Jago Alexander
Jago Alexander
  • Видео 9
  • Просмотров 153 435
The Integral of your Nightmares | Bernoulli's Integral
🎥 The Infamous Bernoulli Integral Solved! 📚🔥
Have you ever wondered if the impossible can be achieved? In this video, I tackle the legendary Bernoulli integral, also known as the integral of x^x, and provide a detailed solution. This complex math problem has puzzled mathematicians for years, but today, we break it down step-by-step. Join me on this incredible math journey and see how we conquer the impossible!
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Просмотров: 3 717

Видео

Essential Derivatives to Learn For Calculus Students
Просмотров 1,1 тыс.16 часов назад
🌟 Today, I'm breaking down the differentiation of two mind-bending functions: x^x and x^x^x. These aren't your everyday derivatives, and mastering them will give you serious bragging rights in any maths circle. In this video, I'll guide you step-by-step through the differentiation process, making complex concepts easy to understand. By the end, you'll not only know how to differentiate x^x and ...
The Hardest Integral From The Hardest Test (Putnam Exam)
Просмотров 39 тыс.21 час назад
🎥 The Putnam's Toughest Integral Solved! 📚🔥 Join me as I tackle one of the most challenging integrals from the Putnam Exam: the infamous integral x^-x ! In this video, we'll break down the problem step-by-step. Whether you're a math enthusiast, a student preparing for the Putnam Exam, or just curious about advanced calculus, this video is for you! 🔍 What You'll Learn: The Putnam Exam and its si...
The Gaussian Integral is DESTROYED by Feynman’s Technique
Просмотров 65 тыс.Месяц назад
In this video I demonstrate the method used to solve the Gaussian integral using Feynman’s integration technique, I was very excited to present this video as it combines 2 of the math world’s favourite internet concepts, the Gaussian integral and Feynman’s integration technique. If you are new here please consider subscribing and comment if you have any suggestions of improvements :) Link to or...
Solving a Cambridge University Integral (HARD)
Просмотров 3963 месяца назад
In this video I integrate this horrible looking integral using series expansions and many other tricks. It has a very satisfying solution. Subscribe for more maths videos
How to derive the Taylor Series for the natural logarithm
Просмотров 3363 месяца назад
In this video I derive the series expansion of ln(1 x) the cool way. Of course, thank you to Taylor Swift for coming up with this fantastic maths theory.
Finding the Reflections of Points and Lines in Vector PLANES (A-Level Further Maths)
Просмотров 1614 месяца назад
In this video I explain how to first find the reflection of a given point in a line. Then how to find the reflection of a given point in a plane, and finally how to find the equation of a line in a plane… This is for A-Level further maths Vectors topic. If you found this video helpful please like :)
Feynman’s Integration Technique Is TOO Powerful!
Просмотров 49 тыс.4 месяца назад
In this video I use maths’ / the internets most favourite integration technique known as Feynman’s technique or differentiation under the integral sign to evaluate a difficult integral of sins / x from zero to infinity. If you enjoyed this video please subscribe.
A-Level Further Maths: Finding Lines of Invariant Points and Invariant Lines
Просмотров 3977 месяцев назад
In this maths video I demonstrate how to find the lines of Invariant points and the Invariant lines of a given matrix. This video is for those studying A-Level Further Maths. This is from an Edexcel question, however the techniques demonstrated apply to all exam boards. If you would like to request a question for a video, don’t hesitate todem me in instagram @ jagoalexander

Комментарии

  • @lucascardoso5332
    @lucascardoso5332 Час назад

    That's funny. I solved this problem while in my second year of undergrad. I was at my friend's place and we had ordered pizza. He had just finished taking his first course on Calculus and I joked that he couldn't find the derivative of x^x, which he did. Then he challenged me to find the integral, which I did too. It was fun!

  • @B00MBASTIC
    @B00MBASTIC 2 часа назад

    Where’s the Family Guy and the Soap Cutting videos on the sides? Please consider adding them next video!

  • @giuseppemalaguti435
    @giuseppemalaguti435 3 часа назад

    1-1/4+1/27-1/256+1/3125-1/6^6...

  • @Chiavaccio
    @Chiavaccio 7 часов назад

    👏👏👏🔝

  • @cameronspalding9792
    @cameronspalding9792 8 часов назад

    @ 10:02 I think it should be Gamma(n+1) not Gamma(n-1)

    • @Jagoalexander
      @Jagoalexander Час назад

      Yes you are right, I made an error. Does not effect the rest of the video though

  • @ghostsofbeauty.9346
    @ghostsofbeauty.9346 10 часов назад

    3..

