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The question is very interesting. The problem was very well changed in the direction of course ordinate geometry. However, the solution of cubic equation is a difficult procedure. The constant Co efficient of this equation is 3000 which has 32 divisors from 1, 2, 3, ......., 1000, 1500, 3000. One can not simply get a conclusion that x-10 is a factor of this equation. The student will check from +1,-1,+2,-2,+3,-3,+4,-4,+5,-5,+6,-6,+8,-8 and then to +10 and -10. Is there any simple method to solve at least one root of cubic equation. Further, this equation has two other roots also. Until one shows that these roots are imaginary, the solution is not complete.v

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Nice sir

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Keep it up sir 😊

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thank you sir

Truly interesting

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What a question sir ji with best solution

Super method ❤

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Mast sir....🔥🔥

Thank u sir for ur giving support

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What an idea sir ji ❤

bahut acha sir

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Happy teacher's day sir 🎉🎉

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