi Год назад

    Many thanks for this book! 😊

  • @punditgi
    @punditgi Год назад

    Namaste-ji! Donnyavad. 😊

  • @kruthikavishwanath3748
    @kruthikavishwanath3748 2 года назад

    Very informative

  • @kruthikavishwanath3748
    @kruthikavishwanath3748 2 года назад

    ohh using function..great!

  • @kruthikavishwanath3748
    @kruthikavishwanath3748 2 года назад

    awesome

  • @kruthikavishwanath3748
    @kruthikavishwanath3748 2 года назад

    explained very well

  • @kruthikavishwanath3748
    @kruthikavishwanath3748 2 года назад

    good explanation

  • @kruthikavishwanath3748
    @kruthikavishwanath3748 2 года назад

    very informative 🤌

  • @harshaswaraj726
    @harshaswaraj726 2 года назад

    👍

  • @shivasmart967
    @shivasmart967 2 года назад

    tq sir

  • @amithkumars562
    @amithkumars562 2 года назад

    Can we have a closed form equation for a quintic equation?

  • @sksadstatus5672
    @sksadstatus5672 2 года назад

    Well Explained Sir 🙂

    • @VishyKN
      @VishyKN 2 года назад

      Thank you sir.

  • @punditgi
    @punditgi 2 года назад

    Many thanks for your very instructive videos! 😃

    • @VishyKN
      @VishyKN 2 года назад

      Well, i am really having fun making them. If it benefits others, thats a bonus.

    • @punditgi
      @punditgi 2 года назад

      @@VishyKN Definitely a huge benefit for all math students! 👍

  • @punditgi
    @punditgi 2 года назад

    Excellent topic! 😃

  • @punditgi
    @punditgi 2 года назад

    Good topic! 😃

    • @VishyKN
      @VishyKN 2 года назад

      Thank you sir.