  • @sajanator3
    @sajanator3 11 часов назад

    Could you prove that the last part converges ?

  • @koenth2359
    @koenth2359 11 часов назад

    5:00 let y=x lnx, you say that lim[n to inf] (y^n/n!) = y. I don't believe that, I think it's 0. Wolfram alpha too.

    • @koenth2359
      @koenth2359 7 часов назад

      Here's the intuition: In the expression (y/1)(y/2)...(y/n) where m<=y<m+1, nearly all factors (those with n>y) are smaller than 1 and they get arbitrarily small as n goes to infinity. So now given your f_n(x), now we have that f(x)=0. That's certainly integrable and therefore it's all fine, it does not affect the rest of the proof.

    • @Jagoalexander
      @Jagoalexander Час назад

      Thank you

  • @winstonridgewayhardy
    @winstonridgewayhardy 11 часов назад

    I am happy there is no music (but no need to be so angry imho). Wonderfully explained but just a gentle constructive comment is maybe try to write a little more clearly. I know what is going on if I listen along but if I am just looking at the integral I start thinking what is planck's constant popping up in inappropriate place. Haha - just kidding - but you wrote the k really well once so I know you can do it :)

    • @Jagoalexander
      @Jagoalexander Час назад

      Yes this is a common theme, I'll wrote more clearly from now on 😅

  • @fderty4
    @fderty4 15 часов назад

    I could solve this integral in the bat of an eye. I chose not to 😎

  • @jorgenharmse4752
    @jorgenharmse4752 16 часов назад

    I'm not exactly opposed to differentiation under the integral sign, but there are conditions that have to be checked if we're doing mathematics (rather than formal manipulations that may or may not make sense). I find it easier to keep track of the conditions for Fubini's theorem (although the conditions for switching integration & differentiation may be equivalent). Here we have a positive integrand (a e^{-a^2(1+x^2)}), so integrating out x & then a or vice versa will give the same answer. 'Destroy' is an over-statement. The approach seems to me no more elegant than the usual polar-coordinates trick. I also suspect that knowing the answer already helped Feynman to find this path to calculate it. On the other hand, knowing the answer and having seen Feynman's solution to two other integrals (although I had also seen one of those presented using Fubini's theorem), I still had no clue what the trick would be in this case. I tried some ways of writing e^{-x^2} as an integral, but nothing helped.

  • @hamoudiayoub9341
    @hamoudiayoub9341 17 часов назад

    Integral is a continuous sum , we solve it by finding the value of that sum but you transfer it to a discreet sum

  • @well_said7846
    @well_said7846 18 часов назад

    The final result is mind blowing great work.😊

  • @sergiokorochinsky49
    @sergiokorochinsky49 19 часов назад

    Suggestion for future videos: Do not write the plus sign like a "t", specially if you are going to use the variable t.

  • @kalo2543
    @kalo2543 21 час назад

    Hello dude, Nice vidéo.. what app did u use in this video?

  • @PrometheusZandski
    @PrometheusZandski 21 час назад

    You are a gentleman and a scholar, sir. Apology accepted. I personally don't want music to distract my thought process when doing math. Absolutely amazing solution.

  • @AndyGoth111
    @AndyGoth111 22 часа назад

    0:37 I'll give you a second[INSTANT JUMP CUT]Right!

  • @rishy773
    @rishy773 День назад

    Hey! I was a bit confused on the very last part. Could you please explain how you rounded the 'sum of alternating inverse squares' to roughly 0.783431. From my limited understanding, the sum should approach (pi^2)/12, which is approximately 0.822467. Thanks for the awesome video either way!!

    • @Jagoalexander
      @Jagoalexander 23 часа назад

      It isn't the sum of inverse squares. If you look carefully each term is n^-n not n^-2

    • @rishy773
      @rishy773 16 часов назад

      @@Jagoalexander ohhhhhh. Thank you so much!

  • @VijayIyer-yq4iu
    @VijayIyer-yq4iu День назад

    I think this is wrong. n! = Gamma (n+1), not Gamma (n-1).

    • @Jagoalexander
      @Jagoalexander День назад

      My bad, I meant to write n+1, solution is still valid and works though

  • @victorfinberg8595
    @victorfinberg8595 День назад

    20:35 not sure if that step is valid. the numerator inside the integral is NOT exp[ 0 x constant ], it is exp [ zero x infinity ] gauss is rolling in his grave, to see mathematical rules treated so cavalierly.

