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Sir class 9 ko length of perpendicular

Solution chai xaina ra sir?

Thankyou soo much sir❤

Sir can you make of sequence and series

Sir grade 9 ko sequence and series please 🙏

Tomorrow opt math exam

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Tqs

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Sir kun publication ko book ho

17:32 ma hjr le y axis ko question lai answer ma x axis manara lekhnu bhako xa kina

Sequence and series for class 8 sir plz bholi exam xa

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Sir 13:30 ma kina divide by 2 gareko kina

Very nice greatly explained

Sir first quadrant ma sin ra cosec positive ho.❤

Nice

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Thanks sir for your help ❤

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Today my exam

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Eyy sir sabai method bhuje trw yo elimination method tw bhujnw garo vayo sir 😢😢😢😢😢

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W teacher

thank u sir . tomorrow is my exam and u helped me a lot

To solve this problem, we will use the section formula. The section formula states: If a point divides the line segment joining two points and in the ratio , then: x = \frac{mx_2 + nx_1}{m + n}, \quad y = \frac{my_2 + ny_1}{m + n} Here: , , Ratio , i.e., , . Calculation: 1. For -coordinate: x = \frac{m x_2 + n x_1}{m + n} = \frac{2(9) + 5(4)}{2 + 5} = \frac{18 + 20}{7} = \frac{38}{7} 2. For -coordinate: y = \frac{m y_2 + n y_1}{m + n} = \frac{2(5) + 5(-5)}{2 + 5} = \frac{10 - 25}{7} = \frac{-15}{7} Final Answer: The coordinates of are: P\left(\frac{38}{7}, \frac{-15}{7} ight)

Aaija math xa

Thank you sir and today is my exam😅❤😂

please make of functions

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Ago bhanepaxi tw minus hunxa haina?

One of the best teacher 💀

Prism ma prisma hoina

Nice

Good teaching😊😊😊 sir

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Sar tax ko bare ma ne video banaunu na ❤

Thank you 👍

Hello sir solve this question please 🥺 sir (1 - sin^2 phi)/(1 + cos phi) + (1 + cos phi)/(sin phi) - (sin phi)/(1 - cos phi) = cot^2 phi * (1 - cos phi) Please sir help by solving this problem

Sir Thank you for your guidance ❤

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Thank u sir

Thank u sir 🙏