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EssEssBii Education
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Добавлен 16 фев 2024
Welcome to my RUclips channel, where I provide clear and concise tutorials on mathematics. Whether you're a student looking to strengthen your understanding or someone interested in exploring further, my channel offers step-by-step explanations, problem-solving strategies, and practical tips to help you excel in your studies. Join me on this journey to mastering complex concepts with ease!
Germany| Math Olympiad | A Nice Algebra Problem | Find value of x
Hi Everyone ☺️
In this video I'll solve A Nice Math Olympiad Algebra Problem x/7*x/7=7/x*7/x for x with full explanation. If you like my video then
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In this video I'll solve A Nice Math Olympiad Algebra Problem x/7*x/7=7/x*7/x for x with full explanation. If you like my video then
Please Like 👍 Share 🔀 and SUBSCRIBE ✅
Popular Videos Links:-
1. Japanese -Math Olympiad Question
ruclips.net/video/WQZZsdif0lY/видео.html
2. Brazil Math Olympiad Question
ruclips.net/video/asdsYglWXcQ/видео.html
3. Simplify Square Root Problem
ruclips.net/video/vI79rLdiKkM/видео.html
4. Thailand Math Olympiad Question
ruclips.net/video/gHBHin9JOFE/видео.html
5. A Nice Math Olympiad Question
ruclips.net/video/glrK0-03uVQ/видео.html
Your Queries:-
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how to solve olympiad maths problems
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Просмотров: 11
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25x = 250 x = log 250 / log 25 x = 1.71534 25^1.71534 = 250
Concise solution but i did without calculator
x=log250/log25=(log25+log10)/log25=1+1/2log5 x≈1+1/(2×0.699)≈1199/699≈1.71532 Deviation is about 0.00003 25^1.71532≈249.985
It was a good attempt but i did without a calculator
x=log180/log6=(2log6+log5)/log6=2+log5/(log2+log3) x≈2+0.699/(0.301+0.477)≈2255/778≈2.898 Deviation is about 0.0002 6^2.898≈179.92
@AlexanderSemashkevich it was good attempt but i did without a calculator
You can simplify it further by doing: 4^x = 16 * 3 Taking log base 4 on both sides, x = log4(16*3) x=log4(16) + log4(3) x=2+log4(3) You can do it with the answer you found aswell by seeing that 1+log4(12) = 1+log4(4*3) = 1+log4(4)+log4(3) = 2+log4(3)
This can also be one solution as well. Good Attempt 👍
GOODBYE
I think you should have explained in more detail the following: 5*√3*i × (-5)*√3*i = (-25)*(+3)*(-1) = (-75)*(-1) = +75 ✓
Absolutely I'll explain more next time
x=2?
Not at all.
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x=log50/2log5=(log5+log10)/2log5≈(0.7+1)/(2×0.7)≈17/14≈1.214. Deviation is about 0.001.
Good attempt but we have to solve it without using a calculator
Mai class 10 ke student ho fbise board sai and Menai thumnail daikh kr question solve kiya and ans check krnai kai liai ap ke video daikhe or mera answer sai hai. yai tricky problem hai? 🤔9th and 10th ke math per yai concept he to pera hai.
15×256²=983040.
Yes without calculator
x=log15/log3=(log3+log5)/log3≈(0.48+0.7)/0.48≈59/24≈2.4583. Deviation of only 0.0066.
Good attempt
Firstly, you should not write "log" without giving any base. Many people write "log()" intending base 10 (Caution: other people intend base e then, which is "ln()" !), but they should write "log_10_()" or just "lg()" instead. Secondly, it is more straightforward to use the base 4 for the logarithm, as the exponential equation has base 4, too: 4^x = 48 x = log_4_(48) x = 2.79248... In this form, you can type in into many modern calculators to get the numerical value of the solution x. However, if you want to simplify this, you can write = log_4_(16 * 3) = log_4_(16) + log_4_(3) = log_4_(4^2) + log_4_(3) = 2 + log_4_(3) If you want to transform it to base 10, which I write lg(), you can use the base converting rule: log_4_(...) = lg(...) / lg(4) In this case x = 2 + log_4_(3) = 2 + lg(3)/lg(4) which is equal to = 1 + log_4_(12) given in the video. Instead of lg(), you can also use ln() in the numerator and denominator of these fractions. It doesn't really matter which base you use. The reason for using lg or ln is that many older or weaker calculators offer only one type of logarithm to a fixed base, namely 10 or e. But as I said, better calculators usually offer a general "log" key, which allows to set an arbitrary (positive) base, like 4 in this case, so you don't need the base converting rule anymore.
x=log48/log4=(log6+log8)/log4≈(0,78+0,9)/0,6≈1,68/0,6≈14/5. Absulute error is about 0,0075.
Good effort. I solved it without calculator
x^2/36=36/x^2 => x^2/36 = 1/ x^2/36 /*(x^2/36) => x^4/36^2 = 1 => x^4=36^2 => x^2=36 => x=6
Complicated.
Oh😢
As x^2/36=x^2/36 X^2/x^2= 36/36 X^4 = 1296 (36x36) X = 4√1296 = 144
Do it again
I'll try
X is 144
This in an exercise on how to make a simple sum complicated! Consider 8^8=(((8^2)^2)^2=(64^2)^2=4,096^2=16,777,216. So 8^8-88=16,777,128. The multiplication involved is trivial.
