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This can be solved in one's head - the answer is 1/9.

Oga go and learn forex trading and help your life

just multiply both sides by 2 and you have the answer.

(3x+2)(x-2)=0 x=2 x=-2/3=0.6 recurring I don’t have to think about it.

3x^2+x-2=0 x=-1 x=2/3=0.6 recurring final answer

Краткость и точность Сестра таланта , а математика точная наука . С таким подходом в такие дебри можно уйти , прямо в дремучий лес и не выбраться . Хотя я очень далека от математики . Тут бла бла бла .

Как же усложнил элементарное решени .

Took me less than 15s to determine that X =3,

Se l'equazione ammette soluzioni razionali, esse vanno ricercate tra i divisori di 36. A tentativi si trova x = 3. (x^3+ x^2 - 36) : (x - 3) = x^2 + 4x+ 12. Uguagliando a 0 si trovano le soluzioni complesse.

Что происходит??? Тебя кто математике учил???

Ааааа, это они своих учат😂

О,боже,что творится!С первого взгляда увидела,что показатели степени равны,значит основания тоже равны.х равно 3. Мне 70 лет,не математик.К чему это блеяние, чтобы детям мозг вынести?

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1

Simply factoring,(x-1) (x-4) =0 X -1=0,x=1 & x-4=0,x=4 So solution x=(1,4)

2

(x²)² -[(x-1)²]²=0 (x²-(x-1)²)(x²+(x-1)²)=0 (x²-x²+2x-1)(x²+x²-2x+1)=0 (2x-1)(2x²-2x+1)=0 2x-1=0 or 2x²-2x+1=0 2x=1 or x=[-(-2)+-✔ 4-4.(2)(1)]/4 x=1/2 or x=[2±✔-4]/4 x=1/2 or x=[2±✔ 2².i²]/4 x=1/2 or x=[2±2i]/4 x=1/2 or x=1/2 ±i/2 The three solutions are x1=1/2 x2=(1+i)/2 x3=(1-i)/2

0,(1).

Il suffit de mettre 2/3 en exposant. X=3

I use the method parcial of derivates. F(x)2x^4 = 8x^3 F'(x)8x^3 = 24x^2 F"(x) 24x^2 = 48x 48x = 32 x = 32 / 48 x = 0.66666 I check demostrate. 0.66666*2*4*3*2 = 32 32 = 32

Apply derivative function and enjoy! Much faster and easier.

You can using,the method parcial of derivates. F(x) x^4 = 4x^3 F'(x)4x^3 = 12x^2 F(x)12x^2 = 24x 24x = 16 x = 16/24 x = 0.66666 We demostrate. 0.66666*4*3*2 = 16 16= 16

Не могу понять ,почему он +х-2 заменил на 1 ? объясните, плиз..... Я бы решала совсем по-другому....)))))))))))

من المغرب اقول لك انك أخطأت

√ x=y y > 0 y/y^2=2 1/y=2 y=1/2 x=y^2=1/4

Am i missing something? I feel like i am. And i dont mean that sarcastically. Im guessing the work to get there was the hard bit and not the solution? The solution i had in a few seconds (cant be 1 or >3 therefore has to be 2.), which isnt a brag, i legitimately feel i'm missing something here.

In my head

Thanks

Х^3/2= З^3/2; Х✓Х=З✓З; Х=З;

1st method is false, x can't be equal to 0

this is not the final answer you lie

У нас в классе была девочка, которая два на три умножала в столбик.

2

2×2×2+2=10

Y is equal to 8

(x^4 ➖ 16}={x^0+x^0 ➖}=x^1 (x ➖ 1x+1).

Нахрена считать это просто х=2😂

What is "i" ?

2×2×2+2=10

Merci

Pourquoi faire simp,e quand on peut faire compliqué. (x+3)²=3² égale x+3=3 ou x+3=-3

x^4=(x-2)^4 x=1 x=1±i

Pourquoi faire simple quand on peut faire compliqué !

x є R !!! 😡

Это не решение а мудистика

1×1×1+9=10😂

2

2×2×2+2=10

Х³+Х=10 ; Х³+Х=8+2; Х³-8=2-Х Х³-8=0; 2-Х=0; Х³=8; -Х=-2 Кубический корень из 8=2 ;Два минуса при умножении дают плюс.Х=2.Вот и все коротенькое решение примера из алгебры за 8й класс ,1982 год.

Для Олимпиады очень простой пример. 2*2*2+2=10