  • @victorfinberg8595
    @victorfinberg8595 День назад

    suggestion: the only people who will be interested in this are likely to have at least one year of university calculus. however, your presentation is done at the level of quite introductory calculus. that's a mismatch. cut out some of the really basic stuff.

  • @ashishreddymv5827
    @ashishreddymv5827 День назад

    Isn’t limit n->infinity of fn(x)=0 for the first condition of the Dominating Convergence theorem? It doesn’t converge to xlnx

    • @maxchemtov3482
      @maxchemtov3482 22 часа назад

      Yes, I think f(x) and fn(x) were mislabelled. DCT is used for swapping a *limit* with an integral, and so in the case of a summation, the relavent sequence of functions is the sequence of partial sums. Take f(x) to be the whole integrand e^(xlnx) and fN(x) to be the sum from 0 to N of (xlnx)^n/n!. Then as N->infinity, fN pointwise converges to f (this is just the convergence of e^x). So we’re good to go!

    • @ashishreddymv5827
      @ashishreddymv5827 22 часа назад

      ​@@maxchemtov3482 thanks for the explanation

  • @misterjaxon2559
    @misterjaxon2559 День назад

    Your "u" looks an awful lot like your "k", leading to confusion.

  • @edreeves6440
    @edreeves6440 День назад

    Really interesting result but a laboured path through a lot of obvious steps.

    • @Jagoalexander
      @Jagoalexander День назад

      Which steps are obvious - I wanted to provide a digestible solution to the average viewer who may not have advanced maths classes in their repertoire

  • @AbhinavShah-hw5pz
    @AbhinavShah-hw5pz 2 дня назад

    Good work dude!! This is one of my favorite integrals and i really liked your explanation on how to solve it. Hoping for more to come! BTW, your voice is very soothing

  • @salmankhan2910
    @salmankhan2910 2 дня назад

    Bro we cannot expand it about x = 0.

    • @Jagoalexander
      @Jagoalexander 2 дня назад

      Explain?

    • @salmankhan2910
      @salmankhan2910 2 дня назад

      x^x is not defined at x=0 and we cannot even find limit of this function at x=0.

    • @krishnamaity5056
      @krishnamaity5056 День назад

      lim x→0 x*lnx = 0, so lim e^(x*lnx) = e^0 = 1. So, lim x→0 e^(ln(x^x)) = x^x = 1..... 0^0 is an indeterminate form obviously, but that only means that _x^y does not exist for x,y=0 in a defined fashion_, like it exists *uniquely* while x,y=1. But that doesn't affect the existence of the limit x→0 x^f(x) (y=f(x)...); the limit could be checked for existence or calculated from itself (if existed).

    • @salmankhan2910
      @salmankhan2910 День назад

      ​@@krishnamaity5056 Pls check differentiability at x = 0, since it's a must condition for expansion.

  • @nirjharchaudhuri6484
    @nirjharchaudhuri6484 2 дня назад

    the gamma function is incredibly cool! love the videos!

  • @X00000370
    @X00000370 2 дня назад

    good math fun...

  • @shreebhattacharjee3502
    @shreebhattacharjee3502 2 дня назад

    thank you so much!!

  • @shreebhattacharjee3502
    @shreebhattacharjee3502 2 дня назад

    amazing thank you so much!! 😊

  • @radiomanroud1559
    @radiomanroud1559 2 дня назад

    Absolutely brillant ! Thank you a lot

  • @alexpher6864
    @alexpher6864 2 дня назад

    Well done. Loved the music. It is slow because explanation are supposed to be slow, you can always fast forward it, but a fast presentation will be difficult to understand for many, with no easy fix.

  • @IcyGM
    @IcyGM 2 дня назад

    I loved the video and everything, but there's one thing that I would like clarification about. Isn't there any condition on the function that needs to be met in order to interchange the integral and the summation? And if so, was it satisfied here? Thank yih

    • @Jagoalexander
      @Jagoalexander 2 дня назад

      Check my latest video, where I go into detail about this I Solved the Impossible Bernoulli Integral! ruclips.net/video/T-1fFR8Nk6A/видео.html

  • @crazy_r7646
    @crazy_r7646 2 дня назад

    Work of art

  • @krishnamaity5056
    @krishnamaity5056 2 дня назад

    What answer did official Putnam authority give. Was it this one?

  • @TheFinav
    @TheFinav 2 дня назад

    Very nice presentation. Thanks.