Good work. My solution involves more steps
Hello? I have used your thumbnail a little bit. Would you mind if I ask could you see my solution way please? :)
Your solution is very to the point.
@EssEssBiiEducation yeah, I agree. I used to find formula simple way. Thank you.
Welcome
16^5 - 16^4 = 16^4 ( 16 - 1 ) 16 ^4 (15)
Follow more steps
Japanese Math Olympiad Question: √(x + 2) + √(x - 4) = 6; x =? 6 > √(x + 2) > √(x - 4) > 0; Let: y = x - 1, x + 2 = y + 3, x - 4 = y - 3 √(x + 2) + √(x - 4) = √(y + 3) + √(y - 3) = 6, [√(y + 3) + √(y - 3)]² = 6² (y + 3) + 2√[(y + 3)(y - 3)] + (y - 3) = 36, √(y² - 9) = 18 - y, y² - 9 = (18 - y)² y² - 9 = y² - 36y + 18², 36y = 18² + 9, y = [9(36 + 1)]/36 = 37/4 = x - 1, x = 41/4 Answer check: √(x + 2) + √(x - 4) = 6 x = 41/4: √(41/4 + 2) + √(41/4 - 4) = √(49/4) + √(25/4) = 7/2 + 5/2 = 6; Confirmed Final answer: x = 41/4 = 10.25
You can solve it this way also
What was the shortcut promise in description of video?
We have expanded using elementary row operations to create zeros in one row.
(15)16^4 = (15) 2^16 = (15)(1024)(64) = (30)(512)(64) = (15360)(60+4) = 921600+61440 = 983040
Good work
much easier way is not this way.
This way is much easier than others.
❤
If everyone at the Olympics were as fast as you, the world record for 100 meters would be at 3 h 15 min and 29 sec.
x^4 = 4^4 x^2 = +/- 16 x = +/- 4, +/- 4i
Man, you just do complex 4th root from 4^4 ... that is a one-liner...
SIR SIR SIR SIR HELLO SIT
5^(х-2)=5^2 X-2=2 X=4
Cut the BS. Factor 4^x out without using the fancy 2-1
The answer will be same.
@ Yes of course, and that’s my point.
1) Factor out √5 top and bottom and cancel leaving (√6+1)/(√6-1) 2) Rationalize the denominator
Since the cube of m is bigger than its square when |m| > 1, a real root will be where |m|^3 is a bit less than 150. That suggests |m| = 5. Then m^2 - m^3 = 25 - (-125) = 150, making m = -5. We can now factorise m^3 - m^2 + 150 = 0 because (m + 5) is a factor. So let (m + 5)(m^2 + Am + 30) be the factorisation, then we can see that A = -6 makes the coefficient of m equal to 0. Solve m^2 - 6m + 30 with the quadratic formula x = -(b/2) ± √( (b/2)^2 - ac) = 3 ± √(9 - 30) = 3 ± i√21
brilliant video g
Answering without watching the video Quite a simple question with a little trick to it. Took less tha a min to solve with pure metal calculation Ans: -5
33% .... Fail. 😋
at 1:39 you can't put a bracket with a minus outside without multiplying the terms inside with -1
you fail to prove that 5*(log2/log5)=2
No. Log2/log5 can be written as log 2 with base 5 then proved
Your solution is wrong the log won't be used separately for the lhs the whole term will be under a single log function
Log(a+b)=loga +log b
@EssEssBiiEducation nooo log(ab) = log(a) + log(b) ....not log(a+b) =log( a)+ log (b)
@EssEssBiiEducation the correct answer to ur question is ln (3.2) / ln2 = 1.67
Perhaps 2*x+1)+(2*x-1)=.2*x (2+1/2) =2*x5/2=8 2*x=16/5 Xlog2=log2*4+log1/5 X=4-(log5/log2)
Die Mathematik (bundesdeutsches Hochdeutsch: [matemaˈtiːk], [matemaˈtik]; österreichisches Hochdeutsch: [mateˈmaːtik];[1] von altgriechisch μαθηματικὴ τέχνη mathēmatikē téchnē ‚die Kunst des Lernens‘) ist eine Formalwissenschaft, die aus der Untersuchung von geometrischen Figuren und dem Rechnen mit Zahlen entstand. Für Mathematik gibt es keine allgemein anerkannte Definition; heute wird sie üblicherweise als eine Wissenschaft beschrieben, die durch logische Definitionen selbstgeschaffene abstrakte Strukturen mittels der Logik auf ihre Eigenschaften und Muster untersucht. Reutersvärd-Dreieck, das im Kern eine Segmentierung des Penrose-Dreiecks ist, als Veranschaulichung für unmögliche Figuren, die eine Schnittstelle zwischen Kunst und Mathematik darstellen0:14
Seriously?
Haha, so, now, 1 = 2 Illogical
Germany Math Olympiad Problem: (3ˣ)(3ˣ)(3ˣ) = 21; x =? (3ˣ)(3ˣ)(3ˣ) = 3³ˣ = 21, 3x = log₃21 = log₃3 + log₃7 = 1 + 1.771, x = 2.771/3 = 0.924 The calculation was achieved on a smartphone with a standard calculator app Answer check: x = 0.924, 3x = log₃21: (3ˣ)(3ˣ)(3ˣ) = 3³ˣ = 3^log₃21 = 21; Confirmed Final answer: x = (log₃21)/3 = 0.924
Calculation lengthy and confusing.
❤
Tnx bro😊😊