  • @skilz8098
    @skilz8098 2 дня назад

    Perhaps rewrite this integral as being the integration from 0 to 1: x^(i^2 * x) dx Maybe this might help. We can think of the exponent: i^2 * x as being periodic where x is the multiple or enumerated counts of a rotation by 180 degrees or PI radians. If we look at i^2 as being sqrt(-1) * sqrt(-1) = -1. We know that the value of -1 is a 180-degree rotation of 1. We can use this along with the trigonometric properties to help solve this. From what I can see, there is no one exact result from this definite integral. In other words, it's not going to give you a discrete area, volume or region under a curve or manifold. It appears that it is going to give you a series or sequence of them with a specific periodicity determined by the magnitude of x within the exponential component.

  • @mauriziofenderico8348
    @mauriziofenderico8348 2 дня назад

    Thank you for the excellent demonstration and...NO MUSIC is perfect so one can really concentrate🙂😂

  • @SeekingTheLoveThatGodMeans7648
    @SeekingTheLoveThatGodMeans7648 3 дня назад

    When I actually went to school, I was quite bothered by things that were distracting or incomplete, for a grade was going to come to hold me responsible for it just the same. Now, nobody is grading me on following it. Still, some others may be trying to keep up with school, and bringing their concerns with them, and perhaps a MITE irritated with the whole thing, because a grade is going to result at the end. I will not cuss you out, but I will urge you to maximize the helpfulness. k is k. It is not h, it is not u. And if on top of it, some random music is coming, this makes it harder. (Turning the sound off is not a good option, for you are speaking.) Thank you very much for understanding. It's not all about you either.

  • @davidwilkie9551
    @davidwilkie9551 3 дня назад

    When learning any practical skills by repeating the rules harmonically to position cause-effect functions in numberness dominance sequences of positioning, (One Electron Theory Wave-packaging guesstimate), it is absolutely always NOW, e-Pi-i sync-duration instantaneously and the Universal state-ment of 1-0-infinity conformity to the Singularity-point Logarithmic Centre of Time Duration Timing, aka QM-TIME Completeness cause-effect Actuality. The exercise demonstrates how i-reflection rotation reduces 0-1-2-ness in 3-ness to the method of reverse-inverted Pi-bifurcation function. Physics combines nodal-vibrational point-line-circle strings and drum head mass-energy-momentum continuous unity-connection categorizations. From self-defining experience of embodiment, we extract the information of In-form-ation substantiation holography vanishing-into-no-thing Perspective Principle. Good practices.

  • @carltauber2939
    @carltauber2939 3 дня назад

    I'm not a mathematician. Is it appropriate to use height of human adults as an example of a normal distribution which is symmetric about the peak, and extends from negative to positive infinity. Height is restricted to positive numbers, and is not symmetric about the peak. Furthermore, humans have two sub-populations: men and women who have different average heights. Is it appropriate to lump them together? Also, for many of us, it's impossible to learn math and listen to music at the same time, please pick one or the other.

  • @gdcuaer4076
    @gdcuaer4076 3 дня назад

    Have a small question, isnt -a² (1+x²) = -a² -a²x² ? He wrote -a²x² Pls let me know if im right or wrong

    • @vegito609
      @vegito609 3 дня назад

      so u are right even he is right like and he dint only take -a²x² e^a*e^b=e^a+b laws of exponent join -2ae^-a^2*e^-a^2x^2 after joing u get what u wrote -2ae^-a² -a²x²

  • @looney1023
    @looney1023 3 дня назад

    Is this actually a Putnam question? What's the problem statement? It's a very cool result but how would a Putnam test taker know that the answer is simplified enough at the end, since it can't be evaluated exactly?

    • @Jagoalexander
      @Jagoalexander 2 дня назад

      The question was show the integral can be written as the sum

  • @paultaufalele1821
    @paultaufalele1821 3 дня назад

    Woa very cool result. Awesome vid

  • @DS-wm6rn
    @DS-wm6rn 3 дня назад

    I would say the problem solved in the video looks harder than the question asked in the actual exam. Namely, asking: "find this integral " does not give you any clues. On the other hand, asking: "prove that this integral equals to this sum" is quite a clue. So the video is a bit misleading/clickbaiting.

  • @dcy665
    @dcy665 3 дня назад

    Gave it a try, but the music is very distracting. Using closed captioning helped, but not really worth the effort when I wanted to actually learn something Feynman today

  • @stephenhicks826
    @stephenhicks826 3 дня назад

    Liked the music but perhaps a little quieter. I really enjoyed this presentation. Thanks.

  • @user-fz9go8pj4t
    @user-fz9go8pj4t 3 дня назад

    Actually you didn't explain why you could interchange the integral and the sum. This is due to the dominated convergence theorem. We must explain all the details why we can do it